How to return prematurely from lambda - node.js

Question

I'm trying to trigger a lambda when I drop a new file in a bucket.
This code is working as in it's detecting the file and send the info to my API.
I'm also trying to ignore every file not name "text.txt" but I can't figure out how to return from the lambda inside that includes block
const http = require('http');
exports.handler = async (event, context) => {
return new Promise((resolve, reject) => {
const srcRegion = event.Records[0].awsRegion;
const srcEventTime = event.Records[0].eventTime;
const srcEventName = event.Records[0].eventName;
const srcIP = event.Records[0].requestParameters.sourceIPAddress;
const srcBucket = event.Records[0].s3.bucket.name;
const srcKey = decodeURIComponent(event.Records[0].s3.object.key.replace(/\+/g, " "));
const srcETag = event.Records[0].s3.object.eTag;
if (!srcKey.includes('text.txt')) {
resolve('Not original file');
}
const data = JSON.stringify({
lambda: {
src_bucket: srcBucket,
src_key: srcKey,
src_region: srcRegion,
src_event_time: srcEventTime,
src_event_name: srcEventName,
src_ip: srcIP,
src_etag: srcETag
}
});
const options = {
host: '*****************'
path: '*****************'
port: '*****************'
method: '*****************'
headers: '*****************'
};
const req = http.request(options, (res) => {
res.on('data', function(d) {
console.log(d);
});
});
req.on('error', (e) => {
// reject(e.message);
resolve('Error');
});
// send the request
req.write(data);
req.end();
resolve('Success');
});
};

Answer 1

Try this inside the includes block: context.done(undefined, 'Done.')