Recover informations from CSV files with my awk script - linux

Question

I have this CSV files :
Monday,linux,6,0.2
Tuesday,linux,0.25,0.2
Wednesday,linux,64,3
I create a little script that allow me to recover the informations from my csv
and to place them like this :
Day : Monday
OS : Linux
RAM : 6
CPU1 : 0.2
My script is :
#!/bin/bash
awk -F'[ ,;|.]' 'FNR==0{next}
FNR>1 {
print "DAY : " $1;
print "OS :\n " $2
print "RAM :\n " $3
print "CPU1 :\n " $4
}' mycsvfile.csv
But the result is :
DAY : Tuesday
OS :
linux
RAM :
0
CPU1 :
25
DAY : Wednesday
OS :
linux
RAM :
64
CPU1
Or I want :
DAY : Monday
OS : linux
RAM : 0.2
CPU 1 : 1
DAY : Tuesday
OS : linux
RAM : 0.25
CPU 1 : 0.2
DAY : Wednesday
OS : linux
RAM : 64
CPU 1 : 3
Can you tell me why my script doesn't works and why floats are not taken into account ?
Thank you !

Answer 1

Added tab and newline to same awk as Cyrus posted.
awk -F ',' '{
print "DAY :",$1
print "OS :",$2
print "RAM :",$3
print "CPU1 :",$4"\n"
}' OFS='\t' file
DAY : Monday
OS : linux
RAM : 6
CPU1 : 0.2
DAY : Tuesday
OS : linux
RAM : 0.25
CPU1 : 0.2
DAY : Wednesday
OS : linux
RAM : 64
CPU1 : 3
A more generic solution:
awk -F, 'BEGIN {split("DAY OS RAM CPU", header, " ")}{for (i=1;i<=4;i++) print header[i]":\t",$i;print ""}' t
DAY: Monday
OS: linux
RAM: 6
CPU: 0.2
DAY: Tuesday
OS: linux
RAM: 0.25
CPU: 0.2
DAY: Wednesday
OS: linux
RAM: 64
CPU: 3
More readable:
awk -F, '
BEGIN {split("DAY OS RAM CPU", header, " ")}
{
for (i=1;i<=4;i++)
print header[i]":\t",$i;
print ""
}' file