using
import sys
folder = sys.argv[1]
for i in folder:
for file in i:
if file == "test.txt":
print (file)
would this access a file in the folder of a subfolder? For Example 1 main folder, with 20 subfolders, and each subfolder has 35 files. I want to pass the folder in commandline and access the first subfolder and the second file in it
Neither. This doesn't look at files or folders.
sys.argv[1] is just a string. i is the characters of that string. for file in i shouldn't work because you cannot iterate a character.
Maybe you want to glob or walk a directory instead?
Here's a short example using the os.walk method.
import os
import sys
input_path = sys.argv[1]
filters = ["test.txt"]
print(f"Searching input path '{input_path}' for matches in {filters}...")
for root, dirs, files in os.walk(input_path):
for file in files:
if file in filters:
print("Found a match!")
match_path = os.path.join(root, file)
print(f"The path is: {match_path}")
If the above file was named file_finder.py, and you wanted to search the directory my_folder, you would call python file_finder.py my_folder from the command line. Note that if my_folder is not in the same directory as file_finder.py, then you have to provide the full path.
No, this won't work, because folder will be a string, so you'll be iterating through the characters of the string. You could use the os module (e.g., the os.listdir() method). I don't know what exactly are you passing to the script, but probably it would be easiest by passing an absolute path. Look at some other methods in the module used for path manipulation.
Related
Scenario: I am trying to Rename all .txt file named "a.txt" in all subfolders of a directory.
Question: I came up with the following code, but it has and issue: My loops don't work as expected, I was hoping to get the directory loop, to use the last part of the path, and use that string to rename the file. Right now, my code will rename the file with the latest directory name. How can this be fixed?
Code:
import os
import fnmatch
directory = "C:/Users/DGMS/Desktop/Test"
for root, subdirectories, files in os.walk(directory):
for subdirectory in subdirectories:
pathtest = os.path.basename(os.path.normpath(os.path.join(root, subdirectory)))
print(pathtest)
for file in files:
if fnmatch.fnmatch(file, 'a.txt'):
os.rename(os.path.join(root, file),(os.path.join(root, pathtest)))
print(os.path.join(root, file))
Here is a better code for what you want. All "a.txt" now becomes "b.txt"
import os
rootdir = 'C:/Users/sid/Desktop/test'
for subdir, dirs, files in os.walk(rootdir):
for file in files:
if file == "a.txt"
os.rename(os.path.join(subdir, file),os.path.join(subdir, "b.txt"))
import os
def compute(path, fileExt):
if os.path.exists(path): # checks if the path entered by the user exists
print("The path exists")
for foldername, subfolder, filename in os.walk(path):
for file in filename:
if file.endswith(fileExt):
print(os.path.join(foldername, subfolder, *file))
else:
print("The path does not exist !")
This program is about printing the full path of all the files in the folder mentioned by the user ending by the extension also mentioned by the user.
When I run the program i get a error on line 10 stating that : TypeError: join() argument must be str or bytes, not 'list'. I checked the variable type of file by using type(file) and it return str.
Where wrong ??
You should double check the os.walk() documentation and look closely at the error message you are getting. Your error message indicates you are trying to combine a list and a string. You have verified that file is a string, but what about foldername and subfolder.
os.walk() returns three things, the current directory file name, a list of all subdirectories of the current directory, and a list of all files in the current directory. This tells us that foldername is also a string but subfolder is actually a list of strings which causes the error message you are seeing.
Additionally, all of the files returned by os.walk() are contained within the root directory, not within the subdirectories. Therefore to print the path of the file, you want to join the file name to the root file path.
Just focusing on the os.walk() portion of your question, the following will print the full path of all files with the given file extension:
import os
for foldername, subfolder, files in os.walk(top, topdown=False):
for file in files:
if file.endswith(fileExt):
print(os.path.join(foldername, file))
I have 4 files (with different extensions) in a directory as shown below.
Test1234_`enter code here`Dir (Directory)
FileA_1234_test.dat
FileAAB_1234_test.log
FileABCD_1234_test.dbm
FileABCDE_1234_test.jdt
I want to replace part of directory and file names as shown below
Test6789_Dir (Directory)
FileA_6789_test.dat
FileAAB_6789_test.log
FileABCD_6789_test.dbm
FileABCDE_6789_test.jdt
How can we achieve this in Python3? I have no idea to do this.
I am not sure what you want to do.
maybe something like this
def replace_names(path, str_to_replace='1234', replacement='6789'):
import os
for filename in os.listdir(first_path):
if '_'+str_to_replace+'_' in filename:
new_filename = filename.replace(str_to_replace, replacement)
os.rename(filename, new_filename )
os.rename(path, .replace(str_to_replace, replacement))
#now, run it...
replace_names('Test1234_Dir')
i have written a python script to rename all the files present in a folder by removing all the numbers from the file name but this doesn't work .
Note :Same code works fine for python2.7
import os
def rename_files():
#(1) get file names from a folder
file_list = os.listdir(r"D:\prank")
print(file_list)
saved_path = os.getcwd()
print("Current working Directory is " + saved_path)
os.chdir(r"D:\prank")
#(2) for each file ,rename filename
for file_name in file_list:
os.rename(file_name, file_name.translate(None,"0123456789"))
rename_files()
Can anyone tell me how to make it work.Is the translate function which is not working properly
The problem is with os.rename() portion of your code.
os.rename() requires you to give it a full path to the file/folder you want to change it to, while you only gave it the file_name and not the full path.
You have to add the full path to the folders/files directory.
so it should look like this:
def rename_files():
# add the folder path
folder_path = "D:\prank\\"
file_list = os.listdir(r"D:\prank")
print(file_list)
saved_path = os.getcwd()
print("Current working Directory is " + saved_path)
os.chdir(r"D:\prank")
# Concat the folder_path with file_name to create the full path.
for file_name in file_list:
full_path = folder_path + file_name
print (full_path) # See the full path here.
os.rename(full_path, full_path.translate(None, "0123456789"))
look up the documentation for os, heres what ive found on rename:
os.rename(src, dst, *, src_dir_fd=None, dst_dir_fd=None)
Rename the file or directory src to dst. If dst is a directory, OSError will be raised. On Unix, if dst exists and is a file, it will be replaced silently if the user has permission. The operation may fail on some Unix flavors if src and dst are on different filesystems. If successful, the renaming will be an atomic operation (this is a POSIX requirement). On Windows, if dst already exists, OSError will be raised even if it is a file.
This function can support specifying src_dir_fd and/or dst_dir_fd to supply paths relative to directory descriptors.
If you want cross-platform overwriting of the destination, use replace().
New in version 3.3: The src_dir_fd and dst_dir_fd arguments.
heres a link to the documentation, hope this helps, thanks
https://docs.python.org/3/library/os.html
Others have pointed out other issues with your code, but as to your use of translate, in Python 3.x, you need to pass a dictionary mapping ordinals to new values (or None). This code would work:
import string
...
file_name.translate(dict(ord(c), None for c in string.digits))
but this seems easier to understand:
import re
...
re.sub(r'\d', '', file_name)
I am working on a search-and-destroy type program which I need it to do is search all directories with a certain file-name and append them to a list. after that delete all those files...not objects in list or the list...
import os
file_list=[]
for root, dirs, files in os.walk(path-to-dir'):
for f_name in files:
if f_name.startswith("file-name"):
file_list.append(f_name)
I could write up to appending part of the code but I don't know next...
Some help please
To remove a file from your computer, use os.remove(). It takes full path to the file as it's parameter, so instead of calling os.remove("infectedFile.dll") you would call os.remove("C:/program files/avira/infectedFile.dll")
So your file_list should contain full paths to the files, and then just call:
for file in file_list:
os.remove(file)
Modify your file_list.append(f_name). The f_name is only a bare name. You need to add the path to the file name in the time of processing, because you do not know where the file was found in the directory hierarchy:
file_list.append(os.path.join(root, f_name))
The root variable contains the path during walking.
To make check whether your code works, just print the content of the list:
print('\n'.join(file_list))
Or you can do it in the loop to get ready for the later part:
for fname in file_list:
print(fname)
Then you just add the os.remove(fname) to remove the file name:
for fname in file_list:
print('removing', fname)
os.remove(fname)