Create dictionary with count of values from list - python-3.x

Question

I'm trying to figure out how to create a dictionary with the key as the school and values the wins-losses-draws, based on each item in the list. For example, calling my_dict['Clemson'] would return the string "1-1-1"
"
team_score_list =[['Georgia', 'draw'], ['Duke', 'loss'], ['Virginia Tech', 'win'], ['Virginia', 'loss'], ['Clemson', 'loss'], ['Clemson', 'win'], ['Clemson', 'draw']]
The output for the above list should be the following dictionary:
{'Georgia': 0-0-1, 'Duke': 0-1-0, 'Virginia Tech': 1-0-0, 'Virginia': 0-1-0, 'Clemson': 1-1-1}
For context, the original data comes from a CSV, where each line is in the form of Date,Opponent,Location,Points For,Points Against.
For example: 2016-12-31,Kentucky,Neutral,33,18.
I've managed to wrangle the data into the above list (albeit probably not in the most efficient manner), however just not exactly sure how to get this into the format above.
Any help would be greatly appreciated!

Answer 1

Not beautiful but this should work.
team_score_list = [
["Georgia", "draw"],
["Duke", "loss"],
["Virginia Tech", "win"],
["Virginia", "loss"],
["Clemson", "loss"],
["Clemson", "win"],
["Clemson", "draw"],
]
def gen_dict_lst(team_score_list):
"""Generates dict of list based on team record"""
team_score_dict = {}
for team_record in team_score_list:
if team_record[0] not in team_score_dict.keys():
team_score_dict[team_record[0]] = [0, 0, 0]
if team_record[1] == "win":
team_score_dict[team_record[0]][0] += 1
elif team_record[1] == "loss":
team_score_dict[team_record[0]][1] += 1
elif team_record[1] == "draw":
team_score_dict[team_record[0]][2] += 1
return team_score_dict
def convert_format(score_dict):
"""formats list to string for output validation"""
output_dict = {}
for key, value in score_dict.items():
new_val = []
for index, x in enumerate(value):
if index == 2:
new_val.append(str(x))
else:
new_val.append(str(x) + "-")
new_str = "".join(new_val)
output_dict[key] = new_str
return output_dict
score_dict = gen_dict_lst(team_score_list)
out_dict = convert_format(score_dict)
print(out_dict)

Answer 2

You can first make a dictionary and insert/increment values of wins,loss and draw while iterating over the dictionary values. Here I have shown a way using variable name same as the string used for win,loss and draw and then increased corresponding value in dictionary using global()['str'] (from another answer)
dct={}
for i in team_score_list:
draw=2
win=0
loss=1
if i[0] in dct:
dct[i[0]][globals()[i[1]]]+=1
else:
dct[i[0]]=[0,0,0]
dct[i[0]][globals()[i[1]]]=1
You can then convert your list to string by using '-'.join(...) to get it in a format you want in the dictionary.

Answer 3

I now get what you mean:
You could do
a = dict()
f = lambda x,s: str(int(m[x]=='1' or j==s))
for (i,j) in team_score_list:
m = a.get(i,'0-0-0')
a[i] = f"{f(0,'win')}-{f(2,'draw')}-{f(4,'loss')}"
{'Georgia': '0-1-0',
'Duke': '0-0-1',
'Virginia Tech': '1-0-0',
'Virginia': '0-0-1',
'Clemson': '1-1-1'}
Now this is an answer only for this example. If you had many data, it would be good to use a list then join at the end. Eg
b = dict()
g = lambda x,s: str(int(m[x]) + (j==s))
for (i,j) in team_score_list:
m = b.get(i,[0,0,0])
b[i] =[g(0,"win"),g(1,"draw"),g(2,"loss")]
{key:'-'.join(val) for key,val in b.items()}
{'Georgia': '0-1-0',
'Duke': '0-0-1',
'Virginia Tech': '1-0-0',
'Virginia': '0-0-1',
'Clemson': '1-1-1'}