If second two characters equal this then that - excel

Question

I have a string of letters and numbers, where if the second two characters of the string equal a certain value, then a location value should be shown in the corresponding column.
I have used the MID function to essentially extract the characters of the string that I want to use MID(A2,2,2) but now I can't figure out how to compare what is returned to a list of options that those two characters could be without typing in each option in an extremely long formula.
Here are possible strings that are situated in a column:
3PH356969
MSFFACEBUS
MBH0007398
MBH0007402
I am extracting the second two characters of these, to compare to a list similar to this
PH
SF
BH
PG
HR
These values then correspond to location (below), which would optimally be returned:
Philadelphia
Bay Area
Birmingham
Western PA
Hartford
I can write =IF(MID(A2,2,2)="PH","Philadelphia",else...) but then the else-ifs will go on for 76 more 2-character strings to compare against. I'm hoping there is a more optimal way for this.
Expected results should be the location corresponding to the string, or just "error" displayed.

Answer 1

Basically we need to use a lookup/reference table, but instead of a much more common VLOOKUP function we can use a much faster INDEX + MATCH combo.
Formula in B1:
=INDEX($E$1:$E$6,MATCH(MID(A1,2,2),$D$1:$D$6;0))

Answer 2

I would use a VLOOKUP, personally. Although it would require a separate lookup table, just feed your MID result as the VLOOKUP key. Then you could easily add/remove locations, and there will be an #N/A error if the key's not there.

Answer 3

If you don't want a separate lookup table, you may try it this way:
=IFERROR(INDEX({"Philadelphia","Bay Area","Birmingham","Western PA","Hartford"},MATCH(MID(A2,2,2),{"PH","SF","BH","PG","HR"},0)),"Not found")