Ti-Basic how to do Raycasting ti-84 plus ce - raycasting

I am trying to create a game similar to doom on my ti-84 plus ce using pure ti-basic, and I have tried several raycasting codes, but most throw up multiple errors, and the ones that dont error are incredibly slow and dont actually do things or are very inconsistent. The most common error is ERROR: INVALID DIMENSION, which usually occurs after one frame is drawn (so 20 seconds or so).
I guess there are a few things I am asking:
How should I go about making a usable raycasting program? (Examples of code please). How can I optimize programs to make them as fast as possible?
Below are the three codes I used to try to do raycasting, 2 made by iPhoenix and one made by Vaelus. I have been working on my own but i am fairly busy with school and such so it is slow.
4→Xmin
24*4+3→Xmax
-1→Ymin
1→Ymax
1.5→S
1.5→T
dim([A])→L₁
L₁(1)→H
L₁(2)→W
seq((I-12.5)*4°+45°,I,1,24)→L₁
1→R
While R
For(I,1,24)
0→C
S→U
T→V
0→D
While C=0 and 1≤int(U) and int(U)≤W and 1≤int(V) and int(V)≤H
L₁(I)→A
If A>0°:Then
If A>90°:Then
-int(-U-1)→P
int(V+1)→Q
Else
int(U+1)→P
int(V+1)→Q
End
Else
If A>-90°:Then
int(U+1)→P
-int(-V-1)→Q
Else
-int(-U-1)→P
-int(-V-1)→Q
End
End
If abs((P-U)/cos(A))<abs((Q-V)/sin(A)):Then
D+abs((P-U)/cos(A))→D
V+(P-U)*tan(A)→V
P→U
Else
D+abs((Q-V)/sin(A))→D
U+(Q-V)/tan(A)→U
Q→V
End
If int(U)≥1 and int(U)≤W and int(V)≥1 and int(V)≤H:Then
If [A](int(U),int(V))
1→C
End
If -int(-U+1)≥1 and -int(-U+1)≤W and -int(-V+1)≥1 and -int(-V+1)≤H:Then
If [A](-int(-U+1),-int(-V+1))
1→C
End
End
I*4→N
Line(N,1,N,-1,0)
Line(N+1,1,N+1,-1,0)
Line(N+2,1,N+2,-1,0)
Line(N+3,1,N+3,-1,0)
If C:Then
tan⁻¹(([A](int(U),int(V))+[A](-int(-U+1),-int(-V+1)))/D)/32°→Z
Line(N,Z,N,-Z)
Line(N+1,Z,N+1,-Z)
Line(N+2,Z,N+2,-Z)
Line(N+3,Z,N+3,-Z)
End
End
getKey→K
(L₁(12)+L₁(13))/2→F
If K=25:Then
S+0.1*cos(F)→S
T+0.1*sin(F)→T
End
If K=34:Then
S-0.1*cos(F)→S
T-0.1*sin(F)→T
End
If K=24:Then
L₁+2°→L₁
End
If K=26:Then
L₁-2°→L₁
End
If K=45
0→R
End
0→Xmin
{BLACK,DARKGRAY,GRAY,MEDGRAY,LTGRAY,WHITE,WHITE→L₁
70→Xmax
-20→Ymin
20→Ymax
90→θ
310→R
119→S
219→T
For(A,1,51,-1
For(B,1,100,50
Pxl-On(163-A,263-B,GRAY
Pxl-On(163-B,263-A,GRAY
Pxl-On(164-A,264-B,GRAY
Pxl-On(110+A,210+B,MEDGRAY
Pxl-On(110+B,210+A,MEDGRAY
Pxl-On(109+B,209+A,MEDGRAY
Pxl-On(109+A,209+B,MEDGRAY
End
End
For(A,1,10
For(B,1,10
If [A](A,B
Then
For(C,1,5
For(D,1,5
Pxl-On(110+(5A-4+C),210+(5B-4+D),BLACK
End
End
End
End
End
Repeat Ans
For(A,­6,13.5,.45
Line(Xmin,A,Xmax,A,WHITE
End
DelVar N
Pxl-Off(S,T
For(A,70-R,1-R,-­1
N+1→N
DelVar C
cos(A→P
sin(A→Q
Repeat K=45 or C>20
C+1→C
pxl-Test(int(S+CP),int(T+CQ
End
If C<20:Then
int(C/3→V
int(40/C)/2→W
If W>4
4→W
For(B,­-W,W
For(D,1,2
Pt-On(N,B,D,L₁(V
End
End
End
End
Pxl-On(S,T
Repeat Ans
getKey
End
Pxl-Off(S,T
Ans→K
If K=24
R-45→R
If K=26
R+45→R
R-220→θ
If K=25
Then
int(S-3cos(θ→S
int(T+3sin(θ→T
Else
If K=34
Then
int(S+3cos(θ→S
int(T-3sin(θ→T
End
End
Pxl-On(S,T
Pause
End
ZStandard
ZSquare
GridOff
AxesOff
LabelOff
BorderColor 4
BackgroundOff
{Black,DarkGray,Gray,MedGray,LtGray->L1
For(A,1,10
For(B,1,10
If [A](A,B
Then
For(C,1,5
For(D,1,5
Pxl-On(115+5A-C,5B-D,Black
End
End
End
End
End
122->A
5->B
DelVar DRepeat K=45
For(theta,~3,3,.1
Line(12+theta,3,12+theta,10,0
End
Circle(12,6,1.8,Black
Line(10,6,14,6,1,Black,1
Line(12,4,12,8,1,Black,1
For(theta,~40+D,40+D
If not(remainder(abs(theta-D),10
Line(12+2.5cos(theta-2D),6+2.5sin(theta-2D),12+2cos(theta-2D),6+2sin(theta-2D),1,Red+(theta=D),1
sin(theta->U
cos(theta->V
DelVar NRepeat Ans or N=10
N+1->N
int(A+NU->I
int(B+NV->J
pxl-Test(I,Ans
End
(theta-D)/5
Line(Ans,5,Ans,~5,0
If N!=10
Line(Ans,(10-N)/2,Ans,~(10-N)/2,1,L1(1+min(int(N/2),dim(L1
End
If not(pxl-Test(A,B
Pxl-On(A,B,Red
getKey
Repeat Ans
getKey
End
Ans->K
Pxl-Off(A,B
D-5(K=11->D
D+5(K=15->D
D-2(K=12->D
D+2(K=14->D
int(A+(K=13)2sin(D)+(K=23)5sin(D->A
int(B+(K=13)2cos(D)+(K=23)5cos(D->B
End
RecallGDB 0```

Related

application.onkey press not working while an infinite loop is running (python accepts that why not vba)

i am currently studying engineering and for my inf project i decided to do a tetris clone started trying to learn python but sadly my college demands that we use excel vba
anyways we started with 1 single square not a whole element and coded it falling down and then a new one creating and falling down too and so on which using an infinite loop proved quite easy
then for the moving left and right part we decided to use the application.onkey method but quickly realised that for some reason this doesnt work while the loop is active but does while its inactive
any help
its a german school so our comments are in german
here our main code
stein.color = 4
stein.posx = 0
stein.posy = 4
'2.3.2:stein im grid einfugen
grid(stein.posx, stein.posy) = stein.color
'2.3.3:grid zeichnen
gridzeichnen
'3 : main loop
Do While gamestate
'3.1:checken ob platz frei ist
If checkplatz(stein.posx, stein.posy) Then
'3.1.1: falls ja dann fallen
warten (50)
grid(stein.posx, stein.posy) = 2
stein.posx = stein.posx + 1
' hinweis: im grid schreiben/anzeigen
grid(stein.posx, stein.posy) = stein.color
gridzeichnen
Else:
'3.1.2:falls nein dann neuen stein erstellen
'3.1.2.1: aber zuerst muss man checken ob die maximale hohe erreicht wurde (also obwohl er
'gerade erst erstellt wurde nicht fallen konnte)
If stein.posx = 0 Then
'hinweis: print grid nur damit man besser weiss was der program gemacht hat und ob er
'irgendwas falsch gemacht hat
printgrid
Exit Do
End If
' 3.1.2.2: falls nicht dann neuen stein erstellen
' hinweis:hier braucht man nicht die farbe neu erstellen da momentarn die farbe immer
' gleich(wird sich spater andern)
stein.posx = 0
stein.posy = 4
grid(stein.posx, stein.posy) = stein.color
gridzeichnen
End If
Loop

Can't access [myself] of myself in nested ask

I want to calculate the mean of the weight of some of the links, called "fs", of a turtle (let's call it turtle A).
In particular, I need to select the turtles that have a "C" breed of link with another turtle, B, and calculate the mean of the weights of fs links of turtle A with this agentset.
I am doing it with a reporter, mean-fs.
To select the links I want to calculate the mean of, I need to nest some ask and access [myself] of myself, which should be turtle A.
I've tried passing who of turtle A to the reporter mean-fs, but there is the error "expected literal value".
I've tried with [myself] of myself but it returns self.
Here is the part of the code I'm talking about:
to go
ask turtles
[move
set-conv]
end
to set-conv
ask other turtles in-cone 4 120
[...
if (C-neighbors != nobody)[add-partecipant]
]
end
to add-partecipant
let turtle1 myself
if ( mean-fs [ turtle1 ] > 0 )
[ ... ]
end
to-report mean-fs [turtle1]
let w-list []
ask C-neighbors
[ set w-list lput [w] of f-with turtle1 w-list]
report mean w-list
end

How do I search and replace in vi to eliminate a random number of random characters preceding a known string?

I have text files which look like this:
0 298047498 /directory1/app/20170417/file1.blob 0 f191
e 6569844 /directory1/app/20170417/file2.blob 0 f191
344 /directory1/app/20170417/file3.blob 0
8946 /directory1/app/20170417/file4.blob 0
196496 /directory1/app/20170417/file5.blob 0
9 182340752 /directory1/app/20170417/file6.blob 0 f191
68802 /directory1/app/20170417/file7.blob 0
I want to remove everything prior to the first / and everything after the file extension.
Results should look like this:
/directory1/app/20170417/file1.blob
/directory1/app/20170417/file2.blob
/directory1/app/20170417/file3.blob
Is there a way to do this using vi search and replace?
This type of question may be better placed here: https://vi.stackexchange.com/
But for now:
Yout can e.g. use a simple vim-macro, in which you collect all the key-strokes you need to edit one line and repeat this macro as many times as you need it.
Here are simply the key-strokes for one line:
dt/WD
d = delete..
t = ..till the first "/"
W = [shift]+[w] jumps to the next Word (after the "file-location-string")
D = [shift]+[d] deletes till the end of the current line
If you want to record this as a macro, do the following, with the keystrokes from above, inbetween - like this:
qmdt/WD[home][down]q
qm = start the recording of a macro in buffer "m"
... key-strokes from above
[home][down] = key [home] followed by [arrow down]-key, to move into the next line (for convenince)
q = end up the macro-recording
Now execute that macro with:
#m
And if you added the [down] key, you can do something like:
7#m
with which you fire your macro 7 times, for all your 7 lines.

Multi-Threading and Parallel Processing in Matlab

I'm coding a project in Matlab, however I want the great efficiency and speed of my execution, for that sake, I want to use parallel processing threads in Matlab as I have multiple objects working or changing their states in a for loop. Is Multi-Threading is appropriate for this purpose? If so, where can I take start or can create a simple thread?
My Code:
% P=501x3 array
for i=1:length(P)
% I used position for example's sake, meaning object changing its state
Object1.position=P(i,:);
Object2.position=P(i,:);
Object3.position=P(i,:);
Object4.position=P(i,:);
% Mulitple objects changing their state on each iteration, after some calculation/formulation.
end
What I need is the basic structure of Multi-Threads according to my scenario if Threading is appropriate in my case. More suggestions for Parallel-Execution or fast processing are welcomed.
Edit1: Parray:
P =
-21.8318 19.2251 -16.0000
-21.7386 19.1620 -15.9640
-21.6455 19.0988 -15.9279
-21.5527 19.0357 -15.8918
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-20.9078 18.5947 -15.6377
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-20.6340 18.4061 -15.5281
-20.5432 18.3432 -15.4915
-20.4524 18.2804 -15.4548
-20.3619 18.2176 -15.4181
-20.2715 18.1548 -15.3814
-20.1813 18.0921 -15.3446
-20.0913 18.0293 -15.3078
-20.0015 17.9666 -15.2709
-19.9118 17.9039 -15.2340
-19.8223 17.8412 -15.1970
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-19.1122 17.3406 -14.9001
-19.0241 17.2781 -14.8628
-18.9363 17.2156 -14.8254
-18.8486 17.1532 -14.7881
-18.7610 17.0907 -14.7507
-18.6736 17.0283 -14.7132
-18.5864 16.9659 -14.6758
-18.4994 16.9035 -14.6383
-18.4124 16.8412 -14.6007
-18.3257 16.7788 -14.5632
-18.2391 16.7165 -14.5255
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-18.0663 16.5919 -14.4502
-17.9802 16.5296 -14.4125
-17.8942 16.4673 -14.3748
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-14.8936 14.2355 -12.9979
-14.8127 14.1737 -12.9593
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-14.5707 13.9885 -12.8432
-14.4903 13.9267 -12.8044
-14.4100 13.8650 -12.7657
-14.3299 13.8033 -12.7269
-14.2498 13.7416 -12.6881
-14.1699 13.6799 -12.6493
-14.0901 13.6182 -12.6105
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-13.2982 13.0017 -12.2216
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-12.9845 12.7553 -12.0657
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-12.6725 12.5090 -11.9097
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-12.2848 12.2012 -11.7144
-12.2075 12.1397 -11.6754
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-12.0533 12.0166 -11.5972
-11.9764 11.9550 -11.5581
-11.8995 11.8935 -11.5190
-11.8228 11.8320 -11.4799
-11.7461 11.7705 -11.4408
-11.6695 11.7089 -11.4017
-11.5930 11.6474 -11.3626
-11.5166 11.5859 -11.3235
-11.4403 11.5244 -11.2844
-11.3641 11.4629 -11.2453
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-11.2120 11.3398 -11.1671
-11.1360 11.2783 -11.1280
-11.0602 11.2168 -11.0889
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-10.9087 11.0938 -11.0106
-10.8331 11.0323 -10.9715
-10.7576 10.9708 -10.9324
-10.6821 10.9093 -10.8933
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-10.5315 10.7863 -10.8150
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-9.6343 10.0482 -10.3460
-9.5600 9.9866 -10.3069
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-9.4117 9.8636 -10.2289
-9.3376 9.8021 -10.1898
-9.2636 9.7405 -10.1508
-9.1897 9.6790 -10.1118
-9.1158 9.6174 -10.0728
-9.0420 9.5559 -10.0338
-8.9683 9.4944 -9.9948
-8.8946 9.4328 -9.9558
-8.8210 9.3712 -9.9169
-8.7474 9.3097 -9.8779
-8.6739 9.2481 -9.8390
-8.6005 9.1865 -9.8000
-8.5272 9.1250 -9.7611
-8.4539 9.0634 -9.7222
-8.3806 9.0018 -9.6833
-8.3074 8.9402 -9.6444
-8.2343 8.8786 -9.6056
-8.1612 8.8170 -9.5667
-8.0882 8.7554 -9.5279
-8.0152 8.6938 -9.4890
-7.9423 8.6322 -9.4502
-7.8695 8.5705 -9.4114
-7.7967 8.5089 -9.3727
-7.7239 8.4473 -9.3339
-7.6513 8.3856 -9.2951
-7.5786 8.3240 -9.2564
-7.5060 8.2623 -9.2177
-7.4335 8.2006 -9.1790
-7.3610 8.1389 -9.1403
-7.2885 8.0772 -9.1017
-7.2161 8.0155 -9.0630
-7.1438 7.9538 -9.0244
-7.0715 7.8921 -8.9858
-6.9992 7.8304 -8.9472
-6.9270 7.7687 -8.9086
-6.8548 7.7069 -8.8701
-6.7827 7.6452 -8.8316
-6.7106 7.5834 -8.7931
-6.6385 7.5217 -8.7546
-6.5665 7.4599 -8.7161
-6.4945 7.3981 -8.6777
-6.4226 7.3363 -8.6393
-6.3507 7.2745 -8.6009
-6.2788 7.2127 -8.5625
-6.2070 7.1508 -8.5242
-6.1352 7.0890 -8.4858
-6.0635 7.0271 -8.4475
-5.9917 6.9653 -8.4093
-5.9200 6.9034 -8.3710
-5.8484 6.8415 -8.3328
-5.7768 6.7796 -8.2946
-5.7052 6.7177 -8.2564
-5.6336 6.6558 -8.2183
-5.5621 6.5938 -8.1802
-5.4906 6.5319 -8.1421
-5.4191 6.4699 -8.1040
-5.3476 6.4079 -8.0660
-5.2762 6.3459 -8.0280
-5.2048 6.2839 -7.9900
-5.1334 6.2219 -7.9521
-5.0621 6.1599 -7.9142
-4.9908 6.0978 -7.8763
-4.9194 6.0358 -7.8384
-4.8482 5.9737 -7.8006
-4.7769 5.9116 -7.7628
-4.7057 5.8495 -7.7250
-4.6344 5.7874 -7.6873
-4.5632 5.7253 -7.6496
-4.4920 5.6631 -7.6119
-4.4209 5.6010 -7.5743
-4.3497 5.5388 -7.5367
-4.2786 5.4766 -7.4992
-4.2074 5.4144 -7.4616
-4.1363 5.3522 -7.4241
-4.0652 5.2899 -7.3867
-3.9941 5.2277 -7.3492
-3.9231 5.1654 -7.3118
-3.8520 5.1031 -7.2745
-3.7809 5.0408 -7.2372
-3.7099 4.9785 -7.1999
-3.6389 4.9161 -7.1626
-3.5678 4.8538 -7.1254
-3.4968 4.7914 -7.0883
-3.4258 4.7290 -7.0511
-3.3548 4.6666 -7.0140
-3.2838 4.6041 -6.9770
-3.2128 4.5417 -6.9400
-3.1418 4.4792 -6.9030
-3.0708 4.4167 -6.8661
-2.9998 4.3542 -6.8292
-2.9288 4.2917 -6.7923
-2.8578 4.2291 -6.7555
-2.7868 4.1666 -6.7187
-2.7158 4.1040 -6.6820
-2.6448 4.0414 -6.6453
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Ahsan,
I think parfor might be what you're looking for. It requires the Parallel Computing Toolbox (PCT) to use. It works like this:
parfor i = 1:length(P)
Object1.position = P(i,:);
end
Also, I would recommend using indexed structure fields, as I've done in the example below, as it increases the flexibility of any code that you write. Let me know if this doesn't work for you, and we'll try something else. I know another technique, but it's much messier. Good luck!
parfor i = 1:length(P)
Object(i).position = P(i,:);
end
Edit: Ok, this may not work because parfor is pretty particular. But it the general concept should apply to the problem you're trying to solve. I can't be more specific without knowing more about your specific problem. The key point is, inside a parfor, you must iterate something (Object, below) by the parfors iterator (i, below) and assign that thing a value. I'm not sure if you can use a for-loop inside a parfor, so the first example below may break. The point is, this is how you do parallel processing in MATLAB. Try this:
parfor i = 1:4
Object(i).position = P(i,:);
end
Edit 2:
parfor i = length(P)
Object1 = struct();
Object1.position = P(i, :);
end
Edit 3: Ok, one last thing. You can't use "sliced" structs (structs with fields) as input or output from a parfor so you have to do this:
parfor i = 1:length(P)
positionArray1(i) = P(i, :);
end
Object1 = struct('position', positionArray1);

Copula Value At Risk

Has anyone of you any experience in copula Value At Risk with Matlab?
In Matlab I've written this code:
copula='Normale, Normale';
B=handles.array;
[~, n]=size(handles.array);
for i=1:n
phat(:,i)=mle(handles.array(:,i))
end
p_1=normcdf(handles.array(:,1), phat(1,1), phat(2,1));
p_2=normcdf(handles.array(:,2), phat(1,2), phat(2,2));
handles.p1=p_1;
handles.p2=p_2;
handles.matrici.Mdati=[handles.array handles.port p_1 p_2];
U=[handles.p1 handles.p2];
handles.U=U;
guidata(handles.figure1, handles);
and
copula='Normale';
RHOHAT=copulafit('Gaussian', handles.U);
figure(1)
scatterhist(handles.U(:,1), handles.U(:,2));
for i=1:100
U=copularnd('Gaussian', RHOHAT, 10000);
X=[norminv(U(:,1),0,1) norminv(U(:,2),0,1)];
port_ret=X*handles.w';
axes(handles.axes1)
plot(port_ret, 'k')
legend('Rendimenti simulati')
My problem is I don't want a single value for VaR but n values to be plotted against returns.
Can anyone help me??

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