I'm trying to make a login for a text-based OS in Python
I have tried to import time and time.sleep but it still doesn't work.
import time
usrname = str(input("What Is Your Username? "))
age = str(input("What Is You Age"))
print("Welcome",usrname)
if age <= 1:
print ("That`s An Invalid Age!")
time.sleep(3)
I don't see any errors because it's so fast it closes in 1/2 a second.
The condition if age <= 1: is never going to be triggered, because age is a string. As a result, the time.sleep() statement within the if block is never going to run.
In order for the conditional to work, you need to make age an int (perhaps by doing if int(age) <= 1:).
Related
I am intending to end a script right after an "if" logic, when the logic returns a "true" result. Here it is:
age=int(input("Enter your age: "))
if age<=18:
print("You are not an adult. Please exit.")
exit() **#here is where I need the code to terminate and exit.**
else:
print("Your age is: ", age)
from datetime import date
print("This is the year ",date.today().year)
yr = date.today().year
yob=yr-age
print("You were born in the year: ",yob)
What would be the most appropriate command to terminate the sequence if the first "if" logic returns "true" i.e. if the age is below 18, the script should terminate. Many thanks in advance.
There can be many ways to end the script. It's tough to say what you want to achieve, without sharing any code here. But still in general you can try this-
1- Use pass keywords
2- if you are using loop, you can use break keyword
3- if you are using a function, just return nothing if the condition is not true.
4- you can also use 'try and except' block
5- You can use while loop
I've implemented a memory game where the user has to sort numbers in his head while a timer of 5 sec is running.
Please see code below:
from random import randint
from threading import Timer
def timeout():
print("Time over\n#####################\n")
while True:
list = []
for i in range(5):
list.append(randint(1000, 10000))
t = Timer(5, timeout)
t.start()
print(list)
print('[ 1 , 2 , 3 , 4 , 5 ]')
solution = sorted(list)[2]
print('please select the 3rd largest number in this row (1-5):')
input_string = input()
selection = int(input_string)
if solution == list[selection - 1]:
print("Your guess is correct\n")
else:
print("Your guess is wrong\n")
t.join()
Here is the game interaction itself (please ignore the syntax highlighting):
USER#HOST:~/$ python3 memory_game.py
[8902, 8655, 1680, 6763, 4489]
[ 1 , 2 , 3 , 4 , 5 ]
please select the 3rd largest number in this row (1-5):
4
Your guess is correct
Time over
#####################
[5635, 3810, 1114, 5042, 1481]
[ 1 , 2 , 3 , 4 , 5 ]
please select the 3rd largest number in this row (1-5):
4
Your guess is wrong
Time over
#####################
[6111, 1430, 7999, 3352, 2742]
[ 1 , 2 , 3 , 4 , 5 ]
please select the 3rd largest number in this row (1-5):
23
Traceback (most recent call last):
File "memory_game.py", line 24, in <module>
if solution == list[selection - 1]:
IndexError: list index out of range
Time over
#####################
Can anybody help me with these things:
1. 'Time over' should only be written if the player needs more than 5 sec for the answer. If the player solves it in time the next challenge should appear silently.
2. If the player does not write any guess and presses 'Enter' the program terminates with error message:
Traceback (most recent call last):
File "memory_game.py", line 22, in
selection = int(input_string)
ValueError: invalid literal for int with base 10:''
3. If the player enters any random number the program quits with an 'Index out of range error' - I couldn't find out where to put try: except:
Any help would be appreciated - Thanks!
As for your questions:
You can accomplish that with t.cancel() (stop the timer and do not call the function) instead of t.join() (wait until the thread has finished; this will ALWAYS result in a timeout, of course)
(and 3.) These are basically the same -- put the query message and all input handling into a while loop, and break out of it once you know that the input is valid
...
As an extra, the "time over" message wasn't really doing anything useful (e.g. you could still enter a valid answer after the time over occurred. I "fixed" that in a brute force way by making the program exit if the timeout is hit. Instead of doing that, you can also use a global variable to store whether the timeout was hit or not and handle that in your input accordingly (make sure to make it threadsafe using e.g. a mutex).
In general, it might be easier to turn around the structure of the program -- let the main thread handle the timeout and verification of the input, let the thread only handle the input (this way, it's easy to kill the thread to stop the input from being handled).
Of course, using the select module, one could implement this even nicer without threads (have one pipe that gets written to by a thread/timer, and the standard input, then select both for reading and it will block until either user input or the timeout occurs).
And maybe someone will post a nice asyncio-based solution? ;)
Here's the modified solution (modifying only as little as possible to get it to work, one could refactor other parts to make it nicer in general):
import random
import threading
import os
def timeout():
print("Time over\n#####################\n")
# You can't use sys.exit() here, as this code is running in a thread
# See also: https://stackoverflow.com/a/905224/1047040
os._exit(0)
while True:
list = []
for i in range(5):
list.append(random.randint(1000, 10000))
t = threading.Timer(5, timeout)
t.start()
print(list)
print('[ 1 , 2 , 3 , 4 , 5 ]')
solution = sorted(list)[2]
while True:
try:
print('please select the 3rd largest number in this row (1-5):')
input_string = input()
selection = int(input_string)
chosen = list[selection - 1]
# If we arrive here, the input was valid, break out of the loop
break
except Exception as e:
# Tell the user that the input is wrong; feel free to remove "e"
# from the print output
print('Invalid input:', e)
if solution == chosen:
print("Your guess is correct\n")
else:
print("Your guess is wrong\n")
# Make sure to cancel the thread, otherwise guessing correct or wrong
# will block the CLI interface and still write "time out" at the end
t.cancel()
So I have been searching the Internet trying to figure out what I am doing wrong here. Basically, I want to create a script that will prompt the user to enter a number, then perform the ctrl-v paste operation that many times. I have tried variation upon variation of the below, but it is just not working.
The commands work fine outside the loop, but the moment I try to loop it, the program just crashes. I am probably missing something obvious, but I have been trying to find that something for the last 2 hours without any luck. Any help is appreciated.
import time
import pyautogui
x = input()
time.sleep(5) #delays the next process by 5 seconds
def work():
global x
pyautogui.hotkey('ctrl','v')
time.sleep(.25)
pyautogui.press('enter')
time.sleep(.25)
x = x - 1
try:
while x > 0:
work()
else:
pass
except KeyboardInterrupt:
pass
OK i figured this out. x > 0 was the problem. As the code stands now x is a string and you can't compare a string to an integer.
So what i did was add this after the user input
x = int(x)
Now it works perfectly. If i had run the program from the command window i would have found this problem hours ago. I will know better for next time.
Okay, trying to make a simple game of Guessing Numbers but I can't find the mistake in this code. Still pretty new to python so probably the reason why but I can't figure out what is wrong with it.
import random
from time import sleep
def start():
print("Welcome To The Guessing Game \n Try to guess the number I'm thinking of \n Good luck!")
selectRandomNumber()
guessCheck(number, numberInput=1)
def restart():
print("Creating new number ...")
sleep(1)
print("OK")
selectRandomNumber()
guessCheck(number,numberInput=1)
def selectRandomNumber():
number = random.randint(0,1000)
tries = 0
return
def tryAgain():
while True:
try:
again = int(input("Do you want to play again? y/n:"))
except ValueError:
print("Couldn't understand what you tried to say")
continue
if again == "y" or "yes":
print("Awesome! Lets go")
restart()
elif again == 'n' or "no":
print("Goodbye!")
break
else:
print("Not a valid option")
continue
def guessCheck(number,numberInput=1):
while True:
try:
numberInput = int(input("What number do you think it is?: "))
except ValueError:
print("Couldn't understand that. Try again")
continue
if numberInput > number:
print("Too high")
tries += 1
continue
elif numberInput < number:
print("Too low")
tries += 1
continue
elif numberInput == number:
print("Congrats! You got my number")
tryAgain()
number = selectRandomNumber()
print(number)
start()
Every time I try to run the program I keep getting the same mistake.
It tells me:
Traceback (most recent call last):
File "python", line 60, in <module>
start()
File "python", line 8, in start
guessCheck(number, numberInput)
NameError: name 'number' is not defined
Don't quite understand what that means.
Some help would be appreciated. Thanks!
* UPDATE *
Was able to fix the part about defining the variable but now new problem happened where when I try to run
Same code as before but added
guessCheck(number,numberInput=1)
and also added the variable number at the end
number = selectRandomNumber()
print(number)
start()
when I run it I get this
None # this is from `print(number)` so instead of getting a number here I'm getting `None`
Welcome To The Guessing Game
Try to guess the number I'm thinking of
Good luck!
What number do you think it is?:
The Traceback is telling you this:
We got to start().
start() called guessCheck().
We tried to pass two pieces of information to guessCheck(): the variable names number and numberInput.
We don't have those variables defined yet! numberInput doesn't get defined until once we've already started guessCheck(), and number isn't actually defined anywhere.
As Manoj pointed out in the comments, you probably want number to hold the output of selectRandomNumber(). So, instead of just calling selectRandomNumber() in start(), try number = selectRandomNumber() instead.
You can add a print(number) on the line right after that to make sure number has a value assigned to it.
Now number has a value, going into your call to guessCheck(). That still leaves numberInput undefined though. You can set a default value for function arguments like this:
guessCheck(number, numberInput=1)
That way, when guessCheck is called but numberInput hasn't been defined yet, it will automatically give it the value 1 until you set it explicitly.
You may encounter other issues with your code the way it is. My advice would be to start really simply - build up your game from each individual piece, and only put the pieces together when you're sure you have each one working. That may seem slower, but trying to go too fast will cause misunderstandings like this one.
I am writing a code for the wind chill index for an assignment for college.
The prof wants us to prevent the code from crashing upon user input of blank or letters, without using Try/Except Blocks. (He refers to string methods only).
Instead of crashing it should out put an error message eg. ("invalid input, digits only")
I tried utilizing the string.isdigit and string.isnumeric, but it won't accept the negative degrees as integers.
Any suggestions? (code below)
Would another "if" statement work?
Replace the punctuation:
if temperature.replace('-','').replace('.','').isnumeric():
Use an infinite loop and check that everything seems right.
Whenever there's an error, use the continue statement. And when all checks and conversions are done, use the break statement.
import re
import sys
while True:
print("Temperature")
s = sys.stdin.readline().rstrip('\n')
if re.match("^-?[0-9]+(\\.[0-9]+)?$", s) is None:
print("Doesn't look like a number")
continue
if '.' in s:
print("Number will be truncated to integer.")
temp = int(float(s))
if not (-50 <= temp <= 5):
print("Out of range")
continue
break