Goal
Create a Cron expression that will run a task at 2 pm and 4 am every day to run a Splunk alert
Except for only run the 2 pm task on Thursday (don't run the task a 4 am on Thursday).
Question
Is this an expression that can be represented in a single expression? (if so how).
Edited:
Agree with Simon, you can configure 2 separate cron schedules:
1st expression(skipping Thursday) - “At minute 0 past hour 4 and 14 on every day-of-week from Monday through Wednesday and every day-of-week from Friday through Sunday.”
0 4,14 * * 1-3,5-7
Cron expression for Thursday:
0 14 * * 4
You can't express that in Cron.
Suggest you go with 2 separate from expressions, both times on all days expect Thursday, and then a separate Cron task just for the 2pm task on Thursday
Related
We have jobs that are scheduled to run 1 time per day - every day
We do maintenance every 3rd Sunday of the month.
Up until now every month we have manually adjusted the cron to make the job run a little later in the morning then after maintenance we reset to the desired schedule
I am trying to change cron so that we
run at 7:00am every day EXCEPT the third Sunday of the month
run at 9:00am only on the third Sunday of the month
the second item I am able to handle
0 13 15-21 * 0
however, the first has me stumped. I thought this would do the job but it will only execute this if the day is between 1-14 or 22-31 but what if the 15th is not Sunday - then it won't run.
0 11 1-14,22-31 * *
How do I tell cron to run a schedule EXCEPT the third Sunday of the month?
There is a large base of guidance on how to limit when a cron runs to a specific window but I haven't found much for how to EXCLUDE a cron from a specific window
******** UPDATE ********
I think I may have come up with an answer - not sure if it is the most efficient but
0 11 1-14,22-31 * 0
0 13 15-21 * 0
0 11 1-14,22-31 * 1-6
The above will
run at 11:00 UTC on Sunday if date is between 1-14 or 22-31
run at 13:00 UTC on Sunday if date is between 15-21 (3rd Sunday)
run at 11:00 UTC Monday through Saturday all month
If a cron job has different timing than others, then it best to just define it by itself rather than trying to combine, unless you put some code in your script to do what you actually want. Doing something in cron on some nth day of the month is a pretty well known problem. Most crontab man pages have this note:
Note: The day of a command's execution can be specified in the following two fields — 'day of month', and 'day of week'. If both fields are restricted (i.e., do not contain the "*" character), the command will be run when either field matches the crent time. For example,
"30 4 1,15 * 5" would cause a command to be run at 4:30 am on the 1st and 15th of each month, plus every Friday.
So it does OR between the day of the week and the day of the month, not an AND. I don't who ever thought this was helpful, but that's the way it is. You can see solutions at:
Run every 2nd and 4th Saturday of the month
you need something like (this assumes cron runs /bin/sh):
[ `date +\%w` -eq 6 ] && <command>
on your cron job line, the above is would restrict to running only on Saturday.
I'm using Azure WebJob to Run Background tasks with WebJobs in Azure App Service. It's scheduled WebJob and I have following cron expression:
0 30 9 2 * 3
But it is not executing.
So my question is it possible to schedule this way. If not how to add 2 different schedules for a single webjob?
Thanks in Advance
Every Wednesday in every month is not equals to every 2nd day in month.
The format of CRON in wenjob is {second} {minute} {hour} {day} {month} {day-of-week}
You can set like this :0 30 9 2 * * or 0 30 9 * * 3
Refer to NCRONTAB expressions docs.
I have a Rundeck job that I would like to schedule to run from Sunday at 10 am to Friday at 17:00.
I could create three separate instances of the job and schedule it as below:
#every Sunday starting at 10 until midnight
0 */15 10-23 ? * 1
# every fifteen minutes starting on Monday midnight to Thursday 11:59 am
0 */15 * ? * 2-5 *
#every Friday starting at 12 am until 17:00 pm
0 */15 00-17 ? * 6
But it seems like there has to be a better way that will allow me to do this in one job. Any ideas? Thanks in advance.
The easiest way to do that is with Calendars feature (Enterprise), you can assign each rule to a single job. Take a look at this.
I need to suppress AppDynamics alerts on every Sunday between 10ma to 3pm and remaining all the time, they should run. To achieve this, i need to write a croj expression to satisfy the condition of "run all the time except every Sunday 10am to 3pm". what could be the cron expression for this ?
You can create a cron job to run from Monday to Saturday, here for each hour:
0 * * * mon-sat
And another to cover the interval you want on Sunday, here one by one hour from 10:00 AM to 03:00 PM:
0 10-15/1 * * sun
i'm trying to do some stuff automatically every 8 Weeks, so i had open a new user crontab like this one:
crontab -e
0 9 * */2 1-5 do_this_stuff
# do it every 2 month on monday till friday at 9:00 am
This should do the job every 2 month on monday till friday on 9:00 am, but i does not. It is doing the job evey week once. Don't get it. What i'm doing wrong?
Running System is a latest debian.
regarding http://wiki.ubuntuusers.de/Cron it should run fine
The Anwer is, cron can't do a job randomly on a random day in a month. I had to change my crontab to: 0 9 1 */2 * do_sm_stuff -- this runs every two Month always on the first Day in a Month
thank you Igor