Can I swap out the library used by a binary with a wrapper when building a third-party crate? - rust

Let's say there is a vendored third-party cargo project consisting of a library plem and a binary plem_main that I want to extend with some functionality of my own. Crucially, the functionality needs to go in the library plem, not the binary plem_main (which can stay the same). I could write a wrapper my_plem around the library that offers the same interface to the binary, but with the extra functionality included. The project would be set up like this:
.
├── Cargo.toml
├── my_plem
│   ├── Cargo.toml
│   └── src
│   └── lib.rs
└── third-party
├── plem
│   ├── Cargo.toml
│   └── src
│   └── lib.rs
└── plem_main
├── Cargo.toml
└── src
└── main.rs
my_plem/src/lib.rs would depend on things in third-party/plem/src/lib.rs and reexport or overwrite the functions exported by the latter. Is there a good way to get cargo to build the binary plem_main on top of my_plem instead of plem?
"Best" here means that the solution has no or minimal merge conflicts when updating plem in my project and doesn't duplicate the code of plem_main. Ideally it does not touch third-party at all.

Related

Can I have a Cargo workspace with two binaries relying on a library where only one binary enables a feature of the library?

I have a Cargo workspaces project with the structure:
├── src
├── lib
│   └── Cargo.toml
├── tools
│   ├── src/bin/foo.rs
│   └── Cargo.toml
└── Cargo.toml
., lib and tools are my three workspace members. lib has a feature that enables tracing of the execution of a performance-sensitive function. As this feature adds performance overhead, the main binary should not enable it, but the foo binary is a testing tool which uses it.
However, Cargo workspaces take the union of the features of the two binaries, so the main binary ends up including the feature anyway.
How can I fix this?

Where to place "common command line" tools in a standard library Rust package structure?

I'm developing a library. For internal development experiments I need a bunch of binary command line entry points that I can execute. I'm using a standard project layout like described in this answer under "Flexible".
What I'd like to achieve: Certain functionality in my command line tools is similar, and I'd like to move that out into its own module. Ideally I'd like to introduce a cli_common.rs module containing some helper functions here in the package structure:
.
├── Cargo.toml
└── src
├── bin
│   ├── cli_common.rs
│   ├── run_foo.rs (uses cli_common)
│   └── run_bar.rs (uses cli_common)
├── lib.rs
└── <various-lib-related-sub-modules>
This doesn't seem to be possible, because the compiler expects every module under bin to have a main function.
This suggest that I have to move the functionality of cli_common.rs into the library itself. This doesn't feel great, because it mixes "peripheral" logic with "core" logic, and I'd like to avoid having this functionality as part of the public interface of the library.
Is there a trick to have such a cli_commons.rs without having to move it into the library?
I found a solution based on this answer.
For simple cases, an extra crate can be avoided by moving the cli_common.rs somewhere, where the compiler doesn't expect a main. In my example I modified the structure for instance to:
.
├── Cargo.toml
└── src
├── bin
│   ├── cli_common.rs
│   │   └── cli_common.rs
│   ├── run_foo.rs
│   └── run_bar.rs
├── lib.rs
└── <various-lib-related-sub-modules>
Within run_foo.rs and run_bar.rs, I can now use mod combined with a #[path] attribute:
#[path="cli_common/cli_common.rs"]
mod cli_common;
For more complex scenarios, going for a separate crate may be preferred.

Workspace optional dependencies (std & no_std)

I am developing a code for my school's rocketry team and I have two programs, one meant to flash the on-board computer and another to run some data analysis on the flight data. The chip code uses no_std while the data analysis program uses std. The data-analysis code will run on my PC, and the chip code will run on the chip.
Here is my workspace root Cargo.toml and my project graph:
[workspace]
members = [
"chip",
"data-analysis",
]
.
├── Cargo.lock
├── Cargo.toml
├── chip
│   ├── Cargo.toml
│   ├── memory.x
│   ├── openocd.cfg
│   ├── openocd.gdb
│   └── src
│   └── main.rs
├── data-analysis
│   ├── Cargo.toml
│   └── src
│   └── main.rs
├── README.md
└── resources
├── 3m.mkd
├── data-stm32f103c8t6.pdf
├── links.txt
├── reference-stm32f103xx.pdf
├── schematic-stm32f103c8t6.png
└── todo.txt
I have decided to use a workspace to organize my code. When I attempt to build the workspace, I get the error:
error[E0463]: can't find crate for `std`
|
= note: the `thumbv7m-none-eabi` target may not support the standard library
= note: `std` is required by `data_analysis` because it does not declare `#![no_std]`
= help: consider building the standard library from source with `cargo build -Zbuild-std`
When I compile with cargo build -Zbuild-std I get the error:
error[E0463]: can't find crate for `panic_abort`
error[E0658]: use of unstable library feature 'restricted_std'
|
= help: add `#![feature(restricted_std)]` to the crate attributes to enable
However I need no_std and not restricted_std.
I understand that dependencies for all files are stored in Cargo.lock and presumably that's why it is producing this error. My question is, how do I express to the compiler that I need std for data_analysis but not for chip code? Should I even be using workspaces over just using one package with multiple binaries and using [features] in the Cargo.toml?
It seems like you're trying to complile data_analysis with the same target as chip. I recommend just getting rid of the root Cargo.toml and compiling the respective ones in the folders. You could make a Makefile to automate this easily

How to Rust macro in another project?

Hi is it possible to use a custom declarative macro across multiple projects? If yes, how?
The project tree structure looks like this:
(the macro is defined in proj1)
.
├── proj1
│   ├── Cargo.toml
│   └── src
│   └── main.rs
├── proj2
│   ├── Cargo.toml
│   └── src
│   └── main.rs
└── proj3
├── Cargo.toml
└── src
└── main.rs
proj1 would need to be a hybrid bin/lib crate for you to be able to use a macro from it. This would mean moving your macro to a proj1/src/lib.rs. However, I suggest you move common functionality to a different crate, let's call it lib1. The rest has already been described in detail, so here is a quick demo only:
cargo new --lib lib1
cargo new proj2
echo 'lib1 = { path = "../lib1" }' >>proj2/Cargo.toml
echo '#[macro_export] macro_rules! mahcro { () => { println!("Hello macro.") } }' >lib1/src/lib.rs
echo 'use lib1::mahcro; fn main() { mahcro!() }' >proj2/src/main.rs
cargo run --manifest-path proj2/Cargo.toml
By the way, workspaces are really useful in this kind of setup, I recommend you read up on them.

What are examples and what are they used for?

The directory layout of a Rust project should look like this (source)
.
├── Cargo.lock
├── Cargo.toml
├── benches
│ └── large-input.rs
├── examples
│ └── simple.rs
├── src
│ ├── bin
│ │ └── another_executable.rs
│ ├── lib.rs
│ └── main.rs
└── tests
└── some-integration-tests.rs
What is the file simple.rs under examples? How do I execute it? How should the file look like?
Examples are useful in library crates to show how the crate is used.
An example can be an executable with a main method or a library; it can either be in a single file examples/example-name.rs or consist of several files in a subdirectory examples/example-name/, with the main method in main.rs. To compile a library example you need to specify its crate type in Cargo.toml:
[[example]]
name = "example-name"
crate-type = ["lib"]
Examples are compiled by cargo test to ensure that they are up to date with the crate. You can run a specific executable example by
cargo run --example <example-name>
and selectively build any example with
cargo build --example <example-name>
This is documented in the Cargo Reference.

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