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Below I shared my console. I want to cut some string from output of some commands.
But there are 17 extra chars which I have no idea where comes from.
Can someone pls explain to me?
$ ls -al | grep total | sed 's/[[:blank:]].*$//' | wc -m
23
$ ns="total"
$ echo $ns | sed 's/[[:blank:]].*$//' | wc -c
6
But there are 17 extra chars which I have no idea where comes from.
Those are ANSI escape codes that grep uses for coloring matching substrings. You probably have an alias (run alias | grep grep to examine) like
alias grep='grep --color=always'
somewhere that causes grep to color matches even if output is not a tty, or something similar.
Try
ls -al | grep --color=never total | sed 's/[[:blank:]].*$//' | wc -m
and you'll get six.
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What I want to achieve is to get the count of all files in directory which contain a pattern String. And also not to count errors.
I have tried few commands but nothing seems to work this is what i have tried so far:
ls -l grep -cri "string" | wc -l
ls /path/ 2> /dev/null | grep -ci 'string' | wc -l
ls -l | grep -v ^l "string" | wc -l
Use the -l option to list just the filename when the contents match the pattern. Yse the -r option to recurse into subdirectories. Use the -F option to match the string exactly, rather than as a regular expression.
You need to tell it the name of the directory to recurse into; you can use . for the current directory.
Then pipe this to wc -l:
grep -rlF "string" . 2>/dev/null | wc -l
If you want to count the files in a directory with "string" in the name you can do it like this:
ls -l | grep -c "string"
or if you want it to be case insensitive use -i
ls -l | grep -ci "string"
-c will print the count of matching lines.
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Specify a command / command set that displays the number of lines of code in the .c and .h files in the current directory, displaying each file in alphabetical order followed by ":" and the number of lines in the files, and finally the total of the lines of code.
An example that might be displayed would be :
test.c: 202
example.c: 124
example.h: 43
Total: 369
I'd like to find a solution in the shortest form possible. I've experimented many commands like:
find . -name '*.c' -o -name '*.h' | xargs wc -l
== it shows 0 ./path/test.c and the total, but isn't close enough
stat -c "%n:%s" *
== it shows test.c:0, but it shows all file types and doesn't show the number of lines or the total
wc -l *.c *.h | tr ' ' '\:
== it shows 0:test.c and the total, but doesn't search in sub-directories and the order is reversed compared to the problem (filename: number_of_lines).
This one is closer to the answer but I'm out of ideas after searching most commands I saw in similar problems.
This should do it:
wc -l *.c *.h | awk '{print $2 ": " $1}'
Run a subshell in xargs
xargs -n1 sh -c 'printf "%s: %s\n" "$1" "$(wc -l <"$1")"' --
xargs -n1 sh -c 'echo "$1 $(wc -l <"$1")"' --
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I have set of commands and I want all of them to be defined in a single variable. below are the commands I want display in output.
pwdx `ps -ef | grep java | cut -d' ' -f4` | cut -d/ -f7
I tried with
app=`pwdx `ps -ef | grep java | cut -d' ' -f4` | cut -d/ -f7`
echo $app
but this gives empty output. Tried using for loop, that failed too.
Use the |& operator to pipe the output (stdout and stderr) of the previous command into the standard input of another one:
pwdx `ps -ef |& grep java |& cut -d' ' -f4` |& cut -d/ -f7
See this write-up for more on executing several bash commands: Running multiple commands in one line in shell
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So, I have about 60k-70k vCard-Files and want to check (or, at this point, count), which vCards contain a mail address (EMAIL;INTERNET:me#my-domain.com)
I tried to pass the output of find to awk, but I just get awk to work with the files list, not with every files content. How can I get awk to do so? I tried several combinations of find, xargs and awk, but I don't get it to work properly.
Thanks for your help,
Wolle
I'd probably use grep for this.
If you want to extract adresses from the files:
grep -rio "EMAIL;INTERNET:.*#[a-z0-9-]*\.[a-z]*" *
Use cut, sed or awk to remove the leading EMAIL;INTERNET::
... | cut -d: -f2
... | sed "s/.*://"
... | awk -F: '{print $2}'
If you want the names of the files containing a particular address:
grep -ril "EMAIL;INTERNET:me#my-domain\.com" *
If grep can't process that many files at once, drop the -r option and try with find and xargs:
find /start/dir -name "*.vcf" -print0 | xargs -0 -I {} grep -io "..." {}
grep recursive can do this
grep -r 'EMAIL.+#'
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When I run
echo "obase=2;3" | bc | grep -v \n\s | wc -m
bash returns 3. But when I run
echo "obase=2;3" | bc
bash returns 11.
Why is wc -m one digit high on its count?
The extra character is the trailing newline.
wc -m receives and counts the following three characters: 1 1 \n.
$ echo "obase=2;3" | bc | grep -v \n\s | od -c
0000000 1 1 \n
0000003
If you get rid of the newline, the count will be as you're expecting:
$ echo "obase=2;3" | bc | grep -v \n\s | tr -d '\n' | wc -m
2