Create 2 publicIPs and assign to nics - azure

Question

I am trying to create 2 public ips and then assign one each to nics
for($i=1; $i -lt 3; $i++)
{
New-AzPublicIpAddress -Name "publicIP$i" -ResourceGroupName $resourceGroup.ResourceGroupName -Location $location -AllocationMethod Dynamic
New-AzNetworkInterface -Name "nic$i" -ResourceGroupName $resourcegroup.ResourceGroupName -Location $location -SubnetId $vnet.subnets[0].Id -PublicIpAddressId "publicIP$i.Id" -NetworkSecurityGroupId $nsg.Id
}
I want to assign the output of new-azPublicIpAddress to a variable and then use that variable's id to assign to -pulicIpAddressId.
like this $pip$i = New-AzPublicIpAddress -Name "publicIP$i" -ResourceGroupName $resourceGroup.ResourceGroupName -Location $location -AllocationMethod Dynamic but this does not work

Answer 1

You cannot set a variable with a '$' inside it.
The following is a correct sample.
$pip = New-AzPublicIpAddress -Name "publicIP$i" -ResourceGroupName $resourceGroup.ResourceGroupName -Location $location -AllocationMethod Dynamic
Considering your requirement, I suggest you use an array:
$pipArr = New-Object 'Object[]' 2;
$nicArr = New-Object 'Object[]' 2;
for($i=0; $i -lt 2; $i++)
{
$pipArr[$i] = New-AzPublicIpAddress -Name "publicIP$i" -ResourceGroupName $resourceGroup.ResourceGroupName -Location $location -AllocationMethod Dynamic
$nicArr[$i] = New-AzNetworkInterface -Name "nic$i" -ResourceGroupName $resourcegroup.ResourceGroupName -Location $location -SubnetId $vnet.subnets[0].Id -PublicIpAddressId $pipArr[$i].Id -NetworkSecurityGroupId $nsg.Id
}
In this way, you can get your first public IP with "$pipArr[0]". As it is an array, you can use index with it.

Answer 2

As Jack requested, here's another way of doing the same is the following:
Set-Variable "pip$i" -Value (New-AzPublicIpAddress -Name "publicIP$i" -ResourceGroupName $resourceGroup.ResourceGroupName -Location $location -AllocationMethod Dynamic)
then you can use Get-Variable to get data from the variable:
Get-Variable "pip$i" | Select -ExpandProperty Value
If you just want to have $ inside the variable you can do this:
${pip$i} = something
this will instanciate new variable with the name pip$i, and you could retrieve it similarly as well:
Do-something -Input ${pip$i}