I hope one of you may be able to help. I have a plot with one y-axis value and one x-axis corresponding to these y values. I want to add a second y-axis on the right hand side of the plot. The values that will appear on the second y-axis are determined through the first y-axis values by some relation: for example, y2 might be y2 = y1**2 - 100. How do I make a second y-axis which has its values determined by the y1 values, so that the y2 values correctly align with their y1 values on the y-axis?
twin axis
Adding a second y axis can be done by creating a twin axes, ax2 = ax.twinx().
The scale of this axes can be set using its limits, ax2.set_ylim(y2min, y2max). The values of y2min, y2max can be calculated using some known relationship (e.g. implemented as a function) from the limits of the left axis.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(0)
x = np.linspace(0,50,101)
y = np.cumsum(np.random.normal(size=len(x)))+20.
fig, ax = plt.subplots()
ax2 = ax.twinx()
ax.plot(x,y, color="#dd0011")
ax.set_ylabel("Temperature [Celsius]")
ax2.set_ylabel("Temperature [Fahrenheit]")
# set twin scale (convert degree celsius to fahrenheit)
T_f = lambda T_c: T_c*1.8 + 32.
# get left axis limits
ymin, ymax = ax.get_ylim()
# apply function and set transformed values to right axis limits
ax2.set_ylim((T_f(ymin),T_f(ymax)))
# set an invisible artist to twin axes
# to prevent falling back to initial values on rescale events
ax2.plot([],[])
plt.show()
secondary axis
From matplotlib 3.1 onwards one can use a secondary_yaxis. This takes care of synchronizing the limits automatically. As input one needs the conversion function and its inverse.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(0)
x = np.linspace(0,50,101)
y = np.cumsum(np.random.normal(size=len(x)))+20.
# Convert celsius to Fahrenheit
T_f = lambda T_c: T_c*1.8 + 32.
# Convert Fahrenheit to Celsius
T_c = lambda T_f: (T_f - 32.)/1.8
fig, ax = plt.subplots()
ax2 = ax.secondary_yaxis("right", functions=(T_f, T_c))
ax.plot(x,y, color="#dd0011")
ax.set_ylabel("Temperature [Celsius]")
ax2.set_ylabel("Temperature [Fahrenheit]")
plt.show()
The output is the same as above, but as you can see one does not need to set any limits.
Related
I am plotting using the contourf function from matplotlib and would like to add a colorbar, I've noticed that sometimes the ticks don't go the max/min values.
Is there a clean way to force it to set ticks at these values?
Note: Checking the max and min of z shows that the colorbar represents values from approx -1 to 1, therefor I would expect this ot be reflected such that one can see the range from the colobar, in addition to some ticks in between.
Plot and code demonstrating what I am talking about:
import matplotlib.pyplot as plt
import numpy as np
# Data to plot.
x, y = np.meshgrid(np.arange(7), np.arange(10))
z = np.sin(0.5 * x) * np.cos(0.52 * y)
fig, ax = plt.subplots()
cs = ax.contourf(x, y, z, levels=25)
ax.grid(c="k", ls="-", alpha=0.3)
fig.colorbar(cs, ax=ax)
fig.savefig("example.png", bbox_inches="tight")
The cleanest way seems to be to give explicit levels to contourf. If no explicit levels are given, contourf seems to choose its own, depending on the minimum and maximum value in the data, and also tries to find "nice looking" numbers. After that, ticks get set to a subset of these numbers, such that a tick always coincides with a real level. (If you use colorbar(..., ticks=...) those ticks will not necessarily coincide with the levels.)
As the sine and cosine don't reach -1 and 1 exact in the given example, they are not part of the range.
The following code shows how the ticks depend on the chosen levels. With np.linspace(-1, 1, 24) the levels aren't nice round numbers, but matplotlib still chooses a subset to show.
import matplotlib.pyplot as plt
import numpy as np
x, y = np.meshgrid(np.arange(7), np.arange(10))
z = np.sin(0.5 * x) * np.cos(0.52 * y)
fig, (ax1, ax2) = plt.subplots(ncols=2, figsize=(12, 3))
for ax in (ax1, ax2):
numcontours = 25 if ax == ax1 else 24
cs = ax.contourf(x, y, z, levels=np.linspace(-1, 1, numcontours))
ax.grid(c="k", ls="-", alpha=0.3)
fig.colorbar(cs, ax=ax)
ax.set_title(f'{numcontours} levels from -1 to 1')
plt.show()
I am trying to fill the area between two vertical curves(RHOB and NPHI) using matplotlib.pyplot. Both RHOB and NPHI are having different scale of x-axis.
But when i try to plot i noticed that the fill_between is filling the area between RHOB and NPHI in the same scale.
#well_data is the data frame i am reading to get my data
#creating my subplot
fig, ax=plt.subplots(1,2,figsize=(8,6),sharey=True)
ax[0].get_xaxis().set_visible(False)
ax[0].invert_yaxis()
#subplot 1:
#ax01 to house the NPHI curve (NPHI curve are having values between 0-45)
ax01=ax[0].twiny()
ax01.set_xlim(-15,45)
ax01.invert_xaxis()
ax01.set_xlabel('NPHI',color='blue')
ax01.spines['top'].set_position(('outward',0))
ax01.tick_params(axis='x',colors='blue')
ax01.plot(well_data.NPHI,well_data.index,color='blue')
#ax02 to house the RHOB curve (RHOB curve having values between 1.95,2.95)
ax02=ax[0].twiny()
ax02.set_xlim(1.95,2.95)
ax02.set_xlabel('RHOB',color='red')
ax02.spines['top'].set_position(('outward',40))
ax02.tick_params(axis='x',colors='red')
ax02.plot(well_data.RHOB,well_data.index,color='red')
# ax03=ax[0].twiny()
# ax03.set_xlim(0,50)
# ax03.spines['top'].set_position(('outward',80))
# ax03.fill_betweenx(well_data.index,well_data.RHOB,well_data.NPHI,alpha=0.5)
plt.show()
ax03=ax[0].twiny()
ax03.set_xlim(0,50)
ax03.spines['top'].set_position(('outward',80))
ax03.fill_betweenx(well_data.index,well_data.RHOB,well_data.NPHI,alpha=0.5)
above is the code that i tried, but the end result is not what i expected.
it is filling area between RHOB and NPHI assuming RHOB and NPHI is in the same scale.
How can i fill the area between the blue and the red curve?
Since the data are on two different axes, but each artist needs to be on one axes alone, this is hard. What would need to be done here is to calculate all data in a single unit system. You might opt to transform both datasets to display-space first (meaning pixels), then plot those transformed data via fill_betweenx without transforming again (transform=None).
import numpy as np
import matplotlib.pyplot as plt
y = np.linspace(0, 22, 101)
x1 = np.sin(y)/2
x2 = np.cos(y/2)+20
fig, ax1 = plt.subplots()
ax2 = ax1.twiny()
ax1.tick_params(axis="x", colors="C0", labelcolor="C0")
ax2.tick_params(axis="x", colors="C1", labelcolor="C1")
ax1.set_xlim(-1,3)
ax2.set_xlim(15,22)
ax1.plot(x1,y, color="C0")
ax2.plot(x2,y, color="C1")
x1p, yp = ax1.transData.transform(np.c_[x1,y]).T
x2p, _ = ax2.transData.transform(np.c_[x2,y]).T
ax1.autoscale(False)
ax1.fill_betweenx(yp, x1p, x2p, color="C9", alpha=0.4, transform=None)
plt.show()
We might equally opt to transform the data from the second axes to the first. This has the advantage that it's not defined in pixel space and hence circumvents a problem that occurs when the figure size is changed after the figure is created.
x2p, _ = (ax2.transData + ax1.transData.inverted()).transform(np.c_[x2,y]).T
ax1.autoscale(False)
ax1.fill_betweenx(y, x1, x2p, color="grey", alpha=0.4)
I'm reading in time series data and I want to make an aggregate plot using matplotlib. I managed to set appropriate font sizes for the axis titles and labels. However, I could not find the function that would allow me to change the font size of the y axis scaling factor.
# Only updates the size of the ticks
plt.yticks(fontsize = 25)
I expected the font size of the scaling factor (shown in the top left) will update as I update the font size of the labels (ticks).
The scaling factor on the y-axis you are referring to is called offsetText. To change its properties, you need to access it via the axis instance of your figure.
Minimal complete answer
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
x = np.linspace(0, 1, 100)
y = x**2/10**7
plt.plot(x, y)
plt.yticks(fontsize = 25)
ax.yaxis.offsetText.set_fontsize(25)
plt.show()
I hope one of you may be able to help. I have a plot with one y-axis value and one x-axis corresponding to these y values. I want to add a second y-axis on the right hand side of the plot. The values that will appear on the second y-axis are determined through the first y-axis values by some relation: for example, y2 might be y2 = y1**2 - 100. How do I make a second y-axis which has its values determined by the y1 values, so that the y2 values correctly align with their y1 values on the y-axis?
twin axis
Adding a second y axis can be done by creating a twin axes, ax2 = ax.twinx().
The scale of this axes can be set using its limits, ax2.set_ylim(y2min, y2max). The values of y2min, y2max can be calculated using some known relationship (e.g. implemented as a function) from the limits of the left axis.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(0)
x = np.linspace(0,50,101)
y = np.cumsum(np.random.normal(size=len(x)))+20.
fig, ax = plt.subplots()
ax2 = ax.twinx()
ax.plot(x,y, color="#dd0011")
ax.set_ylabel("Temperature [Celsius]")
ax2.set_ylabel("Temperature [Fahrenheit]")
# set twin scale (convert degree celsius to fahrenheit)
T_f = lambda T_c: T_c*1.8 + 32.
# get left axis limits
ymin, ymax = ax.get_ylim()
# apply function and set transformed values to right axis limits
ax2.set_ylim((T_f(ymin),T_f(ymax)))
# set an invisible artist to twin axes
# to prevent falling back to initial values on rescale events
ax2.plot([],[])
plt.show()
secondary axis
From matplotlib 3.1 onwards one can use a secondary_yaxis. This takes care of synchronizing the limits automatically. As input one needs the conversion function and its inverse.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(0)
x = np.linspace(0,50,101)
y = np.cumsum(np.random.normal(size=len(x)))+20.
# Convert celsius to Fahrenheit
T_f = lambda T_c: T_c*1.8 + 32.
# Convert Fahrenheit to Celsius
T_c = lambda T_f: (T_f - 32.)/1.8
fig, ax = plt.subplots()
ax2 = ax.secondary_yaxis("right", functions=(T_f, T_c))
ax.plot(x,y, color="#dd0011")
ax.set_ylabel("Temperature [Celsius]")
ax2.set_ylabel("Temperature [Fahrenheit]")
plt.show()
The output is the same as above, but as you can see one does not need to set any limits.
This question already has answers here:
multiple axis in matplotlib with different scales [duplicate]
(3 answers)
Closed 5 years ago.
import numpy as np
import matplotlib as mpl
import matplotlib.pyplot as plt
import seaborn as sns
d = ['d1','d2','d3','d4','d5','d6']
value = [111111, 222222, 333333, 444444, 555555, 666666]
y_cumsum = np.cumsum(value)
sns.barplot(d, value)
sns.pointplot(d, y_cumsum)
plt.show()
I'm trying to make pareto diagram with barplot and pointplot. But I can't print percentages to the right side ytick. By the way, if I manuplate yticks it overlaps itself.
plt.yticks([1,2,3,4,5])
overlaps like in the image.
Edit: I mean that I want to quarter percentages (0, 25%, 50%, 75%, 100%) on the right hand side of the graphic, as well.
From what I understood, you want to show the percentages on the right hand side of your figure. To do that, we can create a second y axis using twinx(). All we need to do then is to set the limits of this second axis appropriately, and set some custom labels:
import matplotlib.pyplot as plt
import numpy as np
import seaborn as sns
d = ['d1','d2','d3','d4','d5','d6']
value = [111111, 222222, 333333, 444444, 555555, 666666]
fig, ax = plt.subplots()
ax2 = ax.twinx() # create a second y axis
y_cumsum = np.cumsum(value)
sns.barplot(d, value, ax=ax)
sns.pointplot(d, y_cumsum, ax=ax)
y_max = y_cumsum.max() # maximum of the array
# find the percentages of the max y values.
# This will be where the "0%, 25%" labels will be placed
ticks = [0, 0.25*y_max, 0.5*y_max, 0.75*y_max, y_max]
ax2.set_ylim(ax.get_ylim()) # set second y axis to have the same limits as the first y axis
ax2.set_yticks(ticks)
ax2.set_yticklabels(["0%", "25%","50%","75%","100%"]) # set the labels
ax2.grid("off")
plt.show()
This produces the following figure: