I have a Python script:
if True:
if False:
print('foo')
print('bar')
However, when I attempt to run my script, Python raises an IndentationError:
File "script.py", line 4
print('bar')
^
IndentationError: unindent does not match any outer indentation level
I kept playing around with my program, and I was able to produce four errors in total:
IndentationError: unexpected indent
IndentationError: expected an indented block
TabError: inconsistent use of tabs and spaces in indentation
IndentationError: unindent does not match any outer indentation level
What do these errors mean? What am I doing wrong? How can I fix my code?
Note: This is an attempt at a canonical question because I see many similar posts every month. This is not a duplicate of existing questions about unindents or unexpected indents because they only deal with one type of indentation error each, and I'm looking to cover them all in one place.
It's also possible to have logically incorrect indentation that does not cause an error message. One common form of this is attaching else: to a for or while loop rather than (as intended) the corresponding if:. See Else clause on Python while statement if you need to close questions where OP did that.
Why does indentation matter?
In Python, indentation is used to delimit blocks of code. This is different from many other languages that use curly braces {} to delimit blocks such as Java, Javascript, and C. Because of this, Python users must pay close attention to when and how they indent their code because whitespace matters.
When Python encounters a problem with the indentation of your program, it either raises an exception called IndentationError or TabError.
A little history
The historical reasons for why Python uses indentation vs the arguably more commonly accepted curly braces {} is outlined in an article of the history of Python by Guido van Rossum - the creator of Python:
Python’s use of indentation comes directly from ABC, but this idea didn’t originate with ABC--it had already been promoted by Donald Knuth and was a well-known concept of programming style. (The occam programming language also used it.) However, ABC’s authors did invent the use of the colon that separates the lead-in clause from the indented block. After early user testing without the colon, it was discovered that the meaning of the indentation was unclear to beginners being taught the first steps of programming. The addition of the colon clarified it significantly: the colon somehow draws attention to what follows and ties the phrases before and after it together in just the right way.
How do I indent my code?
The basic rule for indenting Python code (considering that you treat the entire program as a "basic block") is: The first statement in a basic block, and each subsequent statement after it must be indented by the same amount.
So technically the following Python program is correct:
def perm(l):
# Compute the list of all permutations of l
if len(l) <= 1:
return [l]
r = []
for i in range(len(l)):
s = l[:i] + l[i+1:]
p = perm(s)
for x in p:
r.append(l[i:i+1] + x)
return r
However, as you can probably tell from above, randomly indenting your code makes is extremely hard to read and follow the flow of the program. It's better to be consistent and follow a style.
PEP 8 -- the Python style guide -- says:
Use 4 spaces per indentation level.
That is, each statement that is starting a new block and each subsequent statement in the new block, should be indented four spaces from the current indentation level. Here is the above program indented according to the PEP8 style guide:
def perm(l):
# Compute the list of all permutations of l
if len(l) <= 1:
return [l]
r = []
for i in range(len(l)):
s = l[:i] + l[i+1:]
p = perm(s)
for x in p:
r.append(l[i:i+1] + x)
return r
Can I still use tabs?
Python realizes that some people still prefer tabs over spaces and that legacy code may use tabs rather than spaces, so it allows the use of tabs as indentation. PEP8 touches on this topic:
Spaces are the preferred indentation method.
Tabs should be used solely to remain consistent with code that is already indented with tabs.
Note however the one big caveat is not to use both tabs and spaces for indentation. Doing so can cause all kinds of strange hard to debug indentation errors. Python expands tabs to the next 8th column, but if your editor is set to a tab size of 4 columns, or you you use spaces as well as tabs, you can easily produce indented code that looks fine in your editor, but Python will refuse to run. The Python 3 compiler explicitly rejects any program containing an ambiguous mixture of tabs and spaces, usually by raising a TabError. However, by default, mixing tabs and spaces is still allowed in Python 2, but it is highly recommended not to use this "feature". Use the -t and -tt command line flags to force Python 2 to raise a warning or (preferably) an error respectively. PEP8 also discusses this topic:
Python 3 disallows mixing the use of tabs and spaces for indentation.
Python 2 code indented with a mixture of tabs and spaces should be converted to using spaces exclusively.
When invoking the Python 2 command line interpreter with the -t option, it issues warnings about code that illegally mixes tabs and spaces. When using -tt these warnings become errors. These options are highly recommended!
What does "IndentationError: unexpected indent" mean?
Problem
This error occurs when a statement is unnecessarily indented or its indentation does not match the indentation of former statements in the same block. For example, the first statement in the program below is unnecessarily indented:
>>> print('Hello') # this is indented
File "<stdin>", line 1
print('Hello') # this is indented
^
IndentationError: unexpected indent
In this example, the can_drive = True line in the if block does not match the indentation of any former statement:
>>> age = 10
>>> can_drive = None
>>>
>>> if age >= 18:
... print('You can drive')
... can_drive = True # incorrectly indented
File "<stdin>", line 3
can_drive = True # incorrectly indented
^
IndentationError: unexpected indent
Fix
The fix for this error is to first make sure the problematic line even needs to be indented. For example, the above example using print can be fixed simply be unindenting the line:
>>> print('Hello') # simply unindent the line
Hello
However, if you are sure the line does need to be indented, the indentation needs to match that of a former statement in the same block. In the second example above using if, we can fix the error by making sure the line with can_drive = True is indented at the same level as the former statements in the if body:
>>> age = 10
>>> can_drive = None
>>>
>>> if age >= 18:
... print('You can drive')
... can_drive = True # indent this line at the same level.
...
What does "IndentationError: expected an indented block" mean?
(This might also occur as SyntaxError: unexpected EOF while parsing in Python 3.8 or lower.)
Problem
This error occurs when Python sees the 'header' for a compound statement, such as if <condition>: or while <condition>: but the compound statement's body or block is never defined. For example in the code below we began an if statement, but we never define a body for the statement:
>>> if True:
...
File "<stdin>", line 2
^
IndentationError: expected an indented block
In this second example, we began writing a for loop, but we forget to indent the for loop body. So Python still expects an indented block for the for loop body:
>>> names = ['sarah', 'lucy', 'michael']
>>> for name in names:
... print(name)
File "<stdin>", line 2
print(name)
^
IndentationError: expected an indented block
Comments don't count as bodies:
>>> if True:
... # TODO
...
File "<stdin>", line 3
^
IndentationError: expected an indented block
Fix
The fix for this error is to simply include a body for the compound statement.
As shown above, a common mistake by new users is that they forget to indent the body. If this is the case, make sure each statement meant to be included in the compound statement's body is indented at the same level under the compound statement's beginning. Here is the above example fixed:
>>> names = ['sarah', 'lucy', 'michael']
>>> for name in names:
... print(name) # The for loop body is now correctly indented.
...
sarah
lucy
michael
Another common case is that, for some reason, a user may not want to define an actual body for the compound statement, or the body may be commented out. In this case, the pass statement can be used. The pass statement can be used anywhere Python expects one or more statements as a placeholder. From the documentation for pass:
pass is a null operation — when it is executed, nothing happens. It is useful as a placeholder when a statement is required syntactically, but no code needs to be executed, for example:
def f(arg): pass # a function that does nothing (yet)
class C: pass # a class with no methods (yet)
Here is the above example with the if statement fixed by using the pass keyword:
>>> if True:
... pass # We don't want to define a body.
...
>>>
What does "IndentationError: unindent does not match any outer indentation level" mean?
Problem
This error occurs when you unindent a statement, but now the indentation level of that statement does not match that of any former statement. For example, in the below code we unindent the second call to print. However, the indentation level does not match that of any former statement:
>>> if True:
... if True:
... print('yes')
... print()
File "<stdin>", line 4
print()
^
IndentationError: unindent does not match any outer indentation level
This error is especially hard to catch because even one space will cause your code to fail.
Fix
The fix is to ensure that when you unindent a statement, the indentation level matches that of a former statement. Consider the above example once again. In the example, I want the second call to print to be in the first if statements body. So I need to make sure that that line's indentation level matches that of the former statements in the first if statement's body:
>>> if True:
... if True:
... print('yes')
... print() # indentation level now matches former statement's level.
...
yes
>>>
I'm still getting an IndentationError but my program appears to be correctly indented. What do I do?
If your program visually appears to have correct indentation, but your still getting an IndentationError you have most likely mixed tabs with spaces. This will sometimes cause Python to raises strange errors. See the subsection Special cases under What does "TabError: inconsistent use of tabs and spaces in indentation" mean? for an more in-depth explanation of the problem.
What does "TabError: inconsistent use of tabs and spaces in indentation" mean?
Problem
This error only occurs when you attempt to mix tabs and spaces as indentation characters. As said above, Python will not allow your program to contain a mix of tabs and spaces, and will raise the specific exception TabError if it finds you have. For example, in the program below, a mix of tabs and spaces is used for indentation:
>>> if True:
... if True:
... print()
... print()
... print()
File "<stdin>", line 5
print()
^
TabError: inconsistent use of tabs and spaces in indentation
Here is a picture which visually shows the whitespace in the above program. Gray dots are spaces, and gray arrows are tabs:
We can see we have indeed mixed spaces and tabs for indentation.
Special cases
Note Python will not always raise a TabError if you mix tabs and spaces into your program. If the program indentation is unambiguous, Python will allow tabs and spaces to be mixed. For example:
>>> if True:
... if True: # tab
... pass # tab, then 4 spaces
...
>>>
And sometimes Python simply chokes on the mixture of tabs and spaces and erroneously raises an IndentationError exception when a TabError would be more appropriate. Another example:
>>> if True:
... pass # tab
... pass # 4 spaces
File "<stdin>", line 3
pass # 4 spaces
^
IndentationError: unindent does not match any outer indentation level
As you can see, running your code this way can create mysterious errors. Even though the program visually appears to be fine, Python became confused trying to parse the tabs and spaces used for indention and errored out.
These are excellent examples that demonstrate why to never mix tabs and spaces and make use of the -t and -tt interpreter flags when using Python 2.
Fix
If your program is short, probably the easiest and quickest fix is to simply re-indent the program. Make sure each statement is indented by four spaces per indention level (see How do I indent my code?).
However, if you already have a large program that you've mixed tabs and spaces into, there are automated tools that can be used to convert all of your indentation to just spaces.
Many editors such as PyCharm and SublimeText have options to automatically convert tabs to spaces. There are also several on-line tools such as Tabs To Spaces or Browserling that allow you to quickly re-indent your code. There are also tools written in Python. autopep8 for example can automatically re-indent your code and fix other indentation errors as well.
Even the best tools though will sometimes not be able to fix all of your indentation errors and you'll have to fix them manually. That's why it's important to always properly indent your code from the start.
A note about "SyntaxError" related indentation problems
Although not often, sometimes certain SyntaxError exceptions are raised due to incorrect indentation. For example, look at the code below:
if True:
pass
pass # oops! this statement should be indented!.
else:
pass
When the above code is run, a SyntaxError is raised:
Traceback (most recent call last):
File "python", line 4
else:
^
SyntaxError: invalid syntax
Although Python raises a SyntaxError, the real problem with the above code is that the second pass statement should be indented. Because the second pass isn't indented, Python doesn't realize that the previous if statement and the else statement are meant to be connected.
The fix for this type of error is to simply correctly re-indent your code. To see how to properly indent your code, see the section How do I indent my code?.
I'm still having a hard time with Python's indentation syntax. What do I do?
Don't get discouraged if you're still struggling. It can take time to get use to
Python's whitespace syntax rules. Here are some tips to help:
Get an editor that will tell you when you have an indentation error. Some goods ones are as said above are, PyCharm, SublimeText, and Jupyter Notebook.
When you indent your code, count out loud to yourself how many times you press the space-bar (or tab key). For example, if you needed to indent a line by four spaces, you would say out loud "one, two, three, four" while simultaneously pressing the space-bar each time. It sounds silly, but it helps train your brain to think about how deep you're indenting your code.
If you have an editor, see if it has an option to automatically convert tabs to spaces.
View others' code. Browse github or Stackoverflow and see examples of Python code.
Just write code. That's the single best way to get better. The more you write Python code, the better you'll get.
Resources used
https://en.wikipedia.org/
https://docs.python.org/3/
http://python-history.blogspot.com/2009/02/early-language-design-and-development.html
https://www.python.org/dev/peps/pep-0008/
Sublime Text 3
If it happens that you code in Sublime Text 3, this could help you with indentations problemes
In Sublime Text, while editing a Python file:
Sublime Text menu > Preferences > Settings - Syntax Specific :
Python.sublime-settings
{
"tab_size": 4,
"translate_tabs_to_spaces": true
}
You see, you have a tiny error.
if True:
if False:
print('foo')
print('bar')
You were supposed to do:
if True:
if False:
print('foo')
print('bar')
As you can see your print is only indented 3 spaces, it is supposed to be indented 4 spaces.
Historical note for Python 2
By default, Python 2 allowed tabs and spaces to be mixed, and would not produce an error by default. Passing the -tt option to Python 2.x causes it to raise an exception in the same cases that 3.x does, and -t causes a warning instead. The full details are explained at Python's interpretation of tabs and spaces to indent.
Note in particular that tabs are treated as 8 spaces (rather, they effectively increase the number of perceived spaces up to the next multiple of 8). Thus, if you were displaying the code with a standard 4-space indent, but have mixed spaces and tabs, you could end up with code that satisfies the indentation rules, but is not considered to be indented the same way that it looks.
As a result, you could get all kinds of other errors. For example:
# in 2.x
def example():
def nested(): # suppose this is indented with a tab
x = [1] # and this with two tabs
print x[0] + 1 # but this with 8 spaces instead of a tab
nested()
(Note that Stack Overflow's Markdown rendering will show the indentation as spaces even if I use tabs.)
That gives a NameError, since print x is no longer inside the nested function and x is out of scope in the outer example. Similarly, we could easily create a TypeError by giving example a local x = 1, or ValueError by giving it a local x = [].
Quick checklist
Incorrect indentation most commonly results in IndentationError, but it can also result in TabError (a sub-type of IndentationError) or SyntaxError (the indentation itself was legal, but it caused other code to have a syntax error). Indentation that is valid for Python code, but wrong for the programmer's intent, causes logical errors (the code doesn't raise an exception, but does something wrong).
It is strongly recommended not to use tabs for indentation. In 2.x, running Python with the -tt command line argument causes it to raise the same TabError, which is useful for finding problems.
The community standard, laid out in PEP 8, is to use four spaces per level of indentation.
Statements like if, for, def and class that end with a colon :, need an indented block after them:
if x:
do_y() # <- this must be indented
Blocks cannot be empty. Use the pass statement if nothing should happen:
if x:
pass # this statement does nothing, except make the block non-empty
Code within a block must have the same indentation:
if x:
do_y()
do_z() # this needs to line up with do_y()
The first line of code that lines up with the opening statement, or a lower level of indentation, is outside the block:
if x:
do_y()
do_z() # this happens regardless of the x value
# cannot write `else`: here; that is a syntax error
for i in range(10):
if x:
do_y()
do_z() # both the `if` and `for` blocks are ended
Python interprets tabs as expanding to the next 8th column; but in 3.x, indentation that mixes spaces and tabs must have the exact same pattern to count as the same indentation (and to indent further requires having the same pattern as a prefix). Failure to get this right results in TabError.
while and for loops in Python may have an else clause, which executes if the loop complete normally rather than via break. This is a common source of logical errors:
for i in range(10):
if i % 2:
print(f'{i} is odd')
else: # wrongly indented
print(f'{i} is even') # only happens once, and claims 9 is even!
Quick fix for Sublime users:
Press Ctrl-H to access Find and Replace
In Find: Type 4 spaces
In Replace: Copy and paste a tab from somewhere in your code
Click Replace All
I sincerely apologize as this question has been asked repeatedly and i understand that the answer is that in python 3 that the print has been made a function and that the string has to be encapsulated within parentheses. However, in IDLE, there is only 1 line of code and i have tried this one line with both single and double quotations and achieved the same "syntax error" Any help would be greatly appreciated.
If i run the same code in the shell, i have no issues!
Even if i use the basic help() command i get a "syntax error"
In a python file you don't need any of the things that are printed when the shell starts up. Your problem isn't with the print or the help, it's with the format of the file. Take out everything before the help() and that should fix your problem.
I am struggling with If Else statement in Python 3.5.2 which I recently installed. I am using IDLE to run my code.
Here is my code below (screenshot).
I get syntax error as soon as I press "Enter" key after "Else". I have tried playing with indentation, colon, etc but I am getting error on all combinations I have tried so far. I have seen similar questions (for prior version of python) here as well as on Quora but none of those solutions are working for me. Please help! (I am using MacBook - in case that changes anything).
Take the example of #3:
Python is seeing the code as
if x==10:
print("X is 10")
else:
The indentation on this is clearly messed up. But it looks right to you, because the >>> of the prompt is pushing the first line over a few characters, making it look like it is right. But even though it looks that way in the shell, python still sees if x==10: as being in col 0, and thinks that print("X is 10") is indented by 8 spaces and else: is indented by 4 spaces.
When you typed it in to the edit window, the indentation actually turned out differently, like so
if x==10:
print("X is 10")
else:
which is actually correct (ignoring the fact that there is nothing under else).
Dont indent(tab) 'else:' I think the cause is IDLE's ">>>" prompt is not aligned unlike in terminal
3rd example is almost the right one, but you must provide something on the else branch, either some code or pass (or just drop the else entirely)
EDIT:
After being explained the problem is with the IDLE interactive shell in specific, I tried it myself and the following code works:
This too (so the indentation seems to work on the if branch itself):
And this:
The shell automatic indentation is quiet confusing. not to say buggy.
It is clearer on plain python interactive mode.
The >>> adds a visual indentation, but there is no indentation there. The if body is indented by it's previous plus one, though this comes out as two indentations, it is allowed and causes no trouble.
The else statement needs to have the same indentation as the if - 0 indentation (and not one as the visalization hints). So you actually need to delete the automatically added indentation, of the else statement all the way back to the beginning.
Using Python 3.5.2 but not idle, this what it looks like when your code is run successfully:
>>> x = 8
>>> if x==10:
... print('X is 10')
... else:
... print('Not')
...
Not
>>>
The correct form is else: with the colon. This corresponds to your third attempt for which the error that see complains about indentation. I can't see what indentation you entered but change that until you figure out what idle wants.
"elif" is a shorter way of saying "else if". if the "if" statement isnt true, "elif" can be used to tell the computer what to do if the conditions are fulfilled
I have a function that prints the number of pixels found in an image and then asks the user how they would like to proceed. As long as the interpreter hasn't moved on from the function I want all the output to be indented accordingly.
One such 'sub output' (the input prompt) needs to be multiple lines. So I kick off with the 3*quote (''') followed by two spaces to create the indentation. At the end of the question 'how would you like to proceed?' I use a hard return. An extra indentation is assumed by the text editor so I remove it causing the following list of suggestions to line up flush with the input variable command. Here's how it looks:
def returnColors():
#
# lots of code that does stuff...
#
print("The source image contains", lSize, "px.")
print("")
command=input(''' What would you like to do? You can say:
get all
get unique
''')
The problem with this is that the interpreter is acknowledging the indentation that separates the function body from the function statement as actual string contents, causing the output to look like this:
The source image contains 512 px.
What would you like to do? You can say...
get all
get unique
|
The only way to avoid this is by breaking indentation in the interpreter. Although I know it works, it doesn't look very good. So what options do I have?
EDIT: Just because I have the screenshot_
One thing that you should keep in mind is that once you have start a multiline string declaration, all the text until it is closed is taken as is and syntax (ie, indentation) is no longer considered.
You can start your multiline with an explicit new line so that everything in the multiline string can be indented together in code.
IE.
command=input('''
What would you like to do? You can say:
get all
get unique
''')
would print out the prompt with a new line on top, but the formatting of the text is more explicitly shown and should appear as seen.
OR you could use the \n for each new line in the string to get it formatted more correctly and remember to use a single \ after each new line. E.g.
instead of:
''' What would you like to do? You can say:
get all
get unique
'''
Try
' What would you like to do? You can say:\
\n\
\n get all\
\n get unique\
\n'
The indent won't matter, no matter where you use \n at the beginning of new line, the input() will output the same. This is will give the same input() string:
' What would you like to do? You can say:\
\n\
\n get all\
\n get unique\
\n'