I've made a program that counts weighted average and required weighted value to average being equal to our preference. If I want the average be equal to 85 from (the first value in the list is the weight of next values) [[4,72,78],[3,56],[6,93]] and x value of 6 weight it does not output the right value.
def choice(x):
c = 0
Choice = True
choices = []
while Choice:
if choices == []:
if x != 0:
fill = "weight of required value"
else:
fill = "weight of next values"
else:
if x != 0:
fill = "value of wanted weighted average"
else:
fill = "value"
try:
c = input("Give {}\n" .format(fill))
except:
continue
if isinstance(c, str):
if c == "":
Choice = False
if choices == []:
choices = False
break
else:
try:
choices.append(float(c))
except:
continue
if x != 0 and len(choices) == x:
break
c = 0
return choices
def av(x):
c = 0
alist = x[:]
alist.pop(0)
for a in alist:
c += a*x[0]
return c
def average(k,args):
c = 0
n = 0
for y in range(len(args)):
for a in range(len(args)):
c += (av(args[a]))/2
for b in range(len(args)):
n += (args[b][0]*(len(args[b])-1))/2
if k == 1:
return ([float("{0:.2f}".format(c/n)),c,n])
else:
j = float("{0:.2f}".format(c/n))
print("Weighted average {} from {}" .format(j,args))
def rmark(q,args):
alist = average(1,args)
a = float("{:.2f}" .format((((q[1]*(alist[2]+q[0]))-alist[1])/q[0])))
print("To get weighted average {}, u have to add the value equal to {} of weight {}" .format(q[1],a,q[0]))
# return a
Continue = True
list_choices = []
while Continue:
x = 0
x = choice(0)
if isinstance(x, list):
list_choices.append(x)
elif x == False:
break
print(list_choices)
rmark(choice(2),list_choices)
average(0,list_choices)
Let me break it down for you.
av function is reducing the size of your lists (x1, x2 and x3) to 1 by popping (alist.pop(0)) one element.
Hence, value of len(x1)-1 is 0, which means value of all multipliers in the denominator of (av(x1) + av(x2) + av(x3))/((x1[0]*(len(x1)-1)) + (x2[0]*(len(x2)-1)) + (x3[0]*(len(x3)-1))) is 0. Thus, the error divide by zero.
Related
Heavy python beginner here. I want to create a simple function for a PIN guessing game that receives two 4-digit lists ( [guess], [answer] ) and returns a string with 4 letters stating how close I am to guessing the correct [answer] sequence (eg. Higher, True, Lower, Higher)
However, I get a new list for each string:
def checkNumbers(guess,right):
for n in range(4):
result = []
if guess[n] == right[n]:
result.append("T") #true
elif guess[n] < right[n]:
result.append("H") #higher
elif guess[n] > right[n]:
result.append("L") #lower
else:
result.append("F") #false
print (result)
return
checkNumbers([1,2,3,5],[2,2,1,6])
The result should look like this:
checkNumbers([1,2,3,4], [2, 2, 1 , 6]) #call function with ([guess], [answer])
'HTLH' #returns a string stating how accurate [guess] is to [answer] list
Result looks like this however:
checkNumbers([1,2,3,5],[2,2,1,6])
['H']
['T']
['L']
['H']
Thanks very much in advance for any help I could get.
you can use string instead of list or "".join()
def checkNumbers(guess, right):
result = ""
for n in range(4):
if guess[n] == right[n]:
result += "T" # true
elif guess[n] < right[n]:
result += "H" # higher
elif guess[n] > right[n]:
result += "L" # lower
else:
result += "F" # false
print(result)
but... maybe you want to use zip function
def checkNumbers(guess, right):
result = ""
for g, r in zip(guess, right):
if g == r:
result += "T" # true
elif g < r:
result += "H" # higher
elif g > r:
result += "L" # lower
else:
result += "F" # false
print(result)
Funny bonus here:
def checkNumbers(guess, right):
print("".join("THL"[(g > r) + (g != r)] for g, r in zip(guess, right)))
I don't get why you need else part...
Initiate the list and print the result outside of the loop:
def checkNumbers(guess, right):
result = []
for n in range(4):
# do loopy stuff
print (result)
return # not strictly necessary
If you do it inside, you are creating a new list on every iteration.
# 8-bit-binary adder
#if you have questions about the code just ask
# arrays and funtions
Array1 = []
Array2 = []
#Input A and Validation
def vaildNumberA():
a = int(input("Enter your A value:"))
if (a < 0):
print("Please Enter A Valid Number For Input A")
elif (a > 255):
print("Please Enter A Valid Number For Input A")
else:
Array1 = [int(x) for x in list('{0:08b}'.format(a))]
#Input B and Validation
def vaildNumberB():
b = int(input("Enter your B value:"))
if (b < 0):
print("Please Enter A Valid Number For Input B")
elif (b > 255):
print("Please Enter A Valid Number For Input B")
else:
Array2 = [int(x) for x in list('{0:08b}'.format(b))]
# and gate
# AND Gate
def AND (a,b):
if (a == 1 and b == 1):
return 1
else:
return 0
# or gate
#OR Gate
def OR(a,b):
if (a == 1 or b == 1):
return 1
else:
return 0
# XOR GATEE
#XOR Gate
def XOR (a,b):
if (a == b):
return 0
else:
return 1
#carry formula
def carryformula(a,b,c,d):
return OR(AND(a,b), AND(c,d))
# this is where the calculation should be done
#formula for sum
def calculateSum(Array1,Array2):
carry = ""
sumof = []
for index, in range(len(Array1)):
list2 = Array2[index]
sec_xor_form = XOR(Array1[index],Array2[index])
sumof.append(XOR(sec_xor_form,carry))
carry = carryformula(Array1[index],Array2[index],sec_xor_form,carry)
return list(reversed(sumof))
calculateSum(Array1,Array2)
def main(Array1,Array2):
vaildNumberA()
vaildNumberB()
while True:
a = Array1
b = Array2
total = calculateSum(list(reversed(Array1)),list(reversed(Array2)))
print(total)
quit = input("if want to quit type q: ")
if quit == 'q':
break
main(Array1,Array2)
in the send it prints 0
The only problem in your code is that you need to return Array1 and Array2 from your functions and assign them inside the while true loop, once you do that the code works fine.
The updated code will be
# 8-bit-binary adder
#if you have questions about the code just ask
# arrays and funtions
Array1 = []
Array2 = []
#Input A and Validation
def vaildNumberA():
Array1 = []
a = int(input("Enter your A value:"))
if (a < 0):
print("Please Enter A Valid Number For Input A")
elif (a > 255):
print("Please Enter A Valid Number For Input A")
else:
Array1 = [int(x) for x in list('{0:08b}'.format(a))]
#Return the array
return Array1
#Input B and Validation
def vaildNumberB():
Array2 = []
b = int(input("Enter your B value:"))
if (b < 0):
print("Please Enter A Valid Number For Input B")
elif (b > 255):
print("Please Enter A Valid Number For Input B")
else:
Array2 = [int(x) for x in list('{0:08b}'.format(b))]
#Return the array
return Array2
# AND Gate
def AND (a,b):
if (a == 1 and b == 1):
return 1
else:
return 0
#OR Gate
def OR(a,b):
if (a == 1 or b == 1):
return 1
else:
return 0
#XOR Gate
def XOR (a,b):
if (a == b):
return 0
else:
return 1
#carry formula
def carryformula(a,b,c,d):
return OR(AND(a,b), AND(c,d))
# this is where the calculation should be done
#formula for sum
def calculateSum(Array1,Array2):
carry = ""
sumof = []
for index in range(len(Array1)):
list2 = Array2[index]
sec_xor_form = XOR(Array1[index],Array2[index])
sumof.append(XOR(sec_xor_form,carry))
carry = carryformula(Array1[index],Array2[index],sec_xor_form,carry)
return list(reversed(sumof))
#No need of a main function
while True:
#Call the function from within the while True loop
Array1 = vaildNumberA()
Array2 = vaildNumberB()
total = calculateSum(list(reversed(Array1)),list(reversed(Array2)))
print(total)
quit = input("if want to quit type q: ")
if quit == 'q':
break
And the output will look like
Enter your A value:5
Enter your B value:5
[0, 0, 0, 0, 1, 0, 1, 1]
if want to quit type q: 7
Enter your A value:9
Enter your B value:8
[0, 0, 0, 1, 0, 0, 0, 1]
....
I have created the below script to find out the prime factors of a number :
def check_if_no_is_prime(n):
if n <= 3:
return True
else:
limit = int(math.sqrt(n))
for i in range(2,limit + 1):
if n % i == 0:
return False
return True
def find_prime_factors(x):
prime_factors = []
if check_if_no_is_prime(x):
prime_factors.append(1)
prime_factors.append(x)
else:
while x % 2 == 0 and x > 1:
prime_factors.append(2)
x = x // 2
for i in range(3,x+1,2):
while x % i == 0 and x > 1:
if check_if_no_is_prime(i):
prime_factors.append(i)
x = x // i
if x <= 1:
return prime_factors
return prime_factors
no = int(input())
check = find_prime_factors(no)
print (check)
I am not sure whether this is the best and efficient way to do this ?
Can someone please point out any better way to do this ?
using sieve of erathnostanes to get all prime numbers from 2 to whatever limit inputted
def sieve(N):
from math import floor,sqrt
A=[1 for x in range(N+1)]
for count in range(2):
A[count]=0
for i in range(floor(sqrt(N))+1):
if A[i]==1:
for k in range(i*i,N+1,i):
A[k]=0
ans=list(enumerate(A))
res=[]
for (i,j) in ans:
if j==1:
res+=[i]
return res
print(sieve(100))
#my code
I'm trying to write a program that calculated the average number and determine the maximum + minimum number from user's input. I followed instructor's guideline but at the end, it messed up and I have no idea which step I did wrong. Please take a look and give me some suggestion, thank you.
MAX_PINTS = 256
def valid_real(value):
try:
if float(value) >= 0:
return True
if float(value) < 0:
return False
except ValueError:
return False
def get_real(prompt):
value = ""
value = input(prompt)
while not valid_real(value):
print(value, "is not a valid number. Please try again.")
value = input(prompt)
return float(value)
def y_or_n(prompt):
value = ""
value = input(prompt)
while True:
if value == "Yes" or value == "yes":
return True
elif value == "No" or value == "no":
return False
else:
print("Please enter yes or no!")
value = input(prompt)
def get_pints_collected(pints_collected):
done = False
counter = 0
while not done:
for turn_counter in range (7):
pints_collected[counter] = get_real("Please enter your collected pints: ")
counter = counter + 1
done = y_or_n("Do you want to end program? (Enter yes or no)")
return counter
def calculate_pints_average(pints_collected):
total = 0
minimum = pints_collected[0]
maximum = pints_collected[0]
for i in range (7):
total = total + pints_collected[i]
if pints_collected[i] > maximum:
maximum = pints_collected[i]
if pints_collected[i] < minimum:
minimum = pints_collected[i]
pints_average = total / 7
def output(pints_average, maximum, minimum):
pints_average = 0
maximum = 0
minimum = 0
print ("The average number of pints donated is: ", pints_average)
print ("The highest pints donated is: ", maximum)
print ("The lowest pints donated is: ", minimum)
def final():
pints_collected = [0.0 for x in range (MAX_PINTS) ]
pints_average = 0.0
number_pints_collected = 0
maximum = 0.0
minimum = 0.0
pints_collected = get_pints_collected(pints_collected)
pints_average = calculate_pints_average(pints_collected)
output(pints_average, maximum, minimum)
final()
def primetest(x):
if x < 2:
return False
if x == 2:
return True
if x % 2 == 0:
return False
for i in range(3,(x**0.5)+1):
if x % i == 0:
return False
return True
def nthprime(n):
primes = []
x = 2
while len(primes) < n:
if primetest(x) == True:
primes.append(x)
x = x + 1
return list(-1)
print nthprime(10001)
Whenever I try to run this it says that "print nthprime(10001)" is invalid syntax.
-prime test is to test wether a number is prime and nthprime creates a list of prime numbers a certain lengths and then return the last element of the list.
print is a function in Python 3, not a statement. You should change your last line of code to:
print(nthprime(10001))
In your code:
def nthprime(n):
primes = []
x = 2
while len(primes) < n:
if primetest(x) == True:
primes.append(x)
x = x + 1
return list(-1) // this is the error
I think you meant primes[-1], like this:
def nthprime(n):
primes = []
x = 2
while len(primes) < n:
if primetest(x) == True:
primes.append(x)
x = x + 1
return primes[-1] // this is now correct
You're also going to need to specify a range in integers, not float. So this:
for i in range(3,(x**0.5)+1):
Becomes this:
for i in range(3,int((x**0.5)+1)): // note the "int"