I want to find the highest number using import re .txt - python-3.x

Question

I want to be able to just search for all digits in a text file and find the max number, using the re module. Where do I need to edit my code to accomplish this goal?
The random.txt looks somthing like the following:
Datq15UxkNwMN5zUQhd46J8WeF9RjAq214TlJiQ8EkZvmdOpmBOdd365mICKC67GGvqwbLqV2Gox3n3E5WC1Vq8C22lZ6sL3Ip24untQyw46g2219WlA07GP30PNvc8o3hCb2d283l68mh86RH6gDNbN7kIXmdO4a84hUz73905o3BlR71YCQF985JTz54FRoN32pM8N23YcYd7jv9Ys575UzaH9RZ7sosMdeqnTgnVt0bH99b2P5ilvJ33QaJ6G76VU8vPN
import re
with open('content.txt', 'r',) as f:
contents = f.read()
number = 0
pattern = re.compile(r'\d')
matches = pattern.finditer('content.txt')
for match in matches:
n = int(match)
if saved <= n:
number = int(match)
print(number)
the file just ran once and gave me the answer 0

Answer 1

Try this,
import re
with open('file1.txt', 'r') as f:
data = f.read()
list_of_numbers = re.findall(r'(?:[\d]+)',data)
list_of_numbers = map(int, list_of_numbers)
print(max(list_of_numbers))
Output:
73905 # max number
your list_of_numbers look like this
['15', '5', '46', '8', '9', '214', '8', '365', '67', '2', '3', '3', '5', '1',
'8', '22', '6', '3', '24', '46', '2219', '07', '30', '8', '3', '2', '283', '68',
'86', '6', '7', '4', '84', '73905', '3', '71', '985', '54', '32', '8', '23', '7',
'9', '575', '9', '7', '0', '99', '2', '5', '33', '6', '76', '8']

Answer 2

You are looking for matches within "content.txt" string so there is no match. Also a MatchObject can't be converted to int:
import re
with open('content.txt', 'r',) as f:
contents = f.read()
number = 0
pattern = re.compile(r'\d+')
matches = pattern.finditer(contents)
for match in matches:
n = int(match.group(0))
if number <= n:
number = int(match.group(0))
print(number)