I am trying to find the occurence of arabic character with its harakat in string such as "رَّ" in "بِسْمِ ٱللَّهِ ٱلرَّحْمَٰنِ ٱلرَّحِيمِ".
Arabic characters can take harakat for example "ر" is the original arabic character but can have harakat so it can look something like this "رَّ"> I am using Python 3 to find the character occurence with a specific harakat but could not do that. I have tried for loop and tried converting the string to unicode but could not do that.
str = "مرة رجل حكيم قال بِسْمِ ٱللَّهِ ٱلرَّحْمَٰنِ ٱلرَّحِيمِ"
i=0
for s in str:
if s == "رَّ":
i = i + 1
print(i)
Expected output is 2 but 0 is what I get.
len("رَّ") returns 3, which means the glyph is represented by three characters. Your loop checks a single character at a time and so never finds a match.
You need to be looking for substrings, which is exactly what .count() is for.
i = str.count('رَّ')
Related
Assume there's a string
"An example striiiiiing with other words"
I need to replace the 'i's with '*'s like 'str******ng'. The number of '*' must be same as 'i'. This replacement should happen only if there are consecutive 'i' greater than or equal to 3. If the number of 'i' is less than 3 then there is a different rule for that. I can hard code it:
import re
text = "An example striiiiing with other words"
out_put = re.sub(re.compile(r'i{3}', re.I), r'*'*3, text)
print(out_put)
# An example str***iing with other words
But number of i could be any number greater than 3. How can we do that using regex?
The i{3} pattern only matches iii anywhere in the string. You need i{3,} to match three or more is. However, to make it all work, you need to pass your match into a callable used as a replacement argument to re.sub, where you can get the match text length and multiply correctly.
Also, it is advisable to declare the regex outside of re.sub, or just use a string pattern since patterns are cached.
Here is the code that fixes the issue:
import re
text = "An example striiiiing with other words"
rx = re.compile(r'i{3,}', re.I)
out_put = rx.sub(lambda x: r'*'*len(x.group()), text)
print(out_put)
# => An example str*****ng with other words
I have this string
"Hello there, this is some line-aa."
how to slice it into an array like this?
Hello
there,
this
is
some
line-aa.
this is what I have tried so far
function sliceSpaces(arg)
local list = {}
for k in arg:gmatch("%w+") do
print(k)
table.insert(list, k)
end
return list
end
local sentence = "مرحبا يا اخوتي"
print("sliceSpaces")
print(sliceSpaces(sentence))
this code works for English text, but not for arabic, how can I make it work for arabic too?
Lua strings are sequences of bytes, not Unicode characters. The pattern %w matches alphanumeric characters, but it applies to ASCII only.
Instead, use %S to match a non-whitespace character:
for k in arg:gmatch("%S+") do
The string I am given is as follows:
scrap1 =
a le h
ke fd
zyq b
ner i
You'll notice there are 2 blank spaces indicating a space (ASCII 32) in each row. I need to find the mean ASCII value in each column without taking into account the spaces (32). So first I would convert to with double(scrap1) but then how do I find the mean without taking into account the spaces?
If it's only the ASCII 32 you want to omit:
d = double(scrap1);
result = mean(d(d~=32)); %// logical indexing to remove unwanted value, then mean
You can remove the intermediate spaces in the string with scrap1(scrap1 == ' ') = ''; This replaces any space in the input with an empty string. Then you can do the conversion to double and average the result. See here for other methods.
Probably, you can use regex to find the space and ignore it. "\s"
findSpace = regexp(scrap1, '\s', 'ignore')
% I am not sure about the ignore case, this what comes to my mind. but u can read more about regexp by typying doc regexp.
Trying to make a textfield where people write the unicode without the backslash. I want to add the backslash after they typed it. So the user types u2605 and the code converts it to "\u2605", i then convert this to a unicode character and insert it in textflow.
My code:
this works:
span.text = publicFunctions.htmlUnescape(he.encode("\u2605"))
this doesn't work:
span.text = publicFunctions.htmlUnescape(he.encode("\\u"+"2605"))
how to make a string that acts as a unicode string?
Tried all sorts of things, escape(unescape()), convert to number, "\u", "\u" ... nothing helps.
trace("\u2605" == "\u"+"2605") ... will return false. So will
trace("\u2605" == "\u"+"2605")
"\u2605" is a string with a single character, the character with the code point 2605, while "\\u" + "2605" is a string with 6 characters (the backslash, the u and the four digit number).
If you want to construct a unicode character from just the four digits, you should be able to use String.fromCharCode. The thing is just that the escape sequence uses a hexadecimal number, while the method obviously takes a decimal number. So if the user enters a hexadecimal string, you will have to convert that first:
trace(String.fromCharCode(parseInt('2605', 16)) == '\u2605'));
That's an interesting issue! I don't think you can concatenate a string literal and achieve what you're trying to do. The relevant character escaping happens when the string literal is originally formed, which means that you need the whole sequence together in the first place.
But you should be able to take the user-supplied number and dynamically generate a Unicode string with String.fromCharCode(...).
http://help.adobe.com/en_US/FlashPlatform/reference/actionscript/3/String.html#fromCharCode()
On Python 3 printing unicode characters can be printed like this:
print('\uFFFF')
But how can I print higher unicode characters like 001FFFFF? print('\u001FFFFF') will just print 001F as unicode character and then 4 times F. Trying to use print('\u001F\uFFFF') will result in 2 unicode characters instead of the wanted one. Is it possible to print somehow the unicode character 001FFFFF in Python 3?
Use an upper-case U.
print('\U001FFFFF')
There is another way in Python 3, using the built-in function chr(i), which
Return the string representing a character whose Unicode code point is
the integer i.
and
The valid range for the argument is from 0 through 1,114,111 (0x10FFFF in base 16).
so there are no limitation for the hex digit value.
print(chr(97))
print(chr(0xFFFF))
print(chr(0x10080))