I have this Image Path on Cell A1:
E:\Test\Coll\01\Red\Example\Untitled-1.jpg
I want cells B2 to whatever it takes (in my case H2) to show the Nth substring between the separator "\", meaning:
I know the Data to Columns does the exact same thing, but i need it to be dynamic.
Any ideas please?
Formula for B2
=TRIM(MID(SUBSTITUTE($A2,"\",REPT(" ",100)),(B$1-1)*100+1,100))
Copy accross as far as needed
Related
I have a comma separated value in A2 and same numbers in different cells B1, C1, D1.... I want to match them from comma separated value and find out the count in B2, C2, D2. Please see the image attached you will get the context.
Can we achieve this by formula or macro in excel?
Tried formula:
=LEN(TRIM($A$2))-LEN(SUBSTITUTE(TRIM($A$2),C1,","""))
Also, I have two data sets where I will be using this formula to find out the count of number from comma-separated value and based on count I want the repeated ones to come in a different cell please refer the image for better understanding.
Probably not the best solution but get the job done. Please note it is case-sensitive and please make sure to press Ctrl+Shift+Enter upon finishing this formula.
{=SUM(--(EXACT("!"&TRIM(MID(SUBSTITUTE($A2,",",REPT(" ",100)),(ROW(INDIRECT("1:"&LEN($A2)))-1)*100+1,100)),"!"&B1)))}
You can replace ! in the above formula with a unique symbol that will never appear in the text string to be safer.
The logic is to SUBSTITUTE the comma , with and long string of blanks, then use MID to find each value in the text string and return the result as an array, then use EXACT to match each value in the array with the look up value and return a new array of TRUE and FALSE, then SUM up all TRUE which will give the count of the look up value.
UPDATE #2
As requested by OP, here is one way of solving the second query which is to match the same value with the same occurrence from two text strings separated by comma ,.
The formula in Cell C2 is from the original solution which is used to find the occurrence of a given value in a text string;
The formula for Range C6:K6 is an array formula as shown below. I used a helper row to layout the matching values, and excluding the one that has 0 count for both data set;
{=IFERROR(INDEX($C$1:$K$1,,AGGREGATE(15,7,COLUMN(INDIRECT("1:"&COLUMNS($C$1:$K$1)))/($C$2:$K$2=$C$3:$K$3)/($C$2:$K$2>0),COLUMN()-2))&",","")}
The formula in Cell L8 is concatenating all values from Range C6:K6 and remove the last comma , from the final text string:
=LEFT(CONCATENATE(C6,D6,E6,F6,G6,H6,I6,J6,K6),LEN(CONCATENATE(C6,D6,E6,F6,G6,H6,I6,J6,K6))-1)
The following worked for me, give it a try:
Formula in B2:
=(LEN(","&SUBSTITUTE($A$2,",",",,")&",")-LEN(SUBSTITUTE(","&SUBSTITUTE($A$2,",",",,")&",",","&B$1&",","")))/LEN(","&B$1&",")
Drag right...
A simpler way of doing it is to simply calculate the difference in the length of the string minus the length of the string when replacing the value searched by nothing and dividing by the length of the string searched
The formula would be:
=(LEN($A$1)+1-LEN(SUBSTITUTE($A$1&",",B1&",","")))/LEN(B1&",")
There is a much simpler solution:
=COUNTIF(SPLIT($A$2, ","), B1)
I have in Column C2, formula results which I need to perform LEFT on in order to trim the cell formula value
The formula result MUST have one of the following (. OR _ OR -) in answer
If one of the above exists in the cell , then LEFT(C2,FIND("the_variable_in_the_formula_answer),C2)-1)
My VBA isn't the best, but I think I could use
variable = Left(Sheet1.[C2],InStr(Sheet1.[C2],".")-1)
I don't know how to make the .(period) , _(underscore) OR -(hyphen) a variable to look for
Try this formula at row two and fill down the column:
=IFERROR(LEFT(Sheet1!C2, AGGREGATE(15,6,SEARCH({".","-","_"},Sheet1!C2),1)-1), "")
It truncates until the first found of {".","-","_"}. If you want to truncate till the last found, change 15 into 14.
For your additional requirements:
=IF(ISNA(C2), D2,
IFERROR(LEFT(Sheet1!C2,AGGREGATE(15,6,SEARCH({".","-","_"},Sheet1!C2),1)-1),C2))
I have a scenario where I want my Microsoft excel field to have the same length of the longest word in the column.
Basically lets say if I have:
ACBBASDBBADSAD
BADFDFDDF
So here I want to have the second word with less characters to have white spaces at its end to match the length of the first word.
=&" " this definitely helps but I am unable to achieve the above scenario
Consider this screenshot:
In column B the length of each cell of column A is established with the formula =len(A1) copied down.
Cell D2 has the range name MaximumLength and the formula =max(B:B).
With that in place, you can create the padded values with this formula in cell G1, copied down:
=A1&REPT("*",MaximumLength-LEN(A1))
If you don't want to use the helper column and helper cell, you can use this array formula instead:
=A2&REPT("*",MAX(LEN(A1:A15))-LEN(A2))
This formula must be confirmed with Ctrl-Shift-Enter. It is advisable to use defined ranges, not whole columns in array formulas, hence the range in LEN(A1:A15). Adjust as desired.
I've used the "*" character so it is visible. Replace it with a space " " in your scenario.
You can add this formula to count maximum characters and use on some cell, because you will need to press a command for it to work, so every cell can't contain this formula, let's say it is on Z1:
=MAX(LEN($A:$A))
Certify to press ctrl+shift+enter on the formula
Then you use this formula on your cells:=REPT(" ";Z1-LEN(A2))&A2
Edit: Sorry, anwsered late, teylyn is more complete.
I am new to excel, I have a data of 1000 rows with each row looks like 435362|A|B|C I want a formula in excel which modifies each rows so that the data looks like 435362,A|B|C i.e. it should replace first occurrence of | with comma(,).
One more option: (with data in A1):
=SUBSTITUTE(A1,"|",",",1)
You can't replace existing data with forrmula, so you need to create another column. You can then cut and paste as values to replace existing data.
With data in A1, in B1 enter:
=MID(A1,1,FIND("|",A1)-1) & "," & MID(A1,FIND("|",A1)+1,9999)
and copy down
If every string in all 1000 rows is the same length, this should do the trick:
=REPLACE(A1,LEN(A1)-5,1,",")
Explanations:
The two instances of "A1" in the formula are the cell references, these would need to change for each cell in order to work, but if you copy the formula across cells this value should change automatically.
The LEN is finding the length of the string in the cell, then the -5 is finding the symbol 5th from the end (in this case the "|"). The 1 is saying only replace this one symbol (2 would replace "|" and "A"), and the "," is telling the formula which symbol to replace the "|" with".
I hope this works for you!
If your data have the same char length the you can use =CONCATENATE(LEFT(B3,6),",",RIGHT(B3,5)) B3 is where your data is located in this case.
This is only one way of doing it.
Can you tell me if I want to find the last character in Excel based on condition
let say last character if it is A then replace it with X, or if it is b then replace it with Z.
I want to do it with formula
If your value is in A1 cell, then try applying the following formula in B1 cell.
Formula
=IF(RIGHT(A1,1)="a", LEFT(A1,LEN(A1)-1) &"x", IF(RIGHT(A1,1)="b",LEFT(A1,LEN(A1)-1) & "z",A1))
If you are looking for last character to be exactly A, then try the following formula.
Formula
=IF(EXACT(RIGHT(A1,1),"A"), LEFT(A1,LEN(A1)-1) &"X", IF(EXACT(RIGHT(A1,1),"B"),LEFT(A1,LEN(A1)-1) & "Z",A1))
You can use this formula. See the example sheet to understand the values.
In Example:
"A2": Original Text
"B2": Result
=IF(RIGHT(A2,1)="A",REPLACE(A2,LEN(A2),1,"X"),IF(RIGHT(A2,1)="B",REPLACE(A2,LEN(A2),1,"Z"),A2))