I'm using databricks and trying to read in a csv file like this:
df = (spark.read
.option("header", "true")
.option("inferSchema", "true")
.csv(path_to_my_file)
)
and I'm getting the error:
AnalysisException: 'Unable to infer schema for CSV. It must be specified manually.;'
I've checked that my file is not empty, and I've also tried to specify schema myself like this:
schema = "datetime timestamp, id STRING, zone_id STRING, name INT, time INT, a INT"
df = (spark.read
.option("header", "true")
.schema(schema)
.csv(path_to_my_file)
)
But when try to see it using display(df), it just gives me this below, I'm totally lost and don't know what to do.
df.show() and df.printSchema() gives the following:
It looks like that data are not being read into the dataframe.
error snapshot:
Note, this is an incomplete answer as there isn't enough information about what your file looks like to understand why the inferSchema did not work. I've placed this response as an answer as it is too long as a comment.
Saying this, for programmatically specifying a schema, you would need to specify the schema using StructType().
Using your example of
datetime timestamp, id STRING, zone_id STRING, name INT, time INT, mod_a INT"
it would look something like this:
# Import data types
from pyspark.sql.types import *
schema = StructType(
[StructField('datetime', TimestampType(), True),
StructField('id', StringType(), True),
StructField('zone_id', StringType(), True),
StructField('name', IntegerType(), True),
StructField('time', IntegerType(), True),
StructField('mod_a', IntegerType(), True)
]
)
Note, how the df.printSchema() had specified that all of the columns were datatype string.
I discovered that the problem was caused by the filename.
Perhaps databrick is unable to read filename schemas that begin with '_'. (underscore).
I had the same problem, and when I uploaded the file without the first letter (ie, underscore), I was able to process it.
Related
I am trying to load csv file to a Spark dataframe. The csv file doesn't have any header as such, but I am aware which field corresponds to what.
The problem is my csv has almost 35 odd fields but I am interested in very limited columns so is there a way by which I can load the selected columns and map them to corresponding fields as defined in my schema.
Let's say we have following CSV:
1,Michel,1256,Student,high Street, New Delhi
2,Solace,7689,Artist,M G Road, Karnataka
In Scala my Code is something like this .
val sample_schema = StructType(Array(StructField("Name", StringType, nullable = false),
StructField("unique_number", StringType, nullable = false),
StructField("state", StringType, nullable = false))
val blogsDF = sparkSession.read.schema(sample_schema)
.option("header", true)
.csv(file_path)
This will load the data into a dataframe, but it will not be in the order I want.
What I want is for csv record to be split and data is loaded as per underlying mapping
col1 --> Name
col2 --> unique id
col5 --> state
Not sure if we can do this kind of operation before loading data into DataFrame. I know another approach wherein we can load the data into one dataframe, and then select few columns and create another dataframe, just want to check if we can map during data load itself.
Any help or pointer in this regard will be really helpful.
Thanks
Ashit
Have you tried it:
schema = StructType([StructField("a", IntegerType(), True),
StructField("b", IntegerType(), True),
StructField("c", StringType(), True),
StructField("d", StringType(), True),
StructField("e", DoubleType(), True),
StructField("f", LongType(), True),
])
df = spark.read.csv('blablabla', schema=schema)
I need to read dataset into a DataFrame, then write the data to Delta Lake. But I have the following exception :
AnalysisException: 'Incompatible format detected.\n\nYou are trying to write to `dbfs:/user/class#azuredatabrickstraining.onmicrosoft.com/delta/customer-data/` using Databricks Delta, but there is no\ntransaction log present. Check the upstream job to make sure that it is writing\nusing format("delta") and that you are trying to write to the table base path.\n\nTo disable this check, SET spark.databricks.delta.formatCheck.enabled=false\nTo learn more about Delta, see https://docs.azuredatabricks.net/delta/index.html\n;
Here is the code preceding the exception :
from pyspark.sql.types import StructType, StructField, DoubleType, IntegerType, StringType
inputSchema = StructType([
StructField("InvoiceNo", IntegerType(), True),
StructField("StockCode", StringType(), True),
StructField("Description", StringType(), True),
StructField("Quantity", IntegerType(), True),
StructField("InvoiceDate", StringType(), True),
StructField("UnitPrice", DoubleType(), True),
StructField("CustomerID", IntegerType(), True),
StructField("Country", StringType(), True)
])
rawDataDF = (spark.read
.option("header", "true")
.schema(inputSchema)
.csv(inputPath)
)
# write to Delta Lake
rawDataDF.write.mode("overwrite").format("delta").partitionBy("Country").save(DataPath)
This error message is telling you that there is already data at the destination path (in this case dbfs:/user/class#azuredatabrickstraining.onmicrosoft.com/delta/customer-data/), and that that data is not in the Delta format (i.e. there is no transaction log). You can either choose a new path (which based on the comments above, it seems like you did) or delete that directory and try again.
I found this Question with this search: "You are trying to write to *** using Databricks Delta, but there is no transaction log present."
In case someone searches for the same:
For me the solution was to explicitly code
.write.format("parquet")
because
.format("delta")
is the dafault since Databricks Runtime 8.0 and above and I need "parquet" for legacy reasons.
One can get this error if also tries to read the data in a format that is not supported by spark.read (or if does not specify the format).
The file format should be specified along the supported formats: csv, txt, json, parquet or arvo.
dataframe = spark.read.format('csv').load(path)
I'm trying to import data with parquet format with custom schema but it returns :
TypeError: option() missing 1 required positional argument: 'value'
ProductCustomSchema = StructType([
StructField("id_sku", IntegerType(), True),
StructField("flag_piece", StringType(), True),
StructField("flag_weight", StringType(), True),
StructField("ds_sku", StringType(), True),
StructField("qty_pack", FloatType(), True)])
def read_parquet_(path, schema) :
return spark.read.format("parquet")\
.option(schema)\
.option("timestampFormat", "yyyy/MM/dd HH:mm:ss")\
.load(path)
product_nomenclature = 'C:/Users/alexa/Downloads/product_nomenc'
product_nom = read_parquet_(product_nomenclature, ProductCustomSchema)
As mentioned in the comments you should change .option(schema) to .schema(schema). option() requires you to specify a key (the name of the option you're setting) and a value (what value you want to assign to that option). You are getting the TypeError because you were just passing a variable called schema to option without specifying what that option you were actually trying to set with that variable.
The QueryExecutionException you posted in the comments is being raised because the schema you've defined in your schema variable does not match the data in your DataFrame. If you're going to specify a custom schema you must make sure that schema matches the data you are reading. In your example the column id_sku is stored as a BinaryType, but in your schema you're defining the column as an IntegerType. pyspark will not try to reconcile differences between the schema you provide and what the actual types are in the data and an exception will be thrown.
To fix your error make sure the schema you're defining correctly represents your data as it is stored in the parquet file (i.e. change the datatype of id_sku in your schema to be BinaryType). The benefit to doing this is you get a slight performance gain by not having to infer the file schema each time the parquet file is read.
I'm reading a source that got descriptions longer then 256 chars. I want to write them to Redshift.
According to: https://github.com/databricks/spark-redshift#configuring-the-maximum-size-of-string-columns it is only possible in Scala.
According to this: https://github.com/databricks/spark-redshift/issues/137#issuecomment-165904691
it should be a workaround to specify the schema when creating the dataframe. I'm not able to get it to work.
How can I specify the schema with varchar(max)?
df = ...from source
schema = StructType([
StructField('field1', StringType(), True),
StructField('description', StringType(), True)
])
df = sqlContext.createDataFrame(df.rdd, schema)
Redshift maxlength annotations are passed in format
{"maxlength":2048}
so this is the structure you should pass to StructField constructor:
from pyspark.sql.types import StructField, StringType
StructField("description", StringType(), metadata={"maxlength":2048})
or alias method:
from pyspark.sql.functions import col
col("description").alias("description", metadata={"maxlength":2048})
If you use PySpark 2.2 or earlier please check How to change column metadata in pyspark? for workaround.
I am new to spark and was playing around with Pyspark.sql. According to the pyspark.sql documentation here, one can go about setting the Spark dataframe and schema like this:
spark= SparkSession.builder.getOrCreate()
from pyspark.sql.types import StringType, IntegerType,
StructType, StructField
rdd = sc.textFile('./some csv_to_play_around.csv'
schema = StructType([StructField('Name', StringType(), True),
StructField('DateTime', TimestampType(), True)
StructField('Age', IntegerType(), True)])
# create dataframe
df3 = sqlContext.createDataFrame(rdd, schema)
My question is, what does the True stand for in the schema list above? I can't seem to find it in the documentation. Thanks in advance
It means if the column allows null values, true for nullable, and false for not nullable
StructField(name, dataType, nullable): Represents a field in a StructType. The name of a field is indicated by name. The data type of a field is indicated by dataType. nullable is used to indicate if values of this fields can have null values.
Refer to Spark SQL and DataFrame Guide for more informations.
You can also use a datatype string:
schema = 'Name STRING, DateTime TIMESTAMP, Age INTEGER'
There's not much documentation on datatype strings, but they mention them in the docs. They're much more compact and readable than StructTypes