I have the Midpoint Ellipse drawing Algorithm and I have the Midpoint Circle drawing Algorithm.
Why do I need a separate algorithm for drawing circles, when I can just use the Ellipse midpoint algorithm for drawing a circle simply by specifying the radii along both axes to be of equal length?
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I want to create a path that I can extrude that would be the equivalent of the difference of a square and a circle with radius equal to the side of the square with its center at the upper right corner of the square.
Repeating this question for better visibility. I have a triangular mesh (assume a manifold mesh). I want to sample corners of a square on a mesh that is independent of the triangulation.
I am following these steps
Sample a triangle (based on the areas of the triangles)
Sample a point uniformly on the triangle/face
Sample a pair of random perpendicular directions
I want to calculate the distance of three other corners of the square given an edge length. Since the corners can be on any other face, the output should be of the format (Face, barycentric coordinates on that face).
I am looking at libraries such as Polyscope or pygeodesic that use the heat method to compute the geodesic distance between two vertices of the mesh, but I am not sure how to get points at an arbitrary geodesic distance from another point.
When I want to draw a pie chart in SVG, all tutorials say that you need to calculate the end point of the arc element. Unless you want an exact 90° angle, that calculated point must unvariably fall beside the circumference line of the underlying circle because of rounding, if you scale up the scalable (!) graphic.
I cannot believe there is no way to draw a circle segment by giving a center, a radius and an angle.
Or is there?
How to find Centroid for a rectangular section inclined at an angle theta? Is there any general formula available?
Centroid of a rectangle is situated at intersection of it's diagonals (or arithmetic mean of all vertices). So it is enough to find vertice coordinates after inclination
Centroid of a rectangle does not changes, after inclination.
Only the co-ordinates of a Rectangle changes with the following equation.
x′=xcosθ − ysinθ
y′=xsinθ + ycosθ
where,
(x,y)-initial co-ordinates of rectangle.
(x',y')-final co-ordinates of rectangle.
θ-angle of inclination.
Refer link for detail.
As an input, I receive some planar, triangulated geometry. Now, I need to compute the four coordinates of the corners of the bounding rectangle. Any Ideas?
I'm going to assume that you mean 2D space in the question title, because everything else refers to 2D.
Go through all the vertices (x,y) in your geometry, and calculate the maximum and minimum of the x's, and the max and min of the y's.
Then the vertices of your bounding rectangle will be (min_x,min_y), (max_x,min_y), (max_x, max_y), and (min_x, max_y).