i ma trying to unzip a zip file in google colab and i get this Error
Archive: object_detection.zip
End-of-central-directory signature not found. Either this file is not
a zipfile, or it constitutes one disk of a multi-part archive. In the
latter case the central directory and zipfile comment will be found on
the last disk(s) of this archive.
unzip: cannot find zipfile directory in one of object_detection.zip or
object_detection.zip.zip, and cannot find object_detection.zip.ZIP, period.
from google.colab import drive
drive.mount('/content/drive')
!cp '/content/drive/My Drive/slim.zip' slim.zip
!unzip object_detection.zip
i already uploded my zip files on the drive
Probable reason could be your zip file is corrupt.. may be you are not using proper link.. try downloading the file and then uploading on colab.. it should work.
I had the same problem and it was because I had not uploaded the file completely
Related
I tried to unzip large zipfiles from my Drive into my Colab and got this error:
BadZipFile: zipfiles that span multiple disks are not supported
How do I unzip large files from Drive into Colab?
Im doing that with two options:
!unzip file_location -d file_destination #-d is for quite option.
Or other option more elaborate:
import zipfile
from google.colab import drive
drive.mount('/content/drive/')
zip_ref = zipfile.ZipFile("/content/drive/My Drive/ML/DataSet.zip", 'r')
zip_ref.extractall("/tmp")
zip_ref.close()
The directory I am trying to rename has around 5k parquet files.
Unfortunatelly, os and shutil libraries aren't helping with it
import os, shutil
os.rename('/dbfs/FileStore/AllInOneParquets/SdId=791221', '/dbfs/FileStore/AllInOneParquets/test1')
shutil.move('/dbfs/FileStore/AllInOneParquets/SdId=791221', '/dbfs/FileStore/AllInOneParquets/test2')
Both tries above failed.
os.rename gave me the following exception:
OSError: [Errno 7] Argument list too long
The shutil.move, which tries to use os.rename in the background, started to move the files instead of really renaming.
The 5k files are just a test and I am going for much more than it. Is there a way around?
Try google: python how to move files from one directory to another and you will found the answer :)
How to move a file in Python
and I thing you shod run the code on administrator mode maybe
I am running python 3
I am trying to unzip my train.zip dataset on a GCP notebook instance, however whenever I try to I get a various error:
First I tried:
import os
from zipfile import ZipFile
os.path.exists('/home/jupyter/kerasProject/original_dataset/train.zip')
True
zip_file = ZipFile('/home/jupyter/kerasProject/original_dataset/train.zip')
Error:
BadZipFile: File is not a zip file
Then I tried:
!unzip '/home/jupyter/kerasProject/original_dataset/train.zip'
Error:
Archive: /home/jupyter/kerasProject/original_dataset/train.zip
End-of-central-directory signature not found. Either this file is not
a zipfile, or it constitutes one disk of a multi-part archive. In the
latter case the central directory and zipfile comment will be found on
the last disk(s) of this archive.
unzip: cannot find zipfile directory in one of /home/jupyter/kerasProject/original_dataset/train.zip or
/home/jupyter/kerasProject/original_dataset/train.zip.zip, and cannot find /home/jupyter/kerasProject/original_dataset/train.zip.ZIP, period.
For some reason in both cases it does not recogise the file as a .zip file, I tried reuploading it but it doesn't help, I can unzip it on my mac no problems so I don't think it can be corrupt, what have I done wrong?
How to extract a zip file using python when zip file present in different directory where script file present.
I try this ,but i got error because source path is not accepted ,try to solve me this problem.
from zipfile import ZipFile
def func(source, target):
with ZipFile('source', 'target'):
ZipFile.Extractall('target')
Use this code. To move through directories you could either hard code the directory where your script is present or you could toggle through the directories using simple commands such as "../" to move out of the given directory or "/" to move inside a folder in the directory. For example - "../script.py" or "/folder/script.py". Similarly you can use this to find your .zip file.
import zipfile
with zipfile.ZipFile("file.zip","r") as zip_ref:
zip_ref.extractall("targetdir")
For just unpacking, shutil should suffice:
import shutil
shutil.unpack_archive('path-to-zipfile')
You'll have to check for source path of the zip file which is relative to your current working directory. To know your current working directory you can try
import os
print(os.getcwd())
zip - Unzipping files in python
relative-paths-in-python
img = load_img('train/cat/cat.12499.jpg')
I'm using colab with the same code that I used in Jupyter, but now I get the below error, although the directory and file there are in:
No such file or directory: 'train/cat/cat.12499.jpg'
I copied the directory in google drive!
I solved with these commands
from google.colab import drive
drive.mount('/content/drive')
and I've modified the code in this way:
img = load_img("drive/My Drive/app/train/cat/cat.12499.jpg") # t