I know from experience that if I try to open the same file in Vim in multiple terminals at the same time, I get an error. (Maybe because of temporary files?)
And I know from experience that if I open a text file in Python and read through it, I have to reset the pointer when I'm done.
But I've found that if I run the same Python script in multiple terminals at the same time, I don't get any error; it just successfully runs the script in both. How does this work? Doesn't Python need to read my script from the beginning in order to run it? Is the script copied to a temporary file, or something?
I know from experience that if I try to open the same file in Vim in multiple terminals at the same time, I get an error.
That's not actually true. Vim actually will let you open the same file in multiple terminals at the same time; it's just that it gives you a warning first to let you know that this is happening, so you can abort before you make changes. (It's not safe to modify the file concurrently in two different instances of Vim, because the two instances won't coordinate at all.)
Furthermore, Vim will only give you this warning if you try to open the same file for editing in multiple terminals at the same time. It won't complain if you're just opening the file for reading (using the -R flag).
And I know from experience that if I open a text file in Python and read through it, I have to reset the pointer when I'm done.
That's not exactly true, either. If you make multiple separate calls to open, you'll have multiple separate file objects, and each separately maintains its position in the file. So something like
with open('filename.txt', 'r') as first:
with open('filename.txt', 'r') as second:
print(first.read())
print(second.read())
will print the complete contents of filename.txt twice.
The only reason you'd need to reset the position when you're done reading a file is if you want to use the same file object to read the file again, or if you've opened the file in read/write mode (r+ rather than r) and you now want to switch from reading to writing.
But I've found that if I run the same Python script in multiple terminals at the same time, I don't get any error; it just successfully runs the script in both. How does this work? Doesn't Python need to read my script from the beginning in order to run it? Is the script copied to a temporary file, or something?
As I think should now be clear — there's no problem here. There's no reason that two instances of Python can't both read the same script file at the same time. Linux allows that. (And in fact, if you delete the file, Linux will keep the file on disk until all programs that had it open have either closed it or exited.)
In fact, there's also no reason that two processes can't write to the same file at the same time, though here you have to be very careful to avoid the processes causing problems for each other or corrupting the file.
terminal is just running the command you said it to execute, there is no pointer or anything
you jus
Related
Working with Pure Data, trying to record audio output from a patch I've made, and am 1) unable to create a file within pure data to write to and 2) attempting to use the writesf~ object causes the program to freeze after about two to three seconds. I suspect the two things are related- perhaps the program is attempting to write data somewhere, somehow, but it's going in the wrong place or some such and causing the program to freeze?
I've uninstalled the latest Pure Data release (0.51-1) and installed an earlier stable release (0.5-2) and even tried an alternative called "purr data (latest release)" all with the exact same result on my windows 10 acer laptop: no file created, and program freezes after a few seconds.
I'm testing with this patch:
I first click on the message that reads "open rec.wav" then the start then the stop, and if I take longer than three or so seconds to click on "stop" the program freezes, otherwise nothing at all happens.
I have performed system wide search for the audio file, including the folder that the patch is in, all to no avail.
Any trouble shooting hints will be carefully attempted.
Are you sure you have write-permissions on the target directory?
If your example you use rec.wav which has no explicit target directory (and is just using the "current", so it's hard to tell from outside what this directory would be).
#max-n's answer suggests to use /tmp/foo.wav which is an illegal directory on Windows. Due to a known bug, using an illegal (or otherwise non-writable) path will lock up Pd.
If your "current" directory happens to be your system root (aka C:\), you might well lack the permissions to write there.
You could check by starting the Pd from the cmdline and see whether the terminal spits out any weird errors:
⊞ Win+R
type cmd and hit Enter
in the opening terminal type the full path to your Pd-executable, e.g.:
C:\Program Files\Pd\bin\pd + Enter
(ideally leave out the extension (that is: use .../pd rather than .../pd.exe)
If the problem is indeed a permission problem, you can simply work around it by specifying the full path of the output file (and make sure that it is in a writable directory).
The easiest way to do this is by using a file-selector to choose the output file:
[bang(
|
[savepanel]
|
[open $1(
|
[writesf~]
There might be a reason why the helpfile uses a [delay 1000] to schedule a stop message in a predefined time.
I a series of applications on Linux systems that I need to basically constantly 'stream' out or even just 'tail' out but the challenge is the filenames are constantly rolling and changing.
The are all date encoded (dates being in different formats) and each then have different incremented formats.
Most of them start with one and increase, but one doesn't have an extension and then adds an extension past the first file and the other increments a number but once hitting 99 rolls to increment a alpha and returns the numeric to 01 and then up again as it rolls so quickly.
I just have the OS level shell scripting, OS command line utilities, and perl available to me to handle this situation for another application to pickup and read these logs.
The new files are always created right when it starts writing to the new file and groups of different logs (some I am reading some I am not) are being written to the same directory so I cannot just pickup anything hitting the directory.
If I simply 'tail -n 1000000 -f |' them today this works fine for the reader application I am using until the file changes and I cannot setup file lists ranges within the reader application, but can pre-process them so they basically appear as a continuous stream to the reader vs. the reader directly invoking commands to read them. A simple Perl log reader like this also work fine for a static filename but not for dynamic ones. It is critical I don't re-process any logs lines and just capture new lines being written to the logs.
I admit I am not any form a Perl guru, and the best answers / clue I've been able to find so far is the use of Perl's Glob function to possibly do this but the examples I've found basically reprocess all of the files on each run then seem to stop.
Example File Names I am dealing with across multiple apps I am trying to handle..
appA_YYMMDD.log
appA_YYMMDD_0001.log
appA_YYMMDD_0002.log
WS01APPB_YYMMDD.log
WS02APPB_YYMMDD.log
WS03AppB_YYMMDD.log
APPCMMDD_A01.log
APPCMMDD_B01.log
YYYYMMDD_001_APPD.log
As denoted above the files do not have the same inode and simply monitoring the directory for change is not possible as a lot of things are written there. On the dev system it has more than 50 logs being written to the directory and thousands of files and I am only trying to retrieve 5. I am seeing if multitail can be made available to try that suggestion but it is not currently available and installing any additional RPMs in the environment is generally a multi-month battle.
ls -i
24792 APPA_180901.log
24805 APPA__180902.log
17011 APPA__180903.log
17072 APPA__180904.log
24644 APPA__180905.log
17081 APPA__180906.log
17115 APPA__180907.log
So really the root of what I am trying to do is simply a continuous stream regardless if the file name changes and not have to run the extract command repeatedly nor have big breaks in the data feed while some script figures out that the file being logged to has changed. I don't need to parse the contents (my other app does that).. Is there an easy way of handling this changing file name?
How about monitoring the log directory for changes with Linux inotify, e.g. Linux::inotify2? Then you could detect when new log files are created, stop reading from the old log file and start reading from the new log file.
Try tailswitch. I created this script to tail log files that are rotated daily and have YYYY-MM-DD on their names. To use this script, you just say:
% tailswitch '*.log'
The quoting prevents the shell from interpreting the glob pattern. The script will perform glob pattern from time to time to switch to a newer file based on its name.
When running an interactive session, PyCharm thinks of os.getcwd() as my project's directory. However, when I run my script from the command line, PyCharm thinks of os.getcwd() as the directory of the script.
Is there a good workaround for this? Here is what I tried and did not like:
going to Run/Edit Configurations and changing the working directory manually. I did not like this solution, because I will have to do it for every script that I run.
having one line in my code that "fixes" the path for the purposes of interactive sessions and commenting it out before running from command line. This works, but feels wrong.
Is there a way to do this or is it just the way it is supposed to be? Maybe I shouldn't be trying to run random scripts within my project?
Any insight would be greatly appreciated.
Clarification:
By "interactive session" I mean being able to run each line individually in a Python/IPython Console
By "running from command line" I mean creating a script my_script.py and running python path_to_myscript/my_script.py (I actually press the Run button at PyCharm, but I think it's the same).
Other facts that might prove worth mentioning:
I have created a PyCharm project. This contains (among other things) the package Graphs, which contains the module Graph and some .txt files. When I do something within my Graph module (e.g. read a graph from a file), I like to test that things worked as expected. I do this by running a selection of lines (interactively). To read a .txt file, I have to go (using os.path.join()) from the current working directory (the project directory, ...\\project_name) to the module's directory ...\\project_name\\Graphs, where the file is located. However, when I run the whole script via the command line, the command reading the .txt file raises an Error, complaining that no file was found. By looking on the name of the file that was not found, I see that the full file name is something like this:
...\\project_name\\Graphs\\Graphs\\graph1.txt
It seems that this time the current working directory is ...\\project_name\\Graphs\\, and my os.path.join() command actually spoils it.
I user various methods in my python scripts.
set the working directory as first step of your code using os.chdir(some_existing_path)
This would mean all your other paths should be referenced to this, as you hard set the path. You just need to make sure it works from any location and your specifically in your IDE. Obviously, another os.chdir() would change the working directory and os.getcwd() would return the new working directory
set the working directory to __file__ by using os.chdir(os.path.dirname(__file__))
This is actually what I use most, as it is quite reliable, and then I reference all further paths or file operations to this. Or you can simply refer to as os.path.dirname(__file__) in your code without actually changing the working directory
get the working directory using os.getcwd()
And reference all path and file operations to this, knowing it will change based on how the script is launched. Note: do NOT assume that this returns the location of your script, it returns the working directory of the shell !!
[EDIT based on new information]
By "interactive session" I mean being able to run each line
individually in a Python/IPython Console
By running interactively line-by-line in a Python console, the __file__ is not defined, afterall: you are not executing a file. Hence you cannot use os.path.dirname(__file__) you will have to use something like os.chdir(some_known_existing_dir) to reference a path. As a programmer you need to be very aware of working directory and changes to this, your code should reflect that.
By "running from command line" I mean creating a script my_script.py
and running python path_to_myscript/my_script.py (I actually press the
Run button at PyCharm, but I think it's the same).
This, both executing a .py from command line as well as running in your IDE, will populate the __file__, hence you can use os.path.dirname(__file__)
HTH
I am purposely adding another answer to this post, in regards the following:
Other facts that might prove worth mentioning:
I have created a PyCharm project. This contains (among other things)
the package Graphs, which contains the module Graph and some .txt
files. When I do something within my Graph module (e.g. read a graph
from a file), I like to test that things worked as expected. I do this
by running a selection of lines (interactively). To read a .txt file,
I have to go (using os.path.join()) from the current working directory
(the project directory, ...\project_name) to the module's directory
...\project_name\Graphs, where the file is located. However, when I
run the whole script via the command line, the command reading the
.txt file raises an Error, complaining that no file was found. By
looking on the name of the file that was not found, I see that the
full file name is something like this:
...\project_name\Graphs\Graphs\graph1.txt It seems that this time
the current working directory is ...\project_name\Graphs\, and my
os.path.join() command actually spoils it.
I strongly believe that if a python script takes input from any file, that the author of the script needs to cater for this in the script.
What I mean is you as the author need to make sure you know the following regardless of how your script is executed:
What is the working directory
What is the script directory
These two you have no control over when you hand off your script to others, or run it on other peoples machines. The working directory is dependent on how the script is launched. It seems that you run on Windows, so here is an example:
C:\> c:\python\python your_script.py
The working directory is now C:\ if your_script.py is in C:\
C:\some_dir\another_dir\> c:\python\python.exe c:\your_script_dir\your_script.py
The working directory is now C:\some_dir\another_dir
And the above example may even give different results if the SYSTEM PATH variable is set to the path of the location of your_script.py
You need to ensure that your script works even if the user(s) of your script are placing this in various locations on their machines. Some people (and I don't know why) tend to put everything on the Desktop. You need to ensure your script can cope with this, including any spaces in the path name.
Furthermore, if your script is taking input from a file, the you as the author need to ensure that you can cope with changes in working directory, and changes of script directory. There are a few things you may consider:
Have your script input from a known (static) directory, something like C:\python_input\
Have your script input from a known (configurable) directory, use ConfigParser, you can search here on stackoverflow on many posts
Have your script input from a known directory related to the location of the script (using os.path.dirname(__file__))
any other method you may employ to ensure your script can get to the input
Ultimately this is all in your control, and you need to code to ensure it is working.
HTH,
Edwin.
I am writing a program that handles some data on a server. Throughout the program, many files are made and sent as input into other programs. To do this, I usually make the command string, then run it like so:
cmd = "prog input_file1 input_file2 > outputfile"
os.system(cmd)
When I run the command, however, the programs being called report that they cannot open the files. If I run the python code on my local computer, it is fine. When I loaded it onto the server, it started to fail. I think this is related to issues with permissions, but am not sure how I can fix this. Many of the files, particularly the output files, are being created at run time. The input files have full permissions for all users. Any help or advice would be appreciated!
Cheers!
The python code you list is simple and correct, so the problem is likely not in the two lines of your example. Here are some related areas for you to check out.
Permissions
The user running the python script must have the appropriate permission (read, write, execute). I see from comments that you've already checked this.
What command are you running
If the command is literally typed into your source code like in the example, then you know what command is being run, but if you are generating any part of it (eg. the list of operands, the name of the output file, other parameters, etc), make sure there are no bugs in the portions of your code that generate the command. For example before the call to os.system(cmd) consider including a line like print("About to execute: " + cmd) so you can see exactly what will be run.
Directly invoke the command
If all the above looks good, try to execute the command directly at a terminal on your server. What output do you get then. It's possible that the problem is with the underlying command itself rather than your python code.
I thought about a concurrency issue (in Solaris), what happen if while reading someone tries to delete the same file. I have a query regarding file existence in the Solaris/Linux. suppose I have a file test.txt, I have open it in vi editor, and then I have open a duplicate session and remove that file, but even after deleting that file I am able to read that file. so here are my questions:
Do I need to thinks about any locking mechanism while reading, so no one able to delete same file while reading.
What is the reason of showing different behavior from windows(like in windows if file is open in in some editor than we can not delete that file)
After removing that file, how I am still able to read that file, if I haven't closed file from vi editor.
I am asking files in general,but yes platform specific i.e. unix. what will happen if I am using a java program (buffer reader) for read file and file is deleted while reading, does buffer reader still able to read the file for next chunk or not?
You have basically 2 or 3 unrelated questions there. Text editors like to read the whole file into memory at the start of the editing session. Imagine every character you type being saved to disk immediately, with all characters after it in the file being rewritten one place further along to make room. That would be awful. Much better that the thing you're actually editing is a memory representation of the file (array of pointers to lines, probably with some metadata attached) which only gets converted back into a linear stream when you explicitly save.
Any relatively recent version of vim will notify you if the file you are editing is deleted from its original location with the message
E211: File "filename" no longer available
This warning is not just for unix. gvim on Windows will give it to you if you delete the file being edited. It serves as a reminder that you need to save the version you're working on before you exit, if you don't want the file to be gone.
(Note: the warning doesn't appear instantly - vim only checks for the original file's existence when you bring it back into the foreground after having switched away from it.)
So that's question 1, the behavior of text editors - there's no reason for them to keep the file open for the whole session because they aren't actually using it except at startup and during a save operation.
Question 2, why do some Windows editors keep the file open and locked - I don't know, Windows people are nuts.
Question 3, the one that's actually about unix, why do open files stay accessible after they're deleted - this is the most interesting one. The answer, guaranteed to shock you when presented directly:
There is no command, function, syscall, or any other method which actually requests deletion of a file.
Underlying rm and any other command that may appear to delete a file there is the system call unlink. And it's called unlink, not remove or deletefile or anything similar, because it doesn't remove a file. It removes a link (a.k.a. directory entry) which is an association between a file and a name in a directory. (Note: ANSI C added remove as a more generic function to appease non-unix people who had no intention of implementing unix filesystem semantics, but on unix, remove is just a rmdir if the target is a directory, and unlink for everything else.)
A file can have multiple links (see the ln command for how they are created), which means that the same file is known by multiple names. If you rm one of them, the others stick around and the file is not deleted. What happens when you remove the last link? Well, now you have a file with no name. But names are only one kind of reference to a file. There are at least 2 others: file descriptors and mmap regions. When the last reference to a file goes away, that's when the file is deleted.
Since references come in several forms, there are many kinds of events that can cause a file to be deleted. Here are some examples:
unlink (rm, etc.)
close file descriptor
dup2 (can implicitly closes a file descriptor before replacing it with a copy of a different file descriptor)
exec (can cause file descriptors to be closed via close-on-exec flag)
munmap (unmap memory region)
mmap (if you create a new memory map at an address that's already mapped, the old mapping is unmapped)
process death (which closes all file descriptors and unmaps all memory mappings of the process)
normal exit
fatal signal generated by the kernel (^C, segfault)
fatal signal sent from another process (kill)
I won't call that a complete list. And I don't encourage anyone to try to build a complete list. Just know that rm is "remove name", not "remove file", and files go away as soon as they're not in use.
If you want to destroy the contents of a file immediately, truncate it. All processes already using it will find that its size has suddenly become 0. (This is destruction as far as the normal file access methods are concerned. To destroy it more thoroughly so that even someone with raw disk access can't read what used to be there, you need to overwrite it. There's a tool called shred for that.)
I think your question has nothing to do with the difference between Windows/Linux. It's about how VI works.
when using VI to edit a file. VI will create a .swp file. And the .swp file is what you are actually editing. At the same time, if other users delete the original file will not effect your editing.
And when you type :w in VI, VI will use .swp file to overwrite the original file.