Search array index with double quotes string using awk - linux

Question

File1:
"1"|data|er
"2"|text|rq
""|test2|req
"3"|test4|teq
File2:
1
2
3
Expected Output should be (file3.txt)
"1"|data|er
"2"|text|rq
"3"|test4|teq
awk -F''$Delimeter'' '{print $1}' file1.txt | awk '{gsub(/"/, "", $1); print $1}' | awk 'NF && !seen[$1]++' | sort -n > file2.txt
I am able to extract the ids 1,2,3 from file1 and removed the double quotes and written into the file2 but i need to search these 1,2,3 ids in my file1.txt("1","2","3"), problem is search not recognizing due to dobule qoutes in the file
awk 'BEGIN {FS=OFS="|"} NR==FNR{a[$1]; next} \"$1\" in a' file2.txt file1.txt > file3.txt

Answer 1

Could you please try following.
awk -v s1='"' '
FNR==NR{
val=s1 $0 s1
a[val]
next
}
($1 in a)
' Input_file2 FS='|' Input_file1
Explanation: Adding detailed explanation for above code.
awk -v s1='"' ' ##Starting awk program from here and creating variable s1 whose value is ".
FNR==NR{ ##Checking condition FNR==NR which will be TRUE when first Input_file named Input_file2 is being read.
val=s1 $0 s1 ##Creating variable val whose value is s1 current line value and s1 here.
a[val] ##Creating an array named a whose index is variable val.
next ##next will skip all further statements from here.
} ##Closing FNR==NR BLOCK of this code here.
($1 in a) ##Checking condition if $1 of current line is present in array a then print that line of Input_file1.
' Input_file2 FS='|' Input_file1 ##Mentioning Input_file2 then setting FS as pipe and mentioning Input_file1 name here.

Answer 2

Let's say that your input is
"1"|data|er
"2"|text|rq
""|test2|req
"3"|test4|teq
And you want from these information 2 types of data :
The ids
The lines containing an id
The easiest way to achieve this is, I think, to first get lines that has id, then from this, retrieve the ids.
To do so :
$ awk -F'|' '$0 ~ /"[0-9]+"/' input1 >input3; cat input3
"1"|data|er
"2"|text|rq
"3"|test4|teq
$ sed 's/^"//; s/".*$//' input3 >input2; cat input2
1
2
3