find aria-label in html page using soup python - python-3.x

Question

i have html pages, with this code :
<span itemprop="title" data-andiallelmwithtext="15" aria-current="page" aria-label="you in page
number 452">page 452</span>
i want to find the aria-label, so i have tried this:
is_452 = soup.find("span", {"aria-label": "you in page number 452"})
print(is_452)
i want to get the result :
is_452 =page 452
i'm getting the result:
is_452=none
how to do it ?

Answer 1

It has line breaks in it, so it doesn't match through text.Try the following
from simplified_scrapy.simplified_doc import SimplifiedDoc
html='''<span itemprop="title" data-andiallelmwithtext="15" aria-current="page" aria-label="you in page
number 452">page 452</span>'''
doc = SimplifiedDoc(html)
is_452 = doc.getElementByReg('aria-label="you in page[\s]*number 452"',tag="span")
print (is_452.text)

Answer 2

Possibly the desired element is a dynamic element and you can use Selenium to extract the value of the aria-label attribute inducing WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "section#header a.cart-heading[href='/cart']"))).get_attribute("aria-label"))
Using XPATH:
print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//section[#id='header']//a[#class='cart-heading' and #href='/cart']"))).get_attribute("aria-label"))
Note : You have to add the following imports:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Answer 3

The reason soup fails in doing this is because of the line break. I have a simpler solution which doesn't use any separate library, just BeautifulSoup only. I know this question is old, but it has 1k views so it's clear many people search up this question.
You can use triple-quote strings to take into account the newline.
This:
is_452 = soup.find("span", {"aria-label": "you in page number 452"})
print(is_452)
Would become:
search_label = """you in page
number 452"""
is_452 = soup.find("span", {"aria-label": search_label})
print(is_452)