Dictionary value travel - python-3.x

Question

I need to travel values of the dictionary in a single for loop to add and compare values. Here is my dictionary.
I am aware of iterating dictionary based on key but not sure if we can iterate based on an index of values of the dictionary.
dict = {
0: [1,2,3,4,7]
1: [2,4,6,9,0]
2: [4,6,8,2,1]
}
if I iterate over key-value, it will not help me. I need to execute for loop for each index of the value list.
Assumption: length of list for each dictionary key will be the same.
Total highest_class
7 2
12 2
17 2
15 1
8 0
Basically, sum all number from the value of the dictionary at the same index and also return which key has the highest number.

Answer 1

import pandas as pd
dict = {
0: [1,2,3,4,7],
1: [2,4,6,9,0],
2: [4,6,8,2,1]
}
data = [(sum(item),item.index(max(item))) for item in list(zip(*dict.values()))]
df = pd.DataFrame(data, columns =['Total', 'highest_class'])
print (df)
output:
Total highest_class
0 7 2
1 12 2
2 17 2
3 15 1
4 8 0
EDIT:
data = [(sum(item),item.index(max(item))) for item in list(zip(*dict.values()))]
print ('Total', 'highest_class')
for item in data:
print ("{:<10} {:<10}".format(item[0], item[1]))
output:
Total highest_class
7 2
12 2
17 2
15 1
8 0

Answer 2

As much as I understood what you want. This might help.
mydict = {
0: [1,2,3,4,7],
1: [20,4,6,9,0],
2: [4,6,8,2,1]
}
maxElement={"highest_class":None,
"Total":-1
}
for key,value in mydict.items():
print(sum(value) , maxElement["Total"])
if sum(value) > maxElement["Total"]:
maxElement["highest_class"] = key
maxElement["Total"] = sum(value)
print(maxElement)