http://localhost:55201/SERVICES/customers/CALLME
how to make this link using #Html.ActionLink
Services is RouteArea, Customers is RoutePrefix and Customer is Controller
#Html.ActionLink("Click me", "CallMe",new { area = "Services"})
is this code right? its returning blank anchor.
[RouteArea("Services")]
[RoutePrefix("Customers")]
public class CustomerController : Controller
{
[Route("~/Test")]
public ActionResult Index()
{
ViewBag.Controller = "Customer";
ViewBag.Action = "Index";
return View("ActionName");
}
[Route("CallMe")]
public string CallMeFunction()
{
return string.Format("CallMeFunction() invoked");
}
}
Related
In razor engine way, I can define a BaseRazorPage for all razor views
public abstract class BaseRazorPage<TModel> : RazorPage<TModel>
{
protected BaseRazorPage()
{
}
protected virtual string L(string name)
{
return XXX.Localization.L.Text[name];
}
......
}
Use it in _viewImports.cshtml
#inherits BaseRazorPage<TModel>
Then I can use the L function to do mutiple language in views:
#L("Hello word!")
How can I implement same function in Razor page way? Or is there an alternative way to do this?
The razor page can't inherits any class.
A simple solution would be to create an extension for the PageModel class.
public static class PageModelExtensions
{
public static string L(this PageModel pageModel, string name)
{
// return a new value. put your logic here
return name + "_result";
}
}
Now we can use the L method as a member function.
public class IndexModel : PageModel
{
public void OnGet()
{
string value = this.L("test");
}
}
Or we can use the L method in the view like this
#page
#model IndexModel
#{
ViewData["Title"] = "Home page";
}
<div class="text-center">
<h1 class="display-4">Welcome</h1>
<p>#Model.L("test")</p>
</div>
I hope this helps.
UPDATE
If you want to have a base class with your common methods the following example is what you want.
public class MyPageModel : PageModel
{
public string L(string name)
{
return "sample";
}
}
And your razor page class will look like this.
public class IndexModel : MyPageModel
{
public void OnGet()
{
string value = this.L("test");
}
}
In case you want to inject an object in your base class then you base class should look like this.
public class MyPageModel : PageModel
{
private readonly ApplicationDbContext context;
public MyPageModel(ApplicationDbContext context)
{
this.context = context;
}
public string L(string name)
{
return "sample";
}
}
And the Razor page will look like this
public class IndexModel : MyPageModel
{
private readonly ApplicationDbContext context;
public IndexModel(ApplicationDbContext context)
: base(context)
{
this.context = context;
}
public void OnGet()
{
string value = this.L("test");
}
}
does anyone know how tell the child controller to load base (parent) controller view instead of looking for it in it's own folder?
public class BaseController : Controller
{
public virtual ActionResult Test()
{
return View("Test");
}
}
public class ChildController:BaseController
{
public override ActionResult Test()
{
return base.Test();
}
And the Error is The view 'Test' was not found or no view engine supports the searched locations. The following locations were searched:
~/Views/Child/Test.cshtml.....
So the solution that I found yeat is to make parent action looks like this
public class BaseController : Controller
{
public virtual ActionResult Test()
{
return View("~Views/Base/Test.cshtml");
}
}
Is there any better solution ?
private const string ViewPath = "~/Views/{0}/{1}.cshtml";
private ViewResult GetView(string action, object model = null)
{
var controllerName = ControllerContext.RouteData.Values["controller"].ToString();
var path = string.Format(ViewPath, controllerName, action);
return
new ViewResult
{
ViewName = path
};
}
What I'm trying to do is create a site in Orchard that doesn't have a way for a user to register. An administrator will create the users.
What I have is module that defines the parts, records, views, etc. That is basically working.
Now what I'm trying to do is add a UserPart (from Orchard.Users) to one of the parts in my module.
I'm not sure how to do that. I need the fields displayed for the UserPart with the fields for the parent part in the same view. This also needs to be done in a way that when a save happens, all of the UserPart fields get sent to the Orchard.Users module.
Any suggestions, pointers or links on how to do that?
Thanks!
UPDATE...
The Activating Filter is an interesting idea. I initially chose the migration route. For now, I'll try and get that method working.
For simplicity, let's say I have a "Company" type (there's more to the actual type) that has a "CompanyName" and a UserPart.
Here's what the different pieces look like...
Migrations.cs (simplified)
public int Create()
{
SchemaBuilder.CreateTable("CompanyPartRecord", table => table.ContentPartRecord()
.Column("CompanyName", DbType.AnsiString, c => c.WithLength(50))
.Column("UserId", DbType.Int32));
SchemaBuilder.CreateForeignKey("FK_CompanyPartRecord_UserPartRecord", "CompanyPartRecord", new[] {"UserId" }, "Orchard.Users", "UserPartRecord", new[] { "Id" })
ContentDefinitionManager.AlterTypeDefinition("Company", type => type.WithPart("CommonPart").WithPart("UserPart"));
}
CompanyPartRecord
public class CompanyPartRecord : ContentPartRecord
{
public virtual string CompanyName { get; set; }
public virtual int? UserId { get; set; }
}
CompanyPart
public class CompanyPart : ContentPart<CompanyPartRecord>
{
internal LazyField<UserPart> UserPartField = new LazyField<UserPart>();
public string CompanyName
{
get { return Record.CompanyName; }
set { Record.CompanyName = value; }
}
public UserPart User
{
get { return UserPartField.Value;}
set { UserPartField.Value = value; }
}
}
Handler
public class CompanyPartHandler : ContentHandler
{
private readonly IContentManager _manager;
public CompanyPartHandler(IRepository<CompanyPartRecord> repository, IContentManager manager)
{
_manager = manager;
Filters.Add(StorageFilter.For(repository));
OnActivated<CompanyPart>(OnActivatedHandler);
}
private void OnActivatedHandler(ActivatedContentContext context, CompanyPart part)
{
if(part.User == null)
{
part.User = _manager.Create<UserPart>("User");
}
else
{
part.User = _manager.Get<UserPart>(part.User.Id);
}
}
}
Driver
public class CompanyPartDriver : ContentPartDriver<CompanyPart>
{
protected override DriverResult Editor(CompanyPart part, dynamic shapeHelper)
{
return ContentShape("Parts_Company_Edit", () => shapeHelper.EditorTemplate(TemplateName: "Parts/Company",
Model: part, Prefix: Prefix));
}
protected override DriverResult Editor(CompanyPart part, IUpdateModel updater, dynamic shapeHelper)
{
updater.TryUpdateModel(part, Prefix, null, null);
return Editor(part, shapeHelper);
}
}
Controller
public class AdminCompanyController : Controller, IUpdateModel
{
private readonly IOrchardServices _services;
private readonly INotifier _notifier;
private readonly IContentManager _contentManager;
private readonly ITransactionManager _transactionManager;
private readonly Localizer T = NullLocalizer.Instance;
public AdminCompanyController(IOrchardServices services)
{
_services = services;
_notifier = services.Notifier;
_contentManager = services.ContentManager;
_transactionManager = services.TransactionManager;
}
public ActionResult Create()
{
var company = _contentManager.New<CompanyPart>("Company");
var model = _contentManager.BuildEditor(company);
return View(model);
}
[HttpPost, ActionName("Create")]
public ActionResult CreatePOST()
{
var contentItem = _contentManager.New<CompanyPart>("Company");
var model = _contentManager.UpdateEditor(contentItem, this);
if (!ModelState.IsValid)
{
_transactionManager.Cancel();
return View(model);
}
_contentManager.Create(contentItem.ContentItem);
_notifier.Information(T("Company has been saved"));
return RedirectToAction("Index");
}
public ActionResult Edit(int Id)
{
var contentItem = _services.ContentManager.Get(Id);
dynamic model = _services.ContentManager.BuildEditor(contentItem);
return View(model);
}
[HttpPost, ActionName("Edit")]
public ActionResult EditPOST(int Id)
{
var contentItem = _contentManager.Get<CompanyPart>(Id);
var model = _contentManager.UpdateEditor(contentItem, this);
_notifier.Information(T("Company has been saved"));
return RedirectToAction("Index");
}
public ActionResult Delete(int Id)
{
var contentItem = _contentManager.Get<CompanyPart>(Id);
_contentManager.Destroy(contentItem.ContentItem);
return RedirectToAction("Index");
}
bool IUpdateModel.TryUpdateModel<TModel>(TModel model, string prefix, string[] includeProperties, string[] excludeProperties)
{
return TryUpdateModel(model, prefix, includeProperties, excludeProperties);
}
public void AddModelError(string key, LocalizedString errorMessage)
{
ModelState.AddModelError(key, errorMessage.ToString());
}
}
View (create)
#{ Layout.Title = T("Add Company").ToString(); }
#using (Html.BeginFormAntiForgeryPost())
{
#Display(Model)
}
Editor Template
#model SDS.Models.CompanyPart
<fieldset>
#Html.LabelFor(m => m.CompanyName)
#Html.TextBoxFor(m => m.CompanyName)
</fieldset>
#*
What goes here to display UserPart?
*#
So here's where I'm at. I can see the ContentItem (CompanyType). I can put in the name and save it. The name is getting saved to the db. Right now the UserPart is getting saved to the db, but all of the fields are blank.
The part I'm stuck on is what to put in the editor template to display the UserPart fields so that the values get to the UserPart driver and ultimately the db.
Any ideas on how to do that?
Thanks!
So you don't attach parts to parts, you attach parts to content items, and you can do that in multiple ways.
You can do it through the admin screen, but that isn't a code driven solution and would have problems if you have multiple environments or need to redeploy a fresh version of code.
You can attach the part when you create a new content item in the migration. This might be a good solution, if you already ran your migration you could possibly do it with an update migration. This allows the part to be managed through the admin screen, but has downsides because it can be removed and if you have code that relies on the part then you will start having errors.
The last way and best way is to attach the part dynamically using an Activating Filter.
ActivatingFilter class - Attaches a part to a content type from code. As opposed to attaching parts via migrations, parts attached using this filter will neither be displayed in the Dashboard, nor users will be able to remove them from types. It's a legitimate way of attaching parts that should always exist on a given content type.
So to do this:
1. Add a reference to Orchard.Users to your custom project.
2. Create a handler for you part. Such as MyPartHandler
3. Then add the activating handler like so
Filters.Add(ActivatingFilter.For<UserPart>("MyContentType"));
So now anywhere in your code you can access the UserPart if you already have your part, or the content item using
var userPart = myPart.As<UserPart>();
I'm an Orchard newbie and I'm having difficulty trying to get the form data when a new item is created.
What I have is a module that creates a menu item on the admin dashboard. That menu item will load a page where a user can enter a new "Coach".
There are 3 things needed for a coach, first name, last name and email.
Here's the code I have implemented for this...
migrations.cs
public class SDSDataMigration : DataMigrationImpl
{
public int Create()
{
SchemaBuilder..CreateTable("CoachPartRecord", table => table.ContentPartRecord()
.Column("FirstName", DbType.AnsiString, c => c.WithLength(50))
.Column("LastName", DbType.AnsiString, c => c.WithLength(50))
.Column("Email", DbType.AnsiString, c => c.WithLength(200)))
ContentDefinitionManager.AlterPartDefinition("CoachPart", part => part
.WithField("FirstName", f => f.OfType("TextField"))
.WithField("LastName", f => f.OfType("TextField"))
.WithField("Email", f => f.OfType("TextField"))
);
ContentDefinitionManager.AlterTypeDefinition("Coach", type => type.WithPart("CommonPart")
.WithPart("CoachPart"));
return 1;
}
}
parts/records
public class CoachPartRecord : ContentPartRecord
{
public virtual string FirstName { get; set; }
public virtual string LastName { get; set; }
public virtual string Email { get; set; }
}
public class CoachPart : ContentPart<CoachPartRecord>
{
public string FirstName
{
get { return Record.FirstName; }
set { Record.FirstName = value; }
}
public string LastName
{
get { return Record.LastName; }
set { Record.LastName = value; }
}
public string Email
{
get { return Record.Email; }
set { Record.Email = value; }
}
}
view for creating editor
#{ Layout.Title = T("Add Coach").ToString(); }
#using (Html.BeginFormAntiForgeryPost()) {
// Model is a Shape, calling Display() so that it is rendered using the most specific template for its Shape type
#Display(Model)
}
handler
public class CoachPartHandler : ContentHandler
{
public CoachPartHandler(IRepository<CoachPartRecord> repository)
{
Filters.Add(StorageFilter.For(repository));
}
}
driver
protected override DriverResult Editor(CoachPart part, IUpdateModel updater, dynamic shapeHelper)
{
updater.TryUpdateModel(part, Prefix, null, null);
return Editor(part, shapeHelper);
}
controller (for dashboard menu item)
public ActionResult Create()
{
var coach = _services.ContentManager.New("Coach");
var model = _services.ContentManager.BuildEditor(coach);
return View(model);
}
[HttpPost, ActionName("Create")]
public ActionResult CreatePOST()
{
var contentItem = _services.ContentManager.New("Coach");
_services.ContentManager.Publish(contentItem);
return View("Index");
}
Right now I can get the form to appear to create a new coach. When I hit "Publish" all of the fields (i.e. FirstName, LastName, Email) for the CoachPart parameter in the driver are null.
I can look at the http request and I can see the values I put on the form, but they're not making it to the CoachPart.
Any ideas why the CoachPart fields aren't getting filed in?
Thanks!
First of all, you are defining the properties on your own record. Therefore you don't need new textfields attached to your part, so you should remove this:
ContentDefinitionManager.AlterPartDefinition("CoachPart", part => part
.WithField("FirstName", f => f.OfType("TextField"))
.WithField("LastName", f => f.OfType("TextField"))
.WithField("Email", f => f.OfType("TextField")));
Secondly, because you use your custom controller istead of orchard's content controller, you must implement the IUpdateModel and act on it:
[Admin]
public class MyController : Controller, IUpdateModel {
private readonly IContentManager _contentManager;
private readonly ITransactionManager _transactionManager;
public MyController(IContentManager contentManager,
ITransactionManager transactionManager) {
_contentManager = contentManager;
_transactionManager = transactionManager;
}
[HttpPost, ActionName("Create")]
public ActionResult CreatePOST()
{
var contentItem = _contentManager.New<CoachPart>("Coach");
// The implementation of IUpdateModel is necessary for this next line:
var model = _contentManager.UpdateEditor(contentItem, this);
if (!ModelState.IsValid) {
_transactionManager.Cancel();
return View(model);
}
_contentManager.Publish(contentItem);
return View("Index");
}
bool IUpdateModel.TryUpdateModel<TModel>(TModel model, string prefix, string[] includeProperties, string[] excludeProperties) {
return TryUpdateModel(model, prefix, includeProperties, excludeProperties);
}
void IUpdateModel.AddModelError(string key, LocalizedString errorMessage) {
ModelState.AddModelError(key, errorMessage.ToString());
}
}
I am using visual studio 2013 and created a default mvc project.In home controller I have modified the below
[RoutePrefix("home")]
[Route("{action=index}")]
public class HomeController : Controller
{
public ActionResult Index()
{
return View();
}
//[Route("Home/About")]
public ActionResult About()
{
ViewBag.Message = "Your application description page.";
return View();
}
public ActionResult Contact()
{
ViewBag.Message = "Your contact page.";
return View();
}
}
In RouteConfig.cs I have done the following modification
public class RouteConfig
{
public static void RegisterRoutes(RouteCollection routes)
{
routes.IgnoreRoute("{resource}.axd/{*pathInfo}");
routes.MapMvcAttributeRoutes();
//routes.MapRoute(
// name: "Default",
// url: "{controller}/{action}/{id}",
// defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }
//);
}
}
This is not working.But when I go for convention based routing it is working. Plz help me.
to make a web api create a WebApiConfig.cs :
public static class WebApiConfig
{
public static void Register(HttpConfiguration config)
{
config.MapHttpAttributeRoutes();
}
}
}
in your global.asax :
GlobalConfiguration.Configure(WebApiConfig.Register);
and then you can define controller :
[RoutePrefix("home")]
public class HomeController : ApiController
{
[Route("action")]
public string myaction()
{
return "hello world";
}
}
this way the route /home/action will send back the defined string
now the big difference between WebApi and MVC is that you dont use your server side to Template and provide views, it is mainly used for REST actions: GET PUT POST DELETE
I don't know what you want to achieve but I hope this will be usefull
Edit:
I was thinking maybe you forgot to register your MVC routes in global.asax there should be a similar call to make like:
GlobalConfiguration.Configure(RegisterRoutes.routes);
something like that
and in your code try to change :
[RoutePrefix("Home")]
public class HomeController : Controller
{
[Route("Index")]
public ActionResult Index()
{
return View();
}
[Route("About")]
public ActionResult About()
{
ViewBag.Message = "Your application description page.";
return View();
}
public ActionResult Contact()
{
ViewBag.Message = "Your contact page.";
return View();
}
}
and routes should be /Home/Index and /Home/About