I made a program that swaps character in a string according my data dictionary but I want to display the swapped string as a text in the GUI that i can copy and paste outside the program.
I just started using tkinter a few days ago, but i do understand python:
import tkinter as tk
root = tk.Tk()
root.title("code converter")
itext = tk.StringVar()
top_spacer = tk.Label(root, text=" ")
top_spacer.grid(row=0, column=1)
text_label = tk.Label(root, text="type/paste text you want to convert")
text_label.grid(row=0, column=2)
text_entry = tk.Entry(root, textvariable=itext)#itext is the input text
text_entry.grid(row=1, column=2)
def translate():
trans_dict = {
'a':'z','b':'y', 'c':'x', 'd':'w', 'e':'v', 'f':'u', 'g':'t', 'h':'s', 'i':'r', 'j':'q', 'k':'p', 'l':'o', 'm':'n'
,'n':'m','o':'l', 'p':'k','q':'j','r':'i','s':'h','t':'g' ,'u':'f','v':'e','w':'d','x':'c','y':'b','z':'a'
,'A':'Z','B':'Y', 'C':'X','D':'W','E':'V', 'F':'U','G':'T','H':'S', 'I':'R', 'J':'Q', 'K':'P', 'L':'O', 'M':'N'
,'N':'M','O':'L', 'P':'K','Q':'J','R':'I','S':'H','T':'G','U':'F','V':'E','W':'D','X':'C','Y':'B','Z':'A'
#,'(1)':'(26)','(2)':'(25)','(3)':'(24)','(4)':'(23)','(5)':'(22)','(6)':'(21)','(7)':'(20)','(8)':'(19)', '(9)':'(18)', '(10)':'(17)', '(11)':'(16)', '(12)':'(15)', '(13)':'(14)'
#,'(14)':'(13)','(15)':'(12)','(16)':'(11)','(17)':'(10)','(18)':'(9)','(19)':'(8)','(20)':'(7)','(21)':'(6)','(22)':'(5)','(23)':'(4)','(24)':'(3)','(25)':'(2)','(26)':'(1)'
}
ttext = itext.get()
translation = "".join([trans_dict.get(c,c) for c in ttext])
ntext.set(translation)
convertion_button = tk.Button(root, text="convert text", command=translate)
convertion_button.grid(row=2, column=2)
ntext = tk.StringVar()
ntext_Message = tk.Message(root, textvariable=ntext, relief="sunken", bg="white", width=200)
ntext_Message.grid(row=3, column=2)
copy_button = tk.Button(root, text="copy text to clipboard")
copy_button.grid(row=2, column=1)
root.mainloop()
i want to display the ntext variable string in the GUI and copy it to the system clipboard when the copy button is pressed. is that possible?
Related
This question already has answers here:
Why is my Button's command executed immediately when I create the Button, and not when I click it? [duplicate]
(5 answers)
Closed 2 years ago.
I have a small issue for which I can`t find the reason.
I have the following GUI, and it pops the message box when I run it, even though it is inside a procedure which is triggered only on button press.
Tried even creating a secondary function which will show only the message box and still did not fix the issue.
Thank you for your help... I am quite sure that there is an easy fix which I just do not see...
import tkinter as tk
from tkinter import ttk
import tkinter.messagebox
import jl_generator
def run():
jl_generator.run_process()
tkinter.messagebox.showerror('Done','Done')
def show():
temp_list = user_input_list
for i in range(0, len(user_input_list[0])):
listBox.insert("", "end", values = (user_input_list[0][i],user_input_list[1][i],user_input_list[2][i],user_input_list[3][i],user_input_list[4][i],user_input_list[6][i],user_input_list[8][i]))
# Column Names for the TreeView
cols = ('Entity', 'Customer Nr', 'Account Code', 'Profit Centre', 'Partner Profit Centre', 'Amount', 'Nr Of Journal Lines')
# Input data for the tree view
user_input_list, journal_code = jl_generator.get_user_input()
#Creating the
root = tk.Tk()
root.title('JL Generator')
#Create the treeview
listBox = ttk.Treeview(root, columns=cols, show='headings')
for col in cols:
listBox.heading(col, text=col)
listBox.grid(row=1, column=0, columnspan=3)
#-------------LABELS--------------
#Title Label
label = tk.Label(root, text="Journal Lines Generator", font=("Arial",30)).grid(row=0, columnspan=3)
#Journal Code Label
show_journal_code = tk.Label(root, text = 'Journal Code = ' + journal_code).grid(row=6, column=1)
#Number of Journal Lines Label
show_number_of_journal_lines = tk.Label(root, text = 'Number of Journal Lines = ' + str(sum(user_input_list[8][i] for i in range(0, len(user_input_list[0]))))).grid(row=5, column=1)
#------------BUTTONS-----------
#Run the Generation
run_process = tk.Button(root, text="Generate JLs", width=15, command=run()).grid(row=4, column=1)
#Show the input data
showScores = tk.Button(root, text="Show Input", width=15, command=show).grid(row=4, column=0)
#Close the window
closeButton = tk.Button(root, text="Exit", width=15, command=exit).grid(row=4, column=2)
root.mainloop()
run_process = tk.Button(root, text="Generate JLs", width=15, command=run()).grid(row=4, column=1)
this is incorrect.
I used to feel confused about this.
You should use:
run_process = tk.Button(root, text="Generate JLs", width=15, command=run).grid(row=4, column=1)
In python,function is an object,call function should use function()
If you debug this code,you will find that after debug this code
run_process = tk.Button(root, text="Generate JLs", width=15, command=run()).grid(row=4, column=1)
you will find it will call run function and run it.
And Finally,run_process["command"] will be the returned value ofrun()
I would like to use Tkinter to be able to disable one entry if 'no' is selected from a drop down menu.
from tkinter import *
def disableEntry(entry):
entry.config(state='disable')
def allowEntry(entry):
entry.config(state='normal')
def main():
print("test")
root = Tk() #create a TK root window
root.title("Lunch and Learn") #Title of the window
L1 = Label(root, text = "Label 1").grid(row=0, column=0, padx=30, pady=(20,5))
L2 = Label(root, text = "Label 2").grid(row=1, column=0, pady=5)
var = StringVar()
E1 = Entry(root,bd =3)
E1.grid(row=0, column=1)
D1 = OptionMenu(root,var,"yes","no")
D1.grid(row=1,column=1)
if var.get() == 'no':
disableEntry(E1)
elif var.get() == 'yes':
allowEntry(E1)
B2 = Button(text = "Submit", command=main).grid(row=4, column=2)
root.mainloop()
the above code is a simple example of what i have tried. I have created two functions called 'disableEntry' and 'allowEntry' which should change the state of the entry box but they don't appear to do anything when i change the input of the drop down menu.
i dont know if i am approaching this the wrong way or if there is a standardized way to do this.
any help would be appreciated.
You need a way to check the state of the selection after it is changed. That can be achieved with adding a callback command to the OptionMenu widget.
You were checking the correct variable, but the point you were checking it at was before the screen window had even displayed.
from tkinter import Label, StringVar, OptionMenu, Entry, Tk, Button
# change the state of the Entry widget
def change_state(state='normal'):
E1.config(state=state)
def main():
print("test")
# callback function triggered by selecting from OptionMenu widget
def callback(*args):
if var.get() == 'no':
change_state(state='disable')
elif var.get() == 'yes':
change_state(state='normal')
root = Tk() #create a TK root window
root.title("Lunch and Learn") #Title of the window
L1 = Label(root, text="Label 1").grid(row=0, column=0, padx=30, pady=(20, 5))
L2 = Label(root, text="Label 2").grid(row=1, column=0, pady=5)
var = StringVar()
E1 = Entry(root, bd=3)
E1.grid(row=0, column=1)
D1 = OptionMenu(root, var, "yes", "no", command=callback)
D1.grid(row=1, column=1)
B2 = Button(text = "Submit", command=main).grid(row=4, column=2)
root.mainloop()
I made a text widget to write questions. I want to insert images when add image button is pressed. How can I do that? When I choose another image the first one is deleted. Right now I am able to add one image using the code:
import tkinter as tk
root = tk.Tk()
root.geometry('800x520+0+0')
global img
img = tk.PhotoImage(file="quiz.gif")
def add_img():
T.image_create(tk.INSERT, image=img)
tk.Button(root, text="Add Image", font=('Verdana',8),
command=add_img).place(x=690, y=0)
T = tk.Text(root, width=65, height=17, padx=10, pady=10, font=('Verdana',
14), wrap='word')
T.place(x=0, y=0)
root.mainloop()
I want to add different images when chosen using tk-listbox.
Thanks for the help.
I used dictionary to solve the problem.
import tkinter as tk, glob
root = tk.Tk()
root.geometry('800x520+0+0')
Images = {}
for infile in glob.glob('*.gif'):
img = infile[:-4]
if img not in Images:
Images[img] = tk.PhotoImage(file=infile)
def add_img():
global listbox
listbox = tk.Listbox(root, font=('Verdana',9), width=12)
listbox.place(x=60,y=2)
for infile in glob.glob('*.gif'):
listbox.insert(tk.END, infile[:-4])
listbox.bind('<<ListboxSelect>>',CurSelet)
def CurSelet(event):
fn = listbox.get(tk.ANCHOR)
listbox.destroy()
T.image_create(tk.INSERT, image=Images[fn])
tk.Button(root, text="Add Image", font=('Verdana',8),
command=add_img).place(x=690,y=0)
T = tk.Text(root, width=65, height=17, padx=10, pady=10, font=('Verdana',
14), wrap='word')
T.place(x=0, y=50)
root.mainloop()
im new to Python3.6.2
So I want a program that takes an input (Via text box from tkinter) and outputs a word in my custom "language"
with this function
def Mescre(n):
Words = (n)
Mes = str.maketrans('abcdefghijklmnopqrstuvwxyz', 'ektnopzcamjqwyuxsbfdiglhrv')
print(Words.translate(Mes))
and here's what i want the window to look like
from tkinter import*
root = Tk()
Mescre = Label(root, text="Input:")
English = Label(root , text="Output:")
label1.grid(row=0, sticky=E)
label2.grid(row=1, sticky=E)
entry1 = Entry(root)
entry2 = Entry(root)
entry1.grid = (row=0, column=1)
entry2.grid = (row=1, column=1)
root.mainloop()
if "hello" was in the Input text box, i want the output to be "coqqu" in the Output text box.
See my example below:
from tkinter import *
class App:
def __init__(self, root):
self.root = root
self.sv = StringVar()
self.Mes = str.maketrans('abcdefghijklmnopqrstuvwxyz', 'ektnopzcamjqwyuxsbfdiglhrv')
self.entry = Entry(self.root, textvariable = self.sv)
self.label = Label(self.root)
self.entry.pack()
self.label.pack()
self.sv.trace("w", self.callback)
def callback(self, *args):
self.label.configure({"text": self.entry.get().translate(self.Mes)})
root = Tk()
App(root)
root.mainloop()
Here we define a StringVar() to be the value of the attribute textvariable for the Entry widget.
We then assign a callback to a trace() on the variable so that whenever the variable is updated (When someone types in the Entry) we call callback().
Within callback() we use configure() on the Label widget in order to set the text to equal the post translation version of the value of the Entry widget.
This creates a "live updating" translation effect.
Here's a basic example:
import tkinter as tk
root = tk.Tk()
def Mescre():
val = textfield.get()
Words = (val)
Mes = str.maketrans('abcdefghijklmnopqrstuvwxyz', 'ektnopzcamjqwyuxsbfdiglhrv')
print(Words.translate(Mes))
textfield = tk.Entry(root)
textfield.pack()
button = tk.Button(root, command=Mescre, text='Push')
button.pack()
root.mainloop()
Updated:
import tkinter as tk
root = tk.Tk()
def Mescre():
val = textfield.get()
Words = (val)
Mes = str.maketrans('abcdefghijklmnopqrstuvwxyz', 'ektnopzcamjqwyuxsbfdiglhrv')
translation = Words.translate(Mes)
#print(translation)
outputfield.delete(0, tk.END)
outputfield.insert(0, translation)
textfield = tk.Entry(root)
textfield.pack()
outputfield = tk.Entry(root)
outputfield.pack()
button = tk.Button(root, command=Mescre, text='Push')
button.pack()
root.mainloop()
i am using tkinter to make a gui and have made various different buttons and now i have made all this i am unsure how to correctly make the first gui box close as the second one opens (sign_in function)
from tkinter import *
class login:
def __init__(self, master):
frame = Frame(master)
frame.grid()
self.button1 = Button(frame, text="signup", fg="green",command=self.sign_in)
self.button2 = Button(frame, text="sign in", fg="black",)
self.button3 = Button(frame, text="quit", fg="red", command=frame.master.destroy)
self.button1.grid(stick=W)
self.button2.grid(stick=W)
self.button3.grid(stick=W)
def sign_in(self):
frame = Frame()
frame.grid()
name = Label(root, text="Name: ")
password = Label(root, text="password: ")
entry1 = Entry(root)
entry2 = Entry(root)
name.grid(row=0, sticky=E)
password.grid(row=1, sticky=E)
entry1.grid(row=0, column=1)
entry2.grid(row=1, column=1)
c = Checkbutton(root, text="keep me logged in")
c.grid(columnspan=2, sticky="w")
root = Tk()
account=login(root)
root.mainloop()
Your code contains some indentation errors so I'll just go by your question.
when i click the button 'signup' it closes that gui and opens the next one
You can do so by first withdrawing your root window like this: root.withdraw() which will hide your original window. Then create a Toplevel window like this: newWindow = tk.Toplevel(root) to create a new window. You will just need to place these lines in the button command call.
Here's what you can change in the sign_in note that I changed all the masters to frame and not root:
def sign_in(self):
root.withdraw()
frame = Toplevel(root)
name = Label(frame, text="Name: ")
password = Label(frame, text="password: ")
entry1 = Entry(frame)
entry2 = Entry(frame)
name.grid(row=0, sticky=E)
password.grid(row=1, sticky=E)
entry1.grid(row=0, column=1)
entry2.grid(row=1, column=1)
c = Checkbutton(frame, text="keep me logged in")
c.grid(columnspan=2, sticky="w")