find row number of cell that contains criteria - excel

Question

I'm needing to find the first row numbers of cell in column C that contains "120" without duplicates (data I have has more than 10 of each number code, I only need the first one). So the code should pick up the first row number containing e.g. 120, 7120, 81200.
The code I've tried below have only managed to find the first row number with cell that contained 120. For reference, AGCL is a column letter derived from another find function and tbAC is a user input into a textbox.
Dim AGCN As Long
Dim AGCL As String
Dim AGNN As Long
Dim AGNL As String
Dim i As Long
Dim RowD As Long
Dim AAC As String
Dim rng As Range
Dim rownumber As Long
Dim AGC As Range
Dim AGN As Range
Dim firstaddress As Long
Dim nextaddress As Long
Set rng = Sheet1.Columns(AGCL & ":" & AGCL).Find(what:="*" & tbAC & "*",
LookIn:=xlValues, lookat:=xlPart)
rownumber = rng.Row
Debug.Print rownumber '9
With Sheet1.Range(AGCL & ":" & AGCL)
Set c = .Find("*" & tbAC & "*", LookIn:=xlValues)
If Not c Is Nothing Then
firstaddress = c.Value
Debug.Print firstaddress
With Me.ListBox2
.ColumnCount = 3
.ColumnWidths = "50;150;70"
.AddItem
.List(i, 0) = Str(firstaddress)
i = o + 1
End With
Do
Set c = .FindNext(c)
If c Is Nothing Then
GoTo donefinding
ElseIf firstaddress <> c.Value Then
nextaddress = c.Value
Debug.Print nextaddress 'it doesn't print any value here
'With Me.ListBox2
' .ColumnCount = 3
' .ColumnWidths = "50;150;70"
' .AddItem
' .List(i, 0) = Str(nextaddress)
' Debug.Print nextaddress
' i = o + 1
'End With
End If
Loop While c.Address <> firstaddress
End If
donefinding: Exit Sub
End With
Any help would be greatly appreciated, thank you!

Answer 1

Here is the Range.FindNext Function you can use to retrieve all the cells having 120.
With Sheet1.Range(AGCL & ":" & AGCL)
Set c = .Find("*" & tbAC & "*", lookin:=xlValues)
If Not c Is Nothing Then
firstAddress = c.Address
Do
Set c = .FindNext(c)
If c is Nothing Then
GoTo DoneFinding
Elseif not firstaddress.value = c.value
''Whatever you want to do with the Second Found Value
debug.print c.value
End If
Loop While c.Address <> firstAddress
End If
DoneFinding:
End With
Now to check that the value already found or not, you can play in the If Condition of this loop. So that you don't get the same values again.

Answer 2

UPDATED: Okay I updated one last time. As mentioned, I don't know what you want to do with the extra values... but this function will output them where ever...?
good luck.
Here's a custom function that matches what you're looking for, it will return the first time that 120 appears in a cell...
Here's one more that you could use if you truly wanted "contains" only a partial match.
Function SuperSearcherTHING(ivalue As Variant, theColumn As Range) As String
Dim rCell As Range
Const theSPACER As String = "|"
For Each rCell In Intersect(theColumn.EntireColumn, theColumn.Worksheet.UsedRange).Cells
If InStr(1, rCell.Value, ivalue, vbTextCompare) > 0 Then
SuperSearcherTHING = rCell.Value & theSPACER & SuperSearcherTHING
End If
Next rCell
SuperSearcherTHING = Left(SuperSearcherTHING, Len(SuperSearcherTHING) - Len(theSPACER))
End Function