I have a list of around 12,000 identifying numbers that need to be stored as text to preserve leading 0s, and I use =len to identify any identifying numbers that are the wrong length, but I can't work out how to quickly identify if a cell contains letters.
=isnumber doesn't work as the imported data is stored as text so it says all cells aren't numbers.
Answer can be VBA or formula.
=isnumber doesn't work as the imported data is stored as text so says all cells aren't numbers.
Use it with Value()
=ISNUMBER(VALUE(A1))
try:
=ARRAYFORMULA(IF((LEN(A2:A)<7)*(NOT(ISERR(A2:A*1))), A2:A, ))
if the length is under 7 characters and text string is composed of numbers
Related
I have column of strings mostly composed of numbers. Most of these strings are indeed 10 digit numbers formatted as string like :1234567890 except a few of them. Those exceptions start with a literal character with a letter to be specific like :A1234567890. What I want to do is while looping over that column I want to check on first characters and if it is a literal I want to branch my code. I'm not familiar with LibreOffice Basic yet VBA so any help is appreciated.
Listing 6.14. Display all data in a column in Andrew Pitonyak's Macro Document shows how to loop through all cells in a column.
To find out if the cell's string is numeric, use the IsNumeric function:
If IsNumeric(aCell.String) Then
What is the best way to filter out cell values in a large Excel spreadsheet (over 20,000 lines) for ONLY numeric values that are 6 digits in length, do not contain letters, and are sometimes stored as text.
The cell values may also contain:
-special characters and/or letters
-may have preceding or leading zeroes (stored as text to retain the zeroes)
-up to 30 digits (characters, numbers, letters)
I have tried the functions LEN, ISNUMBER, ISERROR
Any suggestions would be greatly appreciated.
What about
IF(ISNUMBER(A1+0), LEN(A1+0) = 6)
It will implicitly convert anything that can be number to a proper number (i.e. no leading zeros) and see if that's 6 characters long otherwise return false.
If it's possible to do the filtering in Google Sheets you can use regula rexpressions which will make the whole thing a lot easier, espcially if you want to measure the lenght of numbers including their leading zeros.
Once you paste the data you can use =ArrayFormula(REGEXMATCH(A1:A,"^(?:\D*)(\d{6})$")).
This will return true for any six digit number (including leading zeros) that is preceded by anything that is not a number.
I have a column full of text/string values. Some of the values appear to be null, but in reality have some formatting (additional spaces) left over from the exporting program where I get the excel data. I am trying to create an array using all capitalized letter of the English alphabet to cypher through each cell in the column, looking for the instance of any of the alphabet's letters within the first letter of each cell in the specific column, and if not found, returning a completely blank value in the neighboring column. If a letter value is found, then it would return the entire value of the cell. This way I can have true blanks and will be able to sort things a bit better.
I have been trying to find a working argument to build off of but aside from the
LEFT(Cell,1)="A-Z"
I have found little that seems to be a viable workaround. Any help is appreciated! Thanks!
You will want to use the ascii value to check for A-Z. Assuming the data is in the A column you can use the formula below. ASCII value range 65=A 90=Z. The trick is the Code formula which returns the ascii numeric value. Then an if statement to check if it is between the range, If it is return the cell contents and if not return nothing. You can also use Clean() to remove any unprintable characters (that is not used in this example)
=IF(CODE(UPPER(LEFT(A1,1))) > 64, IF(CODE(UPPER(LEFT(A1,1))) < 91,A1,""))
Because of floating point values, I cannot add a string of cells that contain values such as:
0.08178502
0.09262585
0.13261762
0.13016377
0.12302067
0.1136332
0.12176183
0.11430552
0.09971409
0.125285
Even if I try adding the first two through a sum formula or auto sum through selecting them, excel spits out an error. I have googled this like crazy and tried to change number formats. Is there a function that can allow me to add this information ?
Screenshot:
The spreadsheet is available on my Dropbox.
Those numbers are all preceded by a NBSP (Char Code 160). So, in order to sum them, you have to remove that. Many solutions. Here's one:
=SUMPRODUCT(--SUBSTITUTE(A1:A18,CHAR(160),""))
If a formula like:
=A1+A2+A3+A4+A5+A6+A7+A8+A9+A10
produces:
#VALUE!
then your "numbers" cells contain non-visible characters.
They must be removed before the formula will work.
If the cells contain text strings and not actual values you will need to convert the text to numeric values before performing any calculations. The function "=value(cell)" will bring the numeric value.
e.g.: A1 contains "000.12345678" (or some other non-numeric presentation of numerals)
In cell B1 type: =value(a1)
Cell B1 now operates as the real number 0.12345678
Oddly enough, the fact that it said 0.xxxxx in all numbers vs. .xxxxx is what the issue was. I'm just sharing that for folks who google/search and have same issue.
All I had to do was select that whole row and do a search in replace for "0." and make it just "." and now my numbers were usable in equations. For some reason the adjustment of formating as many searches suggested wasn't working
I'm not sure why my VLOOKUP formula is not working like the screenshot below. The value is right there as highlighted. I want to output the value in Column G, but changing the 3rd parameter to 1 or 2 doesn't work.
Help is appreciated. Thanks much in advance.
Formula: =VLOOKUP(B2,$F$1:$G$421,2,FALSE)
One thing you may want to look at.
I notice your data is left justified and that's normally the case for textual rather than numeric fields - it's possible to left justify numerics but it's neither the default nor the general practice.
If they are textual, there's a chance one or more of them may have leading or trailing spaces. That would prevent the lookup from finding a match.
Select (in turn) B2 and F1 and use the arrow keys in the formula box to check this is not the case.
In cases like this, I tend to (temporarily) set B2 to the formula =F1 just to see if it can find a match that's guaranteed (then use CTRL-Z to revert).
If that change results in the lookup working then obviously the (original) B2 and F1 are not the same value, and you need to work out why (hidden spaces, wrong types, and so on).
It looks like you are comparing text to number (see the green triangle in your value cell). You have to convert the value in your source cell or matching cells to same type. To convert source to number use excel function such as int or value. Hope this helps.
Another way to convert text to number format is to multiply by 1 and then replace original text values with these new number values...
If you are doing lookup where you have a mix of text and numbers (i.e. looking up a text version of a number in a list of real numbers) you can also make use of the VALUE function... this will convert numbers stored as text to real numbers.
Embed it like so:
=VLOOKUP(VALUE(B2),$F$1:$G$421,1,FALSE)
If you have a mix of text numbers and text text to look up in numbers/text then you can do:
=VLOOKUP(IFERROR(VALUE(B2),B2),$F$1:$G$421,1,FALSE)
to change numbers stored as text to numbers, but leave other text as is...