I have an Excel book with two columns (text and numbers). The first column has a lot of variables such as 174AXX that repeat themselves.
I'm now trying to create a third column where I want to find the highest value of the second column (the one that has numbers) and that is associated with the numbers 174. Meaning that I don't want it to search for the entire word 174AXX. I want it to go to all variables that start with 174 and search the highest value.
I'm using the Max if function however when I try to use "*174*" in the formula it doesn't recognize it.
{Max(if(K:K="*174*";L:L))}
Unfortunately the Asterisk doesn't work this way in Arrays.
Instead you can use the find function like to end up with this formula:
=MAX(IF(ISNUMBER(FIND("174",K:K)),L:L))
Then press CTRL + SHIFT + ENTER
Related
I have some data in Col"K" where from i am just trying to get the left characters as i tried in Col"H" using formula.
But what i used is Left function like =Function(cell,10) that is not the correct way characters can be more than 10 or less than 10.
1st formula should be dynamic to get the left numeric values.
2nd Formula should copy and paste the same numeric values until next value comes as available in Col"I"
I tried to make it but what i can do is to create left function and do not know how to develop it dynamic.
Any help will be appreciated.
Sheet Link
https://docs.google.com/spreadsheets/d/1nJZeWDZ0EWgmWB0z17xU93fjIOFsu46EL37IJqJzZ_0/edit?usp=sharing
This formula should do the job.
[J2] =IFERROR(TRIM(LEFT(L2,FIND("-",L2)-1)),J1)
Note that it will fail if placed in row 1 and there is no dash in L1.
Use find function to get numeric characters length.
=iferror(trim(left(L3,FIND("-",L3)-1)),M2)
Here we are finding the separator "-" in your text and it gives us index number of separator.
Then picking text from start to before index number i.e., Numeric value and removing blank spaces, if any, using trim function. If we don't have number/separator in the text then showing previous cell value using iferror function. So, Make sure first row always has numeric value.
Same has implemented in the sheet you have shared
As per the latest data I have updated my answer as below , now it is checking output is numeric or not:
=IF(COUNT(FIND({0,1,2,3,4,5,6,7,8,9},J9))=0,K8,TRIM(LEFT(J9,FIND("-",J9)-1)))
I have very basic user Excel knowledge. I have a spreadsheet where I keep track of reloading data. Each load I enter gets a unique load number that is calculated automatically with a formula, based on the caliber name and an incrementally increasing number. As of now, every load I enter gets a number, even if it's been repeated before. Popular loads that I repeat often are all the same except for the date and numbers of rounds made but currently will have different load numbers. Is there a way to skips these repeated loads and assign it the previous load number or not assign a load number at all, with a formula instead of manually?
I know this is asking for a great deal but I'd greatly appreciate any help! I'm certainly open to suggestions if this isn't even the best way to go about this.
Sample workbook at:
https://www.dropbox.com/s/v5y1ufxjiosmnap/My%20Reloading%20Data%20-%20Sample.xlsx?dl=0
Here's what I've tried so far:
In column Q2, combine all the criteria.
=C17&E17&F17&G17&H17&L17&M17&N17&P17
In column R2 look for duplicates.
=IF(COUNTIF($Q$2:$Q17, $Q17)>1, "Duplicate", "")
D2 is the Load # column.
=IF(R17="Duplicate","",(TEXT(C17,0)&"-"&TEXT(COUNTIF($C$2:C17,C17),"000")))
This will skip the duplicate loads and not give them a load # leaving the cell blank. I'd love to find and match what that load # should be and insert it. Also, when the sequential numbering resumes it acts as if it's counted the duplicate row. For instance D2 might look like:
9mm-001
9mm-002
(Skipped for duplicate and left blank, but would like it to find, match, and insert the duplicate load #)
9mm-004 (I'd like to to be 9mm-003)
You should be able to achieve this with a VLOOKUP formula or a combination of MATCH and INDEX.
VLOOKUP (Vertical Lookup) looks for a match in another cell and returns a value from an offset column. A non match, if you use FALSE as the last parameter, returns a #N/A error.
So, in D20 (for example) you could, using column Q as your determinant, use the following, assuming you had a copy of D in column R:
=IFERROR(VLOOKUP(Q20,Q$1:R19,2,FALSE),[value for newly found loadno])
What this formula does is calculates a VLOOKUP - if that doesn't find a record, calculate a new value. The VLOOKUP will look at the concatenated key in the current row Q column, search through all previous columns (note it is anchored at row 1, but not anchored for the bottom of the range so you can copy the formula), it uses the column 2 (Q is column 1, so R is column 2) for the result, and demands an exact match (FALSE). If it doesn't find one, return NA and let the second half of the IFERROR take over.
See how you go with this.
The MATCH INDEX may work better because you won't need the additional R column due to VLOOKUP only being able to look to the right of the key.
Here is an INDEX and MATCH solution - slightly harder to understand, but a more flexible solution.
=IFERROR(INDEX(D$1:D19,MATCH(Q20,Q$1:Q19,0)),[value for newly found load number])
I prefer this.
The outer function says return the nth value in the list. The inner MATCH function says find this value (Q20) in this list (Q1:Q19). The 0 as the third parameter of the MATCH function says the match has to be exact.
I am not an expert in Excel but I have been using the format.
I am trying to make a roster of my staff in Excel sheet using formulas.
The 1st sheet I have uses the row name TIME as a priority and fills other columns with staff names.
Now in the 2nd sheet, I want to use a formula in each staff ROW and the column automatically fills with the TIME at each name.
Please help me if possible.
Thank you.
Use INDEX / MATCH combo. Something like this:
=IFERROR(INDEX(Sheet1!$B$3:$B$9,MATCH($A2,Sheet1!C$3:C$9,0)),"OFF DAY")
Syntax:
=INDEX(rng,index_number) — returns the value based on the index number
=MATCH(lookup_value,rng) — returns the relative position of the lookup value
=INDEX(rng,MATCH(lookup_value,rng)) — we know all the arguments except for one — index_number. Since the output of MATCH function is the same as the index_number, we're going to substitute the index_number with MATCH function.
You can almost think of the INDEX/MATCH combo as:
=INDEX/MATCH(rng,search_value)
=IFERROR(value_or_expression_to_evaluate,value_to_return_if_error) — and finally, we're going to wrap our formula with this one, which will return a value if there is no match, which means, in your example, employee is on-leave, on a rest-day, or whatever. Can be =IFNA, too.
Now, to return all values with multiple matched lookup_value just like in your example, where "Tam" have two shifts on Monday, you may use a trailing number with employee names, i.e. "Tam1" and "Tam2" to indicate the number of shift in a given day. Or you may also use a combination of COUNTIF function (to count the number of shift of "Tam") and CONCATENATE to join the results together so that the output is gonna be: 630-1430 / 1230-2200. There are many ways to do it depending on your requirement.
Hope this helps..
I'm using Excel to run a sort of lottery.
The spreadsheet columns are set up thus:
COL1:Person Name; COL2: Chosen Number A; COL3: Chosen Number B; COL4: Chosen Number C
There is then a set of data, generated using RAND() and ROUND, that gives 3 winning numbers, each between 0 and 10.
What I'm trying to do is identify a winner, by using VLOOKUP or INDEX/MATCH, or some combination, or other function, to identify the winning person, so that there is a single cell that returns the name of the winner.
The added complexity is that by looking up each of the numbers individually by column, an individual selection of, say, 1,4,8, isn't a winning selection against a randomly selection of say, 4,8,1.
Ideas?
You can concatenate numbers to additionalcolumn so it will contain string "1,4,8," and then perform a VLOOKUP for concatenated in the same way winning numbers.
By the way, this solution will show only first person, but isn't it possible that several persons guessed same numbers and won?
If you want to generate a 3-digit number, by far the easiest thing to do is to use the formula
=RANDBETWEEN(0,999)
You can select the cells and then enter (via the format dialog accessible by right-clicking) the custom format 000 if you want it to display as 3 digits so that e.g. 7 displays as 007. This will allow you to directly use VLOOKUP on a single value. #kipar asks an excellent question about potential multiple winners.
I implemented the abovementioned solution and it was quite easy. After your 4 columns, you add one column with
=TEXT(B1;0)&TEXT(C1;0)&TEXT(D1;0)
which combines the number to one string. Then you put your winning number in a cell of preference mine was M28 and the value was 123. After your first five columns you use the following formula.
=IF.ERROR(INDEX(A$1:A$4;SMALL(IF(E$1:E$4=TEXT($M$28;0);ROW(E$1:E$4));RI-OW());1);"")
The IF.ERROR is used to put a blank when there are no multiple winners. The index is used to get the winners out of your first column, that'w why there's a one at the end. The small is used to find the first occurence of the winner. You also have to enter it as an array formula so press ctrl+shift+enter instead of just enter when the formula is completed. I hope this answer is satisfying.
PS. For extra information on the use of this function go here: http://chandoo.org/wp/2014/12/09/multiple-occurrences-lookup-and-extraction/
Imagine my dataset has multiple IDs in columns, for the same item. How can I use VLOOKUP to scan the next column in the order up until it finds the same ID in another dataset? Or if it does not exist just stop searching after 6 columns? Thanks!
You could do this with 6 nested IFERROR statements; that would look like this: (Assuming your ID columns are A->F, your results column is G, and your search term is in J1):
=IFERROR(IFERROR(IFERROR(IFERROR(IFERROR(VLOOKUP(J1,A:G,7,0),VLOOKUP(J1,B:G,6,0)),VLOOKUP(J1,C:G,5,0)),VLOOKUP(J1,D:G,4,0)),VLOOKUP(J1,E:G,3,0)),VLOOKUP(J1,F:G,2,0))
This looks at each column (starting with F and working outwards), and if it can't find a match, it creates an error, so goes to the next column. It is not very clean to read. A better way using this same methodology could be to use a combination of INDEX & MATCH, like so:
=INDEX(G:G,IFERROR(IFERROR(IFERROR(IFERROR(IFERROR(MATCH(J1,A:A,0),MATCH(J1,B:B,0)),MATCH(J1,C:C,0)),MATCH(J1,D:D,0)),MATCH(J1,E:E,0)),MATCH(J1,F:F,0))
Though this is a little shorter [because we don't need to specify the entire block of data, or which column to pull from, as it always pulls from column G], it is still not very readable.
Let's try this instead using an Array Formula which runs the same function multiple times over many cells, gets the result for each cell, and provides an array of results. Then we just need to collapse that array into a single value, like so:
=INDEX(G1:G14,MIN(IFERROR(IF(SEARCH(J1,A1:A14&B1:B14&C1:C14&D1:D14&E1:E14&F1:F14)>0,ROW(A1:A14),""),"")))
Confirm this formula with CTRL + SHIFT + ENTER instead of just ENTER. This adds all strings of all search columns together, basically making a single column of values. It then takes that column, and searches each cell for the word found in J1. If it finds it, it returns that row number, otherwise it returns "". The function then uses MIN to take the lowest row number found (to tie-break to the earliest row, if there is a duplicate), and then uses that with INDEX to return the value from that row in column G.
Note that the logic here is a little different from the options I gave above, as it defaults to the earliest row #, rather than the earliest column #, of a match.