As the title says, is it possible to manipulate (e.g. Create, write, delete image) file from/to the extension folder?
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I am working on a web app project to block all the file executable from file upload.
Example: user can upload, txt, png, image and video files and not any executable scripts like, Perl, Python, exe, PHP, .so, .sh files.
If it is a PHP file, then I strstr for "<?php" tag, If this tag is present, then it is PHP file. How can we find the same for other script/executable files?
Edit: Some time hackers will upload the malicious files using .png or .jpg extn, so what is the pattern to check inside the files?
Rather than making your own checks you make use of an existing library and you block everything that does not register as a desired format.
Most such libraries guess the content type and encoding of a file by looking for certain signatures or magic byte sequences at specific positions within the file.
Other libraries may be more specialised and will for example only identify image or video formats.
https://www.php.net/manual/en/intro.fileinfo.php
https://github.com/ahupp/python-magic
https://docs.python.org/3/library/imghdr.html
The file programme is a command line tool for identification of file types.
After the first pass where you identify and accept only the desired file formats you should then make all files that are not rejected go through an antivirus scanner.
Depending on you use cases you may decide to strip the original file name extension and/or even the complete file name that was provided during the upload and assign the mime-type that was detected rather than rely on user provided properties.
I'm looking to remotely download and detect a file from a website, like this
http://examplewebsite.com/100/download
When viewing in my browser, this automatically downloads as the appropriate file type, 100.pdf, but sometimes it can be a .xls or .doc file. etc.
Looking at libraries available, like file-type, it only works if you already have the extension
Is this possible?
If you have the url, you can split by '.' and select the last element of your list.
The file-type library you linked in your question actually checks the source of the file to guess. It doesn't use the file extension at all.
I am processing a big images dataset and I'm trying to reorder the files in classes, while at the same time keeping the original directory structure.
To do this, I make a second directory structure with symlinks to the files in the first one.
Everything works as it should but for one small detail: the symlinks created via os.symlink() do not show the image thumbnail, while if I make a link of the same file (e.g., via right click & send to Desktop) I do see the thumbnail.
I wanted to check how the two link files differ (note, the link files themselves, not the linked file), but if I try to drag the os.symlink-generated file in a text editor it opens the linked file instead (while this does not happen with the .lnk file generated via right-click).
What's the difference between the link files? Is os.symlink making something different than a .lnk file? If so, is there a way to get the thumbnail? And if there's no such way, how can I make a .lnk file instead?
I am writing a PyQt4 application and one of the file types I wish to open is an Esri Grid format which, rather unusually, is a directory. I also wish to open other GIS filetypes that are just files (e.g. geotiffs). I can open these filetypes OK with the GDAL library by passing either a file or directory name and GDAL figures it out.
The problem I have is making the GUI. I want to open a file open dialog and get either a file name, or directory name. The problem is that the file dialog won't let me choose a directory - only files. I need the dialog to return a path to either. I've tried it on Mac and Linux.
I know PySide has a method called getExistingDirectory
http://pyside.github.io/docs/pyside/PySide/QtGui/QFileDialog.html
PyQt is basically the same, so it should have a similar method. http://pyqt.sourceforge.net/Docs/PyQt4/qfiledialog.html It is in the static methods section.
I think I've cracked it. This snippet tests the functionality I need:
dlg=QtGui.QFileDialog()
dlg.setFileMode(QtGui.QFileDialog.AnyFile);
e=dlg.exec_()
print dlg.selectedFiles()[0]
The solution was to set the file mode to 'AnyFile'. This allows the file dialog to return both directory and file names.
I have a single xcdatamodeld file and would merely like to open this particular file with xcode. However, when I double click the file, it doesn't really show me anything or allow editing. The only way to do this is to run MyApp.xcodeproj and only then can I modify this file. Isn't there any way to edit the coredata file using only the xcdatamodel file? Thanks!
The xcdatamodeld file is not actually a file - it's a directory containing other model files.
Right click the file, choose Show Package Contents and you will get access to the files inside the directory. You can then double-click those files. When I do so I get just the Xcode model editor without the full Xcode project window.