---------------------------
CompanyID: 000000000000
Pizza: 2 3.15 6.30
spaghetti: 1 7 7
ribye: 2 40 80
---------------------------
CompanyID: 000000000001
burger: 1 3.15 6.30
spaghetti: 1 7 7
ribye: 2 40 80
--------------------------
I'm doing a for loop over a list of lines. Every line is an item of a list. I need to keep the companyID while looking for a user input.
While this is printing the variable x=True. I cant take company ID to print it.
a='-'
for line in lines:
if a in line:
companyID= next(line)
if product in line:
x=True
TypeError: 'str' object is not an iterator
You can use your line seperator to identify when new data starts. Once you see the line with "----" then you can start collecing info in a new dictionary. for each line take its key and value by splitting on ":" and create the entry in the dictionary.
When you see the next "----" line you know thats the end of the data for this company so then do your check to see if they have the product and if so print the company id from the dictionary.
line_seperator_char = '-'
company_data = {}
product = 'burger'
with open('data.dat') as lines:
for line in lines:
line = line.rstrip()
if line.startswith(line_seperator_char):
if product in company_data:
print(f'{company_data["CompanyID"]} contains the product {product}')
company_data = {}
else:
key, value = line.split(':')
company_data[key] = value
OUTPUT
000000000001 contains the product burger
No it doesnt run. Could you explain what does "[1] means near split()[1]?
Another try that doesnt run is
y=[]
y=lines[1].split(' ')
for line in lines:
y=line.split(' ')
if len(y[1])==10:
companyID=y[1]
if product in line:
x=True
Thanks for the answers.Something that finally worked in my case was that:
y=[]
y=line[1].split(' ')
a='-'
for line in lines:
if line.startswith("CompanyID:"):
y=line.split(' ')
companyID=y[1]
if product in line:
x=True
Related
So I have these strings that I split by spaces (' ') and I just rolled them into a single list I called 'keyLabelRun'
so it looks like this:
keyLabelRun[0-12]:
0 OS=Dengue
1 virus
2 3
3 PE=4
4 SV=1
5 Split=0
6
7 OS=Bacillus
8 subtilis
9 XF-1
10 GN=opuBA
11 PE=4
12 SV=1
I only want the elements that include and are after "OS=", anything else, whether it be "SV=" or "PE=" etc. I want to skip over those elements until I get to the next "OS="
The number of elements to the next "OS=" is arbitrary so that's where I'm having the problem.
This is what I'm currently trying:
OSarr = []
for i in range(len(keyLabelrun)):
if keyLabelrun[i].count('OS='):
OSarr.append(keyLabelrun[i])
if keyLabelrun[i+1].count('=') != 1:
continue
But the elements where "OS=" is not included is what is tripping me up I think.
Also at the end I'm going to join them all back together in their own elements but I feel like I will be able to handle that after this.
In my attempt, I am trying to append all elements I'm looking for in order to an new list 'OSarr'
If anyone can lend a hand, it would be much appreciated.
Thank you.
These list of strings came from a dataset that is a text file in the form:
>tr|W0FSK4|W0FSK4_9FLAV Genome polyprotein (Fragment) OS=Dengue virus 3 PE=4 SV=1 Split=0
MNNQRKKTGKPSINMLKRVRNRVSTGSQLAKRFSKGLLNGQGPMKLVMAFIAFLRFLAIPPTAGVLARWGTFKKSGAIKVLKGFKKEISNMLSIINKRKKTSLCLMMILPAALAFHLTSRDGEPRMIVGKNERGKSLLFKTASGINMCTLIAMDLGEMCDDTVTYKCPHITEVEPEDIDCWCNLTSTWVTYGTCNQAGEHRRDKRSVALAPHVGMGLDTRTQTWMSAEGAWRQVEKVETWALRHPGFTILALFLAHYIGTSLTQKVVIFILLMLVTPSMTMRCVGVGNRDFVEGLSGATWVDVVLEHGGCVTTMAKNKPTLDIELQKTEATQLATLRKLCIEGKITNITTDSRCPTQGEATLPEEQDQNYVCKHTYVDRGWGNGCGLFGKGSLVTCAKFQCLEPIEGKVVQYENLKYTVIITVHTGDQHQVGNETQGVTAEITPQASTTEAILPEYGTLGLECSPRTGLDFNEMILLTMKNKAWMVHRQWFFDLPLPWTSGATTETPTWNRKELLVTFKNAHAKKQEVVVLGSQEGAMHTALTGATEIQNSGGTSIFAGHLKCRLKMDKLELKGMSYAMCTNTFVLKKEVSETQHGTILIKVEYKGEDVPCKIPFSTEDGQGKAHNGRLITANPVVTKKEEPVNIEAEPPFGESNIVIGIGDNALKINWYKKGSSIGKMFEATARGARRMAILGDTAWDFGSVGGVLNSLGKMVHQIFGSAYTALFSGVSWVMKIGIGVLLTWIGLNSKNTSMSFSCIAIGIITLYLGAVVQADMGCVINWKGKELKCGSGIFVTNEVHTWTEQYKFQADSPKRLATAIAGAWENGVCGIRSTTRMENLLWKQIANELNYILWENNIKLTVVVGDIIGVLEQGKRTLTPQPMELKYSWKTWGKAKIVTAETQNSSFIIDGPNTPECPSVSRAWNVWEVEDYGFGVFTTNIWLKLREVYTQLCDHRLMSAAVKDERAVHADMGYWIESQKNGSWKLEKASLIEVKTCTWPKSHTLWSNGVLESDMIIPKSLAGPISQHNHRPGYHTQTAGPWHLGKLELDFNYCEGTTVVITENCGTRGPSLRTTTVSGKLIHEWCCRSCTLPPLRYMGEDGCWYGMEIRPISEKEENMVKSLVSAGSGKVDNFTMGVLCLAILFEEVMRGKFGKKHMIAGVFFTFVLLLSGQITWRDMAHTLIMIGSNASDRMGMGVTYLALIATFKIQPFLALGFFLRKLTSRENLLLGVGLAMATTLQLPEDIEQMANGIALGLMALKLITQFETYQLWTALISLTCSNTIFTLTVAWRTATLILAGVSLLPVCQSSSMRKTDWLPMAVAAMGVPPLPLFIFGLKDTLKRRSWPLNEGVMAVGLVSILASSLLRNDVPMAGPLVAGGLLIACYVITGTSADLTVEKAADITWEEEAEQTGVSHNLMITVDDDGTMRIKDDETENILTVLLKTALLIVSGIFPYSIPATLLVWHTWQKQTQRSGVLWDVPSPPETQKAELEEGVYRIKQQGIFGKTQVGVGVQKEGVFHTMWHVTRGAVLTYNGKRLEPNWASVKKDLISYGGGWRLSAQWQKGEEVQVIAVEPGKNPKNFQTMPGTFQTTTGEIGAIALDFKPGTSGSPIINREGKVVGLYGNGVVTKNGGYVSGIAQTNAEPDGPTPELEEEMFKKRNLTIMDLHPGSGKTRKYLPAIVREAIKRRLRTLILAPTRVVAAEMEEALKGLPIRYQTTATKSEHTGREIVDLMCHATFTMRLLSPVRVPNYNLIIMDEAHFTDPASIAARGYISTRVGMGEAAAIFMTATPPGTADAFPQSNAPIQDEERDIPERSWNSGNEWITDFAGKTVWFVPSIKAGNDIANCLRKNGKKVIQLSRKTFDTEYQKTKLNDWDFVV
>tr|M4KW32|M4KW32_BACIU Choline ABC transporter (ATP-binding protein) OS=Bacillus subtilis XF-1 GN=opuBA PE=4 SV=1 Split=0
MLTLENVSKTYKGGKKAVNNVNLKIAKGEFICFIGPSGCGKTTTMKMINRLIEPSAGKIFIDGENIMDQDPVELRRKIGYVIQQIGLFPHMTIQQNISLVPKLLKWPEQQRKERARELLKLVDMGPEYVDRYPHELSGGQQQRIGVLRALAAEPPLILMDEPFGALDPITRDSLQEEFKKLQKTLHKTIVFVTHDMDEAIKLADRIVILKAGEIVQVGTPDDILRNPADEFVEEFIGKERLIQSSSPDVERVDQIMNTQPVTITADKTLSEAIQLMRQERVDSLLVVDDEHVLQGYVDVEIIDQCRKKANLIGEVLHEDIYTVLGGTLLRDTVRKILKRGVKYVPVVDEDRRLIGIVTRASLVDIVYDSLWGEEKQLAALS
>sp|Q8AWH3|SX17A_XENTR Transcription factor Sox-17-alpha OS=Xenopus tropicalis GN=sox17a PE=2 SV=1 Split=0
MSSPDGGYASDDQNQGKCSVPIMMTGLGQCQWAEPMNSLGEGKLKSDAGSANSRGKAEARIRRPMNAFMVWAKDERKRLAQQNPDLHNAELSKMLGKSWKALTLAEKRPFVEEAERLRVQHMQDHPNYKYRPRRRKQVKRMKRADTGFMHMAEPPESAVLGTDGRMCLESFSLGYHEQTYPHSQLPQGSHYREPQAMAPHYDGYSLPTPESSPLDLAEADPVFFTSPPQDECQMMPYSYNASYTHQQNSGASMLVRQMPQAEQMGQGSPVQGMMGCQSSPQMYYGQMYLPGSARHHQLPQAGQNSPPPEAQQMGRADHIQQVDMLAEVDRTEFEQYLSYVAKSDLGMHYHGQESVVPTADNGPISSVLSDASTAVYYCNYPSA
I got it! :D
OSarr = []
G = 0
for i in range(len(keyLabelrun)):
OSarr.append(keyLabelrun[G])
G += 1
if keyLabelrun[G].count('='):
while keyLabelrun[G].count('OS=') != 1:
G+=1
Maybe next time everyone, thank you!
Due to the syntax, you have to keep track of which part (OS, PE, etc) you're currently parsing. Here's a function to extract the species name from the FASTA header:
def extract_species(description):
species_parts = []
is_os = False
for word in description.split():
if word[:3] == 'OS=':
is_os = True
species_parts.append(word[3:])
elif '=' in word:
is_os = False
elif is_os:
species_parts.append(word)
return ' '.join(species_parts)
You can call it when processing your input file, e.g.:
from Bio import SeqIO
for record in SeqIO.parse('input.fa', 'fasta'):
species = extract_species(record.description)
From replacement data table (below on the image), I am trying to incorporate the solbox product replace in time series data format(above on the image). I need to extract out the number of consumers per day from the information.
What I need to find out:
On a specific date, which number of solbox product was active
On a specific date, which number of solbox product (which was a consumer) was active
I have used this line of code in excel but cannot implement this on python properly.
=SUMPRODUCT((Record_Solbox_Replacement!$O$2:$O$1367 = "consumer") * (A475>=Record_Solbox_Replacement!$L$2:$L$1367)*(A475<Record_Solbox_Replacement!$M$2:$M$1367))
I tried in python -
timebase_df['date'] = pd.date_range(start = replace_table_df['solbox_started'].min(), end = replace_table_df['solbox_started'].max(), freq = frequency)
timebase_df['date_unix'] = timebase_df['date'].astype(np.int64) // 10**9
timebase_df['no_of_solboxes'] = ((timebase_df['date_unix']>=replace_table_df['started'].to_numpy()) & (timebase_df['date_unix'] < replace_table_df['ended'].to_numpy() & replace_table_df['customer_type'] == 'customer']))
ERROR:
~\Anaconda3\Anaconda4\lib\site-packages\pandas\core\ops\array_ops.py in comparison_op(left, right, op)
232 # The ambiguous case is object-dtype. See GH#27803
233 if len(lvalues) != len(rvalues):
--> 234 raise ValueError("Lengths must match to compare")
235
236 if should_extension_dispatch(lvalues, rvalues):
ValueError: Lengths must match to compare
Can someone help me please? I can explain in comment section if I have missed something.
This is my python file
path = '/my/file/list.txt'
with open(path,'rt') as file:
print("step 1")
collected_lines = []
started = False
for line in file:
for n in range(1, 10):
if line.startswith('PLAY NO.{}'.format(n)):
started = True
print("started at line {}".format(line[0]))
continue
if started:
collected_lines.append(line)
if started and line == 'PLAY NO.{}'.format(n+1):
print("end at line {}".format(line[0]))
break
print(collected_lines.append(line))
This is my code..
OUTPUT:
None
None
None
None
None
None
Now I want the lines starting from play No2 to play No3.... But I am getting None.. Please any suggestions... I am using Python 3.5
Sorry this is the first time asking question on this site..
My file looks like this..
textfile.txt
Hello and Welcome This is the list of plays being performed here
PLAY NO. 1
1. adknjkd
2. skdi
3. ljdij
PLAY NO. 2
1. hsnfhkjdnckj
2. sjndkjhnd and so on
path = 'list.txt'
collected_lines = []
with open(path,'rt') as file:
print("step 1")
started = False
lineNo = 0
for line in file:
lineNo += 1
for n in range(1, 10):
# print('PLAY NO. {}'.format(n))
if started and line.lstrip().startswith('PLAY NO. {}'.format(n)):
print("### end at line {}".format(lineNo))
started = False
break
if line.lstrip().startswith('PLAY NO. {}'.format(n)):
started = True
print("### started at line {}".format(lineNo))
break
if started:
collected_lines.append(line)
print("collected_lines: \n\n", *[ item for item in collected_lines ])
gives:
step 1
### started at line 2
### end at line 7
collected_lines:
PLAY NO. 1
1. adknjkd
2. skdi
3. ljdij
NOTES about fixed issues:
used .lstrip() in order to make .startswith() working as expected
added a space between NO. and {} in startswith('PLAY NO. {}'.format(n) so that the if condition can find the line
rearranged the order of ifs in order to avoid that the end line is considered found at the start line
added started = False to the loop to stop collecting the lines.
The problem with the leading spaces was already enough to prevent the code from finding the line. Fixing this alone wouldn't fix the problem because of the missing space in the format string, so both issues had to be fixed to make the code work as expected. And so on ... see NOTES above.
If you want a dict with as labels the play number and as items a list with the lines about the play you can use a defaultdict
Defining the text
text = """Hello and Welcome This is the list of plays being performed here
PLAY NO. 1
1. adknjkd
2. skdi
3. ljdij
PLAY NO. 2
1. hsnfhkjdnckj
2. sjndkjhnd and so on"""
Defining the regular expression
regex = re.compile('^\s*PLAY NO. (\d+)$')
Parsing the lines
label = None # no play to start with
recorded_lines = defaultdict(list)
for line_no, line in enumerate(StringIO(text)):
# In the real code replace the 'StringIO(text)' with 'file'
try:
play_no = int(regex.findall(line)[0])
# If this regex does not match, it will throw an IndexError
# The code underneath is only executed when a new play starts
if label: # if there is no play underway, there can be no ending
print('PLAY NO. %i ended at line number %i' % (label, line_no-1))
label = play_no
print('PLAY NO. %i started at line number %i' % (play_no, line_no))
except IndexError:
# no new play started
if label and line.strip():
recorded_lines[play_no].append(line.strip())
print(line_no, line)
print(recorded_lines)
yields
defaultdict(list,
{1: [(2, '1. adknjkd'), (3, '2. skdi'), (4, '3. ljdij')],
2: [(7, '1. hsnfhkjdnckj'), (8, '2. sjndkjhnd and so on')]})
and this output on the stout:
0 Hello and Welcome This is the list of plays being performed here
PLAY NO. 1 started at line number 1
1 PLAY NO. 1
2 1. adknjkd
3 2. skdi
4 3. ljdij
5
PLAY NO. 1 ended at line number 5
PLAY NO. 2 started at line number 6
6 PLAY NO. 2
7 1. hsnfhkjdnckj
8 2. sjndkjhnd and so on
Each line contains a special timestamp, the caller number, the receiver number, the duration of the call in seconds and the rate per minute in cents at which this call was charged, all separated by ";”. The file contains thousands of calls looks like this. I created a list instead of a dictionary to access the elements but I'm not sure how to count the number of calls originating from the phone in question
timestamp;caller;receiver;duration;rate per minute
1419121426;7808907654;7807890123;184;0.34
1419122593;7803214567;7801236789;46;0.37
1419122890;7808907654;7809876543;225;0.31
1419122967;7801234567;7808907654;419;0.34
1419123462;7804922860;7809876543;782;0.29
1419123914;7804321098;7801234567;919;0.34
1419125766;7807890123;7808907654;176;0.41
1419127316;7809876543;7804321098;471;0.31
Phone number || # |Duration | Due |
+--------------+-----------------------
|(780) 123 4567||384|55h07m53s|$ 876.97|
|(780) 123 6789||132|17h53m19s|$ 288.81|
|(780) 321 4567||363|49h52m12s|$ 827.48|
|(780) 432 1098||112|16h05m09s|$ 259.66|
|(780) 492 2860||502|69h27m48s|$1160.52|
|(780) 789 0123||259|35h56m10s|$ 596.94|
|(780) 876 5432||129|17h22m32s|$ 288.56|
|(780) 890 7654||245|33h48m46s|$ 539.41|
|(780) 987 6543||374|52h50m11s|$ 883.72|
list =[i.strip().split(";") for i in open("calls.txt", "r")]
print(list)
I have very simple solution for your issue:
First of all use with when opening file - it's a handy shortcut and it provides sames functionality as wrap this funtion into try...except. Consider this:
lines = []
with open("test.txt", "r") as f:
for line in f.readlines():
lines.append(line.strip().split(";"))
print(lines)
counters = {}
# you browse through lists and later through numbers inside lists
for line in lines:
for number in line:
# very basic way to count occurences
if number not in counters:
counters[number] = 1
else:
counters[number] += 1
# in this condition you can tell what number of digits you accept
counters = {elem: counters[elem] for elem in counters.keys() if len(elem) > 5}
print(counters)
This should get you started
import csv
import collections
Call = collections.namedtuple("Call", "duration rate time")
calls = {}
with open('path/to/file') as infile:
for time, nofrom, noto, dur, rate in csv.reader(infile):
calls.get(nofrom, {}).get(noto,[]).append(Call(dur, rate, time))
for nofrom, logs in calls.items():
for noto, callist in logs.items():
print(nofrom, "called", noto, len(callist), "times")
Perl Newbie here and looking for some help.
I have a directory of files and a "keywords" file which has the attributes to search for and the attribute type.
For example:
Keywords.txt
Attribute1 boolean
Attribute2 boolean
Attribute3 search_and_extract
Attribute4 chunk
For each file in the directory, I have to:
lookup the keywords.txt
search based on Attribute type
something like the below.
IF attribute_type = boolean THEN
search for attribute;
set found = Y if attribute found;
ELSIF attribute_type = search_and_extract THEN
extract string where attribute is Found
ELSIF attribute_type = chunk THEN
extract the complete chunk of paragraph where attribute is found.
This is what I have so far and I'm sure there is a more efficient way to do this.
I'm hoping someone can guide me in the right direction to do the above.
Thanks & regards,
SiMa
# Reads attributes from config file
# First set boolean attributes. IF keyword is found in text,
# variable flag is set to Y else N
# End Code: For each text file in directory loop.
# Run the below for each document.
use strict;
use warnings;
# open Doc
open(DOC_FILE,'Final_CLP.txt');
while(<DOC_FILE>) {
chomp;
# open the file
open(FILE,'attribute_config.txt');
while (<FILE>) {
chomp;
($attribute,$attribute_type) = split("\t");
$is_boolean = ($attribute_type eq "boolean") ? "N" : "Y";
# For each boolean attribute, check if the keyword exists
# in the file and return Y or N
if ($is_boolean eq "Y") {
print "Yes\n";
# search for keyword in doc and assign values
}
print "Attribute: $attribute\n";
print "Attribute_Type: $attribute_type\n";
print "is_boolean: $is_boolean\n";
print "-----------\n";
}
close(FILE);
}
close(DOC_FILE);
exit;
It is a good idea to start your specs/question with a story ("I have a ..."). But
such a story - whether true or made up, because you can't disclose the truth -
should give
a vivid picture of the situation/problem/task
the reason(s) why all the work must be done
definitions for uncommon(ly used)terms
So I'd start with: I'm working in a prison and have to scan the emails
of the inmates for
names (like "Al Capone") mentioned anywhere in the text; the director
wants to read those mails in toto
order lines (like "weapon: AK 4711 quantity: 14"); the ordnance
officer wants those info to calculate the amount of ammunition and
rack space needed
paragraphs containing 'family'-keywords like "wife", "child", ...;
the parson wants to prepare her sermons efficiently
Taken for itself, each of the terms "keyword" (~running text) and
"attribute" (~structured text) of may be 'clear', but if both are applied
to "the X I have to search for", things get mushy. Instead of general ("chunk")
and technical ("string") terms, you should use 'real-world' (line) and
specific (paragraph) words. Samples of your input:
From: Robin Hood
To: Scarface
Hi Scarface,
tell Al Capone to send a car to the prison gate on sunday.
For the riot we need:
weapon: AK 4711 quantity: 14
knife: Bowie quantity: 8
Tell my wife in Folsom to send some money to my son in
Alcatraz.
Regards
Robin
and your expected output:
--- Robin.txt ----
keywords:
Al Capone: Yes
Billy the Kid: No
Scarface: Yes
order lines:
knife:
knife: Bowie quantity: 8
machine gun:
stinger rocket:
weapon:
weapon: AK 4711 quantity: 14
social relations paragaphs:
Tell my wife in Folsom to send some money to my son in
Alcatraz.
Pseudo code should begin at the top level. If you start with
for each file in folder
load search list
process current file('s content) using search list
it's obvious that
load search list
for each file in folder
process current file using search list
would be much better.
Based on this story, examples, and top level plan, I would try to come
up with proof of concept code for a simplified version of the "process
current file('s content) using search list" task:
given file/text to search in and list of keywords/attributes
print file name
print "keywords:"
for each boolean item
print boolean item text
if found anywhere in whole text
print "Yes"
else
print "No"
print "order line:"
for each line item
print line item text
if found anywhere in whole text
print whole line
print "social relations paragaphs:"
for each paragraph
for each social relation item
if found
print paragraph
no need to check for other items
first implementation attempt:
use Modern::Perl;
#use English qw(-no_match_vars);
use English;
exit step_00();
sub step_00 {
# given file/text to search in
my $whole_text = <<"EOT";
From: Robin Hood
To: Scarface
Hi Scarface,
tell Al Capone to send a car to the prison gate on sunday.
For the riot we need:
weapon: AK 4711 quantity: 14
knife: Bowie quantity: 8
Tell my wife in Folsom to send some money to my son in
Alcatraz.
Regards
Robin
EOT
# print file name
say "--- Robin.txt ---";
# print "keywords:"
say "keywords:";
# for each boolean item
for my $bi ("Al Capone", "Billy the Kid", "Scarface") {
# print boolean item text
printf " %s: ", $bi;
# if found anywhere in whole text
if ($whole_text =~ /$bi/) {
# print "Yes"
say "Yes";
# else
} else {
# print "No"
say "No";
}
}
# print "order line:"
say "order lines:";
# for each line item
for my $li ("knife", "machine gun", "stinger rocket", "weapon") {
# print line item text
# if found anywhere in whole text
if ($whole_text =~ /^$li.*$/m) {
# print whole line
say " ", $MATCH;
}
}
# print "social relations paragaphs:"
say "social relations paragaphs:";
# for each paragraph
for my $para (split /\n\n/, $whole_text) {
# for each social relation item
for my $sr ("wife", "son", "husband") {
# if found
if ($para =~ /$sr/) {
## if ($para =~ /\b$sr\b/) {
# print paragraph
say $para;
# no need to check for other items
last;
}
}
}
return 0;
}
output:
perl 16953439.pl
--- Robin.txt ---
keywords:
Al Capone: Yes
Billy the Kid: No
Scarface: Yes
order lines:
knife: Bowie quantity: 8
weapon: AK 4711 quantity: 14
social relations paragaphs:
tell Al Capone to send a car to the prison gate on sunday.
Tell my wife in Folsom to send some money to my son in
Alcatraz.
Such (premature) code helps you to
clarify your specs (Should not-found keywords go into the output?
Is your search list really flat or should it be structured/grouped?)
check your assumptions about how to do things (Should the order line
search be done on the array of lines of thw whole text?)
identify topics for further research/rtfm (eg. regex (prison!))
plan your next steps (folder loop, read input file)
(in addition, people in the know will point out all my bad practices,
so you can avoid them from the start)
Good luck!