I am trying to find the date out of a weeknum, weekday and year.
There are many information on the web but after several attempts, I couldn't find what I was looking for.
So far, I have this formula:
=DATE(AZ22,1,AZ3*7-5)-WEEKDAY(DATE(AZ22,1,3))
AZ22=YEAR
AZ3=WEEKNUM
Unfortunately it doesn't seem to work.
In order to add some complexity, my weeks should start for Thursday (Thursday 1st day of the week).
If you are so kind to provide an answer, could you please post the explanation of the formula as well?
as JvdV asked, the output should be a date like
01 dec 2019.
I need this formula to map a current date (and I can't use date-364) with the last two years.
The process works as follow:
I have the current date (date A)
The current week ( of date A) is mapped with a different week last year
From the week (and eventually the WEEKDAY) I should find my date B
I hope it clarifies my request
Thank you,
Use this:
=DATE(A2,1,(B2-1)*7-WEEKDAY(DATE(A2,1,B2*7),14)+C2)
This is just math. But by adding the 14 to the Weekday we start our week on Thursday. This does assume that 2019-1-3, the first Thursday of this year, is the start of the 2nd week. If that is not the case and the week that started on the 3rd is the first week, change the (B2-1) to just B2
Related
I have a formula to calculate the first Friday of the Year and it works okay.
I understand how the formula gets the answer however, I can't seem to find the reasoning behind the formula. The formula is:
=DATE(YEAR(TODAY()),1,8)-WEEKDAY(DATE(YEAR(TODAY()),1,2))
This gives us 2020/01/08 - 5 = 2020/01/03 which is the First Friday of the Year. But why does the formula choose 8 and 2 as the dates?
Can someone please explain the reason.
The first, obvious, part of the formula is that DATE(YEAR(TODAY()),1,8) gives you the eighth day of the month which can't be the first Friday since one of the 7 days before it would must be a Friday.
My guess is that the second part has a little bit of kludgery going on. WEEKDAY(DATE(YEAR(TODAY()),1,1)) would give you the number of days from the first day of the month to the previous Sunday. But if you're looking for the previous Saturday you'd need WEEKDAY(DATE(YEAR(TODAY()),1,1)) + 1 or WEEKDAY(DATE(YEAR(TODAY()),1,2)).
Finally, the day of the week WEEKDAY(DATE(YEAR(TODAY()),1,2)) before the 1st of the month is the same day of the week before the 8th of the month.
Working on a formula that will take a date and translate it to the format FYxxPxxWx.
For example. Input the date of 03/22/20 and the formula will give you FY20P06W4 which is correct.
However if you input 02/02/20 the formula will give you FY20P05W2. The correct output would be FY20P05W1. This issue also rears its head with the date 09/29/19. It gives you FY20P12W5. The correct output would be FY20P1W1.
Something else weird happens when you put in the date 04/5/20 you get FY21P07W2 when it should be FY20P07W2.
The formula is
=CONCATENATE("FY",RIGHT(YEAR(DATE(YEAR(D5),MONTH(D5)+(10-1),1)),2),"P",TEXT(CHOOSE(MONTH(D5),4,5,6,7,8,9,10,11,12,1,2,3),"0#"),"W",WEEKNUM(D5,1)-WEEKNUM(DATE(YEAR(D5),MONTH(D5),1),1)+1)
I think this issue is caused by the strange weeks where the the month ends and another begins throwing off the formula.
I do have a formula that calculates the years fiscal year start date
=(DATE(YEAR(TODAY())-1,10,1)-(WEEKDAY(DATE(YEAR(TODAY())-1,10,1),1)))+1
This outputs 09/29/19 as the start date of the Fiscal year as its the same week as 10/1/19 which is the first month of the fiscal year. IF that makes sense.
The separate formulas are
For FY and grabs only last two digits of year
RIGHT(YEAR(DATE(YEAR(D5),MONTH(D5)+(10-1),1)),2)
For Period (gives me a two digit Period
TEXT(CHOOSE(MONTH(D5),4,5,6,7,8,9,10,11,12,1,2,3),"0#")
For Week
WEEKNUM(D5,1)-WEEKNUM(DATE(YEAR(D5),MONTH(D5),1),1)+1)
I believe I have a solution for you. Discussion to follow, but here's the full formula:
=CONCAT("FY",RIGHT(YEAR(D5+91+WEEKDAY(DATE(YEAR(D5),10,1))),2),"P",TEXT(IF(MONTH(D5+(7-WEEKDAY(D5)))<>MONTH(D5),IF(MONTH(D5)=9,1,CHOOSE(MONTH(D5),5,6,7,8,9,10,11,12,1,2,3,4)),CHOOSE(MONTH(D5),4,5,6,7,8,9,10,11,12,1,2,3)),"0#"),"W",ROUNDUP(((D5-IF(MONTH(D5+(7-WEEKDAY(D5)))<>MONTH(D5),DATE(YEAR(D5),MONTH(D5)+1,1)-WEEKDAY(DATE(YEAR(D5),MONTH(D5)+1,1))+1,DATE(YEAR(D5),MONTH(D5),1)-WEEKDAY(DATE(YEAR(D5),MONTH(D5),1))+1))/7)+0.01,0))
One issue is that this still calculates 2/2/2020 the way you said was incorrect. When I verify it against a calendar, though, it seems that FY20P05W02 should be correct. If the week that includes the first of the month begins a new pay period, that would mean 2/1/2020, falling on a Saturday, would be the last day of fiscal week 1. That would make 2/2/2020 the first day of fiscal week 2.
To calculate fiscal year, I used RIGHT(YEAR(D5+91+WEEKDAY(DATE(YEAR(D5),10,1))),2). Since you can count on there always being 91 days from the beginning of October to the end of December, it helps with this calculation. In your formula, you had MONTH(D5)+(10-1), which would push you 9 months out past the month in D5. This explains why your result for 4/5/2020 was off by a year.
Fiscal period was a bit trickier, requiring a couple nested IF statements. I used IF(MONTH(D5+(7-WEEKDAY(D5)))<>MONTH(D5) first to account for days at the end of the month that would fall into the next fiscal period, then IF(MONTH(D5)=9 to account for the few days at the end of September that might fall into the next fiscal year. Days at the end of September would default to 1, days at the end of a month that are included in the next fiscal period use the first CHOOSE function (they need the next month's number), and everything else gets the CHOOSE function as you wrote it.
The fiscal week took a bit more, but in the end I evaluated the beginning of the current fiscal month and subtracted it from the date in D5, then divided by 7 and added 0.01 so that even numbers would round up correctly.
I tested this out over a few years of dates and it seemed to be functioning correctly, but let me know if you have questions or issues.
One thing to consider when using WEEKNUM is that you'll have a week that is counted twice at the beginning of the year unless you use option 21 or ISOWEEKNUM. These give the same result as each other, and ensure that only one week number is assigned to any given day, no matter the year.
I'm trying to get the week number of a given quarter based on the date.
I currently have this formula
=1+(WEEKNUM(EDATE(Y4,-1)))-(WEEKNUM(DATE(YEAR(EDATE(Y4,-1)),
LOOKUP(MONTH(EDATE(Y4,-1)),{1,4,7,10}),1)))
But for January, it should be giving me 1 but it's giving me 10. Any suggestions?
How do you expect this to work at the start and end of the quarter? Default WEEKNUM function starts week 1 on the 1st of January every year and week 2 starts on the next Sunday after 1st January.
Assuming your quarter week numbers should work the same way, i.e. week 1 starts on the 1st of Jan/Apr/Jul/Oct and week 2 starts on the next Sunday then that's actually equivalent to counting Sundays since 6 days back into the previous quarter.
You can do that using NETWORKDAYS.INTL function, i.e. with this formula:
=NETWORKDAYS.INTL(EOMONTH(Y4,MOD(1-MONTH(Y4),-3)-1)-5,Y4,"1111110")
format result as number with no decimal places
NETWORKDAYS.INTL function is available in Excel 2010 and later versions - for older versions of Excel you can get the same results with this formula:
=INT((13-WEEKDAY(Y4)+Y4-EOMONTH(Y4,MOD(1-MONTH(Y4),-3)-1))/7)
(Expanded from comment)
when you choose a date in January, it's going back to December. 12 in your lookup array gives 10 as the result. Perhaps instead of EDATE, you should use EOMONTH(Y4,-1)+1, so you look at the 1st of the current month for your calculation
=1+(WEEKNUM(EOMONTH(Y4,-1)+1))-(WEEKNUM(DATE(YEAR(EOMONTH(Y4,-1)+1), LOOKUP(MONTH(EOMONTH(Y4,-1)+1),{1,4,7,10}),1)))
This is fairly interesting, since it changes with the year, and changes with what day of the week is the "start" of the week. So if a quarter starts on Saturday, and the week starts on a Saturday, the entire week is week 1. However, if it starts on a Sunday, week 1 is only one day long, and week 2 starts on Sunday.
The first question we have is, what day is it?
=DayCheck
Additionally, I'm going to call the start of each quarter the following:
Q1Start = Date(Year(DayCheck),1,1)
Q2Start = Date(Year(DayCheck),4,1)
Q3Start = Date(Year(DayCheck),7,1)
Q4Start = Date(Year(DayCheck),10,1)
The next question is, what's the first day of the week? We have some control over this with the Weekday function. For the sake of keeping it simple, Sunday is the start of the week.
Ok, that's our day. Next, what quarter is it?
`Quarter=ROUNDDOWN(MONTH(O16)/4,0)+1`
This gives us 1 for Q1, 2 for Q2, etc.
What day of the week is it now?
=WEEKDAY(DayCheck,1)
Ok, and now, what week are we on?
=WEEKNUM(DayCheck,1)
I'm going to put it together in a not very elegant fashion. I'm sure there's a better way out there.
=(Quarter=1)*((Weeknum(DayCheck)-WeekNum(Q1Start)+1)+(Quarter=2)*((Weeknum(DayCheck)-WeekNum(Q2Start)+1)+(Quarter=3)*((Weeknum(DayCheck)-WeekNum(Q3Start)+1)+(Quarter=4)*((Weeknum(DayCheck)-WeekNum(Q4Start)+1)
Try this:
=CHOOSE((MOD(WEEKNUM(Y4),13)=0)+1,WEEKNUM(Y4)-(ROUNDDOWN(WEEKNUM(Y4)/13,0)*13),13)
This will get the week number of a given date within a quarter.
I used this in one of my applications so you might be able to use it too. HTH.
Note: If you use 1st day other than Sunday, then adjust the WEEKNUM formula.
Can try this as I got this as combination of 2 formula
=WEEKNUM(A1,1)-(INT((MONTH(A1)-1)/3)*13)
second part - INT((MONTH(A1)-1)/3) gives us the quarter number of previous quarter which then multiplied with 13 weeks/quarter gives us how many weeks have passed in all previous quarter before current quarter.
First part - "WEEKNUM(A1,1)" gives us the week number of current week in the year.
so by deducting all the previous weeks in previous quarters from current week number of year, we get the current week number in current quarter.
Question is as in title.
I have a cell, "D4", with the date "09/07/2016" in it. Adjacent cell has formula "=weeknum(D4,1)". The output of this function is "28". But on a Sunday-Saturday basis, Saturday the 9th of July wasn't in week 28 - it was in week 27.
I thought this might be something to do with Saturday/Sunday and when the week starts and finishes, etc, so I tried multiple different dates from last week - Monday the 4th, Tuesday the 5th, Wednesday the 6th, etc. In each case, "weeknum" returns a value of "28".
I only noticed the problem because I have a macro which uses the value of the cell with the week number to look for a spreadsheet saved by our accounts team on a weekly basis. As they have - correctly - saved the spreadsheet as "week 27", it didn't work. I initially assumed that the accounts team were wrong, but I checked online and they are correct.
How could this happen? Surely Excel can't be wrong and I must have made a mistake of some sort?
I know that there is an issue with Excel not following ISO standards for when weeks 53 and 1 begin and end, but I don't see how that could affect a mid-year week.
It did occur to me that the issue might be to do with UK versus US date formatting. But, of course, the 7th of June wasn't in week 28 either.
That all is documented in WEEKNUM.
There are two systems used for this function:
System 1 The week containing January 1 is the first week of the
year, and is numbered week 1.
System 2 The week containing the first Thursday of the year is the
first week of the year, and is numbered as week 1. This system is the
methodology specified in ISO 8601, which is commonly known as the
European week numbering system.
Syntax
WEEKNUM(serial_number,[return_type])
Return_type Week begins on System
...
21 Monday 2
So =WEEKNUM("09/07/2016",21) will calculate as defined in ISO 8601 since Return_type 21 is the only one with System 2.
ISOWEEKNUM
=ISOWEEKNUM("09/07/2016")
will also do it.
=ISOWEEKNUM(a2)-1 returns the correct week for me, the same as =WEEKNUM(a2,21)-1
I'm wondering if this is possible. I am creating a spreadsheet to track project due dates. Each project must be completed by the 30th calendar day, but must be turned in on a business day.
Currently, I am just adding 30 days to the start date but this means some due dates aren't always accurate. For example, if the 30th day is Saturday, April 2nd, then the real due date would be Friday April 1st.
Is there a way to construct a conditional such that the due date equals the 30th calendar day, unless that falls on a weekend / holiday, where it then falls on the next earliest business day?
I've been struggling to figure out a way to do this.
For English settings in Excel, with a date in A1, in B1 enter:
=IF(TEXT(A1+30,"DDDD")="Sunday",A1+28,IF(TEXT(A1+30,"DDDD")="Saturday",A1+29,A1+30))
This simple-minded approach only handles Saturdays and Sundays, not arbitrary holidays.
I would prefer more elegant way like using WORKDAY.INTL
=WORKDAY.INTL(A2+31,-1,1,E2:E)
Explanation: start date + 31 days (1 day more than maximum calendar days)
then subtract 1 working day - going to last previous working day
Reason: because this formula does know when are weekends (by using variables) and also knows to skip hollydays by a custom list.
here is an example sheet you can use
Revised after comment:
Try this:
=(A4+30)+CHOOSE(WEEKDAY(A4+30),1,0,0,0,0,0,-1)
Your date, in A4, + 30 days, then add an amount of days until the next workday. If A4 + 30 is a Saturday it will subtract 1 day, a Sunday will add 1.