I would like to set the formula for a picture using VBA.
This is a portion of the simplified version of the VBA used to insert and modify a shape/picture from a given URL.
Dim theShape As Shape
Filename = cell
' Use Shapes instead so that we can force it to save with the document
Set theShape = ActiveSheet.Shapes.AddPicture( _
Filename:=Filename, linktofile:=msoFalse, _
savewithdocument:=msoCTrue, _
Left:=cell.Left, Top:=cell.Top, Width:=60, Height:=60)
With theShape
.LockAspectRatio = msoTrue
' Shape position and sizes stuck to cell shape
.Top = cell.Top + 1
.Left = cell.Left + 1
.Height = cell.Height - 2
.Width = cell.Width - 2
' Move with the cell (and size, though that is likely buggy)
.Placement = xlMoveAndSize
.Name = "Item" & cell.Row
'******What to enter here to set the "Formula" for the picture?
'Trying to set the formula to an existing named range, such as "FQPic3"
'Something like: .formula = FQPic3
End With
However, I don't see a picture property to set the formula.
Thank you.
This would allow you to set the formula:
Dim theShape As Shape
Filename = cell
' Use Shapes instead so that we can force it to save with the document
Set theShape = ActiveSheet.Shapes.AddPicture( _
Filename:=Filename, linktofile:=msoFalse, _
savewithdocument:=msoCTrue, _
Left:=cell.Left, Top:=cell.Top, Width:=60, Height:=60)
With theShape
.LockAspectRatio = msoTrue
' Shape position and sizes stuck to cell shape
.Top = cell.Top + 1
.Left = cell.Left + 1
.Height = cell.Height - 2
.Width = cell.Width - 2
' Move with the cell (and size, though that is likely buggy)
.Placement = xlMoveAndSize
.Name = "Item" & cell.Row
'******What to enter here to set the "Formula" for the picture?
'Trying to set the formula to an existing named range, such as "FQPic3"
'Something like: .formula = FQPic3
theShape.OLEFormat.Object.Formula = "=FQPic3"
End With
Side note: didn't check the rest of your code
Related
I was trying to insert some pictures that are saved on my desktop to an excel file.
I found that some online codes worked well. But it seemed that those inserted pictures were not saved with the documents - the inserted pictures won't be displayed when I opened the file on another computer. I am wondering how I should tweak the codes so it can save the inserted pictures within the excel? If possible with VBA, how to adjust the inserted pictures to their 50% dimensions? I am completely new to VBA. Sorry for this basic question.
Sub add_pictures_R2()
Dim i%, ppath$
For i = 2 To 145
' file name at column A
ppath = "C:\Users\myname\output\" & CStr(Cells(i, 1).Value) & ".png"
If Len(Dir(ppath)) Then
With ActiveSheet.Pictures.Insert(ppath)
With .ShapeRange
.LockAspectRatio = msoTrue
.Width = 75
.Height = 300
End With
.Left = ActiveSheet.Cells(i, 10).Left
.Top = ActiveSheet.Cells(i, 10).Top
.Placement = 1
.PrintObject = True
End With
End If
Next
End Sub
You can do either, edit the path of the file to go along with your excel file or you could embed it. For embedding I would look at this.
https://danny.fyi/embedding-and-accessing-a-file-in-excel-with-vba-and-ole-objects-4d4e7863cfff
Its a bit messy but you would achieve what you want to do with at least the file being in the document and not trying to transfer everything with it.
Try this (using Shapes.AddPicture)
Sub add_pictures_R2()
'Note - type identifiers such as `S`, `%` are very outdated...
Dim i As Long, ppath As String, ws As Worksheet, c As Range
Set ws = ActiveSheet 'use a specific/explicit sheet reference
For i = 2 To 145
ppath = "C:\Users\myname\output\" & CStr(ws.Cells(i, 1).Value) & ".png"
Set c = ws.Cells(i, 10) 'insertion point
'passing -1 to Width/Height preserves original size
With ws.Shapes.AddPicture(Filename:=ppath, linktofile:=msoFalse, _
savewithdocument:=msoTrue, _
Left:=c.Left, Top:=c.Top, Width:=-1, Height:=-1)
.LockAspectRatio = msoTrue
.Placement = xlMove
.Height = .Height / 2 'size to 50%
End With
Next i
End Sub
I got the answer from Jimmypop at mrexcel. It worked.
Sub add_pictures_R2()
Const folderPath As String = "C:\Users\YANG\output\"
Dim r As Long
Application.ScreenUpdating = False
With ActiveSheet
For r = 2 To .Cells(Rows.Count, "A").End(xlUp).Row
If Dir(folderPath & .Cells(r, "A").Value & ".png") <> vbNullString Then
.Shapes.AddPicture Filename:=folderPath & .Cells(r, "A").Value & ".png", _
LinkToFile:=False, SaveWithDocument:=True, _
Left:=ActiveSheet.Cells(r, 10).Left, Top:=ActiveSheet.Cells(r, 10).Top, Width:=.Cells(r, "C").Width, Height:=.Cells(r, "C").Height
Else
.Cells(r, "B").Value = "Not found"
End If
DoEvents
Next
End With
Set myDocument = Worksheets(1)
For Each s In myDocument.Shapes
Select Case s.Type
Case msoLinkedPicture, msoPicture
s.ScaleHeight 0.5, msoTrue
s.ScaleWidth 0.5, msoTrue
Case Else
' Do Nothing
End Select
Next
Application.ScreenUpdating = True
MsgBox "Done"
End Sub
Since a while I am trying to build a code to insert pictures in a cell in Excel and the result until now was very good. Thanks to several post on this webpage like:
Inserting picture using macro vba to adopt to a merged cell or single cell
VBA inserting picture into specific column of the table
How to insert a picture into Excel at a specified cell position with VBA
Insert picture into Excel and keep aspect ratio without exceeding dimensions with VBA
Get the size of a picture
What I found is that, it does not work when I try to adapt a picture with vertical format 4:3 or 16:9. The height of the photo is bigger than the height from the cell.
Also when I get the dimensions of the picture directly with VBA, the result of the code is that the width is bigger than the high. But, and here comes the interesting part, if I cut the photo only a bit it will work like usual. The code will work and the dimensions are right.
Somehow in those formats 4:3 or 16:9, and when the format is vertical, Excel exchanges the dimensions of the photo. Does anyone know why something like this could happen?
Update: Here is the code that I am using plus a link for one of the picture.
Sub Pictures()
Dim wb As Workbook
Set wb = ActiveWorkbook
counter = 0
strCompFilePath = wb.Sheets("List").Cells(1, 1)
If strCompFilePath <> "" Then
counter = counter + 1
Sheets("Template").Activate
Sheets("Template").Range("A" & counter).RowHeight = 250
Call Insert(strCompFilePath, counter)
End If
End Sub
Function Insert(PicPath, counter)
Dim l, r, t, b
Dim w, h ' width and height of range into which to fit the picture
Dim aspect ' aspect ratio of inserted picture
l = 1: r = 8 ' co-ordinates of top-left cell
t = counter: b = counter ' co-ordinates of bottom-right cell
With Sheets("Template").Pictures.Insert(PicPath)
With .ShapeRange
.LockAspectRatio = msoTrue
.Width = Range("H" & counter).Left + Range("H" & counter).Width - Range("A" & counter).Left
.Height = Range("H" & counter).Top + Range("H" & counter).Height - Range("A" & counter).Top
aspect = .Width / .Height ' calculate aspect ratio of picture
.Top = Range("A" & counter).Top + (Range("A" & counter).Height - .Height) / 2 'left placement of picture
.Left = Range("A" & counter).Left + Range("A:H").Left + (Range("A:H").Width - .Width) / 2 'top left placement of picture
End With
.Placement = 1 'Object is moved and sized with the cells
.PrintObject = True
End With
End Function
Update: Here is the updated code thanks to #RaymonWu:
Sub Pictures()
Dim wb As Workbook
Set wb = ActiveWorkbook
counter = 5
strCompFilePath = wb.Sheets("List").Cells(1, 1)
If strCompFilePath <> "" Then
counter = counter + 1
Sheets("Template").Activate
Sheets("Template").Range("A" & counter).RowHeight = 250
Call Insert(strCompFilePath, counter)
End If
End Sub
Function Insert(PicPath, counter)
With Sheets("Template").Pictures.Insert(PicPath)
With .ShapeRange
.LockAspectRatio = msoTrue
.Height = 250
.Top = Range("A" & counter).Top + (Range("A" & counter).Height -
.Height) / 2 'left placement of picture
.Left = Range("A" & counter).Left + Range("A:H").Left +
(Range("A:H").Width - .Width) / 2 'top left placement of picture
End With
.Placement = 1 'Object is moved and sized with the cells
.PrintObject = True
End With
End Function
And is the line .Height = 250 the one which is not actually working. I am starting to think that the code has no problem itself but Excel. Somehow it recognizes the width of the image as the height and vice versa.
I'm having an issue with the code below. I previously had a functioning with the insert picture method, but the pictures weren't being saved with the document. Please ignore the sizing component, as I will have to adjust this when I get the code working.
The object required error occurs in the line of code marked with **.
I'm very new to VBA, so please explain in the most simplistic terms.
If Not Intersect(Target, Range("IMG_FILE_ALL")) Is Nothing And Target.Value <> "" Then
Dim pic As String
pic = Target.Offset(0, 0).Value
Dim myPicture As Shape
**Set myPicture = ActiveSheet.Shapes.AddPicture(Filename:="C:\Users\wallacew\Pictures\Ex4.jpg", linktofile:=msoFalse, savewithdocument:=msoCTrue, Left:=rgTarget.Left, Top:=rgTarget.Top, Width:=-1, Height:=-1)**
Dim rng As Range
Set rng = Range(Target.Offset(0, 0), Target.Offset(12, 1))
With myPicture
.ShapeRange.LockAspectRatio = msoTrue
.Width = 333
.Top = rng.Top + 3
.Left = rng.Left + 3
End With
End If
I'm trying to help out a coworker with her VBA in Excel 2013. It looks like the macro is successfully pulling in the images from the designated path, but it dumps every single photo into cell A1.
Any thoughts?
Sub DeleteAllPictures()
Dim S As Shape
For Each S In ActiveSheet.Shapes
Select Case S.Type
Case msoLinkedPicture, msoPicture
S.Delete
End Select
Next
End Sub
Sub UpdatePictures()
Dim R As Range
Dim S As Shape
Dim Path As String, FName As String
'Setup the path
Path = "G:\In Transit\Carlos\BC Website images"
'You can read this value also from a cell, e.g.:
'Path = Worksheets("Setup").Range("B1")
'Be sure the path has a trailing backslash
If Right(Path, 1) <> "\" Then Path = Path & "\"
'Visit each used cell in column A
For Each R In Range("B1", Range("B" & Rows.Count).End(xlUp))
'Try to get the shape
Set S = GetShapeByName(R)
'Found?
If S Is Nothing Then
'Find the picture e.g. "C:\temp\F500.*"
FName = Dir(Path & R & ".*")
'Found?
If FName <> "" Then
Set S = InsertPicturePrim(Path & FName, R)
End If
End If
If Not S Is Nothing Then
'Show the error if the name did not match the cell
If S.Name <> R Then R.Interior.Color = vbRed
With R.Offset(0, 1)
'Move the picture to the cell on the right side
S.Top = .Top
S.Left = .Left
'Resize it
S.Width = .Width
'Remove the aspect ratio by default if necessary
'S.LockAspectRatio = False
If S.LockAspectRatio Then
'Make it smaller to fit the cell if necessary
If S.Height > .Height Then S.Height = .Height
Else
'Stretch the picture
S.Height = .Height
End If
End With
'Move it behind anything else
S.ZOrder msoSendToBack
Else
R.Offset(0, 1) = "No picture available"
End If
Next
End Sub
Private Function GetShapeByName(ByVal SName As String) As Shape
'Return the shape with SName, Nothing if not exists
On Error Resume Next
Set GetShapeByName = ActiveSheet.Shapes(SName)
End Function
Private Function InsertPicturePrim(ByVal FName As String, ByVal SName As String) As Shape
'Inserts the picture, return the shape, Nothing if failed
Dim P As Picture
On Error Resume Next
'Insert the picture
Set P = ActiveSheet.Pictures.Insert(FName)
'code to resize
With P
.ShapeRange.LockAspectRatio = msoFalse
.Height = ActiveCell.Height
.Width = ActiveCell.Width
.Top = ActiveCell.Top
.Left = ActiveCell.Left
.Placement = xlMoveAndSize
End With
Set P = Nothing
'code to resize
'Success?
If Not P Is Nothing Then
'Return the shape
Set InsertPicturePrim = P.ShapeRange(1)
'Rename it, so we can easily find it later
P.Name = SName
End If
End Function
The short answer is: your macro is inserting the picture at the selected cell. Change the selection before the insert line, and you should get it inserted at each row.
Here in this example, I am selecting the cell to the left of the cell you are pulling the name value from.
If FName <> "" Then
'select the cell 1 to the left of the cell containing the image name
R.Offset(0,-1).select
Set S = InsertPicturePrim(Path & FName, R)
End If
I am looking for a way to insert text into the background of a cell, so that I can still enter numbers on top of that text - similar to a watermark except for an individual cell. Any ways to do this, preferably without using a macro (but open to these solutions as well)?
Similar to Andrews post, this is the VBA version which formats the shape correctly and also allows direct selecting of cells.
Code MODULE:
Sub watermarkShape()
Const watermark As String = "watermark"
Dim cll As Range
Dim rng As Range
Dim ws As Worksheet
Dim shp As Shape
Set ws = Sheet1
Set rng = ws.Range("A1:F10") 'Set range to fill with watermark
Application.ScreenUpdating = False
For Each shp In ws.Shapes
shp.Delete
Next shp
For Each cll In rng
Set shp = ws.Shapes.AddShape(msoShapeRectangle, 5, 5, 5, 5)
With shp
.Left = cll.Left
.Top = cll.Top
.Height = cll.Height
.Width = cll.Width
.Name = cll.address
.TextFrame2.TextRange.Characters.Text = watermark
.TextFrame2.TextRange.Font.Name = "Tahoma"
.TextFrame2.TextRange.Font.Size = 8
.TextFrame2.VerticalAnchor = msoAnchorMiddle
.TextFrame2.TextRange.ParagraphFormat.Alignment = msoAlignCenter
.TextFrame2.WordWrap = msoFalse
.TextFrame.Characters.Font.ColorIndex = 15
.TextFrame2.TextRange.Font.Fill.Transparency = 0.35
.Line.Visible = msoFalse
' Debug.Print "'SelectCell (""" & ws.Name & """,""" & cll.address & """)'"
.OnAction = "'SelectCell """ & ws.Name & """,""" & cll.address & """'"
With .Fill
.Visible = msoTrue
.ForeColor.ObjectThemeColor = msoThemeColorBackground1
.Transparency = 1
.Solid
End With
End With
Next cll
Application.ScreenUpdating = True
End Sub
Sub SelectCell(ws, address)
Worksheets(ws).Range(address).Select
End Sub
UPDATE:
the example below assigns a watermark of the cell address to odd rows and leaves the even rows as the constant watermark. This is an exaple based on my comment that any cell can be assigned any watermark text based on whatever conditons you want.
Option Explicit
Sub watermarkShape()
Const watermark As String = "watermark"
Dim cll As Range
Dim rng As Range
Dim ws As Worksheet
Dim shp As Shape
Set ws = Sheet1
Set rng = ws.Range("A1:F10") 'Set range to fill with watermark
Application.ScreenUpdating = False
For Each shp In ws.Shapes
shp.Delete
Next shp
For Each cll In rng
Set shp = ws.Shapes.AddShape(msoShapeRectangle, 5, 5, 5, 5)
With shp
.Left = cll.Left
.Top = cll.Top
.Height = cll.Height
.Width = cll.Width
.Name = cll.address
If cll.Row Mod 2 = 1 Then
.TextFrame2.TextRange.Characters.Text = cll.address
Else
.TextFrame2.TextRange.Characters.Text = watermark
End If
.TextFrame2.TextRange.Font.Name = "Tahoma"
.TextFrame2.TextRange.Font.Size = 8
.TextFrame2.VerticalAnchor = msoAnchorMiddle
.TextFrame2.TextRange.ParagraphFormat.Alignment = msoAlignCenter
.TextFrame2.WordWrap = msoFalse
.TextFrame.Characters.Font.ColorIndex = 15
.TextFrame2.TextRange.Font.Fill.Transparency = 0.35
.Line.Visible = msoFalse
' Debug.Print "'SelectCell (""" & ws.Name & """,""" & cll.address & """)'"
.OnAction = "'SelectCell """ & ws.Name & """,""" & cll.address & """'"
With .Fill
.Visible = msoTrue
.ForeColor.ObjectThemeColor = msoThemeColorBackground1
.Transparency = 1
.Solid
End With
End With
Next cll
Application.ScreenUpdating = True
End Sub
Sub SelectCell(ws, address)
Worksheets(ws).Range(address).Select
End Sub
You can use a custom number format (select the cell(s), hit Ctrl+1, number formats, custom) to specify a light-grey text to display when the cell value is 0 - Color15 makes a nice watermark color:
[Black]000000;;[Color15]"(order number)";#
No messy shapes, no VBA, and the watermark disappears when the value is actually filled up.
And if you absolutely need to do it in VBA, then you can easily write a function that builds the format string based on some parameters:
Public Function BuildWatermarkFormat(ByVal watermarkText As String, Optional ByVal positiveFormat As String = "General", Optional ByVal negativeFormat As String = "General", Optional ByVal textFormat As String = "General") As String
BuildWatermarkFormat = positiveFormat & ";" & negativeFormat & ";[Color15]" & Chr(34) & watermarkText & Chr(34) & ";" & textFormat
End Function
And then you can do:
myCell.NumberFormat = BuildWatermarkFormat("Please enter a value")
myCell.Value = 0
And you can still supply custom formats for positive/negative values as per your needs; the only thing is that 0 is reserved for "no value" and triggers the watermark.
myCell.NumberFormat = BuildWatermarkFormat("Please enter a value", "[Blue]#,##0.00_)", "[Red](#,##0.00)")
myCell.Value = -25
Select the Cell where you want to make the Background.
Click "Insert" and insert a rectangular Shape in that location.
Right click on the shape - select "Format Shape"
Goto "Fill" and select "Picture or texture fill"
Goto “Insert from File” option
Select the picture you want to make water-mark
Picture will appear at the place of rectangular shape
Now click on the picture “right click” and select Format Picture
Goto “Fill” and increase the transparency as required to look it like a “Water Mark” or light beckground
This will get printed also.
taken from here
Type your text in a cell anywhere.
Copy it and it will be saved on the clipboard.
Insert a rectangular shape anywhere.
Right click and choose "Send to back".
This will make sure it will be at the background.
Right click and "Format Shape".
Do to tab "Fill" and click on "picture or texture fill".
At the "insert from" choose "clipboard".
Now whatever text you have copied onto your clipboard will be in the rectangular shape.
Resize the shape to fit the cell(s) you desired.
Adjust however you like for example remove the rectangular lines, add shadow, change font, remove background etc.