Check if cell is text and if so, delete row - excel

UPDATE:
Data set is made of strings that are number though (I don't get it) -> I can do all the math stuff with them as with regular numbers.
Problem is I need to separate cells that look like this "186.85" and cells that look like this "1.76 Dividend".
====================
I need a loop to check row by row if the cell contains some text (word "dividend" specifically) or if it's just number. If it is a text, then delete it and move to the next row.
It does some deleting BUT it wipes like 50 rows of data almost every time (I have only two text populated rows in this particular data set). These rows are numbers.
Dim i As Long
i = 2
Do
If WorksheetFunction.IsText(Sheets("Data").Cells(i, 5)) = True Then
If Not Worksheets("Data").Cells(i, 5).Value = "" Then
Worksheets("Data").Rows(i).Delete
End If
End If
i = i + 1
Loop Until i = 100
I expected to loop through the data and delete the entire row if a cell contains text.
This code so far deletes things kinda randomly.

The below has been updated to a dynamic range. This will not need modification regardless of how many rows your sheet has.
More importantly, deleting rows inside a loop will cause your range to shift at every deletion. The way around this is to loop backwards
OR, even better..
Don't delete cells inside your loop. Every time your criteria is met, you force an action (deletion). Instead, gather up all of the cells to be deleted inside your loop and then delete the entire collection (Union) all at once outside of the loop. This requires 1 action in total rather 1 action per text instance
Sub Looper()
Dim ws As Worksheet: Set ws = ThisWorkbook.Sheets("Sheet1") '<-- Update sheet name
Dim i As Long, LR As Long
Dim DeleteMe As Range
LR = ws.Range("E" & ws.Rows.Count).End(xlUp).Row
For i = 2 To LR
If WorksheetFunction.IsText((ws.Range("E" & i))) Then
If Not DeleteMe Is Nothing Then
Set DeleteMe = Union(DeleteMe, ws.Range("E" & i))
Else
Set DeleteMe = ws.Range("E" & i)
End If
End If
Next i
If Not DeleteMe Is Nothing Then DeleteMe.EntireRow.Delete
End Sub

Try something like this:
Sub test()
Dim i As Long
For i = 100 To 2 Step -1
With ThisWorkbook.Worksheets("Data")
If WorksheetFunction.IsText(.Cells(i, 5)) = True Then
If Not .Cells(i, 5).Value = "" Then
.Rows(i).EntireRow.Delete
End If
End If
End With
Next i
End Sub

You can use SpecialCells with xlCellTypeConstants-2... No need for a loop. See Range.SpecialCells method (Excel) and XlSpecialCellsValue enumeration (Excel)
Is this what you are trying?
Option Explicit
Sub Sample()
Dim ws As Worksheet
Dim rng As Range
'~~> Change this to the relevant sheet
Set ws = Sheet1
With ws
On Error Resume Next
Set rng = .Columns(5).SpecialCells(xlCellTypeConstants, 2)
On Error GoTo 0
If Not rng Is Nothing Then rng.EntireRow.Delete
End With
End Sub

Thank you all for quick responses and effort.
I managed to get this solution working with InStr() function:
''loop through the Data and remove all rows containing text (Dividend payments which we don't need)
Dim i As Long
Dim ws As Worksheet
Dim searchText As String
Dim searchString As String
i = 2
Set ws = Sheets("Data")
Do Until ws.Cells(i, 2).Value = ""
searchText = "Dividend"
searchString = ws.Cells(i, 2).Value
If InStr(searchString, searchText) Then
ws.Rows(i).Delete
End If
i = i + 1
Loop

Related

VBA Index Match with a loop with two conditions

I hope that someone could help me with an index match formula that is made using a loop and storing the results data on the column.
Let's say that my data is following to make it simple:
We have an employee column and a salary column. I want to find all the salary options for HR employees.
I would like to store automatically all the results found on the column J (Researched input is in column I). And I want to finish the loop after not finding any new values.
Here is the data:
My initial code is down below without a loop to go down on the range:
Sub test()
Dim oCell As Range
Dim i As Long
i = 1
Do While Worksheets("Sheet1").Cells(i, 9).Value <> ""
Set oCell = Worksheets("Sheet1").Range("A:A").Find(What:=Worksheets("Sheet1").Cells(i, 9))
If Not oCell Is Nothing Then Worksheets("Sheet1").Cells(i, 10) = oCell.Offset(0, 1)
i = i + 1
Loop
End Sub
The problem stems from two main things:
The .Find range you are searching is the entire column A, which is then set to a .Range object (oCell). However, from my VBA understanding the .Find method cannot apply the cell address of each instance of the string/search parameter you are looking for. It will only apply the cell address of the first one it finds. To set a .Range object of non-contiguous rows you could use UNION function.
The .Find(What:= ... is set to a dynamic range which moves down column I as the loop continues. This means it will never find a match because it is searching the preceding column.
Here is a suggested solution, which hopefully you can adapt to your real world data:
Option Explicit
'
Sub test()
Dim oCell As Range
Dim i As Long
i = 1
Do While Worksheets("Sheet1").Cells(i, 2).Value <> ""
' Included as a sense check when stepping through your code to confirm loop is on correct cell
'Debug.Print Cells(i, 2).Address
'Debug.Print Cells(i, 2).Value
'Debug.Print "NEXT"
Set oCell = Worksheets("Sheet1").Range("A1:A10").Find(What:="HR")
If Not oCell Is Nothing Then Worksheets("Sheet1").Cells(i, 3) = oCell.Offset(0, 1)
i = i + 1
Loop
End Sub
Try this:
Option Explicit
Sub test()
Dim i As Long
Dim wb as Excel.Workbook
Dim ws as Excel.Worksheet
i = 2 ' we don't need the header
set wb = ActiveWorkBook
set ws = wb.Sheets("Sheet1") ' or wb.Sheets(1)
Do While ws.Cells(i, 1) <> ""
If ws.Cells(i,1) = "HR" then
ws.Cells(i, 3) = ws.Cells(i,2)
End If
i = i + 1
Loop
End Sub
Tested and found working

AutoFilter Function is Deleting my Column Headers

I run my VBA code and the first time it runs I get the result I want but if I run it a second time my column headers get deleted. FYI my table starts on E and goes through N. My button is on column O and also gets deleted when I run it a second time.
Switching the Range did not help and setting AutoFilter to false also did not work.
#
Sub Auto_filter()
Dim sh As Worksheet
Set sh = ThisWorkbook.Worksheets("HP Service Manager")
sh.AutoFilterMode = False
With sh
On Error Resume Next
.ShowAllData
.Range("E1:N1").AutoFilter 1, "IM*"
AutoFilter = False
End With
End Sub
#
Expect to not have column headers deleted.
The issue is in the second code you shared.
The code is first setting the range here:
Set Rng = Range("E1", Cells(iRow, "E"))
And then here it is trying to delete all visible cells in the range (after applying the filter)
Rng.SpecialCells(xlCellTypeVisible).EntireRow.Delete
which also includes your header cell.
So, a simple way to deal with it could be to set another range like this
Set Rng2 = Range("E2", Cells(iRow, "E"))
and then using it to delete the data
Rng2.SpecialCells(xlCellTypeVisible).EntireRow.Delete
Here is the re-written function for your reference. This only deletes the rows starting from row 2 that are blank. You may want to add some error handing in case there are no blank rows to delete etc.
Sub DeleteRowsAll()
Dim iRow As Long
Dim Rng As Range
Application.ScreenUpdating = False
Rows(1).Insert
Range("E1").Value = "rabbitohs"
With ActiveSheet
.UsedRange
iRow = .Cells.SpecialCells(xlCellTypeLastCell).Row
Set Rng = Range("E1", Cells(iRow, "E"))
Rng.AutoFilter Field:=1, Criteria1:=""
Set Rng2 = Range("E2", Cells(iRow, "E"))
Rng2.SpecialCells(xlCellTypeVisible).EntireRow.Delete
.UsedRange
End With
End Sub
Sub DeleteRowsAll()
Dim LastRow As Long
Dim CellValue As String
LastRow = Worksheets("HP Service Manager").Cells(Rows.Count, "E").End(xlUp).Row
For i = LastRow To 2 Step -1
CellValue = Worksheets("HP Service Manager").Cells(i, "E").Value
If CellValue = "" Then
Worksheets("HP Service Manager").Rows(i).Delete
End If
Next i
End Sub

How can I repeat code through entire data?

I have written a few lines of code that work like I want them too but I don't know how to repeat it through all rows of my data.
This probably seems like a rather simple thing but since I started VBA just a few days ago I struggle with this line of code
If I continue with ActiveCell.Offset(-1,-4) after my code it's a bug and I don't know how to repeat the code through all rows.
Sub SelectRowsWithNoBlanks()
Range("A2").Select
If ActiveCell.Offset(0, 0).Value <> "" And ActiveCell.Offset(0, 1) <> "" And ActiveCell(0, 1) <> "" And ActiveCell(0, 1) <> "" Then
Range(ActiveCell, Cells(ActiveCell.Row, ActiveCell.Column + 4)).Select
End If
End Sub
#SiddharthRout As I don't have Access to the data yet I can't tell. But I thought extending the code for more columns later on wouldn't be a problem. So in the code I have written now I was checking for the columns A-D but I thought I could easily add the "checking" for more columns if needed – Anna von Blohn 43 secs ago
In that case, here is a sample code.
Logic
As #Pᴇʜ mentioned avoid the use of .Select. Work with the objects.
Find the last row and loop through the rows. To find the last you you may want to see This
One way (which I am using) is to count the number of cells which are filled using Application.WorksheetFunction.CountA. So if it is columns A to D then there should be 4 cells to be filled to consider the "row" as filled. Similarly for Cols A to E, there should be 5 cells to be filled to consider the "row" as filled as so on.
Code
I have commented the code. So if you have a problem understanding it, let me know.
Option Explicit
Sub SelectRowsWithNoBlanks()
Dim ws As Worksheet
Dim lRow As Long, i As Long
Dim myRange As Range, rng As Range
'~~> Change this to the relevant sheet
Set ws = Sheet1
With ws
'~~> Find the last row in Col A
lRow = .Range("A" & .Rows.Count).End(xlUp).Row
'~~> Loop through the rows
For i = 2 To lRow
'~~> Change this as applicable
Set rng = .Range("A" & i & ":D" & i)
'~~> Check if the range is completely filled
If Application.WorksheetFunction.CountA(rng) = rng.Columns.Count Then
'~~> Store the range in a range object
If myRange Is Nothing Then
Set myRange = rng
Else
Set myRange = Union(myRange, rng)
End If
End If
Next i
End With
'If Not myRange Is Nothing Then Debug.Print myRange.Address
'~~> Check if any filled rows were found
If Not myRange Is Nothing Then
With myRange
'
'~~> Do what you want with the range
'
End With
Else
MsgBox "No filled rows were found"
End If
End Sub

When a specific word is found, delete that row AND the 2 rows under. Is this possible with VBA?

As the photo shows, all my data is on ONE column. The "trigger word" is "Past Car" and want that entire row PLUS the two rows under it deleted.
So according to the photo below rows 5,6,7 and 18,19,20 and 26,27,28 would be deleted.
Is this possible with VBA? I've tried using search functions and some VBA techniques but got overwhelmed.
Screenshot
I would suggest to do it like that
Option Explicit
Sub DelIt()
Const PAST_CAR = "Past Car"
Const OFF_SET = 3
Dim lastRow As Long, i As Long
Dim ws As Worksheet
Dim deleteRange As Range
Set ws = ActiveSheet
lastRow = ws.Cells(Rows.Count, "A").End(xlUp).Row
With ws
For i = 1 To lastRow
If .Cells(i, 1).Value = PAST_CAR Then
If deleteRange Is Nothing Then
Set deleteRange = .Rows(i).Resize(OFF_SET)
Else
Set deleteRange = Union(deleteRange, .Rows(i).Resize(OFF_SET))
End If
End If
Next i
End With
If Not (deleteRange Is Nothing) Then
deleteRange.EntireRow.Delete
End If
End Sub
In this way you do not need to loop backwards or turn of ScreenUpdatings as you only have one "write" access to the sheet.
You must loop through the cells in column A in reverse order and check if the cell content is Past Car and if so, delete the rows accordingly.
You may try something like this...
Sub DeleteRows()
Dim lr As Long, i As Long
Application.ScreenUpdating = False
lr = Cells(Rows.Count, "A").End(xlUp).Row
For i = lr To 1 Step -1
If Cells(i, 1) = "Past Car" Then
Range("A" & i).Resize(3).EntireRow.Delete
End If
Next i
Application.ScreenUpdating = True
End Sub

Hiding row if cell equals next visible cell

I am trying to write a macro that hides the row if the cell value equals the next visible cell in that column and loops through the whole column. I have read that SpecialCells(xlCellTypeVisible) only works up to 8192 cells and my spreadsheet has 15,000 rows.
I have tried something like this but want to restrict it to only visible cells
Sub Test()
For i = 7 To 15258
If Range("P" & i).Value = Range("P" & i + 1).Value Then
Rows(i).Hidden = True
End If
Next i
End Sub
I have tried to search for a solution but haven't been able to find one yet.
Thanks!
I'd be surprised if this couldn't be optimized just a little bit, but it will work for what you are needing.
You can follow the comments within the code itself to kind of get a sense of what it's doing, but in a nutshell, you are using a For...Next statement to loop through your visible cells. For each visible cell, you will search for the next visible cell and then check to see if that matches. If it does, you add that cell to a special range that tracks all the rows to hide at the end of the code, then hide it.
Sub Test()
Dim ws As Worksheet, lookupRng As Range, rng As Range, lstRow As Long
Set ws = ThisWorkbook.Worksheets(1)
lstRow = 15258
Set lookupRng = ws.Range("P7:P" & lstRow)
Dim rngToHide As Range, i As Long
For Each rng In lookupRng.SpecialCells(xlCellTypeVisible)
Application.StatusBar = "Checking row " & rng.Row & " for matches."
For i = rng.Row + 1 To lstRow 'Loop through rows after rng
If Not ws.Rows(i).Hidden Then 'Check if row is hidden
If rng.Value = ws.Cells(i, "P") Then 'check if the non-hidden row matches
If rngToHide Is Nothing Then 'Add to special range to hide cells
Set rngToHide = ws.Cells(i, "P")
Else
Set rngToHide = Union(rngToHide, ws.Cells(i, "P"))
End If
End If
Exit For 'Exit the second For statement
End If
Next i
Next rng
Application.StatusBar = "Hiding duplicate rows"
If Not rngToHide Is Nothing Then rngToHide.EntireRow.Hidden = True
Application.StatusBar = False
End Sub

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