I have 1900 codes (rows) (eg V933) that correspond to surgical operation types. I need to convert them all from V93.3 to V933 - ie remove a period after the first three characters.
I have seen solutions for prefixing and appending but not in the middle of a string.
How about substitute(), like this:
=SUBSTITUTE(A2,".","")
Related
I take this beautiful formula from JvdV answer:
=TRIM(CONCAT(IF(ISNUMBER(SEARCH(MID(A1,ROW(A$1:INDEX(A:A,LEN(A1))),1),"-./ 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ")),MID(A1,ROW(A$1:INDEX(A:A,LEN(A1))),1)," ")))
This formula replace any non-alphanumeric character (&^%]#$) with simple space " ".
I put in formula some exception (-./ ), but this is not all exceptions.
How about wildcards? How to filter wildcards (~*?) with this formula?
I think: Ok, I will use FIND instead of SEARCH and all will be right, just put lowercase and uppercase alphabet in the FIND index, like this: *"-./ 0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"*
Then I think: But, what if I want to keep not only numeric and regular alphabet? What if I want to keep all diacritics, like this: "ÁÀȦÄǍĀÃÅĄȺẤẦẮẰǠǺǞẪẴẢȀȂẨẲẠḀẬẶĂÂḂɃƁḄḆĆĊĈČÇȻḈƇƆḊĎḐĐƊḌḒḎÐƉÉÈĖÊËĚĔĒẼĘȨɆẾỀḖḔỄḜẺȄȆỂẸḘḚỆÉÈÊËḞƑǴĠĜǦĞḠĢǤƓḢĤḦȞḨĦḤḪⱧÍÌİÏǏĬĪĨĮƗḮỈȈȊỊḬÍÌÏÎȷĴǰḰǨĶƘᶄḲḴⱩꝀꝂꝄĹĿĽⱢⱠĻȽŁḶḼḺḸꝈḾṀṂŃǸṄŇÑŅƝṆṊṈÑŊÓÒȮÔÖǑŎŌÕǪŐỐỒƟØṒṐṌȪỖṎǾȬǬỎȌȎƠỔỌỚỜỠỘỞỢÓÒÔÖÕØṔṖⱣƤƦŔṘŘŖɌⱤȐȒṚṞṜŚṠŜŠṤṦṢṨŞṪŤƬṬƮṰṮȾŢŦÚÙÛÜǓŬŪŨŮŲŰɄǗǛṸṺỦȔȖƯỤṲỨỪṶṴỮỬỰÚÙÛÜṼṾẂẀẆŴẄẈẊẌÝỲẎŶŸȲỸɎỶƳỴÝŹŻẐŽƵẒẔ"
Then lowercase and uppercase alphabet is too much for FIND index.
Ok, for SEARCH index is also too much, because function accept max. 255 length, but lets say we have only 200 characters in index (numbers, alphabet and some diacritics)
So, the question is available:
How to filter (replace with space) wildcards (~*?) with this kind of formula?
As I read this question there are a few problems:
How to include over 255 characters in the 2nd parameter of SEARCH();
How to exclude literal wildcard characters in the 2nd parameter of SEARCH();
One way around the length limit is to feed SEARCH() an array of options, in this case an array of two elements of a lenght of <255:
Formula in C1:
=TRIM(CONCAT(IF(MMULT(IFERROR(SEARCH("~"&MID(A1,ROW(A$1:INDEX(A:A,LEN(A1))),1),{"ÁÀȦÄǍĀÃÅĄȺẤẦẮẰǠǺǞẪẴẢȀȂẨẲẠḀẬẶĂÂḂɃƁḄḆĆĊĈČÇȻḈƇƆḊĎḐĐƊḌḒḎÐƉÉÈĖÊËĚĔĒẼĘȨɆẾỀḖḔỄḜẺȄȆỂẸḘḚỆÉÈÊËḞƑǴĠĜǦĞḠĢǤƓḢĤḦȞḨĦḤḪⱧÍÌİÏǏĬĪĨĮƗḮỈȈȊỊḬÍÌÏÎȷĴǰḰǨĶƘᶄḲḴⱩꝀꝂꝄĹĿĽⱢⱠĻȽŁḶḼḺḸꝈḾṀṂŃǸṄŇÑŅƝṆṊṈÑŊÓÒȮÔÖǑŎŌÕǪŐỐỒƟØṒṐṌȪỖṎǾȬǬỎȌȎƠỔỌỚỜỠỘỞỢÓÒÔÖÕØṔṖⱣƤƦŔṘŘŖɌⱤ";"ȐȒṚṞṜŚṠŜŠṤṦṢṨŞṪŤƬṬƮṰṮȾŢŦÚÙÛÜǓŬŪŨŮŲŰɄǗǛṸṺỦȔȖƯỤṲỨỪṶṴỮỬỰÚÙÛÜṼṾẂẀẆŴẄẈẊẌÝỲẎŶŸȲỸɎỶƳỴÝŹŻẐŽƵẒẔ-./*? 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"}),0),{1,1}),MID(A1,ROW(A$1:INDEX(A:A,LEN(A1))),1)," ")))
What we did here is:
Use an horizontal array {abc;xyz} to check against our characters which was an vertical array {a,b,c}. Note the difference between semi-column and comma.
The result will be a 2D-array which MMULT() can sum. Meaning if the character was found in any of the two elements of the array it will return that same character. Otherwise, a space.
The special wildcard characters are now also included with an extra tilde to escape them as with actually all characters.
If Excel doesn't recognize all lowercase diacritics as their uppercase counterparts, just add them to one of the two elements. If need be, add a 3rd. But know that you'd need to extend on the 2nd parameter in MMULT() too then.
To visualize the above:
Remember, you are using Excel 2019 which means you need to CSE-enter this formula. Needles to say that all will be much easier in ms365 using its dynamic array functionality.
I need help with an Excel formula to extract a value from a string, based on delimiters.
This is the string I would like to extract the first 10 fields from: ES_ABC_FACEBOOK_SocialImage_FACEBOOK_Reach(CPM)_DEM_18-45_Apr19_abc_def_ghi
In other words, I would need to get ES_ABC_FACEBOOK_SocialImage_FACEBOOK_Reach(CPM)_DEM_18-45_Apr19_abc
Bearing in mind that the number of fields (separated by delimiters) may vary in the dataset but that I need to consistently only pick up the first 10 fields and drop however many fields are succeeding the 10th field.
Thanks in advance!
Robin
You could try this:
=LEFT(<your cell>,FIND("||",SUBSTITUTE(<your cell>,"_","||",10))-1)
e.g. =LEFT(A1,FIND("||",SUBSTITUTE(A1,"_","||",10))-1)
The formula finds the 10th underscore, and the gives you all the characters up to it (minus the underscore).
If you need to change how many fields it gives you back, change the 10. The -1 at the end just removes the final underscore. Of note, the || is just a simple set of characters I can't imagine will ever appear in your strings. If it does, something else will need to be selected.
Lastly, if some of your strings will have less than 10 fields, try:
=IF(ISERROR(FIND("||",SUBSTITUTE(<your cell>,"_","||",10))-1),<your cell>,LEFT(<your cell>,FIND("||",SUBSTITUTE(<your cell>,"_","||",10))-1))
This gives you the whole string in the event that there are less than 10 fields.
Hope that helps.
I have a string, and I need to calculate the number of spaces that I remove when I do trimStart.
For example, I have the following string \t\t \tabcs
so I have two tabs and two spaces and another tab that will be removed using trim start (the rest is non space related chars).
I need to know how many spaces will be removed. since I don't know how much is \t, I can't just count it as a single char.
(My purpose is to calculate the column shift of a string due to the trimming action. Obviously comparing the lengths before and after the trim will not return me the desired result.
Do you have any ideas?
Thanks!
I'm using Excels find and replace to remove hyphens from long numbers. They are mixed between birth dates and organisation numbers that have been filled with leading zeros to have the same number of characters. There are a LOT of numbers so find and replace seems to be the simplest solution to remove the hyphens.
But when i use find and replace the leading zeros are truncated and I have not found a solution to keep them afterwards.
For example i have:
19551230-1234
01234567-8901
and after find and replace I have
1,95512E+11
12345678901
but want the format as:
195512301234
012345678901
So I want to keep the leading zeros after find and replace. I've tried formatting the cells as text, but it doesn't work as the find and replace automatically truncates the leading zero and keeps the remaining characters, so the zero is completely removed. I am using Excel 2010, but answers for several versions are appreciated.
Just put a single quote in front of your leading number - ex. '01234 It will take the number as-is literally and the quote will not show in the field.
Use the SUBSTITUTE formula instead of Find and Replace like so:
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A1," ",""),"/",""),")",""),"(",""),"-","")
The result is text.
I have table with strings like this:
abc-1.2.3-1
abc-1.2.11-3
abc-1.11.3-2
abc-1.2.11-21
abcd-12345-7
abcd-12345-21
abc-def-1-3
Now, what I know for sure that there is a name (I don't know the length, it can be 1 character as well as it can be 15 characters and it can contain hyphens itself) then hyphen character and then version number.
As you have probably noticed, "version numbers" have different structures, one looks like 12345-7 and in next line there can be 1.2.3-3 (basically, I know this is a number with optional dots beetwen digits (1.2.3 part) which ends with hyphen and a number (e.g. -23).
If I simply sort it, then I have something like this:
abc-1.11.3-2
abc-1.2.11-21
abc-1.2.11-3
abc-1.2.3-1
abcd-12345-21
abcd-12345-7
abc-def-1-3
What I'd like would be:
abc-1.2.3-1
abc-1.2.11-3
abc-1.2.11-21
abc-1.11.3-2
abcd-12345-7
abcd-12345-21
abc-def-1-3
Sort it alphabetically, but whenever you find a number, treat it like a number.
I've seen a solutions with using functions LEN/MID/RIGHT and similar, but don't know how to apply them to my case.