extract last day and first day from month in python - python-3.x

Question

i am new in python ,i have a string of this format
Ex. 'Mar-00'
how could i calculate first day and last day from this month.
OUTPUT :
first day : 01-Mar-00
last day : 31-Mar-00
ex : 'Feb-17'
first day : 01-Feb-17
last day : 28-Feb-17

Answer 1

you can use calendar.monthrange(year, month)[1] to get the number of days in a given month+year.
the first is alway 01, and last is the value of calendar.monthrange(year, month)[1]
try this, let me know if it works:
import calendar
month_abbr_to_num = {v: k for k,v in enumerate(calendar.month_abbr)}
month_abbr, year_2_digit = input("please enter month, e.g. Mar-00: ").split('-')
month = month_abbr_to_num[month_abbr]
year = int('20'+year_2_digit)
days_in_month = calendar.monthrange(year,month)[1]
print("first day : {:02d}-{}-{}".format(1, month_abbr, year_2_digit))
print("last day : {:02d}-{}-{}".format(days_in_month, month_abbr, year_2_digit))
EDIT:
following your comment on original question, here it is in the form of a function that returns both as datetime objects:
import calendar
import datetime
month_abbr_to_num = {v: k for k,v in enumerate(calendar.month_abbr)}
def get_first_and_last_day(user_input):
month_abbr, year_2_digit = user_input.split('-')
month = month_abbr_to_num[month_abbr]
year = int('20' + year_2_digit)
days_in_month = calendar.monthrange(year, month)[1]
first_day = datetime.datetime(year, month, 1)
last_day = datetime.datetime(year, month, days_in_month)
return first_day, last_day
first, last = get_first_and_last_day(input("please enter month, e.g. Mar-00: "))
print("first day : ",first)
print("last day : ",last)