https://repl.it/repls/DeadlyRemarkableKeys
const test1 = {["123"]:{stuff: '123'}};
console.log(test1);
var test2 = [];
test2["123"] = {stuff: '123'};
console.log(test2);
I would like to get proper array with objects linked to keys, like in test2 variable, however written in style of test1 ? test1 results with test1[0][123], whereas I need test1[123].
Thank you
Using an array as key of an object looks weird.
Probably this is what you're looking for:
const test1 = {'123': {stuff: '123'}};
console.log(test1['123']); // prints {stuff: '123'};
Related
I am iterating over a collection of data, in my case, an array of objects. Here is a sample of 2 data points from it:
{
violation_id: '211315',
inspection_id: '268804',
violation_category: 'Garbage and Refuse',
violation_date: '2012-03-22 0:00',
violation_date_closed: '',
violation_type: 'Refuse Accumulation' },
{
violation_id: '214351',
inspection_id: '273183',
violation_category: 'Building Conditions',
violation_date: '2012-05-01 0:00',
violation_date_closed: '2012-04-17 0:00',
violation_type: 'Mold or Mildew' }
I need to create a new array of objects from this, one for each "violation_category" property. If Violation category already exists in the new array I am creating, i simply add the information to that existing category object (instead of having two "building conditions" objects for example, I would just add to an existing one).
However, I am having trouble assigning to the existing object if the current one exists (it's easy to check if it does not, but not the other way around). This is what am attempting to do currently:
if (violationCategory.uniqueCategoryName) {
violationCategory.uniqueCategoryName.violations = results[i].violation_id;
violationCategory.uniqueCategoryName.date = results[i].violation_date;
violationCategory.uniqueCategoryName.closed =
results[i].violation_date_closed;
} else {
category.violations = results[i].violation_id;
category.date = results[i].violation_date;
category.closed = results[i].violation_date_closed;
violationCategory.push(category);
}
In first condition, if this category (key) exists, I simply add to it, and in the second condition, this is where I am struggling. Any help appreciated. Thanks guys.
Just add an empty object to the key if there no object there :
violationCategory.uniqueCategoryName = violationCategory.uniqueCategoryName || {};
And only then, add the data you want to the object.
violationCategory.uniqueCategoryName.violations = results[i].violation_id;
violationCategory.uniqueCategoryName.date = results[i].violation_date;
violationCategory.uniqueCategoryName.closed =
results[i].violation_date_closed;
No condition needed.
Good luck!
Assuming that you have an input variable which is an array of objects, where the objects are looking like the objects of the question, you can generate your output like this:
var output = {};
for (var item of input) {
if (!output[item.violation_category]) output[item.violation_category] = [];
output[item.violation_category].push(item);
}
Of course you might customize it like you want.
I have a two dimensional array.
Like for example :
viewScope.myTest = [];
viewScope.myTest.push(["row1col1", "row1col2", "row1col3"]);
viewScope.myTest.push(["row2col1", "row2col2", "row2col3"]);
etc
In my combobox I would like to show all the values of column3.
How can I do this ?
To iterate through all 3rd Columns of the array, you would need to do something like this:
// Creating the Structure you already got
var viewScope = {
myTest: []
}
viewScope.myTest.push(["row1col1", "row1col2", "row1col3"]);
viewScope.myTest.push(["row2col1", "row2col2", "row2col3"]);
viewScope.myTest.push(["row3col1", "row3col2", "row3col3"]);
// Get the Combobox by ID
var myCombobox = document.getElementById("myCombo");
// Iterate through all options of myTest
for (var i in viewScope.myTest)
{
// Create a new Option for the Select
var option = document.createElement("option");
// Add the 3rd Columns as Text
option.text = viewScope.myTest[i][2];
// Add the Option to the Select
myCombobox.add(option);
}
Why?! - you are creating a 2 Dimensional Array. it works like: Array[row][col] from your example.
Because those are indexes, they start with 0 and count up to length-1.
Please take a look at: JSFiddle Link
Contrary to what you say, you don't have a 2-dim array. It's a 1-dim array that contains 2 1-dim arrays. To get only the values for column 3, you have to create a new array:
var col3values= [];
for(var i in viewScope.myTest)
if(viewScope.myTest[i].length>=3)
col3values.push(viewScope.myTest[i][2];
I have a xml string that i'm trying to convert to JSON using JSON.Net. The problem is that i want only certain part of this xml in my JSON string. Below is the code i use and what i need.
var x = XDocument.Parse(xmlString);
var json = JsonConvert.SerializeXNode(x);
This will convert the whole doc. This is how json string looks like in a JSON Viewer
What i want is ONLY the table (The Arrowed one in image 1) and its descendants to be inside string json.
Is it possible? How to achieve it? Can i use a custom ContractResolver with SerializeXnode?
You've got an XDocument, so why not simply select the part you want and then serialize just that part?
Try something like this:
var doc = XDocument.Parse(xmlString);
var table = doc.XPathSelectElement("//table[#class=\"form\"]");
var json = JsonConvert.SerializeXNode(table);
Note that XPathSelectElement is an extension method, so you will need using System.Xml.XPath; at the top of your code if you don't already have it.
EDIT
You can do it without XPath like this:
var doc = XDocument.Parse(xmlString);
var table = root.Descendants(XName.Get("table"))
.Where(e => e.Attributes(XName.Get("class"))
.Select(a => a.Value)
.FirstOrDefault() == "form")
.First();
var json = JsonConvert.SerializeXNode(table);
Both approaches give the same results, the table plus all descendants.
In MongoDb Shell
db.keyword.update({"state":"UT"}, {$unset:{'abc.def':1}});
unsets removes def from abc . However, if I do it like this :
var key = 'def'
var key1 = 'abc.'+key
db.keyword.update({"state":"UT"}, {$unset:{key1:1}});
doesnt unset def.
How do I get to unset "abc.def" by passing key1 ?
Yes, this is how json parser works. By the standard, hash keys must be enclosed in quotes, but some parsers are too forgiving and allow you to omit them. So, this is how mongo sees your code.
db.keyword.update({"state": "UT"}, {"$unset": {"key1": 1}});
You can get around this problem by constructing the hash manually. Something like this:
var key = 'def';
var key1 = 'abc.' + key;
var mod = {"$unset": {}};
mod["$unset"][key1] = 1;
db.keyword.update({"state": "UT"}, mod);
I am doing a few exhaustive searches and need to determine if a new domain (URL) is already in a Spreadsheet. However, none of the Spreadsheet objects have search functions, namely findText() found in most Document objects. I feel like I am missing something significant.
What am I missing?
findText function: https://developers.google.com/apps-script/class_table#findText
SearchResult object: https://developers.google.com/apps-script/class_searchresult
Spreadsheet object: https://developers.google.com/apps-script/class_sheet
My best guess is to try and convert specific Spreadsheet ranges in Document tables, then perform the search. Mendokusai
Unfortunately there is no searching functionality in the Spreadsheet services. You can get the data for the range you are searching on, and then iterate over it looking for a match. Here's a simple function that does that:
/**
* Finds a value within a given range.
* #param value The value to find.
* #param range The range to search in.
* #return A range pointing to the first cell containing the value,
* or null if not found.
*/
function find(value, range) {
var data = range.getValues();
for (var i = 0; i < data.length; i++) {
for (var j = 0; j < data[i].length; j++) {
if (data[i][j] == value) {
return range.getCell(i + 1, j + 1);
}
}
}
return null;
}
I wrote a search tool with a graphical user interface that performs a global search in 3 columns of a single sheet. It could be easily modified to suit your needs. I guess it would be a good idea to add an anchor in the UI to let you open the url you just found.
Here is the code, hoping it will help you to design your own version.
EDIT : I added the anchor widget in the code below (getting its ref in column E)
// G. Variables
var sh = SpreadsheetApp.getActiveSheet();
var ss = SpreadsheetApp.getActiveSpreadsheet();
var lastrow = ss.getLastRow();
//
function onOpen() {
var menuEntries = [ {name: "Search GUI", functionName: "searchUI"},
];
ss.addMenu("Search Utilities",menuEntries);// custom menu
}
// Build a simple UI to enter search item and show results + activate result's row
function searchUI() {
var app = UiApp.createApplication().setHeight(130).setWidth(400);
app.setTitle("Search by name / lastname / adress");
var panel = app.createVerticalPanel();
var txtBox = app.createTextBox().setFocus(true);
var label=app.createLabel(" Item to search for :")
panel.add(label);
txtBox.setId("item").setName("item");
var label0=app.createLabel("Row").setWidth("40");
var label1=app.createLabel("Name").setWidth("120");
var label2=app.createLabel("Lastname").setWidth("120");
var label3=app.createLabel("Street").setWidth("120");
var hpanel = app.createHorizontalPanel();
hpanel.add(label0).add(label1).add(label2).add(label3)
//
var txt0=app.createTextBox().setId("lab0").setName("0").setWidth("40");
var txt1=app.createTextBox().setId("lab1").setName("txt1").setWidth("120");
var txt2=app.createTextBox().setId("lab2").setName("txt2").setWidth("120");
var txt3=app.createTextBox().setId("lab3").setName("txt3").setWidth("120");
var hpanel2 = app.createHorizontalPanel();
hpanel2.add(txt0).add(txt1).add(txt2).add(txt3)
var hidden = app.createHidden().setName("hidden").setId("hidden");
var subbtn = app.createButton("next ?").setId("next").setWidth("250");
var link = app.createAnchor('', '').setId('link');
panel.add(txtBox);
panel.add(subbtn);
panel.add(hidden);
panel.add(hpanel);
panel.add(hpanel2);
panel.add(link);
var keyHandler = app.createServerHandler("click");
txtBox.addKeyUpHandler(keyHandler)
keyHandler.addCallbackElement(panel);
//
var submitHandler = app.createServerHandler("next");
subbtn.addClickHandler(submitHandler);
submitHandler.addCallbackElement(panel);
//
app.add(panel);
ss.show(app);
}
//
function click(e){
var row=ss.getActiveRange().getRowIndex();
var app = UiApp.getActiveApplication();
var txtBox = app.getElementById("item");
var subbtn = app.getElementById("next").setText("next ?")
var txt0=app.getElementById("lab0").setText('--');
var txt1=app.getElementById("lab1").setText('no match').setStyleAttribute("background", "white");// default value to start with
var txt2=app.getElementById("lab2").setText('');
var txt3=app.getElementById("lab3").setText('');
var link=app.getElementById('link').setText('').setHref('')
var item=e.parameter.item.toLowerCase(); // item to search for
var hidden=app.getElementById("hidden")
var data = sh.getRange(2,2,lastrow,4).getValues();// get the 4 columns of data
for(nn=0;nn<data.length;++nn){ ;// iterate trough
if(data[nn].toString().toLowerCase().match(item.toString())==item.toString()&&item!=''){;// if a match is found in one of the 4 fields, break the loop and show results
txt0.setText(nn+2);
txt1.setText(data[nn][0]).setStyleAttribute("background", "cyan");
txt2.setText(data[nn][1]);
txt3.setText(data[nn][2]);
link.setText(data[nn][3]).setHref(data[nn][3]);
sh.getRange(nn+2,2).activate();
subbtn.setText("found '"+item+"' in row "+Number(nn+2)+", next ?");
hidden.setValue(nn.toString())
break
}
}
return app ;// update UI
}
function next(e){
var row=ss.getActiveRange().getRowIndex();
var app = UiApp.getActiveApplication();
var txtBox = app.getElementById("item");
var subbtn = app.getElementById("next").setText("no other match")
var hidden=app.getElementById("hidden");
var start=Number(e.parameter.hidden)+1;//returns the last search index stored in the UI
var item=e.parameter.item.toLowerCase(); // item to search for
var txt0=app.getElementById("lab0");
var txt1=app.getElementById("lab1").setStyleAttribute("background", "yellow");
var txt2=app.getElementById("lab2");
var txt3=app.getElementById("lab3");
var link=app.getElementById('link').setText('').setHref('')
var data = sh.getRange(2,2,lastrow,4).getValues();// get the 4 columns of data
for(nn=start;nn<data.length;++nn){ ;// iterate trough
if(data[nn].toString().toLowerCase().match(item.toString())==item.toString()&&item!=''){;// if a match is found in one of the 4 fields, break the loop and show results
txt0.setText(nn+2);
txt1.setText(data[nn][0]).setStyleAttribute("background", "cyan");
txt2.setText(data[nn][1]);
txt3.setText(data[nn][2]);
link.setText(data[nn][3]).setHref(data[nn][3])
sh.getRange(nn+2,2).activate();
subbtn.setText("found '"+item+"' in row "+Number(nn+2)+", next ?");
hidden.setValue(nn.toString())
break
}
}
return app ;// update UI
}// eof 05-12 Serge insas
I ended up using spreadsheet formulas to solve my problem instead. Specifically, I used the MATCH() function, which can look up a string in an array (in this case a column in another sheet in the same document).
This is significantly simpler than looping through an array, though less efficient and does not allow for full automation. In fact, when the column reached 2,000 entries, Google Drive froze so often, I had to start using Excel instead. Nevertheless, the Match() solution was more appropriate for what I was looking for.
Appreciate all the other responses though.
You can "search" using the SpreadsheetAPI List Feed query parameter. This will return any row that matches using full word matching. Throw some asterisks around your parameter (URL encoded of course) and it becomes wildcard.
I have not tried it, but it appears that the Google Visualization API Query Language will allow you to execute SQL queries against Google sheets.