convert curl to python requests (pisignage API) - python-3.x

Question

I am trying to convert a curl of pisignage into python requests. The curl is,
curl -X POST "https://swagger.piathome.com/api/files" -H "accept:
application/json" -H "x-access-token: login_session_token" -H
"Content-Type: multipart/form-data" -F "Upload
file=#test.jpg;type=image/jpeg"
My code is,
import requests
files = {'Upload file': open('test.jpg', 'rb'), 'type': 'image/jpeg'}
headers = {'Content-type': 'multipart/form-data', 'accept': 'application/json', 'x-access-token': 'login_session_token'}
file_response = requests.post(
'https://swagger.piathome.com/api/files',
files=files,
headers=headers
)
print(file_response)
It returns 404. I tried uncurl, the code is:
import uncurl
u = uncurl.parse('curl -X POST "https://swagger.piathome.com/api/files" -H "accept: application/json" -H "x-access-token: login_session_token" -H "Content-Type: multipart/form-data" -F "Upload file=test.jpg;type=image/jpeg"')
print(u)
The output is ,
error: unrecognized arguments: -F Upload file=test.jpg;type=image/jpeg

Answer 1

After a day of searching it turns out the swagger documentation is incorrect.
use
files = {
'assets': (open('test.jpg', 'rb'))
}

Answer 2

Try this
import requests
headers = {
'accept': 'application/json',
'x-access-token': 'login_session_token',
'Content-Type': 'multipart/form-data',
}
files = {
'Upload file': (None, 'test.jpg;type'),
}
response = requests.post('https://swagger.piathome.com/api/files', headers=headers, files=files)
link to parse curl to request python