Python 3: Unable to convert ASCII String to Hexadecimal - python-3.x

Question

Python Version: 3.7.2
I need to convert a string in ASCII like Øâþ  ÿþ !Zk2ìm "Ï"À>q úÞ to Hexademical, which in this case would be d8 e2 02 12 02 fe 01 20 9b 10 20 20 03 ff 07 fe 20 20 21 5a 6b 32 ec 17 6d 20 0e 22 cf 22 c0 3e 71 20 02 20 03 fa de. I found several solutions for doing this on Python 2, however I can't find any way of doing this on Python 3.
To summarise: The intender behaviour is ASCII to HEX as follows:
Øâþ  ÿþ !Zk2ìm "Ï"À>q úÞ TO d8 e2 02 12 02 fe 01 20 9b 10 20 20 03 ff 07 fe 20 20 21 5a 6b 32 ec 17 6d 20 0e 22 cf 22 c0 3e 71 20 02 20 03 fa de.
I've even checked on https://www.rapidtables.com/convert/number/ascii-to-hex.html and found it works, but I'm unable to implement it in Python 3.

Answer 1

You may use the code:
print(*[hex(ord(letter))[2:] for letter in 'Øâþ ÿþ !Zk2ìm "Ï"À>q úÞ'])
which gives the following output:
d8 e2 fe 20 10 20 20 ff fe 20 20 21 5a 6b 32 ec 6d 20 e 22 cf 22 c0 3e 71 20 20 fa de
ord() - get ascii code,
hex() - get hex from int,
[2:] - to omit 0x in every number.
EDIT
Slightly modified version (to get 0e instead of e):
string = 'Øâþ ÿþ !Zk2ìm "Ï"À>q úÞ'
print(*['{:02x}'.format(ord(letter)) for letter in string])

Answer 2

Use ord():
s = 'Øâþ  ÿþ !Zk2ìm "Ï"À>q úÞ'
bytes = bytearray(ord(char) for char in s)
print(bytes)
Output:
bytearray(b'\xd8\xe2\xfe \x10 \xff\xfe !Zk2\xecm \x0e"\xcf"\xc0>q \xfa\xde')
That being said I can't match your output exactly because you copied and pasted a garbage char:
print(''.join(chr(char) for char in bytes)) # Øâþ ÿþ !Zk2ìm "Ï"À>q úÞ