sig literals in Alloy - alloy

How can I write out a literal for a sig in Alloy? Consider the example below.
sig Foo { a: Int }
fact { #Foo = 1 }
If I execute this, I get
| this/Foo | a |
|----------|---|
| Foo⁰ | 7 |
In the evaluator, I know I can get a reference to the Foo instance with Foo$0 but how can I write a literal that represents the same value?
I've tried {a: 7}, but this is not equal to Foo$0. This is intentionally a trivial example, but I'm debugging a more complex model and I need to be able to write out literals of sigs with multiple fields.

Ah, this is one of the well hidden secrets! :-) Clearly in your model you cannot refer to atoms since the model is defining all possible values of those atoms. However, quite often you need your hands on some atom to reason about it. That is, you want to be able to name some objects.
The best way to get 'constants' is to create a predicate you call from a run clause. In this predicate, you define names for atoms you want to discuss. You only have to make sure this predicate is true.
pred collision[ car1, car2 : Car, road : Road ] {
// here you can reason about car1 and car2
}
run collision for 10
Another way is to create a quantification whenever you need to have some named objects:
run {
some car1, car2 : Car, road : Road {
// here you can reason about car1 and car2 and road
}
} for 10
There was a recent discussion to add these kinds of instances to the language so that Kodkod could take advantage of them. (It would allow faster solving and it is extremely useful for test cases of your model.) However, during a discussion this solution I presented came forward and it does not require any new syntax.

try to put a limitation for 'Integer' in the 'run' command. I mean :
sig Foo {a : Int}
fact{ #Foo = 1}
pred show {}
run show for 1 Foo, 2 Int

Related

Alloy pred declaration: is there a difference between square brackets and parentheses?

The question probably has a yes/no answer. Consider the snippet:
sig A { my : lone B }
sig B { }
pred single1 [x:A]{ // defined using []
#x.my = 0
}
pred single2 (x:A){ // defined using ()
#x.my = 0
}
// these two runs produce the exact same results
run single1 for 3 but exactly 1 A
run single2 for 3 but exactly 1 A
check oneOfTheMostTrivialQuestionsOnStackOverflow { all x: A |
single1[x] iff single2[x] // pred calls use [], so as expected, single2(x) would cause a syntax error
} for 3000 but exactly 1 A // assertion holds :)
Are single1 and single2 exactly the same?
They seem to be, but am I missing something?
When we extended the syntax in Alloy 4, we changed the predicate invocations to []. My recollection is that we did it to make parsing easier, so that if you had a predicate P with no args, you could call it as just "P", and there would be no problems if it were followed by a formula in parens "P (...)". As Peter notes, it also seemed reasonable since it's similar to the relational lookup operator, and this makes sense especially for functions. We added the ability to declare predicates and functions with [] for consistency, but saw no reason to prevent () in decls (since there's no possible ambiguity there).
I think the parentheses were originally used for predicates and functions. However, they were changed in favour of the square brackets because it made it look more relational. I vaguely recall that Daniel Jackson explains this in his book.
That said, why ask because you seem to have proven it yourself? :-)

Unexpected results in playing with relations

/*
sig a {
}
sig b {
}
*/
pred rel_test(r : univ -> univ) {
# r = 1
}
run {
some r : univ -> univ {
rel_test [r]
}
} for 2
Running this small test, $r contains one element in every generated instance. When sig a and sig b are uncommented, however, the first instance is this:
In my explanation, $r has 9 tuples here and still, the predicate which asks for a one tuple relation succeeds. Where am I wrong?
An auxiliary question: are these two declarations equivalent?
pred rel_test(r : univ -> univ)
pred rel_test(r : set univ -> univ)
The problem is that with the Forbid Overflow option set to No the integer semantics in Alloy is wrap around, and with the default scope of 3 (bits), then indeed 9=1, as you can confirm in the evaluator.
With the signatures a and b commented the biggest relation that can be generated with scope 2 has 4 tuples (since the max size of univ is 2), so the problem does not occur.
It also does not occur in the latest build because I believe it comes with the Forbid Overflow option set to Yes by default, and with that option the semantics of integers rules out instances where overflows occur, precisely the case when you compute the size of the relation with 9 tuples. More details about this alternative integer semantics can be found in the paper "Preventing arithmetic overflows in Alloy" by Aleksandar Milicevic and Daniel Jackson.
On the main question: what version of Alloy are you using? I'm unable to replicate the behavior you describe (using Alloy 4.2 of 22 Feb 2015 on OS X 10.6.8).
On the auxiliary question: it appears so. (The language reference is not quite as explicit as one might wish, but it begins one part of its discussion of multiplicities with "If the right-hand expression denotes a unary relation ..." and (in what I take to be the context so defined) "the default multiplicity is one"; the conditional would make no sense if the default multiplicity were always one.
On the other hand, the same interpretive logic would lead to the conclusion that the language reference believes that unary multiplicity keywords are only allowed before expressions denoting unary relations (which would appear to make r: set univ -> univ ungrammatical). But Alloy accepts the expression and parses it as set (univ -> univ). (The alternative parse, (set univ) -> univ, would be very hard to assign a meaning to.)

Behavior of `=` in alloy fact

I was experimenting with alloy and wrote this code.
one sig s1{
vals: some Int
}{
#vals = 4
}
one sig s2{
vals: some Int
}{
#vals = 4
}
fact {
all a : s1.vals | a > 2
all i : s2.vals | i < 15
s1.vals = s2.vals
}
pred p{}
run p
It seems to me that {3,4,5,6} at least is a solution however Alloy says no instance found. When I comment s1.vals = s2.vals or change i < 15 to i > 2, it finds instances.
Can anyone please explain me why? Thanks.
Alloy's relationship with integers is sometimes mildly strained; it's not designed for heavily numeric applications, and many uses of integers in conventional programming are better handled in Alloy by other signatures.
The default bit width for integers is 4 bits, and Alloy uses twos-complement integers, so your run p is asking for a world in which integers range in value from -8 to 7. In that world, the constraint i < 15 is subject to integer overflow, and turns out to mean, in effect, i < -1. (To see this, comment out both of your constraints so that you get some instances. Then (a) leaf through the instances produced by the Analylzer and look at the integers that appear in them; you'll see their range is as I describe. Also, (b) open the Evaluator and type the numeral "15"; you'll see that its value in this universe is -1.)
If you change your run command to provide an appropriate bit width for integers (e.g. run p for 5 int), you'll get instances which are probably more like what you were expecting.
An alternative change, however, which leads to a more idiomatic Alloy model, is to abstract away from the specific kind of value by defining a sig for values:
sig value {}
Then change the declaration for vals in s1 and s2 from some Int to some value, and comment out the numeric constraints on them (or substitute some other interesting constraints for them). And then run p in a suitable scope (e.g. run p for 8 value).

Equality in alloy

I've got an Alloy model which contains the following :
abstract sig person{}
one sig john,Steve extends person {Gender: man}
sig man{}
fact {
all name: person, Gender: man |
name.Gender = name.Gender => person =person}
How can I make equality between two signatures?
It's not clear from your question what you want to do, and from your sample Alloy code it looks as if you may be suffering from some confusions.
First, the model you show uses the name Gender in two different ways, which is not illegal in itself but seems to suggest some confusion. (It certainly confuses the willies out of this reader.)
In the declaration for the two singleton signatures john and Steve, Gender denotes two binary relations, one holding between the signature john and the signature man, the other holding between Steve and man. To say the same thing in symbolic form, Gender denotes (a) some subset of john -> man, and (b) some subset of Steve -> man.
In the anonymous fact, however, Gender denotes a variable of type man.
Your model will be easier to understand if you find a way to rename one or the other of these. Since variable names in a quantified expression are arbitrary, your fact will mean the same thing if you reformulate it as
fact { all P : person, M : man | P.M = P.M => person = person }
If that's not what you meant to say, then you may have meant to say something like
fact { all P : person, M : man |
P.Gender = P.Gender => person = person
}
Renaming the variable forces you to choose one meaning or the other. This is a good thing. (It is an unfortunate fact that neither formulation is actually satisfactory in Alloy. But let's deal with one problem at a time; getting rid of the double use of the name Gender is the first step.)
A second issue is that whichever formulation of the fact you meant, it almost certainly doesn't mean what you wanted it to mean. Ignoring the specifics of the model for a moment, your fact takes the form
fact { all V1 : sig1, V2 : sig2 |
Expression = Expression => sig1 = sig1
}
where Expression is either V1.V2 or V1.Relation, for some Relation defined in the model. There are several things wrong here:
V1.V2 is meaningless where V1 and V2 are both names of signatures or variables ranging over given signatures: the dot operator is meaningful only if one of its arguments is the name of a relation.
If any expression E is meaningful at all, then a Boolean expression of the form E = E (for example, person.Gender = person.Gender) is true regardless of what E means. Anything denoted by E is naturally going to be equal to itself. So the conditional might as well be written
1 = 1 => person = person
For the same reason, person = person will always be true, regardless of the model: for any model instance the set of persons in the instance will be identical to the set of persons in the instance. So the conditional will always be true, and the fact won't actually impose any constraint on instances of the model.
It's not clear how best to help you move forward. Perhaps one way to start would be to ask yourself which of the following statements you are trying to capture in your model.
There is a set of persons.
Some persons are males (have gender = 'man'). Others are not males.
John is a male individual.
Steve is a male individual.
John and Steve are distinct individuals.
If x and y are individuals with the same gender, then x and y are the same individual. I.e. no two individuals have the same gender.
Note that these statements cannot all be true at the same time. (If that's not obvious, you might do worse than try to figure out why. Alloy can be helpful in that effort.)
Good luck.

meaning of Alloy predicate in relational join

Consider the following simple variant of the Address Book example
sig Name, Addr {}
sig Book { addr : Name -> Addr } // no lone on Addr
pred show(b:Book) { some n : Name | #addr[b,n] > 1 }
run show for exactly 2 Book, exactly 2 Addr, exactly 2 Name
In some model instances, I can get the following results in the evaluator
all b:Book | show[b]
--> yields false
some b:Book | show[b]
--> yields true
show[Book]
--> yields true
If show was a relation, then one might expect to get an answer like: { true, false }. Given that it is a predicate, a single Boolean value is returned. I would have expected show[Book] to be a shorthand for the universally quantified expression above it. Instead, it seems to be using existential quantification to fold the results. Anyone know what might be the rational for this, or have another explanation for the meaning of show[Book]?
(I'm not sure I have the correct words for this, so bear with me if this seems fuzzy.)
Bear in mind that all expressions in Alloy that denote individuals denote sets of individuals, and that there is no distinction available in the language between 'individual X' and 'the singleton set whose member is the individual X'. ([Later addendum:] In the terms more usually used: the general rule in Alloy's logic is that all values are relations. Binary relations are sets of pairs, n-ary relations sets of n-tuples, sets are unary relations, and scalars are singleton sets. See the discussion in sec. 3.2.2 of Software Abstractions, or the slide "Everything's a relation" in the Alloy Analyzer 4 tutorial by Greg Dennis and Rob Seater.)
Given the declaration you give of the 'show' predicate, it's easy to expect that the argument of 'show' should be a single Book -- or more correctly, a singleton set of Book --, and then to expect further that if the argument is not actually a singleton set (as in the expression show[Book] here) then the system will coerce it to being a singleton set, or interpret it with some sort of implicit existential or universal quantification. But in the declaration pred show(b:Book) ..., the expression b:Book just names an object b which will be a set of objects in the signature Book. (To require that b be a singleton set, write pred show(one b: Book) ....) The expression which constitutes the body of show is evaluated for b = Book just as readily as for b = Book$0.
The appearance of existential quantification is a consequence of the way the dot operator at the heart of the expression addr[b,n] (or equivalently n.(b.addr) is defined. Actually, if you experiment you'll find that show[Book] is true whenever there is any name for which the set of all books contains a mapping to two different addresses, even in cases where an existential interpretation would fail. Try adding this to your model, for example:
pred hmmmm { show[Book] and no b: Book | show[b] }
run hmmmm for exactly 2 Book, exactly 2 Addr, exactly 2 Name

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