Using PySpark, I need to load "Properties" object (map's value) from an avro file into its own Spark dataframe. Such that, "Properties" from my avro file will become a dataframe with its elements and values as columns and rows. Hence, struggling to find some clear examples accomplishing that.
Schema of the file:
root
|-- SequenceNumber: long (nullable = true)
|-- Offset: string (nullable = true)
|-- EnqueuedTimeUtc: string (nullable = true)
|-- SystemProperties: map (nullable = true)
| |-- key: string
| |-- value: struct (valueContainsNull = true)
| | |-- member0: long (nullable = true)
| | |-- member1: double (nullable = true)
| | |-- member2: string (nullable = true)
| | |-- member3: binary (nullable = true)
|-- Properties: map (nullable = true)
| |-- key: string
| |-- value: struct (valueContainsNull = true)
| | |-- member0: long (nullable = true)
| | |-- member1: double (nullable = true)
| | |-- member2: string (nullable = true)
| | |-- member3: binary (nullable = true)
|-- Body: binary (nullable = true)
The resulting "Properties" dataframe loaded from the above avro file needs to be like this:
member0
member1
member2
member3
value
value
value
value
map_values is your friend.
Collection function: Returns an unordered array containing the values of the map.
New in version 2.3.0.
df_properties = df.select((F.map_values(F.col('Properties'))[0]).alias('vals')).select('vals.*')
Full example:
df = spark.createDataFrame(
[('a', 20, 4.5, 'r', b'8')],
['key', 'member0', 'member1', 'member2', 'member3'])
df = df.select(F.create_map('key', F.struct('member0', 'member1', 'member2', 'member3')).alias('Properties'))
df.printSchema()
# root
# |-- Properties: map (nullable = false)
# | |-- key: string
# | |-- value: struct (valueContainsNull = false)
# | | |-- member0: long (nullable = true)
# | | |-- member1: double (nullable = true)
# | | |-- member2: string (nullable = true)
# | | |-- member3: binary (nullable = true)
df_properties = df.select((F.map_values(F.col('Properties'))[0]).alias('vals')).select('vals.*')
df_properties.show()
# +-------+-------+-------+-------+
# |member0|member1|member2|member3|
# +-------+-------+-------+-------+
# | 20| 4.5| r| [38]|
# +-------+-------+-------+-------+
df_properties.printSchema()
# root
# |-- member0: long (nullable = true)
# |-- member1: double (nullable = true)
# |-- member2: string (nullable = true)
# |-- member3: binary (nullable = true)
I try to show maximum value from column while I group rows by date column.
So i tried this code
maxVal = dfSelect.select('*')\
.groupBy('DATE')\
.agg(max('CLOSE'))
But output looks like that:
+----------+----------+
| DATE|max(CLOSE)|
+----------+----------+
|1987-05-08| 43.51|
|1987-05-29| 39.061|
+----------+----------+
I wanna have output like below
+------+---+----------+------+------+------+------+------+---+----------+
|TICKER|PER| DATE| TIME| OPEN| HIGH| LOW| CLOSE|VOL|max(CLOSE)|
+------+---+----------+------+------+------+------+------+---+----------+
| CDG| D|1987-01-02|000000|50.666|51.441|49.896|50.666| 0| 50.666|
| ABC| D|1987-01-05|000000|51.441| 52.02|51.441|51.441| 0| 51.441|
+------+---+----------+------+------+------+------+------+---+----------+
So my question is how to change the code to have output with all columns and aggregated 'CLOSE' column?
Scheme of my data looks like below:
root
|-- TICKER: string (nullable = true)
|-- PER: string (nullable = true)
|-- DATE: date (nullable = true)
|-- TIME: string (nullable = true)
|-- OPEN: float (nullable = true)
|-- HIGH: float (nullable = true)
|-- LOW: float (nullable = true)
|-- CLOSE: float (nullable = true)
|-- VOL: integer (nullable = true)
|-- OPENINT: string (nullable = true)
If you want the same aggregation all your columns in the original dataframe, then you can do something like,
import pyspark.sql.functions as F
expr = [F.max(coln).alias(coln) for coln in df.columns if 'date' not in coln] # df is your datafram
df_res = df.groupby('date').agg(*expr)
If you want multiple aggregations, then you can do like,
sub_col1 = # define
sub_col2=# define
expr1 = [F.max(coln).alias(coln) for coln in sub_col1 if 'date' not in coln]
expr2 = [F.first(coln).alias(coln) for coln in sub_col2 if 'date' not in coln]
expr=expr1+expr2
df_res = df.groupby('date').agg(*expr)
If you want only one of the columns aggregated and added to your original dataframe, then you can do a selfjoin after aggregating
df_agg = df.groupby('date').agg(F.max('close').alias('close_agg')).withColumn("dummy",F.lit("dummmy")) # dummy column is needed as a workaround in spark issues of self join
df_join = df.join(df_agg,on='date',how='left')
or you can use a windowing function
from pyspark.sql import Window
w= Window.partitionBy('date')
df_res = df.withColumn("max_close",F.max('close').over(w))
I have a list as shown below:
It is of the type as shown below:
[(key1, [(key11, value11), (key12, value12)]), (key2, [(key21, value21), (key22, value22)...])...]
A sample structure is shown below:
[('1052762305',
[('1007819788', 0.9206884810054885),
('1005886801', 0.913818268123084),
('1003863766', 0.9131746152849486),
('1007811435', 0.9128666156173751),
('1005879599', 0.9126368405937075),
('1003705572', 0.9122051062936369),
('1007804896', 0.9083424459788203),
('1005890270', 0.8982097535650703),
('1007806781', 0.8708761186829758),
('1003670458', 0.8452789033694487)]),
('1064808607',
[('1007804896', 0.9984397647563017),
('1003705572', 0.9970498347406341),
('1005879599', 0.9951581013190172),
('1007811435', 0.9934813787902085),
('1005886801', 0.9930572794622374),
('1003863766', 0.9928815742735568),
('1007819788', 0.9869723713790797),
('1005890270', 0.9642640856016443),
('1007806781', 0.9211558765137313),
('1003670458', 0.8519872445941068)])]
I want to convert this into a dataframe of the form
key1 key2 score
1052762305 1007819788 0.9206884810054885
1052762305 1005886801 0.913818268123084
1052762305 1003863766 0.9131746152849486
... ... ...
1064808607 1007804896 0.9984397647563017
1064808607 1003705572 0.9970498347406341
1064808607 1005879599 0.9951581013190172
... ... ...
How can we implement this in pyspark?
You can create a schema upfront with the input. Use explode and access the elements with in the value struct.
from pyspark.sql import SparkSession
from pyspark.sql import functions as F
from pyspark.sql.types import StructType, StructField,StringType,ArrayType, DoubleType
spark = SparkSession.builder \
.appName('SO')\
.getOrCreate()
schema = StructType([StructField("key1",StringType()), StructField("value",ArrayType(
StructType([ StructField("key2", StringType()),
StructField("score", DoubleType())])
)) ])
df = spark.createDataFrame(
[('1052762305',
[('1007819788', 0.9206884810054885),
('1005886801', 0.913818268123084),
('1003863766', 0.9131746152849486),
('1007811435', 0.9128666156173751),
('1005879599', 0.9126368405937075),
('1003705572', 0.9122051062936369),
('1007804896', 0.9083424459788203),
('1005890270', 0.8982097535650703),
('1007806781', 0.8708761186829758),
('1003670458', 0.8452789033694487)]),
('1064808607',
[('1007804896', 0.9984397647563017),
('1003705572', 0.9970498347406341),
('1005879599', 0.9951581013190172),
('1007811435', 0.9934813787902085),
('1005886801', 0.9930572794622374),
('1003863766', 0.9928815742735568),
('1007819788', 0.9869723713790797),
('1005890270', 0.9642640856016443),
('1007806781', 0.9211558765137313),
('1003670458', 0.8519872445941068)])
],schema
)
df.show()
+----------+--------------------+
| key1| value |
+----------+--------------------+
|1052762305|[[1007819788, 0.9...|
|1064808607|[[1007804896, 0.9...|
+----------+--------------------+
df.printSchema()
root
|-- key1: string (nullable = true)
|-- value: array (nullable = true)
| |-- element: struct (containsNull = true)
| | |-- key2: string (nullable = true)
| | |-- score: double (nullable = true)
df1=df.select('key1',F.explode('value').alias('value'))
df1.show()
+----------+--------------------+
| key1| value |
+----------+--------------------+
|1052762305|[1007819788, 0.92...|
|1052762305|[1005886801, 0.91...|
|1052762305|[1003863766, 0.91...|
|1052762305|[1007811435, 0.91...|
|1052762305|[1005879599, 0.91...|
|1052762305|[1003705572, 0.91...|
|1052762305|[1007804896, 0.90...|
|1052762305|[1005890270, 0.89...|
|1052762305|[1007806781, 0.87...|
|1052762305|[1003670458, 0.84...|
|1064808607|[1007804896, 0.99...|
|1064808607|[1003705572, 0.99...|
|1064808607|[1005879599, 0.99...|
|1064808607|[1007811435, 0.99...|
|1064808607|[1005886801, 0.99...|
|1064808607|[1003863766, 0.99...|
|1064808607|[1007819788, 0.98...|
|1064808607|[1005890270, 0.96...|
|1064808607|[1007806781, 0.92...|
|1064808607|[1003670458, 0.85...|
+----------+--------------------+
df1.printSchema()
root
|-- key1: string (nullable = true)
|-- value: struct (nullable = true)
| |-- key2: string (nullable = true)
| |-- score: double (nullable = true)
df1.select("key1", "value.key2","value.score").show()
+----------+----------+------------------+
| key1| key2| score|
+----------+----------+------------------+
|1052762305|1007819788|0.9206884810054885|
|1052762305|1005886801| 0.913818268123084|
|1052762305|1003863766|0.9131746152849486|
|1052762305|1007811435|0.9128666156173751|
|1052762305|1005879599|0.9126368405937075|
|1052762305|1003705572|0.9122051062936369|
|1052762305|1007804896|0.9083424459788203|
|1052762305|1005890270|0.8982097535650703|
|1052762305|1007806781|0.8708761186829758|
|1052762305|1003670458|0.8452789033694487|
|1064808607|1007804896|0.9984397647563017|
|1064808607|1003705572|0.9970498347406341|
|1064808607|1005879599|0.9951581013190172|
|1064808607|1007811435|0.9934813787902085|
|1064808607|1005886801|0.9930572794622374|
|1064808607|1003863766|0.9928815742735568|
|1064808607|1007819788|0.9869723713790797|
|1064808607|1005890270|0.9642640856016443|
|1064808607|1007806781|0.9211558765137313|
|1064808607|1003670458|0.8519872445941068|
You basically need to do following:
create a dataframe from your list
promote the pairs from elements of array into a separate row by using explode
extract key & value from pair via select
This could be done by something like this (source data is in the variable called a):
from pyspark.sql.functions import explode, col
df = spark.createDataFrame(a, ['key1', 'val'])
df2 = df.select(col('key1'), explode(col('val')).alias('val'))
df3 = df2.select('key1', col('val')._1.alias('key2'), col('val')._2.alias('value'))
we can check that schema & data is matching:
>>> df3.printSchema()
root
|-- key1: string (nullable = true)
|-- key2: string (nullable = true)
|-- value: double (nullable = true)
>>> df3.show(2)
+----------+----------+------------------+
| key1| key2| value|
+----------+----------+------------------+
|1052762305|1007819788|0.9206884810054885|
|1052762305|1005886801| 0.913818268123084|
+----------+----------+------------------+
only showing top 2 rows
we can also check the schema for intermediate results:
>>> df.printSchema()
root
|-- key1: string (nullable = true)
|-- val: array (nullable = true)
| |-- element: struct (containsNull = true)
| | |-- _1: string (nullable = true)
| | |-- _2: double (nullable = true)
>>> df2.printSchema()
root
|-- key1: string (nullable = true)
|-- val: struct (nullable = true)
| |-- _1: string (nullable = true)
| |-- _2: double (nullable = true)
I have a file(csv) which when read in spark dataframe has the below values for print schema
-- list_values: string (nullable = true)
the values in the column list_values are something like:
[[[167, 109, 80, ...]]]
Is it possible to convert this to array type instead of string?
I tried splitting it and using code available online for similar problems:
df_1 = df.select('list_values', split(col("list_values"), ",\s*").alias("list_values"))
but if I run the above code the array which I get skips a lot of values in the original array i.e.
output of the above code is:
[, 109, 80, 69, 5...
which is different from original array i.e. (-- 167 is missing)
[[[167, 109, 80, ...]]]
Since I am new to spark I don't have much knowledge how it is done (For python I could have done ast.literal_eval but spark has no provision for this.
So I'll repeat the question again :
How can I convert/cast an array stored as string to array i.e.
'[]' to [] conversion
Suppose your DataFrame was the following:
df.show()
#+----+------------------+
#|col1| col2|
#+----+------------------+
#| a|[[[167, 109, 80]]]|
#+----+------------------+
df.printSchema()
#root
# |-- col1: string (nullable = true)
# |-- col2: string (nullable = true)
You could use pyspark.sql.functions.regexp_replace to remove the leading and trailing square brackets. Once that's done, you can split the resulting string on ", ":
from pyspark.sql.functions import split, regexp_replace
df2 = df.withColumn(
"col3",
split(regexp_replace("col2", r"(^\[\[\[)|(\]\]\]$)", ""), ", ")
)
df2.show()
#+----+------------------+--------------+
#|col1| col2| col3|
#+----+------------------+--------------+
#| a|[[[167, 109, 80]]]|[167, 109, 80]|
#+----+------------------+--------------+
df2.printSchema()
#root
# |-- col1: string (nullable = true)
# |-- col2: string (nullable = true)
# |-- col3: array (nullable = true)
# | |-- element: string (containsNull = true)
If you wanted the column as an array of integers, you could use cast:
from pyspark.sql.functions import col
df2 = df2.withColumn("col3", col("col3").cast("array<int>"))
df2.printSchema()
#root
# |-- col1: string (nullable = true)
# |-- col2: string (nullable = true)
# |-- col3: array (nullable = true)
# | |-- element: integer (containsNull = true)