I have a table in Excel from A1:A5
a
a
b
a
b
I want to find the row of the nth occurrence of the value 'a' using Excel Functions and not VBA
If I put in 1 into this function, I want to get 1.
If I put in 2 into this function, I want to get 2.
If I put in 3 into this function, I want to get 4
A solution that works is to add the following formula
=COUNTIF($A5:A5,"a") in B1 and then drag it down to B5.
I can then use =MATCH(C1,B1:B5,0) where C1 holds the variable n.
However is there a neater way without having to add extra columns?
=AGGREGATE(15,6,1/(myMatch=myRange)*ROW(myRange),Occurrence)
The 1/(..) portion of the formula converts non-matches to DIV/0! errors, which the AGGREGATE function can ignore. So the Smallest value will be the first matching value; etc.
this should work ARRAY FORMULA: CTRL + SHIFT + ENTER
=SMALL(IF(C1=$A$1:$A$5,ROW($A$1:$A$5)),$C$2)
Related
Hi I have the following two tables
I am trying to get the col
I am trying to automate Column E so that every time the data changes in cell D2 it would automatically get changed based on the shift patter that the Agent is assigned on that day.
I cannot used vlookup because it will obviously just take the first text found with for example 9am-5pm - all cells would be populated with Agent 3.
=INDEX($A$2:$A$10,AGGREGATE(15,3,($B$2:$B$10=D3)/($B$2:$B$10=D3)*ROW($B$2:$B$10)-1,COUNTIF(D$3:D3,D3)))
As an alternate approach to ZygD's answer.
It uses AGGREGATE. It checks for the values in the B column range to equal the value in column D and divides the result by itself, which will result in 1 if True and multiplies that by the row number. The result gives the row numbers of all TRUEs and checks for the Nth smallest value based on how many of the same agent are already found in your result list above and finally shows the value of that row in your range of values in column A.
Seems like this array formula in E3 in part does what you want (it is entered not using usual Enter key, but instead, Ctrl + Shift + Enter).
=INDEX($A$2:$A$10,SMALL(IF(D3=$B$2:$B$10,ROW($B$2:$B$10)-ROW($B$2)+1),COUNTIF($D$3:D3,D3)))
Use XLOOKUP() instead. Column position does not matter with this function.
I have these two rows with an image path.
In Columns D-H i have only one cell that his length is 2.
I need to find it and do formulas based on it, and I would prefer not writing 5 times "IF", any quick way to find it?
It's unclear what you're asking but it seems like you're just trying to figure out which column has a string with a length of 2 characters.
If this is the case use this formula (assuming your data starts in row 2 of the columns you mentioned):
=match(2,len(D2:H2),0) However, when you write this hit CTRL + SHIFT + ENTER
Which will give you {=match(2,len(D2:H2),0)} this is an array formula you must carry down. This will give you the relative column of the string with 2 as its length. Relative meaning, if the criteria is met in column D, it will return 1 (instead of 4).
If you want the value, just use an Index match like so, using the same CTRL + SHIFT + ENTER I mentioned earlier.
{=index(D2:H2,match(2,len(D2:H2),0))}
Here's a non-vba, non-CTE/Array formula way to do this:
=SUMPRODUCT((LEN(D1:H1)=2)*COLUMN(D1:H1))
Will spit out the number of the column that has a length of 2. If more than one column fulfills this criteria then you will get back garbage. So don't do that.
You can pop that into Index() to get the value that was hit:
=INDEX(A1:H1, 1, SUMPRODUCT((LEN(D1:H1)=2)*COLUMN(D1:H1)))
I am trying to get the max value of a column based on the Left function
What I am doing is the following :
These are the results I get when i write this into column C :
=MAX(LEFT(A:A, 2))
But what I truly want is to get in column C the max value of all column A not for each cell.
So the result should be in this case 90 for all rows.
What should be the formula here?
Just another option that gets entered normally:
=AGGREGATE(14,6,--LEFT($A$1:INDEX(A:A,MATCH("ZZZ",A:A)),2),1)
Array formulas will calculate the enitre referenced array. So care should be taken to limit the number of iterations to only the data set.
The $A$1:INDEX(A:A,MATCH("ZZZ",A:A)) part of the formula does that. It finds the last cell in column A with data in it and sets that as the upper bound. So in this instance the reference range is A1:A3. But, it will grow dynamically as data in Column A is added, so no need to change the formula each time data is added.
Update 2
Here is another solution which I think is better than my original (below)
=INT(SUMPRODUCT(MAX(SUBSTITUTE(A:A,"-",".")*1)))
it can be entered as normal (just Enter)
Orignal Answer
You need numbers and arrays
=MAX(IFERROR(LEFT(A:A,2)*1,0))
Let's break this down. Multiplying by turns your strings into numbers - since Left only returns a string
LEFT(A:A,2)*1
Unfortunately this method returns #Value if you multiply an empty string by 1. You will definitely have some empty strings in the range A:A so we wrap the whole thing with an IFERROR function.
IFERROR(LEFT(A:A,2)*1,0)
Now we still need excel to treat this as an array (i.e. a whole column of numbers, rather than just one number). So we put the MAX formula in and enter it with Ctrl+Shift+Enter rather than just Enter. The result is that the formula looks like this in the formula bar
{=MAX(IFERROR(LEFT(A:A,2)*1,0))}
which would return 90 in your example, as required
Update 1
If you are using Excel 2013 or later, you can also use the NUMBERVALUE function
=MAX(NUMBERVALUE(LEFT(A:A,2)))
again, enter it with Ctrl+Shift+Enter
I currently have this:
=SUMPRODUCT(SUMIF(A:A;Index(List;;1);B:B))
Column A is a list of names, column B is a list of values for each names. The named range List has 2 columns, the first one are names and the second one are boolean values (0 or 1).
My formula actually works to return the sum of every column B values of its corresponding name in the A column IF that name is in the first column of my named range List. It works fine.
However, I would like to filter that to only include names from List that have the boolean value equal to 1 (ie. Index(List;;2) = 1.
How is this possible?
This is what I tried but it gives me a #REF! error:
=SUMPRODUCT(SUMIF(A:A;Index(List;;1)*Index(List;;2);B:B))
Probably best to switch to an array formula**:
=SUM(SUMIF(A:A,IF(INDEX(List,,2),INDEX(List,,1)),B:B))
**Array formulas are not entered in the same way as 'standard' formulas. Instead of pressing just ENTER, you first hold down CTRL and SHIFT, and only then press ENTER. If you've done it correctly, you'll notice Excel puts curly brackets {} around the formula (though do not attempt to manually insert these yourself).
Since your Named Range consists of discontinous ranges, when INDEXing it you will need to include INDEX's 4th parameter (area_num) in order to clarify which of the ranges ($B$2:$B$100 or $L$2:$W$100) you wish to refer to, e.g.:
=INDEX(List,60,1,**2**)
which will return the value in cell L61.
Regards
I have a simple worksheet with 2 columns
I want to get all the results(on column "H") (I can get only the first occurrence,I want to know if I can get the others) that contains the value from cell G1, is that possible without a macro ? any way of doing it would be appreciated...Any ideas?
You can use ROW() and SMALL() to get those instead of MATCH() since this always gets the first match.
=IFERROR(INDEX($C$4:$C$7,SMALL(IF($D$4:$D$7=$G$1,ROW($D$4:$D$7)-(ROW()-1)),ROWS($D$4:D4))),"Null")
So, if the array $D$4:$D$7=$G$1 returns true (i.e. the value equals that in G1), you will get the row numbers of these values, in this case, you will get 4 and 6. All the other will return False.
After some processing with -(ROW()-1), the 4 and 6 become 1 and 3. those two values are what will be fed to the INDEX.
SMALL() then picks the smallest, starting with the 1st (you get 1 from ROWS($D$4:D4)) and when you drag the formula down, the ROWS become ROWS($D$4:D5) which gives 2, and SMALL ends up taking the 2nd smallest value, which is 3.
EDIT: Forgot to mention. You have to array enter the above formula. To do this, type the combination keys of Ctrl+Shift+Enter after typing the formula (edit the formula again if necessary) instead of Enter alone.