In my variable 'Datelist3' there is a pandas Timestamp list, in the following format:
[Timestamp('2019-12-04 09:00:00+0100', tz='Europe/Rome'), Timestamp('2019-12-04 09:30:00+0100', tz='Europe/Rome'), ....]
I'm having difficulty converting this list to a datetime string list, in this format:
['2019-12-04 09:00:00', '2019-12-04 09:30:00', .....]
I did these tests:
Datelist3.to_datetime # -> error: 'list' object has no attribute 'to_datetime'
Datelist3.dt.to_datetime # -> error: 'list' object has no attribute 'dt'
Datelist3.to_pydatetime() # -> error: 'list' object has no attribute 'to_pydatetime()'
Datelist3.dt.to_pydatetime() # -> error: 'list' object has no attribute 'dt'
I got to the variable 'Datelist3' with the following statement:
Datelist3 = quoteIntraPlot.index.tolist()
If I this instruction changes it to:
Datelist3 = quoteIntraPlot.index.strftime("%Y-%m-%d %H:%M:%S").tolist()
That's exactly what I want to achieve.
The problem is that out of 10 times, 6-7 times is ok and 3-4 times it gives me an error: " 'Index' object has no 'strftime' ". It's very strange. How could I solve this problem?
If your data is well formed, this would work :
time_list = [Timestamp('2019-12-04 09:00:00+0100', tz='Europe/Rome'), Timestamp('2019-12-04 09:30:00+0100', tz='Europe/Rome'), ....]
str_list = [t.strftime("%Y-%m-%d %H:%M:%S") for t in time_list]
However, if you face the same error as before, it means that not all your index are timestamps. In this case, you need to clean your data first.
Related
When writing list inside tuple, getting error:
AttributeError: 'int' object has no attribute 'pop'
fruits=('apple','banana', ['kiwi','grapes'])
fruits[1].pop()
fruits[1].append('rice')
print(fruits)
I am getting:
str object has no attribute pop
which is what I was expecting since fruits[1] is 'banana' which is a string and strings do not have a pop method.
If you look at the next line you will run into a similar issue since strings also don't have an append method.
If you remove both of those lines you shouldn't have any errors with just the list inside of the tuple.
fruits = ('apple','banana', ['kiwi','grapes'])
print(fruits)
Your issue is coming from you trying to pop a string, in the second line of your code - not from adding a list in the tuple. Now as tuples are immutable in python, you will need to convert it into a list if you wish to start modyfing what is inside of it. A simple example using your code is below.
fruits=('apple','banana', ['kiwi','grapes'])
fruits_list = list(fruits)
fruits_list.pop(1)
fruits_list.insert(1, 'rice')
fruits = tuple(fruits_list)
print(fruits)
You can read more about it here: pop/remove items out of a python tuple
I have a series of fluorescence intensity data in a column ('2.4M'). I tried to create a new column 'ln_2.4M' by taking the ln of column '2.4M' I got an error:
AttributeError: 'float' object has no attribute 'log'
df["ln_2.4M"] = np.log(df["2.4M"])
I tried using a for loop to iterate the log over each fluorescence data in the column "2.4M":
ln2_4M = []
for x in df["2.4M"]:
ln2_4M = np.log(x)
print(ln2_4M)
Although it printed out ln2_4M as log of column "2.4M" correctly, I am unable to use the data because it gave alongside a TypeError:
ufunc 'log' not supported for the input types, and the inputs could not be safely coerced to any supported types according to the casting rule ''safe'
Not sure why? - Any help at understanding what is happening and how to fix this problem is appreciated. Thanks
.
I then tried using the method below and it worked:
df["2.4M"] = pd.to_numeric(df["2.4M"],errors = 'coerce')
df["ln_24M"] = np.log(df["2.4M"])
I am trying to split dataframe in equal samples and applying some function to calculate value of each sample if any sample value greater than 0.3 then in result dataframe i want to save filename
df=pd.DataFrame({'Value':[-0.016,-0.006,0.003,-0.011,-0.036,-0.031,-0.014,-0.006,-0.01 ,-0.009,0.004,0.001,-0.012,-0.021,-0.008,0.001,-0.011,-0.01,-0.006,0.002,0.004],'Nmae':[1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1]})
x=pd.DataFrame([x.values.sqrt(np.mean(df2['Value']**2)) for x in np.array_split(df2, (len(df2)/10))])
getting this error
AttributeError: 'numpy.ndarray' object has no attribute 'sqrt'
if someone have any other effective way to do this task
This is a working version of your Code:
res= [np.sqrt(np.mean((x.Value**2))) for x in np.array_split(df, (len(df)/10))]
An alternative way of approaching this with Pandas would be. You define a new column 'Split_variable' and use it to apply your calculations:
df.groupby('Split_variable')['Value'].apply(lambda x: np.sqrt(np.mean((x**2))))
When I am trying to do MA or rolling average with log transformed data I get this error. Where am I going wrong?
This one with original data worked fine-
# Rolling statistics
rolmean = data.rolling(window=120).mean()
rolSTD = data.rolling(window=120).std()
with log transformed data-
MA = X.rolling(window=120).mean()
MSTD = X.rolling(window=120).std()
AttributeError: 'numpy.ndarray' object has no attribute 'rolling'
You have to convert the numpy array to a pandas dataframe to use the pandas.rolling method.
The change could be something like this
dataframe = pd.DataFrame(data)
rolmean = dataframe.rolling(120).mean()
Try this instead:
numpy.roll(your_array, shift, axis = None)
There is no attribute rolling in numpy. So you shoud use the above syntax
Hope this helps
I'm making a small function that should sort alphabetically the degreecheme by last name ("also using first name if the last name for 2 persons are the same ) and I stack into the error "TypeError: 'NoneType' object is not subscriptable.
I have never before seen this error, so I have no idea what it means.
def degreescheem(listing,x):
printed=False
temporlist=[]
for i in listing:
if i[3] == x :temporlist.append(i)
slist=sorted(temporlist,key=lambda s:(s[4],s[5]))
for j in slist :
informationsformat(j)
printed = True
if not printed: print("no",x)
also it says that the error here is if i[3] == x :temporlist.append(i) but i cant found out something!!
This means that you are subscripting on a "None" on your error line, which is not a subscriptable type. It needs to by of type list, string, tuple, or some other subscriptable type in Python.
Print out your "i" before the error shows up. It'll help with debugging.