I am downloading two excel spreadsheets, one is a list of TLD's and their definitions the other is a list of the top one million websites. Part of my function is to find the top position of a particular TLD based off a user input. The code 'works' however it is printing the rank/key infinitely and I don't know why, any help is appreciated.
def parseCSV(tlds, top):
tldDict = {
" ":" "
}
topDict = {
" ":" "
}
#opening CSV file using string from parameter
file = open(r"C:\Users\bubba\OneDrive\Documents\Foundation Programming\tlds.csv", 'r')
file2 = open(r"C:\Users\bubba\OneDrive\Documents\Foundation Programming\top 1m.csv", 'r')
#iterating through file and splitting each line by comma
#this is put into a dictionary
for i in file.readlines():
x=i.split(",")
tldDict[x[0]]=x[1]
file.close()
for i in file2.readlines():
x=i.split(",")
topDict[x[0]]=x[1]
file2.close()
return [tldDict,topDict]
def getTopTLD(tld, tldDict, topDict):
matched_keys = []
for key, pair in topDict.items():
if tld in pair:
matched_keys.append(key) # Simple append statement
print('The position of this tld is:', min(matched_keys))
return matched_keys
tldDict, topDict = parseCSV("tlds","top-1m")
while True:
tld = input("Enter tld ")
if tld == "exit":
break
getTopTLD(tld, tldDict, topDict)
console example:
Enter tld com
The position of this tld is: 1
The position of this tld is: 1
The position of this tld is: 1
The position of this tld is: 1
The position of this tld is: 1
I thought it might be the while loop but if I remove it the result is the same.
Related
I am looking for some resource, my code print the first unequal value between two txt files. what I am trying to do is how to get to the next unequal values if I press a key. I think the while loop would help, but I fail in every logic. any resource where I could find some answers?
def textdiff():
text1 = open("text1.txt", "r")
text2 = open("text2.txt", "r")
for orgtext1 in text2:
for oldtext2 in text1:
if oldtext2 != orgtext1:
return oldtext2
text1.close()
text2.close()
print(textdiff())
thanks a lot
If you want to compare the nth character of file 1 with the nth character of file 2, I would use yield to jump out of the function after each found inequality and the with statement to make sure that the files are properly closed if an error is raised:
def textdiff():
with open("text1.txt", "r") as file1:
with open("text2.txt", "r") as file2:
text1 = file1.read()
text2 = file2.read()
shared_length = min(len(text1), len(text2))
for pos in range(shared_length):
if text1[pos] != text2[pos]:
yield text1[pos] + " != " + text2[pos]
for diff in textdiff():
print(diff)
input('Press <Return> to continue')
I am trying to pull a string of input names that get saved to a text file. I need to pull them by capital letter which is input. I.E. the saved text file contains names DanielDanClark, and I need to pull the names that begin with D. I am stuck at this part
for i in range(num):
print("Name",i+1," >> Enter the name:")
n=input("")
names+=n
file=open("names.txt","w")
file.write(names)
lookUp=input("Did you want to look up any names?(Y/N)")
x= ord(lookUp)
if x == 110 or x == 78:
quit()
else:
letter=input("Enter the first letter of the names you want to look up in uppercase:")
file=open("names.txt","r")
fileNames=[]
file.list()
for letter in file:
fileNames.index(letter)
fileNames.close()
I know that the last 4 lines are probably way wrong. It is what I tried in my last failed attempt
Lets break down your code block by block
num = 5
names = ""
for i in range(num)
print("Name",i+1," >> Enter the name:")
n=input("")
names+=n
I took the liberty of giving num a value of 5, and names a value of "", just so the code will run. This block has no problems. And will create a string called names with all the input taken. You might consider putting a delimiter in, which makes it more easier to read back your data. A suggestion would be to use \n which is a line break, so when you get to writing the file, you actually have one name on each line, example:
num = 5
names = ""
for i in range(num)
print("Name",i+1," >> Enter the name:")
n = input()
names += n + "\n"
Now you are going to write the file:
file=open("names.txt","w")
file.write(names)
In this block you forget to close the file, and a better way is to fully specify the pathname of the file, example:
file = open(r"c:\somedir\somesubdir\names.txt","w")
file.write(names)
file.close()
or even better using with:
with open(r"c:\somedir\somesubdir\names.txt","w") as openfile:
openfile.write(names)
The following block you are asking if the user want to lookup a name, and then exit:
lookUp=input("Did you want to look up any names?(Y/N)")
x= ord(lookUp)
if x == 110 or x == 78:
quit()
First thing is that you are using quit() which should not be used in production code, see answers here you really should use sys.exit() which means you need to import the sys module. You then proceed to get the numeric value of the answer being either N or n and you check this in a if statement. You do not have to do ord() you can use a string comparisson directly in your if statement. Example:
lookup = input("Did you want to look up any names?(Y/N)")
if lookup.lower() == "n":
sys.exit()
Then you proceed to lookup the requested data, in the else: block of previous if statement:
else:
letter=input("Enter the first letter of the names you want to look up in uppercase:")
file=open("names.txt","r")
fileNames=[]
file.list()
for letter in file:
fileNames.index(letter)
fileNames.close()
This is not really working properly either, so this is where the delimiter \n is coming in handy. When a text file is opened, you can use a for line in file block to enumerate through the file line by line, and with \n delimiter added in your first block, each line is a name. You also go wrong in the for letter in file block, it does not do what you think it should be doing. It actually returns each letter in the file, regardless of whay you type in the input earlier. Here is a working example:
letter = input("Enter the first letter of the names you want to look up in uppercase:")
result = []
with open(r"c:\somedir\somesubdir\names.txt", "r") as openfile:
for line in openfile: ## loop thru the file line by line
line = line.strip('\n') ## get rid of the delimiter
if line[0].lower() == letter.lower(): ## compare the first (zero) character of the line
result.append(line) ## append to result
print(result) ## do something with the result
Putting it all together:
import sys
num = 5
names = ""
for i in range(num)
print("Name",i+1," >> Enter the name:")
n = input("")
names += n + "\n"
with open(r"c:\somedir\somesubdir\names.txt","w") as openfile:
openfile.write(names)
lookup = input("Did you want to look up any names?(Y/N)")
if lookup.lower() == "n":
sys.exit()
letter = input("Enter the first letter of the names you want to look up in uppercase:")
result = []
with open(r"c:\somedir\somesubdir\names.txt", "r") as openfile:
for line in openfile:
line = line.strip('\n')
if line[0].lower() == letter.lower():
result.append(line)
print(result)
One caveat I like to point out, when you create the file, you open the file in w mode, which will create a new file every time, therefore overwriting the a previous file. If you like to append to a file, you need to open it in a mode, which will append to an existing file, or create a new file when the file does not exist.
I have a text file named "paintingJobs". The data looks like this:
E5341,21/09/2015,C102,440,E,0
E5342,21/09/2015,C103,290,A,290
E5343,21/09/2015,C104,730,N,0
E5344,22/09/2015,C105,180,A,180
I have written a program that only finds the first entry but cannot find any data beyond the first line (I think it is to do with Python including /n in front of the username) The program looks like this.
def ASearch():
print("Option A: Search for an estimate")
print("Please enter the estimate number: ")
estimateNumber = str(input())
file = open("paintingJobs.txt", "r")
paintJobs = file.readlines()
file.close()
length = len(paintJobs)
paintData = []
for line in paintJobs:
estNumber, estDate, CustID, FinalTotal, Status, AmountPaid = line.split(",")
if estimateNumber == estNumber:
print("Estimate number: ", estNumber)
print("Customer ID: ", CustID)
options()#this is a function in a for a different part of the program that works fine
else:
print("You have entered an incorrect estimate number; please try again")
ASearch()
How do I get the program to read (and return the values of) the second entry in the list E.G. E5342 (any help would be appreciated greatly)
so I have to write a program that:
Takes the filename as an argument.
Reads the file and counts, for each band, how many albums of that band are listed in the file. (http://vlm1.uta.edu/~cconly/teaching/cse1310_spring2015/assignments/assignment7/albums.txt)
Prints on the screen, in descending order of number of albums, a line for each band. Each line should contain the name of the band, followed by a colon and space, and then the number of albums for that band. This would look like this:
band1: number1
band2: number2
band3: number3
so there is my code below, but I keep getting tremendous errors that tells me that things aren't defined when they are, and I'll get this one as well --> TypeError: 'NoneType' object is not iterable, any help would be great!
import fileinput
import os
filename = open("albums.txt", "r") # open album.txt file
def process_line(line):
line = line.lower()
new_line = ""
for letter in line:
if letter in (""",.!"'()"""):
continue
elif letter == '-':
letter = ' '
new_line = new_line + letter
words = new_line.split()
return words
def count_words(filename):
if (os.path.isfile(filename) == False):
print("\nError: file " + filename + " does not exist.\n")
return
#in_file = open(filename, "r")
result = {}
for line in filename:
words = process_line(line)
for word in words:
if (word in result):
result[word] += 1
else:
result[word] = 1
def print_word_frequencies(dictionary):
print()
inverse = inverse_dictionary(dictionary)
frequencies = inverse.keys()
frequencies = list(frequencies) # convert frequencies to a list, so that we can sort it.
frequencies.sort() # sorting the list
frequencies.reverse() # reverse the sorting of the list
for frequency in frequencies: # for words with the same frequency, we want them sorted in
list_of_words = inverse[frequency]
list_of_words.sort() # sorting in alphabetical order
for word in list_of_words:
print(word + ":", frequency)
def inverse_dictionary(in_dictionary):
out_dictionary = {}
for key in in_dictionary:
value = in_dictionary[key]
if (value in out_dictionary):
list_of_keys = out_dictionary[value]
list_of_keys.append(key)
else:
out_dictionary[value] = [key]
return out_dictionary
def main():
filename = "albums.txt"
dictionary = count_words(filename)
print_word_frequencies(dictionary)
main()
Since this is an assignment, I will not give you the full code, but just point out some errors.
First, your indentation is all wrong, and indentation is important in Python! This may just have happened when you pasted your code into the question editor, but maybe not. Particularly, make sure your are not mixing tabs and spaces!
Your count_words method does not return anything, thus dictionary is None and you get TypeError: 'NoneType' object is not iterable in inverse_dictionary
When you do for line in filename, you are iterating the characters in the file name, not the lines in the file, as the global variable filename is shadowed by the filename parameter. Open the file in that method using with open(filename) as the_file:
Your process_line method seems odd. It seems like you remove all the special characters, but then how do you plan to separate band name and album name? You seem to just count words, not albums per band. Try line.split(" - ")[0] to get the band.
All that dictionary-inversing is not needed at all. In print_word_frequencies, just sort the items from the dictionary using some custom key function to sort by the count.
With those hints, you should be able to fix your program. (In case you want to know, I got your program down to about ten lines of code.)
I need to make a program in a single def that opens a text file 'grades' where first, last and grade are separated by comas. Each line is a separate student. Then it displays students and grades as well as class average. Then goes on to add another student and grade and saves it to the text file while including the old students.
I guess I just don't understand the way python goes through the text file. If i comment out 'lines' I see it prints the old_names but its as if everything is gone after. When lines is not commented out 'old_names' is not printed which makes me think the file is closed? or empty? however everything is still in the txt file as it should be.
currently i get this error.... Which I am pretty sure is telling me I'm retarded there's no information in 'line'
File "D:\Dropbox\Dropbox\1Python\Batch Processinga\grades.py", line 45, in main
first_name[i], last_name[i], grades[i] = line.split(',')
ValueError: need more than 1 value to unpack
End goal is to get it to give me the current student names and grades, average. Then add one student, save that student and grade to file. Then be able to pull the file back up with all the students including the new one and do it all over again.
I apologize for being a nub.
def main():
#Declare variables
#List of strings: first_name, last_name
first_name = []
last_name = []
#List of floats: grades
grades = []
#Float grade_avg, new_grade
grade_avg = new_grade = 0.0
#string new_student
new_student = ''
#Intro
print("Program displays information from a text file to")
print("display student first name, last name, grade and")
print("class average then allows user to enter another")
print("student.\t")
#Open file “grades.txt” for reading
infile = open("grades.txt","r")
lines = infile.readlines()
old_names = infile.read()
print(old_names)
#Write for loop for each line creating a list
for i in len(lines):
#read in line
line = infile.readline()
#Split data
first_name[i], last_name[i], grades[i] = line.split(',')
#convert grades to floats
grades[i] = float(grades[i])
print(first_name, last_name, grades)
#close the file
infile.close()
#perform calculations for average
grade_avg = float(sum(grades)/len(grades))
#display results
print("Name\t\t Grade")
print("----------------------")
for n in range(5):
print(first_name[n], last_name[n], "\t", grades[n])
print('')
print('Average Grade:\t% 0.1f'%grade_avg)
#Prompt user for input of new student and grade
new_student = input('Please enter the First and Last name of new student:\n').title()
new_grade = eval(input("Please enter {}'s grade:".format(new_student)))
#Write new student and grade to grades.txt in same format as other records
new_student = new_student.split()
new_student = str(new_student[1] + ',' + new_student[0] + ',' + str(new_grade))
outfile = open("grades.txt","w")
print(old_names, new_student ,file=outfile)
outfile.close()enter code here
File objects in Python have a "file pointer", which keeps track of what data you've already read from the file. It uses this to know where to start looking when you call read or readline or readlines. Calling readlines moves the file pointer all the way to the end of the file; subsequent read calls will return an empty string. This explains why you're getting a ValueError on the line.split(',') line. line is an empty string, so line.split(",") returns a list of length 0, but you need a list of length 3 to do the triple assignment you're attempting.
Once you get the lines list, you don't need to interact with the infile object any more. You already have all the lines; you may as well simply iterate through them directly.
#Write for loop for each line creating a list
for line in lines:
columns = line.split(",")
first_name.append(columns[0])
last_name.append(columns[1])
grades.append(float(columns[2]))
Note that I'm using append instead of listName[i] = whatever. This is necessary because Python lists will not automatically resize themselves when you try to assign to an index that doesn't exist yet; you'll just get an IndexError. append, on the other hand, will resize the list as desired.