I am making a GUI that had the Welcome page and the main page. The purpose is to let user agree on the welcome page, the welcome page is dismissed and the main page will show up for further step. However, the icon in the taskbar only shows up in the welcome page, when we click into the main window the icon is disappeared and the app appeared to be a minimized window on the bottom left corner in the screen.
The starting page and main window layout is appear like this.
class welcome_window(QtWidgets.QMainWindow):
def __init__(self,parent = None):
super(welcome_window, self).__init__(parent)
self.confirm_button = QtWidgets.QPushButton('Yes')
self.confirm_button.clicked.connect(self.startup)
Main_layout = QtWidgets.QHBoxLayout()
Main_layout.addWidget(self.confirm_button)
self.main.setLayout(Main_layout)
def startup(self):
self.close()
dialog = Main_window(self)
self.dialogs.append(dialog)
dialog.show()
class Main_window(QtWidgets.QMainWindow):
def __init__(self,parent = None):
super(Main_window, self).__init__(parent)
self.setGeometry(50, 50, 1500, 850)
# here is all the step for later operation
def main():
app = QtWidgets.QApplication(sys.argv)
main = welcome_window()
main.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
I expected that if the icon located in the taskbar could always stay on, it would be great for my GUI. Thank you all.
First of all, the MRE you gave is not reproducible. When I tried to run it it just didn't work. In this case you had a simple issue so I could just guess what was intended, but when you get more complicated problems people might not be able to help you. So in the future please make sure that we can just copy-paste-execute your code.
The reason that the main window disappears is that it's a member of the Welcome window. When you close the Welcome window, the corresponding python object will deleted and therefore Python will no longer have a reference to the main window. The main window object will be garbage-collected and all kinds of strange things might happen (I would expect it to just disappear).
The solution is to have a reference to the main window that stays valid until the program closes. This can be done by defining it in the main function (and then giving it as a parameter to the Welcome window). Like this...
import sys
from PyQt5 import QtWidgets
# Use a QWidget if you don't need toolbars.
class welcome_window(QtWidgets.QWidget):
def __init__(self, main_window=None, parent = None):
super(welcome_window, self).__init__(parent)
self.main_window = main_window
self.confirm_button = QtWidgets.QPushButton('Yes')
self.confirm_button.clicked.connect(self.startup)
main_layout = QtWidgets.QHBoxLayout() # use lower case for variable names
main_layout.addWidget(self.confirm_button)
self.setLayout(main_layout)
def startup(self):
self.main_window.show()
self.close()
class Main_window(QtWidgets.QMainWindow):
def __init__(self,parent = None):
super(Main_window, self).__init__(parent)
self.setGeometry(50, 50, 1500, 850)
# here is all the step for later operation
# Don't use self.setLayout on a QMainWindow,
# use a central widget and set a layout on that.
self.main_widget = QtWidgets.QWidget()
self.setCentralWidget(self.main_widget)
main_layout = QtWidgets.QHBoxLayout()
self.main_widget.setLayout(main_layout)
main_layout.addWidget(QtWidgets.QLabel("Hello"))
def main():
app = QtWidgets.QApplication(sys.argv)
main = Main_window()
welcome = welcome_window(main_window=main)
welcome.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
Some more tips. Don't use setLayout on a QMainWindow. Use a central widget and add your widgets to the layout of the central widget. The layout of the main window is for toolbars and such. See: https://doc.qt.io/qt-5/qmainwindow.html#qt-main-window-framework
Just use a QWidget if you want a simple window without toolbars (like your welcome window),
Best to use lower case for variable names and upper case for class names. E.g. I renamed Main_layout to main_layout. Look at the difference in syntax highlighting by Stack Overflow above.
Related
I have a question: i am tossing the code from 2ch files, i have already lost ideas. Calling fileA.py opens a window for me with two buttons exit and start. Exit works but when I click start I need to open the second window fileB.pt. (I want both windows to open in one window) Seemingly works only problem I have is it doesn't open "window on window" but "docks underneath" and I have the effect of two windows open :/. Please help, thank you in advance:) Python 3.10
fileA.py
import tkinter as tk
from GUI.module.scale_of_img import get_scale
class FirstPage:
def __init__(self, root):
self.root = root
def get_settings(self):
# Window settings
self.root.title('....')
self.root.resizable(False, False)
self.root.geometry("1038x900")
if __name__ == '__main__':
first = FirstPage(tk.Tk())
first.get_run_first_page()
fileB.py
import tkinter as tk
"importy..."
''' The second side of the application '''
class SecondPage:
def __init__(self, root=None):
self.root = root
self.my_canvas = tk.Canvas(self.root, width=1038, height=678)
self.my_canvas.pack(fill="both", expand=True)
if __name__ == '__main__':
second = SecondPage(tk.Tk())
second.get_run()
in order to put two "windows" in the same "window" you need to put all items inside a Frame, which is basically a container than you can simply pack when you want everything to show and unpack when you want everything in it to disapear.
all items in the first window will be children of a frame and all items in the second window will be children of another frame, and to switch you just need to call pack_forget() on one and pack() on another.
for the first file
class FirstPage:
def __init__(self, root):
self.root = root
self.frame = tk.Frame(root)
self.frame.pack(expand=True)
def get_picture(self):
# all items inside this window must be children of self.frame
self.my_canvas = tk.Canvas(self.frame, width=1038, height=500)
...
def get_second_page(self):
from GUI.module.second_page import SecondPage
self.frame.pack_forget() # to hide first page
# self.frame.destroy() # if you are never brining it back
SecondPage(self.root).get_run()
and for the second file
class SecondPage:
def __init__(self, root=None):
self.root = root
self.frame = tk.Frame(root) # new frame
self.frame.pack(expand=True)
self.my_canvas = tk.Canvas(self.frame, width=1038, height=678)
self.my_canvas.pack(fill="both", expand=True)
def get_button(self):
# Add buttons
# all here should be children of self.frame now
button1 = tk.Button(self.frame, text="...", )
...
you could destroy the first frame when you switch over to save some resources if you don't intend to return to it ever again, but the difference in memory is negligible.
assuming what you want is another Tk window to open, you shouldn't give it the same root, instead use an instance of Toplevel
from tkinter import Toplevel
# class definition here
def get_second_page(self):
from GUI.module.second_page import SecondPage
SecondPage(Toplevel(self.root)).get_run()
passing the Toplevel as a child of self.root is necessary, but note that the two windows have different roots.
Edit: turns out this wasn't what the OP ment by "window on window" -_-, but it am keeping it here for other readers.
I am using these calendar modules found in this post for my program, with some slight modifications to the imports to make it work for the latest python version.
I'll just show the snippets of my code that I feel does matter to this problem.
So I have this pop up window that I made that I use for alerts:
#class for pop-up windows for alerts, errors etc.
class PopUpAlert():
def __init__(self, alert='Alert!'):
self.root = tk.Tk()
tk.Label(self.root,
text=alert,
font="Verdana 15",
fg='red',
padx=10,
pady=5).pack(side=tk.TOP)
self.root.bind('<Return>', (lambda event: self.ok()))
tk.Button(self.root,
text='ok',
pady=10,
command=self.ok).pack(side=tk.TOP)
def ok(self):
print('ok clicked')
self.root.destroy()
The function ok was made just for me to test if the function is even being called. This window works completely fine in my code, except when I try to implement with the calendar, where the "ok" button of my PopUpAlert (which is supposed to destroy the window) stops working:
class CalendarDialog(tkSimpleDialog.Dialog):
"""Dialog box that displays a calendar and returns the selected date"""
def body(self, master):
self.calendar = ttkcalendar.Calendar(master)
self.calendar.pack()
def apply(self):
self.result = self.calendar.selection
def validate(self):
if self.calendar.selection == None:
PopUpAlert(alert='Please select a date or click cancel!')
return False
return True
The calendar has an "ok" button that is used to confirm selection of the date and close the calendar window. What I was trying to do is make it such that the user cannot click "ok" to close the window if he/she has not picked a date. For that, I used the function validate which is pre-defined in the class tkSimpleDialog.Dialog which my CalendarDialog inherits from. I overwrote the function in my CalendarDialog class to call up PopUpAlert, then returned False to the parent function ok (which is called when the "Ok" button is pressed on the calendar window):
def ok(self, event=None):
if not self.validate():
self.initial_focus.focus_set() # put focus back
return
self.withdraw()
self.update_idletasks()
self.apply()
self.cancel()
def cancel(self, event=None):
# put focus back to the parent window
self.parent.focus_set()
self.destroy()
(The whole thing can be found in the tkSimpleDialog file that's linked in the other SO page that I linked above.)
After commenting out lines one by one I found that the "ok" button on my PopUpAlert only didn't work when self.root.destroy() isn't called on the calendar. Why? How do I fix this?
I already tried changing my PopUpAlert to be a Toplevel window, which also didn't work.
It would be a lot nicer of you to provide a mcve instead of asking us to make it.
The problem is that a dialog by default disables clicks to other windows, including windows it spawns. To fix this you need to use a Toplevel instead of Tk (as mentioned) AND add this line of code to the end of PopUpAlert.__init__:
self.root.grab_set()
It would be a lot neater if you subclassed Toplevel rather than that weird wrapper. Here's a mcve:
try:
import Tkinter as tk
import tkSimpleDialog as sd
except:
import tkinter as tk
from tkinter import simpledialog as sd
#class for pop-up windows for alerts, errors etc.
class PopUpAlert(tk.Toplevel):
def __init__(self, master, alert='Alert!', **kwargs):
tk.Toplevel.__init__(self, master, **kwargs)
tk.Label(self,
text=alert,
font="Verdana 15",
fg='red',
padx=10,
pady=5).pack(side=tk.TOP)
self.bind('<Return>', self.ok)
tk.Button(self,
text='ok',
pady=10,
command=self.ok).pack(side=tk.TOP)
self.grab_set() # this window only gets commands
def ok(self, *args):
print('ok clicked')
self.destroy()
class CalendarDialog(sd.Dialog):
"""Dialog box that displays a calendar and returns the selected date"""
def body(self, master):
self.calendar = tk.Label(master, text="Whatever you do, don't click 'OK'!")
self.calendar.pack()
def validate(self):
PopUpAlert(self, alert='Please select a date or click cancel!')
def display():
CalendarDialog(root)
root = tk.Tk()
tk.Button(root, text='data data data', command=display).pack()
root.mainloop()
Note I also got rid of that useless lambda, which happens to be a pet peeve of mine. lambda is great in some cases, but it's very rarely needed.
So I've been trying my luck with PyQT5 to give a GUI to an app I've been working on.
I've encountered an issue with QMessageBox feature.
I've been trying to create an "Exit" Action on the MenuBar of the app.
And at first I only made it exit when clicked and it worked.
Now I want to make it give a pop up message of "Are you sure?", which is exactly what the QMessageBox does. So this is my code now:
class Window(QtWidgets.QMainWindow):
def __init__(self):
super(Window, self).__init__()
self.ui = uic.loadUi('rent_creation.ui', self)
self.home()
def home(self):
self.ui.actionExit.triggered.connect(self.close_application)
self.show()
def close_application(self):
choice = QMessageBox.question(self, 'Quit?',
"Are you sure you want to quit?",
QMessageBox.Yes | QMessageBox.No)
if choice == QMessageBox.Yes:
sys.exit()
else:
pass
Now every time I click on the Exit button when I run this code, The Python crashes.
I'm not sure what I'm doing wrong... I've been looking around the internet and it all look well.... I've tried all the variation possible of passing QmessageBox (for example I tried adding QWidgets.QMessageBox.Yes/No and it didn't fix this issue).
I've been following a tutorial on the internet where This code is practically the same as his, and it works for him in the tutorial somehow.
caveat: I am on linux, so things are likely a bit different.
However I wouldn't be surprised if the problem is related with the fact that you use sys.exit to quit the GUI. You probably should cleanly close the window, the QApplication and then exit the program.
The following example might solve your issue. Since I don't have you ui file, I just added a menu action to close the the window and connect it with the QMainWindow.close slot and then override the closeEvent method. See the comments in the code:
import sys
from PyQt5 import QtWidgets
class Window(QtWidgets.QMainWindow):
def __init__(self):
super(Window, self).__init__()
self.home()
def home(self):
# add a menu bar with a File menu and a Close action
menu_bar = QtWidgets.QMenuBar(self)
menu = QtWidgets.QMenu('File', menu_bar)
menu_bar.addMenu(menu)
action = menu.addAction('Close')
# connect the Close action with the QMainWindow.close slot
action.triggered.connect(self.close)
self.setMenuBar(menu_bar)
def closeEvent(self, event):
"""override the QMainWindow.closeEvent method to:
* fire up a QMessageBox with a question
* accept the close event if the user click yes
* ignore it otherwise.
Parameters
----------
event : QtCloseEvent
emitted when someone or something asks to close the window
"""
if self.ask_quit():
event.accept()
else:
event.ignore()
def ask_quit(self):
choice = QtWidgets.QMessageBox.question(self, 'Quit?',
"Are you sure you want to quit?",
QtWidgets.QMessageBox.Yes | QtWidgets.QMessageBox.No)
return choice == QtWidgets.QMessageBox.Yes
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
w = Window()
w.resize(250, 150)
w.move(300, 300)
w.setWindowTitle('Simple')
w.show()
sys.exit(app.exec_())
The above way of closing the window, i.e. using the closeEvent and connect the menu action to close, has the advantage that the confirmation box is opened every time someone asks to close the window, independently of the method: you get the message box also clicking on the window X button or with alt+F4
Edit: example of how to cleanly close the QApplication only from the Close menu. This should be more in line with the original behavior of the app in the question (see comment).
class Window(QtWidgets.QMainWindow):
def __init__(self):
super(Window, self).__init__()
self.home()
def home(self):
menu_bar = QtWidgets.QMenuBar(self)
menu = QtWidgets.QMenu('File', menu_bar)
menu_bar.addMenu(menu)
action = menu.addAction('Close')
# connect the Close menu to the ``ask_quit`` slot to ask and exit the
# application on "yes"
action.triggered.connect(self.ask_quit)
self.setMenuBar(menu_bar)
def closeEvent(self, event):
"""Ignore all ways of closing"""
event.ignore()
#QtCore.pyqtSlot()
def ask_quit(self):
choice = QtWidgets.QMessageBox.question(self, 'Quit?',
"Are you sure you want to quit?",
QtWidgets.QMessageBox.Yes | QtWidgets.QMessageBox.No)
if choice == QtWidgets.QMessageBox.Yes:
QtWidgets.QApplication.quit()
I want to create a PyQt combobox with a fixed title. More specific this means that I want to have a dropdown menu from which the user can select but the dropdown button is always labeled the same. So for example I want to create an option for the user to specify where the legend of a plot is drawn. The button for this should always be labled "Legend" but when you click on it, it opens a dropdown menu with the placing options such as "upper right", "upper left", "top", etc. Once the user selected an option the legend is updated but the button still sais "Legend".
I have this so far:
self.fnLegendButton = QtGui.QComboBox()
self.fnLegendButton.addItems('Upper right,Lower right,Upper left,Lower left,Top,Disable'.split(','))
self.fnLegendButton.setCurrentIndex(0)
self.fnLegendButton.setToolTip('Select the legend position.')
self.fnLegendButton.currentIndexChanged.connect( <positioning function> )
self.fnLegendButton.setMaximumWidth(60)
Here's a working example:
import sys
from PyQt4 import QtGui, QtCore
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def initUI(self):
self.fnLegendButton = QtGui.QComboBox(self)
self.fnLegendButton.addItems(
'Legend,Upper right,Lower right,Upper left,Lower left,Top,Disable'.split(','))
self.fnLegendButton.setCurrentIndex(0)
self.fnLegendButton.setToolTip('Select the legend position.')
self.fnLegendButton.currentIndexChanged[
str].connect(self.avoid_db_change)
self.fnLegendButton.setMaximumWidth(100)
self.fnLegendButton.move(50, 50)
self.setGeometry(300, 300, 250, 150)
self.setWindowTitle('QtGui.QCheckBox')
self.show()
def avoid_db_change(self, text):
print("Processing {0} item".format(text))
self.fnLegendButton.blockSignals(True)
self.fnLegendButton.setCurrentIndex(0)
self.fnLegendButton.blockSignals(False)
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
The important bits of this code are inside the avoid_db_change, that function is the one used to keep the "Legend" text no matter which item you've pressed. Now, you don't want to fire that function again when self.fnLegendButton.setCurrentIndex(0) is executed, so to avoid that, you surround it by a couple of blockSignals methods. Just try to comment the blockSignals methods and you'll understand what this means.
I'm trying to make a tool window for Maya, in which I can right-click anywhere, and if I click 'add', a rectangle widget shows up at my cursor position.
Now my right-click functionality works. I can also get my cursor position in addPicker() function. But I am having problem with placing newly-created widgets. If I add a layout and add the newly-created widgets to it, they actually show up. However, if I didn't create a layout for those widgets, no matter what position I tested, nothing shows up in my window.
Hopefully someone has some ideas. Thank you all in advance.
A right-click screenshot:
class RightClickMenu(QtGui.QMenu):
def __init__(self, *args, **kwargs):
super(RightClickMenu, self).__init__(*args)
self.parentWidget().setContextMenuPolicy(QtCore.Qt.CustomContextMenu)
self.parentWidget().customContextMenuRequested.connect(self.menuPos)
def menuPos(self, *args):
self.exec_(QtGui.QCursor.pos())
class Ui_window(object):
def setupUi(self, window):
window.setObjectName("window")
window.resize(555, 900)
self.widget_base = QtGui.QWidget()
self.verticalLayout_window = QtGui.QVBoxLayout(window)
self.verticalLayout_window.addWidget(self.widget_base)
self.menu_popup = RightClickMenu(self.widget_base)
self.menu_popup.setObjectName("popupMenu")
self.verticalLayout_widget = QtGui.QVBoxLayout(self.widget_base)
# Action - add picker
addAction = QtGui.QAction('Add Picker', self.widget_base)
addAction.setShortcut('Ctrl+A')
addAction.setStatusTip('Add Picker')
addAction.triggered.connect(self.addPicker)
self.menu_popup.addAction(addAction)
# Action - delete picker
deleteAction = QtGui.QAction('Delete Picker', self.widget_base)
deleteAction.setShortcut('Ctrl+D')
deleteAction.setStatusTip('Delete Picker')
deleteAction.triggered.connect(self.deletePicker)
self.menu_popup.addAction(deleteAction)
def addPicker(self):
cursorPos = QtGui.QCursor.pos()
localPos = self.widget_base.mapFromGlobal(cursorPos)
######################################################################
# how??? below doesn't work.
self.pushButton = QtGui.QPushButton(self.widget_base)
self.pushButton.setGeometry(QtCore.QRect(220, 50, 75, 23))
self.pushButton.setObjectName("pushButton")
def deletePicker(self):
print 'delete'
def run():
import sys
try:
Ui_window.close()
except:
pass
pickerWindow = QtGui.QDialog()
ui = Ui_window()
ui.setupUi(pickerWindow)
pickerWindow.show()
pickerWindow.exec_()
Surprising solution (see this question):
self.pushButton.show()