Bash Script To Remove Users From Wordlist - linux

Question

I wrote the following script to remove users from a wordlist. The wordlist has 3 or 4 fields which are First Name, Middle Name, Last Name, and User ID. I am using awk to create a username that comprises of the user's firstname initial, lastname and last two digits of their ID. Then using the command userdel with flag r to remove users with their home directories as well.
However when I run the script it gives me an error saying the following:
Usage: userdel [options] LOGIN
Options:
-f, --force force some actions that would fail otherwise
e.g. removal of user still logged in
or files, even if not owned by the user
-h, --help display this help message and exit
-r, --remove remove home directory and mail spool
-R, --root CHROOT_DIR directory to chroot into
-Z, --selinux-user remove any SELinux user mapping for the user
The script:
#! /bin/bash
# Removing users using positional parameters
getusername(){
line=${1}
len=`echo ${line}|awk '{ FS = " " } ; { print NF}'`
if [[ ${len} -eq 3 ]]
then
initial=`echo ${line}| awk {'print $1'} |cut -c1`
lastname=`echo ${line} | awk {'print $2'}`
id=`echo ${line}| awk {'print $3'}|grep -o '..$'`
username=`echo ${initial}${lastname}${id} |tr '[:upper:]' '[:lower:]'`
elif [[ ${len} -eq 4 ]]
then
initial=`echo ${line} | awk {'print $1'} |cut -c1`
lastname=`echo ${line} | awk {'print $3'}`
id=`echo ${line}| awk {'print $4'}|grep -o '..$'`
username=`echo ${initial}${lastname}${id} |tr '[:upper:]' '[:lower:]'`
else
echo "Line ${line} is not expected as it should be considered for creating Username and Password"
fi
}
sudo userdel -r $getusername

Answer 1

How to invoke userdel?
userdel -r username
This deletes the account of user username, and removes that user's home directory and associated mail files.
For that, you need to use a variable instead of to invoke a function.
Otherwise userdel will complain, like it is already doing or like just typing userdel.