How to delete a certain part of an Image? - python-3.x

Question

I have an image:
Original Image
I want to remove the grey mesh part of the image without affecting the rest of the image i.e., the part inside the black circle.
I have written a code for that
import cv2
import numpy as np
from PIL import Image
imag = Image.open('results.jpg')
imag.show()
pixelMap = imag.load()
img = Image.new( imag.mode, imag.size)
pixelsNew = img.load()
for i in range(img.size[0]):
for j in range(img.size[1]):
if (( pixelMap[i,j]> (200,0,0)) and (pixelMap[i,j]< (240,0,0))):
pixelsNew[i,j] = (255,255,255)
else:
pixelsNew[i,j] = pixelMap[i,j]
img.show()
with this code I have got the following output image:
Output Image
But, Some of the pixels inside the black circle were also changed to white, which is not what I want. I would like to know how can this problem be solved.

Answer 1

You can find the indices of black circle and assign values to the pixels that are either to the left or to the right of black circle. Below is the sample code for this
import cv2
import numpy as np
# read the image
img = cv2.imread('original.png')
cv2.imshow("Image", img)
# convert image to numpy array and also to grayscale
img = np.array(img)
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
# get height and width of image
[rows, cols] = gray.shape
# now extract one row from image, find indices of black circle
# and make those pixels white which are to the left/right
# of black cirlce
for i in range(rows):
row = gray[i, :] # extract row of image
indices = np.where(row == 0) # find indices of black circle
indices = indices[0]
# if indices are not empty
if len(indices) > 0:
# find starting/ending column index
si = indices[0]
ei = indices[len(indices)-1]
# assign values to the range of pixels
img[i, 0:si-1] = [255, 255, 255]
img[i, ei+1:] = [255, 255, 255]
# if indices is empty then make whole row white
else:
img[i,:] = [255, 255, 255]
cv2.imshow("Modified Image", img)
cv2.waitKey(0)
cv2.destroyAllWindows()
Input Image
Output Image