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TLDR: I need a way to track date values in a dynamic calendar and count the days I've worked on on a monthly base.
So I've made a dynamic calendar (in the 1904 Date system to enable negative time handling) to help me track days and hours worked in Excel that has some automatic features. I would now like to add a calculator to calculate the accumulation of vacation days based on the following conditions:
Days worked per month >= 14
OR
The total hours worked per month >= 35
If one or both of these conditions are met I will receive 2 vacation days (2.5 after the 1st year of employment) and the accumulated vacation days should be shown in a single cell C7 (see picture for reference).
I know that I need to calculate the days that I've worked on on a monthly base and compare the result to the 1st condition (and the same for the worked hours and compare the result to the 2nd condition, but the solution for that is much the same as for the 1st condition). I've made my calendar in a way that I can't use fixed cells to do the calculation, as the length of the calendar is fixed to 53 full weeks and the dates change to accommodate the length according to the year in cell C2 i.e. January 1st will not always be in cell D17. Here are the first 10 rows of my dynamic calendar in Table Markdown format with the formulas as asked.
Year
2023
Quota
=SUM(J11:J375;'2022'!C2)
Hours per week
37.5
Gross working days
=NETWORKDAYS(DATE(C2;1;1);DATE(C2;12;31);'1pyhapaivat'!B7:B21)
Net working days
=COUNTIF(H11:H381;">0")
Vacation Accumulation
Kilometers per day
36
Week No.
Date
Day
Start
end
Hours
Sum
Quota
Kilometers
Holidays
Note
=ISOWEEKNUM(D11)
=SEQUENCE(371;1;DATE($C$2;1;1)-WEEKDAY(DATE($C$2;1;1);2)+1;1)
=D11
=IF(M11="quota";-7,5/24;IF(G11>F11;IF((G11-F11)>(6/24);(G11-F11)-(0,5/24);(G11-F11));""))
=SUMIF(H11:H15;">0")
=I11-COUNTA(G11:G15)(($C$4/5)/24)-COUNTIF(M11:M15;"quota")(($C$4/5)/24)
=COUNTA(F11:F15)$C$8-(SUM(COUNTIF(M11:M15;"Remote");COUNTIF(M11:M15;"Office"))$C$8)
=XLOOKUP(D11;_1pyhapaivat3[Start Date];_1pyhapaivat3[Subject];"")
A snippet of the dynamic calendar
I've tried combining the DATE and SUM functions with other functions like COUNTA, and COUNTIF. I've also tried using different LOOKUP functions but to no avail.
The new dataset filtered by Year
And filtered again by Month
Working on a formula that will take a date and translate it to the format FYxxPxxWx.
For example. Input the date of 03/22/20 and the formula will give you FY20P06W4 which is correct.
However if you input 02/02/20 the formula will give you FY20P05W2. The correct output would be FY20P05W1. This issue also rears its head with the date 09/29/19. It gives you FY20P12W5. The correct output would be FY20P1W1.
Something else weird happens when you put in the date 04/5/20 you get FY21P07W2 when it should be FY20P07W2.
The formula is
=CONCATENATE("FY",RIGHT(YEAR(DATE(YEAR(D5),MONTH(D5)+(10-1),1)),2),"P",TEXT(CHOOSE(MONTH(D5),4,5,6,7,8,9,10,11,12,1,2,3),"0#"),"W",WEEKNUM(D5,1)-WEEKNUM(DATE(YEAR(D5),MONTH(D5),1),1)+1)
I think this issue is caused by the strange weeks where the the month ends and another begins throwing off the formula.
I do have a formula that calculates the years fiscal year start date
=(DATE(YEAR(TODAY())-1,10,1)-(WEEKDAY(DATE(YEAR(TODAY())-1,10,1),1)))+1
This outputs 09/29/19 as the start date of the Fiscal year as its the same week as 10/1/19 which is the first month of the fiscal year. IF that makes sense.
The separate formulas are
For FY and grabs only last two digits of year
RIGHT(YEAR(DATE(YEAR(D5),MONTH(D5)+(10-1),1)),2)
For Period (gives me a two digit Period
TEXT(CHOOSE(MONTH(D5),4,5,6,7,8,9,10,11,12,1,2,3),"0#")
For Week
WEEKNUM(D5,1)-WEEKNUM(DATE(YEAR(D5),MONTH(D5),1),1)+1)
I believe I have a solution for you. Discussion to follow, but here's the full formula:
=CONCAT("FY",RIGHT(YEAR(D5+91+WEEKDAY(DATE(YEAR(D5),10,1))),2),"P",TEXT(IF(MONTH(D5+(7-WEEKDAY(D5)))<>MONTH(D5),IF(MONTH(D5)=9,1,CHOOSE(MONTH(D5),5,6,7,8,9,10,11,12,1,2,3,4)),CHOOSE(MONTH(D5),4,5,6,7,8,9,10,11,12,1,2,3)),"0#"),"W",ROUNDUP(((D5-IF(MONTH(D5+(7-WEEKDAY(D5)))<>MONTH(D5),DATE(YEAR(D5),MONTH(D5)+1,1)-WEEKDAY(DATE(YEAR(D5),MONTH(D5)+1,1))+1,DATE(YEAR(D5),MONTH(D5),1)-WEEKDAY(DATE(YEAR(D5),MONTH(D5),1))+1))/7)+0.01,0))
One issue is that this still calculates 2/2/2020 the way you said was incorrect. When I verify it against a calendar, though, it seems that FY20P05W02 should be correct. If the week that includes the first of the month begins a new pay period, that would mean 2/1/2020, falling on a Saturday, would be the last day of fiscal week 1. That would make 2/2/2020 the first day of fiscal week 2.
To calculate fiscal year, I used RIGHT(YEAR(D5+91+WEEKDAY(DATE(YEAR(D5),10,1))),2). Since you can count on there always being 91 days from the beginning of October to the end of December, it helps with this calculation. In your formula, you had MONTH(D5)+(10-1), which would push you 9 months out past the month in D5. This explains why your result for 4/5/2020 was off by a year.
Fiscal period was a bit trickier, requiring a couple nested IF statements. I used IF(MONTH(D5+(7-WEEKDAY(D5)))<>MONTH(D5) first to account for days at the end of the month that would fall into the next fiscal period, then IF(MONTH(D5)=9 to account for the few days at the end of September that might fall into the next fiscal year. Days at the end of September would default to 1, days at the end of a month that are included in the next fiscal period use the first CHOOSE function (they need the next month's number), and everything else gets the CHOOSE function as you wrote it.
The fiscal week took a bit more, but in the end I evaluated the beginning of the current fiscal month and subtracted it from the date in D5, then divided by 7 and added 0.01 so that even numbers would round up correctly.
I tested this out over a few years of dates and it seemed to be functioning correctly, but let me know if you have questions or issues.
One thing to consider when using WEEKNUM is that you'll have a week that is counted twice at the beginning of the year unless you use option 21 or ISOWEEKNUM. These give the same result as each other, and ensure that only one week number is assigned to any given day, no matter the year.
For a backtesting trading system, I need to rotation my positions every 2 weeks, BUT if the day is a Saturday or Sunday, I need to take the Friday.
Semi-Monthly updates are made twice a month; mid-month and month end.
Mid-month updates are on the 15th calendar day of each month. Should the 15th be a weekend or holiday, the update will occur on the last trading day prior to the 15th.
For example, if the 15th is a Saturday then the update will occur on the close of Friday the 14th.
I need to return a list of dates of rotation based on a start date and end date.
Let's say, I need every 15 days from January 1st 2018 to 31st December 2018, it should return only the valid dates based on the rules described above.
The formula should be for Google Sheet or Excel.
I tried the following:
It is not returning exactly what I need, since the google sheet googlefinance formula allows to use daily and weekly intervals (1 or 7). See below the googlefinance definition (https://support.google.com/docs/answer/3093281?hl=en):
"interval - [ OPTIONAL ] - The frequency of returned data; either "DAILY" or "WEEKLY".
interval can alternatively be specified as 1 or 7. Other numeric values are disallowed."
You need to be more precise in your specifications. You've provided multiple inconsistent intervals. eg: Two weeks (which would be every 14 days and will always fall on the same weekday); every 15 days (which will NOT be mid-month and EOM over most time periods); mid-month and end-of-month.
I suggest developing formulas for each of your desired intervals.
Once you have developed those relevant formulas, depending on your desired interval, to avoid a date falling on a weekend (or holiday if required for your system), you can use the WORKDAY function:
=WORKDAY(computedDate+1,-1, [holiday])
If your computedDate is on a Saturday, or Sunday; by adding 1 day and then subtracting to the previous workday, Friday will result.
If your trading interval is every Two weeks, you only need to ensure that the First date is not on a Saturday or Sunday. For other intervals, you may have to apply the formula to every computedDate.
I'm trying to get the week number of a given quarter based on the date.
I currently have this formula
=1+(WEEKNUM(EDATE(Y4,-1)))-(WEEKNUM(DATE(YEAR(EDATE(Y4,-1)),
LOOKUP(MONTH(EDATE(Y4,-1)),{1,4,7,10}),1)))
But for January, it should be giving me 1 but it's giving me 10. Any suggestions?
How do you expect this to work at the start and end of the quarter? Default WEEKNUM function starts week 1 on the 1st of January every year and week 2 starts on the next Sunday after 1st January.
Assuming your quarter week numbers should work the same way, i.e. week 1 starts on the 1st of Jan/Apr/Jul/Oct and week 2 starts on the next Sunday then that's actually equivalent to counting Sundays since 6 days back into the previous quarter.
You can do that using NETWORKDAYS.INTL function, i.e. with this formula:
=NETWORKDAYS.INTL(EOMONTH(Y4,MOD(1-MONTH(Y4),-3)-1)-5,Y4,"1111110")
format result as number with no decimal places
NETWORKDAYS.INTL function is available in Excel 2010 and later versions - for older versions of Excel you can get the same results with this formula:
=INT((13-WEEKDAY(Y4)+Y4-EOMONTH(Y4,MOD(1-MONTH(Y4),-3)-1))/7)
(Expanded from comment)
when you choose a date in January, it's going back to December. 12 in your lookup array gives 10 as the result. Perhaps instead of EDATE, you should use EOMONTH(Y4,-1)+1, so you look at the 1st of the current month for your calculation
=1+(WEEKNUM(EOMONTH(Y4,-1)+1))-(WEEKNUM(DATE(YEAR(EOMONTH(Y4,-1)+1), LOOKUP(MONTH(EOMONTH(Y4,-1)+1),{1,4,7,10}),1)))
This is fairly interesting, since it changes with the year, and changes with what day of the week is the "start" of the week. So if a quarter starts on Saturday, and the week starts on a Saturday, the entire week is week 1. However, if it starts on a Sunday, week 1 is only one day long, and week 2 starts on Sunday.
The first question we have is, what day is it?
=DayCheck
Additionally, I'm going to call the start of each quarter the following:
Q1Start = Date(Year(DayCheck),1,1)
Q2Start = Date(Year(DayCheck),4,1)
Q3Start = Date(Year(DayCheck),7,1)
Q4Start = Date(Year(DayCheck),10,1)
The next question is, what's the first day of the week? We have some control over this with the Weekday function. For the sake of keeping it simple, Sunday is the start of the week.
Ok, that's our day. Next, what quarter is it?
`Quarter=ROUNDDOWN(MONTH(O16)/4,0)+1`
This gives us 1 for Q1, 2 for Q2, etc.
What day of the week is it now?
=WEEKDAY(DayCheck,1)
Ok, and now, what week are we on?
=WEEKNUM(DayCheck,1)
I'm going to put it together in a not very elegant fashion. I'm sure there's a better way out there.
=(Quarter=1)*((Weeknum(DayCheck)-WeekNum(Q1Start)+1)+(Quarter=2)*((Weeknum(DayCheck)-WeekNum(Q2Start)+1)+(Quarter=3)*((Weeknum(DayCheck)-WeekNum(Q3Start)+1)+(Quarter=4)*((Weeknum(DayCheck)-WeekNum(Q4Start)+1)
Try this:
=CHOOSE((MOD(WEEKNUM(Y4),13)=0)+1,WEEKNUM(Y4)-(ROUNDDOWN(WEEKNUM(Y4)/13,0)*13),13)
This will get the week number of a given date within a quarter.
I used this in one of my applications so you might be able to use it too. HTH.
Note: If you use 1st day other than Sunday, then adjust the WEEKNUM formula.
Can try this as I got this as combination of 2 formula
=WEEKNUM(A1,1)-(INT((MONTH(A1)-1)/3)*13)
second part - INT((MONTH(A1)-1)/3) gives us the quarter number of previous quarter which then multiplied with 13 weeks/quarter gives us how many weeks have passed in all previous quarter before current quarter.
First part - "WEEKNUM(A1,1)" gives us the week number of current week in the year.
so by deducting all the previous weeks in previous quarters from current week number of year, we get the current week number in current quarter.
I am writing a program that shows the current years sales from the beginning of the fiscal year to the current date, compared to the same date range of the year before.
My question is, what efforts do I need to take for leap year?
UPDATE:
OK they want it like I said (compare last year up to same date) but if today is non leap year and last year is and today is feb 28th compare to last year up to 29th. Or if today is Feb 29th compare to last year up to 28th.
This strikes me as a business decision. Depending on the type of business, that extra day may not matter. Otherwise, I suppose you could treat is as "first n days of the year" rather than "Jan 1 through X".
Here's an idea, but like others have said it might be based on your specific domain.
Consider 1 "normalized" year = 365.242199 days counting all the leap stuff (says google)
Calculate the average sales per day in your year based on the real number of days in that year
Scale it up or down to sales per 365.242199 days
So for example
2007 = $4000 in sales.
There's 365 days in 2007, so avg sale per day = $10.96
Multpiplying times num days in a normalized year (365.242199)
gives you $4003.05 normalized sales
You can compare this directly to a similar calculation for 2008,
2008 = $5000 in sales.
There's 366 days in 2008, so avg sale per day = $13.66
Multpiplying times num days in a normalized year (365.242199)
gives you $4975.655 normalized sales for 2008!
You could scale down the leap year values to take the extra day into account.
So if you compare, say, the 1st of September of a regular year with the 1st of September of a leap year you would do:
if(year == leapyear && day > 28Feb)
Convert date to dayOfYear
leapYearValue *= dayOfYear / (dayOfYear + 1)
This should really be in the specification, though.