I'm trying to do something like that
var name = "Thiago Valente"
switch name {
case .contains("Valente"):
return "Hello, My surname is like your"
default:
return "Hi ;)"
}
The contains don't exists, so it is possible to do with switch case? ( I know it's simple to do with if-else )
You can use the let x pattern, followed by a where clause:
var name = "Thiago Valente"
switch name {
case let x where x.contains("Valente"):
return "Hello, My surname is like your"
default:
return "Hi ;)"
}
Normally let x will match every value, but you say more specifically what kind of values you want to match in the where clause.
Related
How can I check if multiple strings are empty in an elegant way? This is how I currently do it:
//if one required field is empty, close the connection
if (registerRequest.Email == "") ||
(registerRequest.PhoneNumber == "")||
(registerRequest.NachName =="") ||
(registerRequest.VorName =="") ||
(registerRequest.Password =="") ||
(registerRequest.VerificationId ==""){
//Could not proceed
w.WriteHeader(UNABLE_TO_PROCEED)
w.Write([]byte("Unable to register account."))
return
}
Note: You may use the solution below if you keep the "is-valid" condition in your handler, and also if you separate your condition into another function or method.
You can create a simple helper function, which has a variadic parameter, and you can call it with any number of string values:
func containsEmpty(ss ...string) bool {
for _, s := range ss {
if s == "" {
return true
}
}
return false
}
Example using it:
if containsEmpty("one", "two", "") {
fmt.Println("One is empty!")
} else {
fmt.Println("All is non-empty.")
}
if containsEmpty("one", "two", "three") {
fmt.Println("One is empty!")
} else {
fmt.Println("All is non-empty.")
}
Output of the above (try it on the Go Playground):
One is empty!
All is non-empty.
Your example would look like this:
if containsEmpty(registerRequest.Email,
registerRequest.PhoneNumber,
registerRequest.NachName,
registerRequest.VorName,
registerRequest.Password,
registerRequest.VerificationId) {
// One of the listed strings is empty
}
Also registerRequest is a kinda long name, it could be shortened to like r. If you can't or don't want to rename it in the surrounding code and if you want to shorten the condition, you could also do something like this:
If registerRequest is a pointer (or interface), you could also write:
if r := registerRequest; containsEmpty(r.Email,
r.PhoneNumber,
r.NachName,
r.VorName,
r.Password,
r.VerificationId) {
// One of the listed strings is empty
}
Actually you can do this even if registerRequest is not a pointer, but then the struct will be copied. If registerRequest is a struct, then you can take its address to avoid having to copy it like this:
if r := ®isterRequest; containsEmpty(r.Email,
r.PhoneNumber,
r.NachName,
r.VorName,
r.Password,
r.VerificationId) {
// One of the listed strings is empty
}
As Mario Santini mentioned in comment, a way to increase testability, encapsulate this logic, and decouple it from your handler method (which judging by the number of fields looks like it is at risk of changing at a different rate than your handler) could be to put this logic in a function:
func validRequest(registerRequest ?) bool {
return registerRequest.Email == "" ||
registerRequest.PhoneNumber == "" ||
registerRequest.NachName == "" ||
registerRequest.VorName == "" ||
registerRequest.Password == "" ||
registerRequest.VerificationId == ""
}
This now supports very focused, table driven tests, that can exercise what it means to be a valid request independent of any method involving writing headers.
It allows you to verify the valid/invalid path of your enclosing function, but to have very focused tests here. It also allows you to change what it means to be a valid request and verify it independent of your enclosing function.
You can use a switch:
switch "" {
case registerRequest.Email,
registerRequest.NachName,
registerRequest.Password,
registerRequest.PhoneNumber,
registerRequest.VerificationId,
registerRequest.VorName:
w.WriteHeader(UNABLE_TO_PROCEED)
w.Write([]byte("Unable to register account."))
return
}
https://golang.org/ref/spec#Switch_statements
I've got a switch case like this:
def someString = 'hello1234bla'
// ...
switch (someString) {
case {it.contains('1234')}:
doSomething()
break
case {it.contains('2468')}:
doSomethingElse()
break
default:
throw new Exception("ERROR: Number not found")
break
}
This seems to be quite a lot of code for something so seemingly simple. All I want is to have different functions be executed when someString contains a specific substring. Is there no simpler way to do this, apart from maybe an if-else cascade?
This is pretty close to what the comments above suggest, but I'll write out a working example with indentation etc and perhaps it will be a bit more readable:
def someString = "hello1234bla"
def found = [
'1234': { println "do something" },
'2468': { println "do something else" }
].find { pattern, action ->
if (someString.contains(pattern)) { action(); true }
else false
}
if (!found) throw new Exception("ERROR: Number not found")
this executes the first matching action and throws an exception if no matches were found. If you need to execute an action for every match, replace the find call with a findAll call.
Another way of executing code based on a pattern in the string is the groovy String eachMatch method:
def someString = "hello1234blae"
someString.eachMatch(/1234/) { println "do something" }
someString.eachMatch(/2468/) { println "do something else" }
which uses regular expressions and runs the closure (the block in the curlies after the eachMatch call) once for every match. Thus:
someString.eachMatch(/e/) { println "runs twice" }
on the above string would execute twice as there are two 'e' characters in the string.
I was using this, in Swift 1.2
let urlwithPercentEscapes = myurlstring.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)
This now gives me a warning asking me to use
stringByAddingPercentEncodingWithAllowedCharacters
I need to use a NSCharacterSet as an argument, but there are so many and I cannot determine what one will give me the same outcome as the previously used method.
An example URL I want to use will be like this
http://www.mapquestapi.com/geocoding/v1/batch?key=YOUR_KEY_HERE&callback=renderBatch&location=Pottsville,PA&location=Red Lion&location=19036&location=1090 N Charlotte St, Lancaster, PA
The URL Character Set for encoding seems to contain sets the trim my
URL. i.e,
The path component of a URL is the component immediately following the
host component (if present). It ends wherever the query or fragment
component begins. For example, in the URL
http://www.example.com/index.php?key1=value1, the path component is
/index.php.
However I don't want to trim any aspect of it.
When I used my String, for example myurlstring it would fail.
But when used the following, then there were no issues. It encoded the string with some magic and I could get my URL data.
let urlwithPercentEscapes = myurlstring.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)
As it
Returns a representation of the String using a given encoding to
determine the percent escapes necessary to convert the String into a
legal URL string
Thanks
For the given URL string the equivalent to
let urlwithPercentEscapes = myurlstring.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)
is the character set URLQueryAllowedCharacterSet
let urlwithPercentEscapes = myurlstring.stringByAddingPercentEncodingWithAllowedCharacters( NSCharacterSet.URLQueryAllowedCharacterSet())
Swift 3:
let urlwithPercentEscapes = myurlstring.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed)
It encodes everything after the question mark in the URL string.
Since the method stringByAddingPercentEncodingWithAllowedCharacters can return nil, use optional bindings as suggested in the answer of Leo Dabus.
It will depend on your url. If your url is a path you can use the character set
urlPathAllowed
let myFileString = "My File.txt"
if let urlwithPercentEscapes = myFileString.addingPercentEncoding(withAllowedCharacters: .urlPathAllowed) {
print(urlwithPercentEscapes) // "My%20File.txt"
}
Creating a Character Set for URL Encoding
urlFragmentAllowed
urlHostAllowed
urlPasswordAllowed
urlQueryAllowed
urlUserAllowed
You can create also your own url character set:
let myUrlString = "http://www.mapquestapi.com/geocoding/v1/batch?key=YOUR_KEY_HERE&callback=renderBatch&location=Pottsville,PA&location=Red Lion&location=19036&location=1090 N Charlotte St, Lancaster, PA"
let urlSet = CharacterSet.urlFragmentAllowed
.union(.urlHostAllowed)
.union(.urlPasswordAllowed)
.union(.urlQueryAllowed)
.union(.urlUserAllowed)
extension CharacterSet {
static let urlAllowed = CharacterSet.urlFragmentAllowed
.union(.urlHostAllowed)
.union(.urlPasswordAllowed)
.union(.urlQueryAllowed)
.union(.urlUserAllowed)
}
if let urlwithPercentEscapes = myUrlString.addingPercentEncoding(withAllowedCharacters: .urlAllowed) {
print(urlwithPercentEscapes) // "http://www.mapquestapi.com/geocoding/v1/batch?key=YOUR_KEY_HERE&callback=renderBatch&location=Pottsville,PA&location=Red%20Lion&location=19036&location=1090%20N%20Charlotte%20St,%20Lancaster,%20PA"
}
Another option is to use URLComponents to properly create your url
Swift 3.0 (From grokswift)
Creating URLs from strings is a minefield for bugs. Just miss a single / or accidentally URL encode the ? in a query and your API call will fail and your app won’t have any data to display (or even crash if you didn’t anticipate that possibility). Since iOS 8 there’s a better way to build URLs using NSURLComponents and NSURLQueryItems.
func createURLWithComponents() -> URL? {
var urlComponents = URLComponents()
urlComponents.scheme = "http"
urlComponents.host = "www.mapquestapi.com"
urlComponents.path = "/geocoding/v1/batch"
let key = URLQueryItem(name: "key", value: "YOUR_KEY_HERE")
let callback = URLQueryItem(name: "callback", value: "renderBatch")
let locationA = URLQueryItem(name: "location", value: "Pottsville,PA")
let locationB = URLQueryItem(name: "location", value: "Red Lion")
let locationC = URLQueryItem(name: "location", value: "19036")
let locationD = URLQueryItem(name: "location", value: "1090 N Charlotte St, Lancaster, PA")
urlComponents.queryItems = [key, callback, locationA, locationB, locationC, locationD]
return urlComponents.url
}
Below is the code to access url using guard statement.
guard let url = createURLWithComponents() else {
print("invalid URL")
return nil
}
print(url)
Output:
http://www.mapquestapi.com/geocoding/v1/batch?key=YOUR_KEY_HERE&callback=renderBatch&location=Pottsville,PA&location=Red%20Lion&location=19036&location=1090%20N%20Charlotte%20St,%20Lancaster,%20PA
In Swift 3.1, I am using something like the following:
let query = "param1=value1¶m2=" + valueToEncode.addingPercentEncoding(withAllowedCharacters: .alphanumeric)
It's safer than .urlQueryAllowed and the others, because it this will encode every characters other than A-Z, a-z and 0-9. This works better when the value you are encoding may use special characters like ?, &, =, + and spaces.
In my case where the last component was non latin characters I did the following in Swift 2.2:
extension String {
func encodeUTF8() -> String? {
//If I can create an NSURL out of the string nothing is wrong with it
if let _ = NSURL(string: self) {
return self
}
//Get the last component from the string this will return subSequence
let optionalLastComponent = self.characters.split { $0 == "/" }.last
if let lastComponent = optionalLastComponent {
//Get the string from the sub sequence by mapping the characters to [String] then reduce the array to String
let lastComponentAsString = lastComponent.map { String($0) }.reduce("", combine: +)
//Get the range of the last component
if let rangeOfLastComponent = self.rangeOfString(lastComponentAsString) {
//Get the string without its last component
let stringWithoutLastComponent = self.substringToIndex(rangeOfLastComponent.startIndex)
//Encode the last component
if let lastComponentEncoded = lastComponentAsString.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.alphanumericCharacterSet()) {
//Finally append the original string (without its last component) to the encoded part (encoded last component)
let encodedString = stringWithoutLastComponent + lastComponentEncoded
//Return the string (original string/encoded string)
return encodedString
}
}
}
return nil;
}
}
Swift 4.0
let encodedData = myUrlString.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlHostAllowed)
I am looking for a way to replace a word inside a string in swift. Can anyone help?
this is what I have so far, I can find the specific word, but i do not know how to replace it...
var str = "helo, playgound"
var findWords = ["helo","playgound"]
var replaceWords = ["hello","playground"]
extension String {
var wordList:[String] {
return "".join(componentsSeparatedByCharactersInSet(NSCharacterSet.punctuationCharacterSet())).componentsSeparatedByString(" ")
}
}
func stringToArray() -> Array<String> {
var arr = str.wordList
return arr
}
func correction(var _arr:Array<String>) -> String{
for var i = 0; i < _arr.count; i++ {
if str.lowercaseString.rangeOfString(findWords[i]) != nil {
println("exists")
}
}
return str
}
It depends what your definition of a "word" is. If you're looking for an intelligent built-in notion of a "word", the easiest solution is probably to use NSRegularExpression, which knows where "word" boundaries are:
var s = NSMutableString(string:"hello world, go to hell")
let r = NSRegularExpression(
pattern: "\\bhell\\b",
options: .CaseInsensitive, error: nil)!
r.replaceMatchesInString(
s, options: nil, range: NSMakeRange(0,s.length),
withTemplate: "heaven")
After that, s is "hello world, go to heaven", which is the right answer; we replaced the "hell" that is a word, but not the "hell" in "hello". Notice that we are also matching case-insensitively, which seems to be one of your desiderata.
That example shows how do just one pair ("hell" and "heaven") but it is easy to abstract it into a method so that you can do it again and again for further pairs:
var str = "helo, playgound"
var findWords = ["helo", "playgound"]
var replaceWords = ["hello", "playground"]
func correct(str:String, orig:String, repl:String) -> String {
var s = NSMutableString(string:str)
let r = NSRegularExpression(
pattern: "\\b\(orig)\\b",
options: .CaseInsensitive, error: nil)!
r.replaceMatchesInString(
s, options: nil, range: NSMakeRange(0,s.length),
withTemplate: repl)
return s
}
for pair in Zip2(findWords,replaceWords) {
str = correct(str, pair.0, pair.1)
}
str // hello, playground
The easiest is probably this:
let statement = "Swift is hard."
let swiftRange = statement.startIndex..<advance(statement.startIndex, 5)
let newStatement = statement.stringByReplacingCharactersInRange(swiftRange, withString: "Objective-C")
// now newStatement = "Objective-C is hard."
Following a longer commenting tour: The above is under the assumption of the OP "I can find the specific word, but i do not know how to replace it...", so it's not about finding a "word" which to define is another discussion. It's just about replacing an already found word.
Another word on stringByReplacingCharactersInRange: #matt states that this is Cocoa cross-over. In that case Apple is telling a plain lie:
I fostered the web but there's no Apple source telling anything. Only the Foundation method for NSString. Their Swift book is silent too (in many respects). Well, I don't trust Apple anyway any longer since Yosemite-fail.
If want to both assign a string and check that its not empty in Swift.
if let alternative3Text = attributes.stringForKey("choiceThree") && alternative3Text != "" {
// do stuff with alternative3Text
}
Is this possible in Swift, or do i have to do a nested if-statement?
Update: As of Swift 3 (Xcode 8), additional clauses are
separated by a comma, not by where:
if let alternative3Text = attributes.string(forKey: "choiceThree"),
alternative3Text != "" {
// do stuff with alternative3Text
}
Update: As of Swift 1.2 (Xcode 6.3 beta), you can combine
optional binding with additional conditions:
if let alternative3Text = attributes.stringForKey("choiceThree") where alternative3Text != "" {
// do stuff with alternative3Text
}
Using switch-case still works but is not necessary anymore for this purpose.
Old answer:
It is not possible with an if statement, but with switch.
A switch case can use a where clause to check for additional conditions
(documentation).
Assuming (from your question) that attributes.stringForKey("choiceThree") returns
String?, the following would work:
switch (attributes.stringForKey("choiceThree")) {
case .Some(let alternative3Text) where alternative3Text != "":
// alternative3Text is the unwrapped String here
default:
break
}
No, you can't require additional expressions to be true in an if let statement. You will need to add additional code to do this in either the form of a nested if statement as you've already mentioned, or in some other way. If your only requirement is to keep this statement looking clean and wouldn't mind moving some of the logic elsewhere, you could always make an extension to what ever type your attributes variable is to add this functionality.
Here's an example if attributes was an instance of NSUserDefaults. (just because it already contains a stringForKey() instance method.)
extension NSUserDefaults {
func nonEmptyStringForKey(key: String) -> String? {
let full = self.stringForKey(key)
return full != "" ? full : nil
}
}
And then use it like this
if let alternative3Text = attributes.nonEmptyStringForKey("choiceThree") {
// stuff
}