I have an output file with a load of information in and I want to read a number value that appears after a specific word.
In my file, I have a line such as
"Final energy, E = -82137.1098 eV"
What I would like to do is search my file for the string 'Final energy' and then read and store the number value.
So far I have managed to search the file for 'Final energy' and print the entire line containing that string but I can't seem to find a way to then read the number.
So far my code goes like this
energystring = 'Final energy'
with open(filename, 'r') as file:
for line in file:
if energystring in line:
energyline = line
print(energyline)
Thank you for any help you can give.
You just need to parse the number out of the string then. You can split the string on whitespace to get all the words, try to cast each word to a float, and get the one that works. Since there's only one number in the string, whatever successfully casts to float is your energy number.
def get_energy_level(line):
for word in line.split():
try:
return float(word)
except ValueError:
pass
with open(filename, 'r') as file:
for line in file:
if energystring in line:
energy_level = get_energy_level(line)
Related
I have a .txt file that I want to search for specific words, or phrases. I want to be able to use an input to do this. Then I would like the file parsed for the input and printed. Basically something like this:
input("Search For:")I WANT TO ENTER MY SEARCH TERM HERE
print(I WANT TO PRINT WHAT I SEARCHED FOR ABOVE)
I am able to do this another way by creating a variable, and then just changing the variable name as needed, but this is not ideal for me. Any ideas on how to create an input to search my .txt?
word = 'Scrubbing'
#variable to store search term
with open(r'/Users/kev/PycharmProjects/find_text/common.txt', 'r') as fp:
lines = fp.readlines()
# read all lines in a list
for line in lines:
if line.find(word) != -1:
# check if string present on a current line
print(word, 'string exists in file')
print('Line Number:', lines.index(line))
print('Line:', line)
The question:
Write a function file_size(filename) that returns a count of the number of characters in the file whose name is given as a parameter. You may assume that when being tested in this CodeRunner question your function will never be called with a non-existent filename.
For example, if data.txt is a file containing just the following line: Hi there!
A call to file_size('data.txt') should return the value 10. This includes the newline character that will be added to the line when you're creating the file (be sure to hit the 'Enter' key at the end of each line).
What I have tried:
def file_size(data):
"""Count the number of characters in a file"""
infile = open('data.txt')
data = infile.read()
infile.close()
return len(data)
print(file_size('data.txt'))
# data.txt contains 'Hi there!' followed by a new line
character.
I get the correct answer for this file however I fail a test that users a larger/longer file which should have a character count of 81 but I still get 10. I am trying to get the code to count the correct size of any file.
I am searching for a string in .gz files and trying to print the last line with a specific string. It is giving me 'list Index is out of range' if the string is not present. Below is the code I was working on
with gzip.open(files, 'r') as r, open ('output.txt', 'w') as w:
string = [line.strip() for line in r.readlines() if b'STRING' in line]
print (string[-1])
With the above code, I can print the last line if the 'STRING' is in the file. If it is not present it is throwing an error. In the else case, I would like to print "NO STRING PRESENT" or something like that. Any help in understanding this will really be helpful. Thanks in advance
Use try-except:
try:
print (string[-1])
except:
print ("NO STRING PRESENT")
or write your own conditional. Start thinking on the lines of the list string itself, what its length would be in either case and then what would you want to do for each case.
sample input
in parsing a text file .txt = ["'blah.txt'", "'blah1.txt'", "'blah2.txt'" ]
the expected output in another text file out_path.txt
blah.txt
blah1.txt
blah2.txt
Code that I tried, this just appends "[]" to the input file. While I also tried perl one liner replacing double and single quotes.
read_out_fh = open('out_path.txt',"r")
for line in read_out_fh:
for word in line.split():
curr_line = re.findall(r'"(\[^"]*)"', '\n')
print(curr_line)
this happens because while you reading a file it will be taken as string and not as a list even if u kept the formatting of a list. thats why you getting [] while doing re.for line in read_in_fh: here you are taking each letters in the string thats why you are not getting the desired output. so iwrote something first to transform the string into a list. while doing that i also eliminated "" and '' as you mensioned. then wrote it in to a new file example.txt.
Note: change the file name according to your files
read_out_fh = open('file.txt',"r")
for line in read_out_fh:
line=line.strip("[]").replace('"','').replace("'",'').split(", ")
with open("example.txt", "w") as output:
for word in line:
#print(word)
output.write(word+'\n')
example.txt(outputfile)
blah.txt
blah1.txt
blah2.txt
The code below works out for your example you gave in the question:
# Content of textfile.txt:
asdasdasd=["'blah.txt'", "'blah1.txt'", "'blah2.txt'"]asdasdasd
# Code:
import re
read_in_fh = open('textfile.txt',"r")
write_out_fh = open('out_path.txt', "w")
for line in read_in_fh:
find_list = re.findall(r'\[(".*?"*)\]', line)
for element in find_list[0].split(","):
element_formatted = element.replace('"','').replace("'","").strip()
write_out_fh.write(element_formatted + "\n")
write_out_fh.close()
I tried to find the solution on different platform, but I couldn't able to. So I am here.
I am reading a line in a file which contains a specific string(user Input). But the Problem is, my Code is reading all the lines. For an example.
Here user Input is: "Mon_ErrEntryEspSqPlaus"
Output line:
/begin MEASUREMENT Icsp_Dem_Deb_LfEve_Mon_ErrEntryEspSqPlaus
Here Output line string has Suffix with it. Not intended.
Instead of reading just below line:
941 "Mon_ErrEntryEspSqPlaus"
No Suffix and prefix in the above line with user Input string.
Here is the Code:
import re
def a2l_reader(parameter):
count = 0;
count_1 = 0;
with open("TPT.a2l", errors = 'replace') as myfile:
for num, line in enumerate(myfile,1):
if parameter in line:
if re.match(r'sample', line):
count += 1
else:
count_1 += 1
print(count)
print(count_1)
The Question is how to search for the specific line which contains a specific string without Suffix and prefix. Since I have to use the number associated with that string.
Thanks in advance
Instead of
if parameter in line:
you can simply do
if parameter == line:
and it will only proceed if there is an exact match. The first example (which is the one you have in your code) will match if there are substrings matching your input
In that case if you want to match the exact string you can split by spaces and then check contains using in ::
Split by Spaces and the check in list
if parameter in re.split("( )",line):